Show that vertex cover is NP-Complete even if all vertices are restricted to have only even degrees. Hint: Try to reduce from the regular vertex cover problem. Add new nodes connected to those who have odd degrees. Then those have even degree now. But the newly added ones have odd degree. How can you take care of it?

Answers are of each function cos(π - t) = -2/5 and cos(t + π) = -2/5.

To evaluate these functions, we can use the trigonometric identity.

(a) To evaluate cos(π - t), use the property of cosine, which is cos(π - x) = -cos(x). So, we have:

cos(π - t) = -cos(t)

Since cos(t) = 2/5, we have:

cos(π - t) = -2/5

(b) To evaluate cos(t + π), use the property of cosine, which is cos(x + π) = -cos(x). So, we have:

cos(t + π) = -cos(t)

Since cos(t) = 2/5, we have:

cos(t + π) = -2/5

So, the answers are cos(π - t) = -2/5 and cos(t + π) = -2/5.

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The value of f ⁻¹ (x) would be,

⇒ f⁻¹(x) = - x/2 - 1

We have to given that;

Function is,

⇒ f (x) = - 2x - 2

Now, We can find the inverse of function as;

⇒ f (x) = - 2x - 2

⇒ y = - 2x - 2

Solve for x;

⇒ y + 2 = - 2x

⇒ x = - (y + 2)/2

⇒ x = - y/2 - 1

⇒ f⁻¹(x) = - x/2 - 1

Thus, The value of f ⁻¹ (x) would be,

⇒ f⁻¹(x) = - x/2 - 1

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The compound statement is not entirely clear as it contains several separate expressions. However, I can break down and analyze each of the parts:

7 + 1 2 7: This is a mathematical expression that represents the sum of 7, 1, and 27, which evaluates to 35.

7,1,7: This is a list of three individual numbers.

7+1: This is a mathematical expression that represents the sum of 7 and 1, which evaluates to 8.

74157: This is a five-digit number with no apparent mathematical relationship to the other expressions.

7+1=7: This is a mathematical equation that tests the equality of the expressions 7+1 and 7. Since 7+1 is not equal to 7, this equation is false.

27: This is a single number that is not obviously related to the other expressions.

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The milk chocolate bar contains 250 grams in total.

To solve it, we'll use the given percentages of cocoa and sugar in milk chocolate.
Determine the percentage of cocoa in the chocolate:
20% of the chocolate's mass is cocoa.
Find the mass of cocoa in the chocolate:
We are given that there is 50g of cocoa in the bar of milk chocolate.
Calculate the total mass of the chocolate:
Since 20% of the chocolate's mass is cocoa, we can set up the following equation:
(20% * Total Mass) = 50g
Solve for the total mass:
To find the total mass, we need to isolate the Total Mass variable in the equation:
Total Mass = 50g / 20%
Convert the percentage to decimal:
20% = 0.20
Perform the calculation:
Total Mass = 50g / 0.20 = 250g.

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Answer:

6/8, 9/12, 12/16, 15/20

Step-by-step explanation:

If you simplify the fractions it will all equal 3/4.

Simplify by finding the Greatest Common Factor and dividing both numbers by the GCF.

We would need a sample size of at least 1073 children under age 6 in Washington to estimate the true proportion of children living in poverty with 95% confidence and a margin of error of 2%.

To estimate the true proportion of children under age 6 living in poverty in Washington with 95% confidence and a margin of error of 2%, we can use the formula:

n = (Z² * p * q) / E²

where:

Z = the Z-score corresponding to the desired confidence level (1.96 for 95% confidence)

p = the estimated proportion (0.17 based on the federal report)

q = 1 - p

E = the desired margin of error (0.02)

Plugging in these values, we get:

n = (1.96² * 0.17 * 0.83) / 0.02²

n = 1072.45

Rounding up to the next whole number, we would need a sample size of at least 1073 children under age 6 in Washington to estimate the true proportion of children living in poverty with 95% confidence and a margin of error of 2%.

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To find the interval of convergence and radius of convergence for the power series sigma^[infinity]_n=1 ((−1)^n x^n/n), we will use the ratio test.

Ratio test: Let the series sigma^[infinity]_n=1 a_n be a power series centered at x = c. Then, the radius of convergence is given by R = lim_n→∞ |a_n/a_n+1|, if the limit exists.

