Solve. Suppose that 1,000 students took a math examination wherein the maximum score that they can obtain is 100. Their average score is 70 with a standard of the deviation of 5. How many of the students obtained a score from 70 to 95?

Answer:

prolly like 689

Step-by-step explanation:

As per the given data, approximately 499 of the 1,000 students obtained a score from 70 to 95.

A standardized score is an example of a z-score. A z-score is a measure of how far a data point is from the mean in a distribution.

To solve this problem, we need to calculate the number of students who obtained a score from 70 to 95.

First, we need to calculate the z-scores for these two scores using the formula:

z = (score - mean) / standard deviation

For a score of 70:

z = (70 - 70) / 5 = 0

For a score of 95:

z = (95 - 70) / 5 = 5

Next, we need to find the area under the standard normal distribution curve between these two z-scores using a standard normal distribution table or calculator.

The area between z = 0 and z = 5 is approximately 0.499, or 49.9%.

Finally, we can calculate the number of students who obtained a score from 70 to 95 by multiplying this proportion by the total number of students:

Number of students = proportion x total number of students

Number of students = 0.499 x 1000

Number of students ≈ 499

Therefore, approximately 499 of the 1,000 students obtained a score from 70 to 95.

For more details regarding standard deviation, visit:

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Part D

What do the measures of angles BDA and BEA and the fact that AD and AE are radii of circle A tell us about BD and BE



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