Exact form is x = 86/11
Mixed number form is x = 7 whole number 9/11
heyyy.... can someone pls help asap. Rearrange the formula to write r in terms of P and pi.
[tex]p = 2r + \pi \: r[/tex]
Step-by-step explanation:
p = 2r + pi×r
p = r(2 + pi)
r = p/(2 + pi)
Answer:
r = [tex]\frac{p}{2+\pi }[/tex]
Step-by-step explanation:
p = 2r + πr ← factor out r from each term
p = r(2 + π) ← divide both sides by (2 + π )
[tex]\frac{p}{2+\pi }[/tex] = r
Write 0.15 as a fraction in the simplest form.
Answer:
3/20
Step-by-step explanation:
0.15 = 15/100
This is not simplified though :
15/100 ÷ 5/5 = 3/20
This is simplified
Hope this helped and brainliest please.
What is another name for an X-Value
9TH GRADE ALGEBRA 1
A-output values
B- range
C- domain
D- function
Answer:
see explanation
Step-by-step explanation:
the set of x- values ( the input ) are called the domain
Answer:
domain
Step-by-step explanation:
as the y values is the range
What is the value of a?
A. 12
B. 15
C. 17.25
D. 21.25
Answer:
C 17.25
Step-by-step explanation:
i think aanswer its c
answer this now for 10
Answer:
15
Step-by-step explanation:
First lets simplify the left side :
5/12 + 5/12 + 5/12 = 15/12
15/12
To make the right side into 15/12 we must multiply it by 15:
15 × 1/12 = 15/12
So the blank is 15
Hope this helped and brainliest please.
Answer:
15/1
Step-by-step explanation:
you simply add the 5's only not the 12. when u multiply 1 and 12 u get 12 and when you multiply 15 and 1 you get 15
In each problem below, find the total area of the shaded regions.
Thanks!
The area of the shaded region = area of semicircle - area of triangle ACB = 11.32 cm².
What is the Area of a Semi-circle and Triangle?Area of a triangle = 1/2(base)(height).
Area of a semi-circle = 1/2(πr²).
m∠ACB is a right triangle based on the central angle theorem. Therefore, ΔACB is a right triangle.
Radius of circle = OC = 4 cm
CB = 4 cm
Diameter AB = 2(4) = 8 cm
Using the Pythagorean theorem, find AC in ΔACB:
AC = √(AB² - CB²)
AC = √(8² - 4²)
AC ≈ 6.9 cm
Area of ΔACB = 1/2(CB)(AC)
Area of ΔACB = 1/2(4)(6.9)
Area of ΔACB ≈ 13.8 cm²
Area of semicircle = 1/2(πr²) = 1/2(π)(4²)
Area of semicircle ≈ 25.12 cm²
Area of the shaded region = area of semicircle - area of triangle ACB = 25.12 - 13.8
Area of the shaded region = 11.32 cm²
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What is the value of log 256/ log 1024
Answer:
0.8
Step-by-step explanation:
The change of base formula for logarithms can be used to find this value exactly. (Your calculator can also tell you.)
[tex]\log_b(a)=\dfrac{\log(a)}{\log(b)}[/tex]
__
Using this relation with the given numbers, we have ...
[tex]\dfrac{\log(256)}{\log(1024)}=\dfrac{\log(2^8)}{\log(2^{10})}=\dfrac{8\cdot\log(2)}{10\cdot\log(2)}=\dfrac{8}{10}\\\\\boxed{\dfrac{\log(256)}{\log(1024)}=0.8}[/tex]
It+is+said+60%+of+families+own+a+pet. +of+a+sample+of+95+families,+70+owned+pets. +perform+a+hypothesis+test+to+determine+whether+the+percent+of+families+who+own+pets+is+different+than+60%
There is sufficient evidence to conclude that, the percentage of the families who own a pet is different than 60%.
What are null hypotheses and alternative hypotheses?In null hypotheses, there is no relationship between the two phenomena under the assumption that it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.
It Is said That 60% of families own a pet.
Of a sample of 95 families, 70 owned pets.
Whether the percent of families who own pets is different than 60%.