First, we apply the ratio test:

|(-1)^(n+1) * x^(n+1)/(n+1)| / |(-1)^n * x^n/n|

= |x/(n+1)|

Taking the limit as n → ∞, we get

lim_n→∞ |x/(n+1)| = 0

Therefore, the radius of convergence is R = ∞.

Next, we need to find the interval of convergence. Since R = ∞, the series converges for all x. Thus, the interval of convergence is

I = (-∞, ∞).

Therefore,

I = (-∞, ∞)
R = ∞
To find the interval of convergence (I) and radius of convergence (R) for the given power series, we can use the Ratio Test. The power series is:

Σ(−1)^n * (x^n / n) from n=1 to infinity.

Applying the Ratio Test:

lim (n→∞) |(a_(n+1)) / a_n| = lim (n→∞) |((-1)^(n+1) * x^(n+1) / (n+1)) / ((-1)^n * x^n / n)|

After simplification:

lim (n→∞) |n * x / (n+1)|

Since the (-1) terms cancel out, we are left with:

lim (n→∞) |n / (n+1) * x|

As n approaches infinity, the limit becomes 1, and thus:

|x| < 1

This gives us the interval of convergence (I):

I = (-1, 1)

For the radius of convergence (R), since |x| < 1:

R = 1

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Answer:

1: $1.75

2: 1470 calories

3: $172.32

4: 350 in

5: 14 tabs

6: 2.22 weeks

Step-by-step explanation:

1: (2*3.75)+(1*4.85)+(2*2.95) = 18.25

   20-18.25 = 1.75 dollars

2: 2500-(520+220+290) = 1470 cal

3: 209.59+59.33+121.35+137.95+107.14+36.96 = 672.32

   672.32-500 = 172.32 dollars

4: (30*12)-10 = 350 in

5: (3*24)/4 = 18 total doses in 3 days,

   2 tabs per dose ->  18*2 = 36 tablets taken

   50-36 = 14 tabs

6: 45*5 = 225 patients per week

   500/225 = 2.22 weeks

The measure of the missing part of proportion is 17.50

Since the relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

Given that Weight Price 2 -lb. $7.00

5 - lb. $

1: 3.50 dollars

Now multiply by 5 on each side

5 : 17.50

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Having drawn and attached the scatter plot for the given data, the equation for the line of best fit is y = 0.083x + 97.55

After plotting the scatter point, we choose two points on the line of best fit that are far apart.

The points chosen are:

(150, 110) And (1240, 200)

Using the slope-intercept form we proceed to find the equation

y = mx + b

y =  cost of plane tickets

x = distance

m = slope

m = (y2-y1)/(x2-x1)
m = (200-110) / (1240 - 150)
m = 0.083

So, we can state

y = mx + b

110 = 0.083 * 150 + b
b = 97.55

hence,

the line of best fit is:

y = 0.083x + 97.55


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The ways in which we can shade the shape to get the total is: Shape 1: 3/5 shaded. Shape 2: 2/5 shaded. Shape 3: 2/5 shaded. To decompose g we use 7/5 = 4/5 + 3/5.

To express a quantity that is a portion of a whole, use fractions. They are made up of a denominator and a numerator, two integers separated by a horizontal line. The denominator is the total number of equally sized components that make up the whole, while the numerator is the portion of the whole that is being taken into account.

Because they are different ways of expressing the same quantity, decimals and percentages have a relationship to fractions. With a base of 10, decimals can be used to express fractions, with each digit standing for a different power of 10.

Given that, the total shaded area must be 7/5.

The ways in which we can shade the shape to get the total is:

Shape 1: 3/5 shaded

Shape 2: 2/5 shaded

Shape 3: 2/5 shaded

Now, for two shapes we can use the addition of two fractions as follows:

7/5 = 4/5 + 3/5

The example of the form is:

7/5 = 4/5 + 3/5

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The Euclidean algorithm gives gcd(a,b) = gcd(b,r) and gcd(b,r) = gcd(r,s).

The Euclidean algorithm is a recursive algorithm to find the greatest common divisor (gcd) of two integers a and b. It works by repeatedly finding the remainder of the division of the larger number by the smaller number, until the remainder is 0, at which point the gcd is the last non-zero remainder.

When applying the algorithm to a and b with a > b, we can write a = qb + r, where q is the quotient and r is the remainder. Then, we apply the algorithm to b and r to find the gcd(b,r), and so on until we reach 0. At each step, the gcd of the current pair of numbers is equal to the gcd of the previous pair, since any common divisor of the current pair must also divide the previous pair. Therefore, we have gcd(a,b) = gcd(b,r) = gcd(r,s), where s is the final non-zero remainder.

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Answer:

624 rounded 624.3 not rounded

Step-by-step explanation:

hope this helps <3

The number of 3-permutations of a set of cardinality eight is 336.

To determine the number of 3-permutations of a set of cardinality eight, we need to calculate the number of ways to arrange three distinct elements from an eight-element set.

This is done using the formula for permutations: P(n, r) = n! / (n - r)!, where n is the number of elements in the set, and r is the number of elements to be arranged. In this case, n = 8 and r = 3.

Applying the formula: P(8, 3) = 8! / (8 - 3)!. Calculate factorials: 8! = 40,320 and 5! = 120. Finally, divide 40,320 by 120 to get the answer: 336.

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Using the ADT list, we can implement the function f(n) to compute the values of the recurrence relation F(n) = F(n-1) + 3 x F(n-5), for n > 5, where F(1) = 1, F(2) = 1, F(3) = 1, F(4) = 3, and F(5) = 5.

By computing the values of f(n) in an ordered manner, we can avoid computing the same value more than once. We can use this approach to compute f(6), f(7), f(12), and f(15).

We will use the ADT list to implement the function f(n) to compute the values of the recurrence relation F(n) = F(n-1) + 3 x F(n-5), for n > 5, where F(1) = 1, F(2) = 1, F(3) = 1, F(4) = 3, and F(5) = 5. We will compute the values of f(n) in an ordered manner to avoid computing the same value more than once.

First, we initialize an empty list to store the values of f(n). Then, we add the initial values of f(1), f(2), f(3), f(4), and f(5) to the list.

Next, we use a for loop to compute the values of f(n) for n = 6 to 15. Inside the for loop, we use the recurrence relation F(n) = F(n-1) + 3 x F(n-5) to compute the value of f(n). We check if the value of f(n) has already been computed by checking if the length of the list is greater than or equal to n.

If the value has already been computed, we skip the computation and move on to the next value of n. Otherwise, we add the computed value of f(n) to the end of the list.

After the for loop, the list contains the values of f(1) to f(15). We can extract the values of f(6), f(7), f(12), and f(15) from the list and print them out.

For example, the Python code to implement the above approach is:

# Initialize an empty list to store the values of f(n)

f_list = []

# Add the initial values of f(1), f(2), f(3), f(4), and f(5) to the list

f_list.extend([1, 1, 1, 3, 5])

# Compute the values of f(n) for n = 6 to 15

for n in range(6, 16):

   if len(f_list) >= n:

       # Value of f(n) has already been computed

       continue

   else:

       # Compute the value of f(n) using the recurrence relation

       f_n = f_list[n-2] + 3 * f_list[n-6]

       # Add the computed value to the end of the list

       f_list.append(f_n)

# Extract the values of f(6), f(7), f(12), and f(15) from the list

f_6 = f_list[5]

f_7 = f_list[6]

f_12 = f_list[11]

f_15 = f_list[14]

Print out the values of f(6), f(7), f(12), and f(15)

print("f(6)).

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Hi! To find a set of the smallest possible size that has both {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10} as subsets, follow these steps:

1. List out the given subsets: {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10}.
2. Combine the elements of both subsets without repeating any numbers: {1, 2, 3, 4, 5, 6, 8, 10}.
3. The combined set is {1, 2, 3, 4, 5, 6, 8, 10}, which has a size of 8.

So, the smallest possible set that has both {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10} as subsets is {1, 2, 3, 4, 5, 6, 8, 10}.

The smallest possible set that includes both  {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10}  subsets is {1, 2, 3, 4, 5, 6, 8, 10}.

To find a set of the smallest possible size that has both {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10} as subsets, follow these steps:
1. Identify the given subsets: {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10}.
2. Combine the elements from both subsets without repeating any numbers.
3. Organize the combined elements in ascending order.
Your answer: The smallest possible set that includes both subsets is {1, 2, 3, 4, 5, 6, 8, 10}.