Let P be a proportion of the family who owns pets
Then by the test, we have
H₀: P = 0.60
Hₐ: P ≠ 60
Then by the test statistic, we have
[tex]z_o = \dfrac{\bar{P} - P_o}{\sqrt{\dfrac{P_o(1 - P_o)}{n}}}[/tex]
Where
[tex]\bar P[/tex] = sample proportion
P₀ = hypothesis proporion
n = sample size
Then we have
[tex]\bar P[/tex] = x/n
[tex]\bar P[/tex] = 70/95
[tex]\bar P[/tex] = 0.74
Then the test statistic will be
[tex]z_o = \dfrac{0.74-0.60}{\sqrt{\dfrac{0.60(1-0.60)}{95}}}[/tex]
z₀ = 2.785
Then the critical region will be
Critical value = ± [tex]z_{\alpha /2}[/tex]
α = 0.05
α/2 = 0.025
Then we have
z₀.₀₂₅ = 1.96
Then the critical value will be
Critical value = ± 1.96
We reject if [tex]|z_o| > |z_{\alpha /2}|[/tex]
We have
[tex]|z_o| > |z_{\alpha /2}|\\[/tex]
2.79 > 1.96
We reject the null hypothesis at a 5% significance level.
There is sufficient evidence to conclude that, the percentage of the families who own a pet is different than 60%.
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Hypothesis Test for the Population Mean (II)
A team averaging 110 points is likely to do very well during the regular season. The coach of your team has hypothesized that your team scored at an average of less than 110 points in the years 2013-2015. Test this claim at a 1% level of significance. For this test, assume that the population standard deviation for relative skill level is unknown.
You are to write this code block yourself.
Use Step 3 to help you write this code block. Here is some information that will help you write this code block. Reach out to your instructor if you need help.
The dataframe for your team is called your_team_df.
The variable 'pts' represents the points scored by your team.
Calculate and print the mean points scored by your team during the years you picked.
Identify the mean score under the null hypothesis. You only have to identify this value and do not have to print it. (Hint: this is given in the problem statement)
Assuming that the population standard deviation is unknown, use Python methods to carry out the hypothesis test.
Calculate and print the test statistic rounded to two decimal places.
Calculate and print the P-value rounded to four decimal places.
The test statistic is -0.46 and the p-value is gotten as 0.3340
How to Calculate the P-value?The question is not complete because the data from the sample is 105, 107, 117, 106, 110.
Mean of sample is;
Mean = (105 + 107 + 117 + 106 + 110)/5
Mean; x' = 109
From online standard deviation calculator, the standard deviation of the sample is; S = 4.848
Now, the claim is that your team scored an average significantly less than 110 points. Thus, let's define the hypothesis as;
Null Hypothesis; μ = 110
Alternative Hypothesis; μ < 110
standard error of the mean; S_m = S/√n
S_m = 4.848/5
S_m = 2.17
Thus, the t-statistic is;
t = (x' - μ)/S_m
t = (109 - 110)/2.17
t = -0.46
Degree of freedom for this sample size is;
D.F = N - 1 =5 - 1 = 4
From online p-value from t-score calculator, we have;
p-value = 0.3340
The p-value is greater than the significance value and as such we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim that your team scored an average significantly less than 110 points.
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Integrate h(x,y)=(x y)i (y2−x)j over the closed curve that begins at (−7,0), goes along the x-axis to (7,0), and returns to (−7,0) by the upper part of the circle x2 y2=49
Green's theorem in vector calculus connects a line integral around a simple closed curve C to a double integral over the plane area D limited by C.
What is Green's Theorem?Green's theorem in vector calculus connects a line integral around a simple closed curve C to a double integral over the plane area D limited by C. It is a two-dimensional variant of Stokes' theorem.
The path of the particle is positively oriented so we can use Green's theorem to find the work done in moving particle along C.
The work done is given by [tex]\oint_{c}\vec F \cdot \vec{dr}[/tex]
Here, [tex]\vec F[/tex](x,y)=<x+y, y²-x>
Then [tex]\oint_{c}\vec F \cdot \vec{dr} = \oint_{c}(x+y)dx+(y^2-x)dy[/tex]
In comparison with [tex]\oint_{c}Pdx+Qdy[/tex] what we have,
P= x+y and Q=y²-x
Then [tex]\dfrac{\partial P}{\partial y} = 1[/tex] and [tex]\dfrac{\partial Q}{\partial x} =-1[/tex]
Using the Green's Theorem,
[tex]\oint_{c}Pdx+Qdy = \iint_{D} \left ( \dfrac{\partial Q}{\partial x}-\dfrac{\partial P}{\partial y}\right )dA[/tex]
Here D in polar Co-ordinates is given by,
D={(r,θ) : 0 ≤ r ≤ 7, 0 ≤ θ ≤ π}
Then
[tex]\oint_{c}(x+y)dx+(y^2-x)dy\\\\=-\iint_D 2dA\\\\=-\int_{\pi}^{0}\int_{0}^7 2r drd\theta\\\\=-49\pi[/tex]
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Solve the compound inequality y + 7 ≥ –1 and y∕4 + 3 ≤ 5
A)
6 < y ≤ 32
B)
–8 < y ≤ 8
C)
–8 ≤ y ≤ 8
D)
6 ≤ y ≤ 32
Working alone, steve can complete a task in 6 hours. working simultaneously at their respective constant rates, he and mike can complete the same task in 4 hours. how long will it take mike working alone to complete the task
Answer:
It would take him 4 hrs.