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Hi! To find a set of the smallest possible size that has both {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10} as subsets, follow these steps:

1. List out the given subsets: {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10}.
2. Combine the elements of both subsets without repeating any numbers: {1, 2, 3, 4, 5, 6, 8, 10}.
3. The combined set is {1, 2, 3, 4, 5, 6, 8, 10}, which has a size of 8.

So, the smallest possible set that has both {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10} as subsets is {1, 2, 3, 4, 5, 6, 8, 10}.

The smallest possible set that includes both  {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10}  subsets is {1, 2, 3, 4, 5, 6, 8, 10}.

To find a set of the smallest possible size that has both {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10} as subsets, follow these steps:
1. Identify the given subsets: {1, 2, 3, 4, 5} and {2, 4, 6, 8, 10}.
2. Combine the elements from both subsets without repeating any numbers.
3. Organize the combined elements in ascending order.
Your answer: The smallest possible set that includes both subsets is {1, 2, 3, 4, 5, 6, 8, 10}.

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Answer:

32

Step-by-step explanation:

43-11=32

Missing side is bc ≈ 24.784

The triangle missing angle γ is approximately 92.507°.

We are given the following information:

ac = 9

α = 60°

We can use the law of cosines to find the missing side bc:

bc² = ab² + ac² - 2ab(ac)cos(α)

Since we don't know ab, we can use the law of sines to find it:

ab/sin(α) = ac/sin(β)

where β is the angle opposite ab. Solving for ab, we get:

ab = (sin(α) x ac)/sin(β)

Since we know α and ac, we just need to find β to compute ab. Using the fact that the angles of a triangle sum to 180°, we have:

β = 180° - 90° - α

= 30°

Substituting the given values, we get:

ab = (sin(60°) x 9)/sin(30°)

= 15.588

Now we can use the law of cosines to find bc:

bc² = ab² + ac² - 2ab(ac)cos(α)

bc² = (15.588)² + 9² - 2(15.588)(9)cos(60°)

bc² = 613.436

bc ≈ 24.784

To find the remaining angle, we can use the law of sines again:

sin(γ)/bc = sin(α)/ac

Solving for γ, we get:

γ = sin⁻¹((sin(α) x bc)/ac)

= sin⁻¹((sin(60°) x 24.784)/9)

≈ 92.507°

Therefore, the missing angle γ is approximately 92.507°.

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The equation that best models the population P(t) of the country, given the constant relative birth and death rates and the number of people emigrating every year, is dP/dt = 0.5P - 30,000.

The rate of population growth is determined by the difference between the birth rate and the death rate, which is (97 - 47) per thousand people per year, or 0.05. This means that the population will grow by 0.05 times the current population each year if there is no emigration. However, since 30,000 people emigrate every year, we need to subtract this number from the population growth rate. Therefore, the rate of population growth can be expressed as 0.05P - 30,000.

To get the population at any given time t, we need to integrate this rate equation concerning time t. The solution to this differential equation is P(t) = (P0 - 60,000)e^(0.05t) + 60,000, where P0 is the initial population at time t=0.

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Answer: 108 cups of cranberry juice. Brainliest?

Step-by-step explanation:

mixed juice. How many cups of cranberry juice did Jetia use?

Let's start by assuming that Jetia used x cups of cranberry juice to make the mixed juice. Then, since the ratio of cranberry juice to apple juice is 5:8, she must have used (5/8)x cups of apple juice.

We know that the total amount of mixed juice is 177 cups, so we can set up an equation based on the total amount of juice:

x + (5/8)x = 177

Simplifying this equation, we get:

(13/8)x = 177

Multiplying both sides by 8/13, we get:

x = 108

Therefore, Jetia used 108 cups of cranberry juice to make the mixed juice.

The graph of the function f(x) = 2x + 26 will be a line graph.

Some key points about the graph:

• The slope of the line will be 2.

• The y-intercept will be 26, since f(0) = 26.

• The line will pass through the points (0, 26) and (x, 2x + 26).

• As x increases, the value of f(x) also increases but at a increasing rate.

• The graph will be a positively sloped line, increasing from left to right.

A rough sketch of the graph would be:

y

26

24

22

20

18

16

14

12

10

8

6

4

2

-6 -4 -2 0 2 4 6 8 10 12 14 x

Does this help explain the graph? Let me know if you have any other questions!

The power (P) when I = 64.1 A and V = 12.8 V is 819.68 watts (W).