Step-by-step explanation:
Hope this helps!
Time taken by mike alone to finish the Task is 12 hours.
steve can complete a task in 6 hours.
he and mike can complete the same task in 4 hours.
What is rate of change?
Rate of change is defined as the change in value with rest to the time is called rate of change.
Here,
Rate of steve finishing task per hour = 1/6
Rate at which both finishes the task per hour = 1/4
Rate at which mike finishes the task per hour = M
now
M = 1/4-1/6
M = 3-2/12
M = 1/12
here, mike finishes his task at 12 hours
Thus, Time taken by mike alone to finish the Task is 12 hours.
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PYTHAGOREAN THEOREM IN 3D URGENT PLEASE PHOTO INSERTED
To find the length of the diagonal, we need to calculate the length of the base first and then use the value to calculate the diagonal since we are given the value of height of the triangle.
Pythagorean TheoremThis theorem is used to find the missing side of a right angle triangle given that we have the length of two sides.
To calculate the base of the triangle, let's use Pythagorean theorem here
[tex]x^2 = y^2 + z^2\\x^2 = 2^2 + 3^2\\x^2 = 4 + 9 \\x^2 = 13\\x = \sqrt{13} \\x = 3.61[/tex]
Having the length of the base, let's consider the height of the triangle which is 6 and substitute the values.
[tex]d^2 = 6^2 + 3.61^2\\d^2 = 36 + 13.0321\\d^2 = 49.0321\\d = \sqrt{49.0321} \\d = 7.00[/tex]
From the calculations above, the values of the triangle are
diagonal = 7base = 3.61height = 6Learn more on pythagorean theorem here;
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there is 1 litre of tea in a teapot, alex pours 275ml of the tea into a cup what percentage of the tea has alex poured
Answer:
27.5%
Step-by-step explanation:
Given:
1 Liter In TeapotAlex poured 275 milliliters of the tea into a cupReview:
1,000 Milliliters = 1 LiterConcepts:
A liter is a noun meaning a unit of capacity redefined in 1964 by a reduction of 28 parts in a million to be exactly equal to one cubic decimeter. It is equivalent to 1.0567 U.S. liquid quarts and is equal to the volume of 1 kilogram of distilled water at 4°C.A millimeter is a noun meaning a unit of capacity equal to one thousandth of a liter, and equivalent to 0.033815 fluid ounce, or 0.061025 cubic inch.Formula:
The mℓ to ℓ formula is [L] = [mL] / 1000.Now we must convert 275 milliliters to liters.
1. Divide the volume by 1,000.
275 ÷ 1000 = 0.275
2. Add the Unit Symbol for Liter.
0.275 ⇒ 0.275 L
Now we have to find how much of 1 liter- 0.275 liters as a percentage is.
To convert 0.275 to percent multiply 0.275 by 100. The result is 27.5 percent, or, using the percent sign, 27.5 %.
(Will mark Brainliest)Function g can be thought of as translated(shifted)version of f(x)=x²
Write The equation for g(x)
g(x)=__?__
Answer:
g(x) = (x + 2)² + 1
Explanation:
Given parent function: f(x) = x²
If the function translates two units right
g(x) = (x + 2)²If the function translates one units up
g(x) = (x + 2)² + 1 ← final function.Find CE. pleaseee help
Answer:
Radius = 20+5 = 25
We can find CE with the pythagorean theorem
20^2 + CE^2 = 25^2
CE = 15
Is 1 1/7 a rational number?
Answer:
Yes, it is rational because it is a fraction. All rational numbers are either decimals or fractions. Since a fraction can also be represented as division, creating a decimal when divided, it counts as a rational number.
The original price of a sweatshirt is $50. The sale price is 75% off the original price. Find the sale price of the sweatshirt.
Answer:
$87.5
Step-by-step explanation:
Original price also means COST PRICE
C.P=$50
S.P=75% of $50-$50
To find the sale price it will be 75% of C.P -C.P
75% × $50 + $50= 0.75 × $50-$50
=$37.5-$50.
= $12.5
therefore the sale price is $12.5
THANK YOU
The price of the sweatshirt at the sale is $12.5 which is 75% off of the original price.
What is the percentage?A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.
Given, The original price of a sweatshirt is $50.
Also given that the sale price is 75% off the original price So, the cost of the sweatshirt is (100 - 75)% = 25% of the original price which is,
= (25/100)×50.
= $12.5.
So, The sale price of the sweatshirt is $12.5.
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Antra calculated the product 2222 × 2223 × 22 × 24 and got a number. What will be the remainder when the product is divided by 10?
Answer:
the remainder is 8
Step-by-step explanation:
2222 x 2223 x 22 x 24 = 2,608,059,168
2,608,059,168 ÷ 10 = 260,805,916.8
so the remainder is 8
What is the length of the major axis of the conic section shown below? (x-3)^2/25+(y+2)^2/49=1
this is the answer hope it helps please if am wrong ask another person
thank you
Answer:
the answer is 14
Step-by-step explanation:
precalculus honors
Suppose that a, b, x and y are real numbers such that ax+by = 1, ax² + by² = 11, ax³ + by³ = 25 and ax⁴ + by⁴ = 83. Find the value of ax⁵ + by⁵.
Answer:
[tex]ax^5+ by^5=241[/tex]
Step-by-step explanation:
Given:
[tex]ax + by = 1[/tex][tex]ax^2+ by^2 = 11[/tex][tex]ax^3+ by^3 = 25[/tex][tex]ax^4+ by^4 = 83[/tex]We can re-write the left sides of the given equations as follows:
[tex]ax^2+ by^2=(ax+by)(x+y)-xy(a+b)[/tex]
[tex]ax^3+ by^3=(ax^2+by^2)(x+y)-xy(ax+by)[/tex]
[tex]ax^4+ by^4=(ax^3+by^3)(x+y)-xy(ax^2+by^2)[/tex]
Therefore, following this pattern:
[tex]ax^5+ by^5=(ax^4+by^4)(x+y)-xy(ax^3+by^3)[/tex]
Use the given values and the expanded expressions to create 2 equations to help find the values of (x+y) and xy:
Equation 1
[tex]ax^3+ by^3=(ax^2+by^2)(x+y)-xy(ax+by)[/tex]
[tex]\implies 25=11(x+y)-xy(1)[/tex]
[tex]\implies 25=11(x+y)-xy[/tex]
Equation 2
[tex]ax^4+ by^4=(ax^3+by^3)(x+y)-xy(ax^2+by^2)[/tex]
[tex]\implies 83=25(x+y)-xy(11)[/tex]
[tex]\implies 83=25(x+y)-11xy[/tex]
Multiply Equation 1 by 11:
[tex]\implies 275=121(x+y)-11xy[/tex]
Then subtract Equation 2 from this to eliminate 11xy and find the value of (x+y):
[tex]\implies 192=96(x+y)[/tex]
[tex]\implies (x+y)=2[/tex]
Multiply Equation 1 by 25:
[tex]\implies 625=275(x+y)-25xy[/tex]
Multiply Equation 2 by 11:
[tex]\implies 913=275(x+y)-121xy[/tex]
Subtract the 2nd from the 1st to eliminate 275(x+y) and find the value of xy:
[tex]\implies 288=-96xy[/tex]
[tex]\implies xy=-3[/tex]
Therefore, we now have:
[tex]ax^4+ by^4 = 83[/tex][tex]ax^3+ by^3 = 25[/tex][tex](x+y)=2[/tex][tex]xy=-3[/tex]Substitute these into the equation for ax⁵ + by⁵ and solve:
[tex]\implies ax^5+ by^5=(ax^4+by^4)(x+y)-xy(ax^3+by^3)[/tex]
[tex]\implies ax^5+ by^5=(83)(2)-(-3)(25)[/tex]
[tex]\implies ax^5+ by^5=166+75[/tex]
[tex]\implies ax^5+ by^5=241[/tex]
Represent each cylinder as a net. Find the surface area of each cylinder.
Answer:
113.04m^2
Step-by-step explanation:
Surface area for Base and top
[tex]2*\pi d=2*3.14*4=25.12[/tex]
Surface area for the other part
[tex]\pi d*h = 12.56*7 = 87.92[/tex]
you will get
113.04m^2
Jamie had seven posters, but only three could fit on his closet door. How many different ways can he arrange the three posters out of the seven on his closet door?