Hello! I understand that you need help in finding the power (P) when the current (I) is 64.1 A and the voltage (V) is 12.8 V.
Understand the relationship between power, current, and voltage.
The power (P) in an electrical circuit can be calculated using the formula P = I × V,

where I is the current in amperes (A) and V is the voltage in volts (V).
Plug in the given values.
In this case, we are given I = 64.1 A

and V = 12.8 V.

Plug these values into the formula:
P = 64.1 A × 12.8 V
Calculate the power.
Multiply the current and voltage to find the power:
P = 819.68 W.

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Using a table of sample sizes and factors for ratio estimation, we find that a sample size of 90 items is appropriate and based on the information provided, we can project a total misstatement of $405,480.67 using ratio projection.

1. To determine the sample size given the information provided, we can use the formula:

Sample size = (Tolerable misstatement / Expected misstatement)² x (Total gross balance in inventory / Sampled balance)

Plugging in the values, we get:

Sample size = ($155,000 / $55,000)² x ($5,500,000 / Sampled balance)
Sample size = 6.73 x ($5,500,000 / Sampled balance)

Assuming a moderate risk of material misstatement, we can use a confidence level of 95%, which corresponds to a Z-score of 1.96. Using a table of sample sizes and factors for ratio estimation, we find that a sample size of 90 items is appropriate.

2. To calculate the total projected misstatement using ratio projection, we first need to determine the ratio of misstatement in the sample to the total inventory. We can do this using the formula:

Ratio of misstatement = Sample misstatement / Sampled balance

Assuming the expected misstatement of $55,000 and a sample size of 90 items, we can set a sampling interval of:

Sampling interval = Total gross balance in inventory / Sample size
Sampling interval = $5,500,000 / 90
Sampling interval = $61,111.11

Using systematic sampling, we can select every 61,111th item from the inventory. Let's say our sample includes 3 items with misstatements totaling $4,500. Then the ratio of misstatement would be:

Ratio of misstatement = $4,500 / Sampled balance

To project the total misstatement, we can use the formula:

Total projected misstatement = Ratio of misstatement x Total gross balance in inventory

Plugging in the values, we get:

Total projected misstatement = ($4,500 / Sampled balance) x $5,500,000

Since we don't know the actual sampled balance, we can use the average sampled balance as an estimate. Assuming an equal distribution of items, the average sampled balance would be:

Average sampled balance = Total gross balance in inventory / Sample size
Average sampled balance = $5,500,000 / 90
Average sampled balance = $61,111.11

Plugging this value in, we get:

Total projected misstatement = ($4,500 / $61,111.11) x $5,500,000
Total projected misstatement = 0.0736 x $5,500,000
Total projected misstatement = $405,480.67

Therefore, based on the information provided, we can project a total misstatement of $405,480.67 using ratio projection.

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The period of this function is 6 seconds and it means the time it takes for a person's lung to inhale and exhale in a full cycle.

The function's period alludes to the duration required for one complete cycle, culminating in its initial point. Furthermore, this term represents the length of time necessary for a person's lungs to perform a full inhalation and exhalation sequence.

To determine the period, it is integral to recognize the temporal gap between two successive peaks (or troughs) on the chart. This interval deviation precludes:

8. 5 - 2. 5 = 6 seconds

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The required ‘test statistic’ is 36.25

To solve this problem, we'll use the Chi-squared test statistic for testing the variance of a population. Here are the steps:

Identify the given information:
  - Sample size (n) = 30
  - Sample variance (s²) = 625
  - Null hypothesis (H₀): σ² = 500
  - Alternative hypothesis (Hₐ): σ² ≠ 500

Calculate the degrees of freedom (df) using the formula: df = n - 1
  - df = 30 - 1 = 29

Calculate the Chi-squared test statistic (χ²) using the formula: χ² = (n - 1) * (s² / σ²)
  - χ² = (29) * (625 / 500)

Compute the test statistic value:
  - χ² = 29 * (1.25) = 36.25

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The required equation is [tex]x^2y^4 + 4x^3y^3 - 4x^2y^2 - 12x^2y[/tex] + 25 = 0

The direction of fastest change of a function at a point is given by the gradient of the function at that point. Therefore, to find the points at which the direction of fastest change of the function f(x, y) = [tex]x^2 y^2[/tex] − 6x − 8y is in the direction of the vector i j, we need to find the gradient of f(x, y) and then find the points where the gradient is parallel to the vector i j.