A. 52.5
B. 210
C. 1260
D. 5,040
Explanation:
Jamie has 7 choices for the first slot, then 6 choices for the next, and 5 choices for the final slot. Order matters. He has 7*6*5 = 210 permutations.
Alternatively you can use the nPr permutation formula with n = 7 and r = 3.
That formula is
[tex]nPr = \frac{n!}{(n-r)!}[/tex]
The exclamation marks indicate factorials. For instance, 4! = 4*3*2*1 = 24.
Answer:
B. 210 is correct!
Step-by-step explanation:
I got it correct on the quiz.
PLEASE HELP ME!!! It’s High School Math. Algebra 2 and it’s on Big Ideas Math.
Answer:
hope this will help you
[tex]let \: the \: angle \: be \: \alpha \\ \cos( \alpha ) = \frac{b}{h} \\ \cos(60) = \frac{x}{9} \\ \frac{1}{2} = \frac{x}{9} \\ x = \frac{9}{2} \\ x = 4.5[/tex]
What is the area of the figure? The figure is not drawn to scale.
A. 5.1 cm2
B. 11.7 cm2
C. 27.72 cm2
D. 55.44 cm2
Area of a Parallelogram = base x height
base = 3.3
height = 8.4
Area = 3.3 x 8.4 = 27.72
Answer: 27.72 cm^2
Hope this helps!
can someone help me with this question? Thank you!
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's evaluate ~
The given expression is :
[tex]\qquad \sf \dashrightarrow \:4x + 8[/tex]
plug the value of x as 3
[tex]\qquad \sf \dashrightarrow \:4(3) + 8[/tex]
[tex]\qquad \sf \dashrightarrow \:12 + 8[/tex]
[tex]\qquad \sf \dashrightarrow \:20[/tex]
Therefore, the required value is 20
1. Find the area of the shaded area of this figure:
Solve the following quadratic equation 5x^2+18x+9=0
Answer:
[tex]x = -3~\text{and}~ x = -\dfrac 35[/tex]
Step-by-step explanation:
[tex]~~~~~~5x^2 +18x +9=0\\\\\implies 5x^2 +15x +3x +9 = 0\\\\\implies 5x(x+3) +3(x+3) = 0\\\\\implies (x+3)(5x+3) = 0\\\\\implies x = -3,~ x = -\dfrac 35[/tex]
Answer:
x = -3
OR
x = -(3/5)
Step by step explanation:
Given:
5x^2+18x+9=0To Find:
xSoln:
Use quadratic formulae:
Here I typed Quadratic formula as x[tex] \rm x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2}[/tex]
According to the question,on the formula,
a = 5b = 18c = 9So substitute them on the formula:
THEN solve for x.
[tex] \rm \implies \: x = \cfrac{-1 8 \pm \sqrt{18 {}^{2} - 4(5 \times 9) }}{2 \times 5} [/tex]
[tex] \rm \implies \: x = \cfrac{-1 8 \pm \sqrt{324- 20 \times 9) }}{10} [/tex]
[tex]\rm \implies \: x = \cfrac{-1 8 \pm \sqrt{324- 180}}{10} [/tex]
[tex] \rm \implies \: x = \cfrac{ - 18 \pm \sqrt{144} }{10} [/tex]
[tex] \rm \implies \: x = \cfrac{ - 18 \pm12}{10}[/tex]
[tex] \rm \implies \: x = \cfrac{9 \pm 6}{5} [/tex]
Final solution will after adding first(9+6),then secondly subtracting both 9-6
[tex] \rm \implies \boxed{x = - \cfrac{3 }{5} }[/tex]
[tex] \implies \boxed{\rm x = - 3}[/tex]
So there'll be two possible answers.
For tax purposes, a car rental company assumes each car in their fleet depreciates by 6% per year. If the initial value of a car is $38,800.00, what will the value be when the car is 10 years old?
Options:
a.) $20,898.27
b.) $31,702.42
c.) $28,612.06
d.) $62,694.80
The value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.
What is an exponential function?It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent [tex]\rm y = a^x[/tex]
where a is a constant and a>1
We can solve this problem by exponential function:
The word depreciate means the price is decreasing.
We can find the value be when the car is 10 years old:
p = 38800(1 - 0.06)¹⁰
p = 38800(0.94)¹⁰
p = 20898.266 ≈ $20898.27
Thus, the value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.
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Can someone help me with this please
Answer:
D
Step-by-step explanation:
A function input can only have ONE output value
so the number 5 can't output two different numbers