The gradient of f(x, y) is given by:

∇f(x, y) = <∂f/∂x, ∂f/∂y> =[tex]< 2xy^2 - 6, 2x^2y - 8 >[/tex]

To find the points at which the direction of fastest change is in the direction of i j, we need to find the points where the gradient is parallel to i j. This means that the dot product of the gradient and i j should be equal to the product of their magnitudes:

∇f(x, y) · i j = ||∇f(x, y)|| ||i j||

Substituting the values, we get:

[tex](2xy^2 - 6, 2x^2y - 8)[/tex]· (1, 0) = sqrt(([tex]2xy^2 - 6)^2 + (2x^2y - 8)^2[/tex]) * sqrt([tex]1^2 + 0^2[/tex])

Simplifying this equation, we get:

[tex]2xy^2[/tex]- 6 = sqrt(([tex]2xy^2 - 6)^2[/tex] + ([tex]2x^2y - 8)^2[/tex])

Squaring both sides and simplifying, we get:

[tex]x^2y^4 + 4x^3y^3 - 4x^2y^2 - 12x^2y + 25 = 0[/tex]

Therefore, the points at which the direction of fastest change of f(x, y) is in the direction of i j are given by the solution of the quartic equation above.

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Th solution of the given seperable differential equation is :

u = (1/5)ln(25t^2 + e^75)

To solve the separable differential equation for u, we need to separate the variables and integrate both sides.

First, we can write the equation as:
(1/e^5u)du = 5t dt

Now we can integrate both sides:
∫(1/e^5u)du = ∫5t dt

To integrate the left side, we can use u-substitution:
Let u = 5u
Then du = 5e^5u du

Substituting into the integral, we get:
(1/5)∫e^5u du = ∫5t dt
(1/5)e^5u = 5t^2/2 + C
Where C is the constant of integration.

Now we can solve for u:
e^5u = 25t^2 + 2C

Taking the natural logarithm of both sides:
5u = ln(25t^2 + 2C)
u = (1/5)ln(25t^2 + 2C)

Using the initial condition u(0) = 15, we can solve for C:
15 = (1/5)ln(2C)
ln(2C) = 75
2C = e^75
C = (1/2)e^75

Substituting this value of C into our solution for u, we get:
u = (1/5)ln(25t^2 + e^75)

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N(e ∪ f) = 194.

Using the inclusion-exclusion principle, we have:

n(e ∪ f) = n(e) + n(f) - n(e ∩ f)

We are given n(e ∩ f) = 73 and n(e ∪ f) = 194, so we can rearrange to solve for n(f):

n(f) = n(e ∪ f) - n(e) + n(e ∩ f)

n(f) = 194 - 106 + 73

n(f) = 161

Finally, to find n(e ∪ f), we can substitute the values we have found into the first equation:

n(e ∪ f) = n(e) + n(f) - n(e ∩ f)

n(e ∪ f) = 106 + 161 - 73

n(e ∪ f) = 194

Therefore, n(e ∪ f) = 194.

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The argument is valid. According to modus tollens, the conclusion "I will not eat" logically follows

The argument follows a valid logical form known as modus tollens, which is a valid deductive argument form. Modus tollens states that if a conditional statement (e.g., "if A, then B") is true and the consequent (B) is false, then the antecedent (A) must also be false.

In this argument, the conditional statement is "If I'm hungry, then I will eat" (A = I'm hungry, B = I will eat), and the premise "I'm not hungry" establishes that the consequent (B) is false.

Therefore, according to modus tollens, the conclusion "I will not eat" logically follows

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The most general antiderivative of f(x) = 1/2 + 5/6x² − 4/5x³ is F(x) = 1/2x + 5/18x³ − 1/5x⁴ + C, where C is the constant of the antiderivative.

To check this answer, we can differentiate F(x) and see if it gives us back f(x). Taking the derivative of F(x), we get f(x) = d/dx (1/2x + 5/18x³ − 1/5x⁴ + C) = 1/2 + 5/6x² − 4/5x³, which matches the original function f(x). Therefore, F(x) is the most general antiderivative of f(x).

The constant of integration, denoted by C, is added because when taking the derivative of a constant, it is equal to zero. Thus, the constant of integration can be any real number, and it is included in the antiderivative to account for all possible functions that have f(x) as their derivative.

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