Round to the nearest tenth

2.642 to the nearest tenth

29.10 to the nearest tenth

2,492 to the nearest tenth

3.44 to the nearest tenth

5,239 to the nearest tenth

89.43 to the nearest tenth

Round to the nearest hundredth

23.987 to the nearest hundredth

3,7096 to the nearest hundredth

4,449 to the nearest hundredth

44.043 to the nearest hundredth

999.474 to the nearest hundredth

7.44430 to the nearest hundredth

the answer is -6.

the negative 7 turns the answer negative.

Answer:

-72

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]a^{-m}=\dfrac{1}{a^{m}}\\\\8^{-3}=\dfrac{1}{8^{3}}=\dfrac{1}{8*8*8}=\dfrac{1}{512}[/tex]

Answer:

8.) Rational

10.) Irrational

Step-by-step explanation:

8.) This is rational because although it is a decimal, it is terminating, meaning it has an end.

10.) This is irrational because it is a repeating decimal with seemingly no pattern.

Answer:

8.3

Step-by-step explanation:

Answer:

x = -2

Step-by-step explanation:

m(x) = 4x+15; m(x) = 7

7= 4x+15

7-4x=15

-4x=15-7

-4x=8 / :(-4)

x= -2

Answer:

Thus, width is 6 and length is 25.

Step-by-step explanation:

Let us assume the width is x, then, the length is (4x+1).

Therefore, 2x + 2(4x+1) = 62

Or, 2x + 8x + 2 =62

Or, 10x = 60

Or, x = 6

Answer:

27 units.

Step-by-step explanation:

The perimeter is equal to 2 x length + 2 x width.

If the width is 4 then:

62 = 2 x length + 2 x 4

62 = 2 x length + 8

Then, we can subtract 8 from both sides.

54 = 2 x length

Next, divide both sides by 2

27 = length

so,

The length is 27 units.

The sum of the measure of angle of a triangle = 180° .

Given two angles = 92° and 72°

92° + 72° = 164°

180° - 164° = 16° (Ans)

Answer:

the answer is  16!

Answer:

continuous becasue the arrows point out meaning the go on forever

Step-by-step explanation:

Answer:

14/25=0.56

29/50=0.58

53/100=0.53

13/20=0.65

3/5=0.60

Answer:

2

Step-by-step explanation:

1) Subtract 44 from both sides of the equation

3x + 44 - 44 = 50 - 44

2) Simplify

a. Subtract the numbers

3x = 50 - 44

b. Subtract the numbers

3x = 6

3) Divide both sides of the equation by the same term

3x/3 = 6/3

4) Simplify

a. Cancel terms that are in both the numerator and denominator

x = 6/3

b. Divide the numbers

x = 2

Answer:

3x - 2 = 4

x = 2

Step-by-step explanation:

3x - 2 = 4 ---> plus 2 on both sides

3x = 6 --> divide by 3 on both sides

x = 2

Answer:

180 out of 300

Step-by-step explanation:

Basically,

300÷120=2.5

Thereof,

72×2.5=180.

Hope this helps!

tag brainliest please...

Answer:

b = 2S/n - a.

Step-by-step explanation:

S=n/2(a + b)

a + b = S / n/2

a + b = 2S/n

b = 2S/n - a.

If the formula for determining the sum of the given arithmetic sequence is S = n/2(a + b), then 'b' can be expressed as b = [(2S/n) - a].

An arithmetic sequence is a sequence where the difference between any to consecutive terms are always equal.

Here, a and b are the first and the last terms respectively and n is the number of terms.

Therefore, the sum of the arithmetic sequence is:

S = n/2(a + b)

⇒ 2S/n = (a + b)

⇒ b = (2S/n) - a

Learn more about an arithmetic sequence here: https://brainly.com/question/25715593

#Tag #SPJ2

Answer:

Hey there, first let's find the slope.

M=y2-y1/x2-x1.

M=7-3/2-1 which is 4/1.

So your slope is 4

So now we have y=4x+b.

Now we need our Y-intercept (B). which is -1

So your answer is Y=4x-1

Answer:

[tex]A = 48.815[/tex]

Step-by-step explanation:

[tex] \frac{a}{ \sin(A) } = \frac{b}{ \sin(B) } [/tex]

[tex] \frac{12.5}{ \sin(A) } = \frac{15.4}{ \sin(68) } [/tex]

[tex]12.5 \sin(68) = 15.4 \sin(A) [/tex]

[tex] \frac{12.5 \sin(68) }{15.4} = \frac{15.4 \sin(A) }{15.4} [/tex]

[tex] \sin(A) = \frac{12.5 \sin(68) }{15.4} [/tex]

[tex] A=\sin ^{ - 1} ( \frac{12.5 \sin(68) }{15.4} ) [/tex]

[tex]A = 48.815[/tex]

Answer:

2.4 cm

Step-by-step explanation:

1.2/3 = 0.96/x

x = (3 *0.96) / 1.2

x = 2.4 cm

Answer:

the answer is the third one 3

Answer:

a)-30

b)-60

c)98

d)-54

Step-by-step explanation:

320/-4

-180/3

-14X-7

6X-9

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

and

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

So, By using Long Division Method, we have

[tex]\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\: {x}^{2} - 3x + 2\:\:}}}\\ {\underline{\sf{x + 1}}}& {\sf{\: {x}^{3}  -  {2x}^{2} - x + 2 \:\:}} \\{\sf{}}& \underline{\sf{- {x}^{3} - {x}^{2} \: \: \:  \:  \:  \:  \:  \:  \:  \: \:\:}} \\ {{\sf{}}}& {\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 3{x}^{2} - x +2  \:  \:  \:  \:   \:  \:  \:  \:\:}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  3{x}^{2} + 3x  \:  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2x + 2 \:\:}} \\{\sf{}}& \underline{\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: - 2x - 2\:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 0\:\:}}  \end{array}\end{gathered}\end{gathered}\end{gathered}[/tex]

So,

[tex]\bf\implies \:Remainder = 0[/tex]

Verification

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

[tex] \purple{\rm :\longmapsto\:Remainder = 0}[/tex]

[tex] \purple{\rm :\longmapsto\:Quotient = {x}^{2} - 3x + 2}[/tex]

Now, Consider

[tex]\rm :\longmapsto\:Divisor \times Quotient + Remainder[/tex]

[tex]\rm \:  =  \: (x + 1)( {x}^{2} - 3x + 2) + 0[/tex]

[tex]\rm \:  =  \: {x}^{3} - {3x}^{2} + 2x + {x}^{2} - 3x + 2[/tex]

[tex]\rm \:  =  \: {x}^{3} - {2x}^{2} - x + 2[/tex]

[tex]\rm \:  =  \: Dividend[/tex]

Hence, Verified

CARRY ON LEARNING

CAN YOU BRAINLEST ME PLEASE

Answer:

[tex] \sf k = 1 \\\\ \sf y = x [/tex]

Step-by-step explanation:

A graph between the amount of time that backpacker hikes to the distance travelled is given .

According to the Question ,

[tex]\sf \implies y \propto x \\\\\sf \implies y = kx [/tex]

[tex]\sf\implies 5 = k(5) \\\\\sf \implies k =\dfrac{5}{5}\\\\\sf \implies \boxed{\frak{\pink{ k = 1 }}}[/tex]

Again the constant of proportionality is the slope of the line.

[tex]\sf\implies y = mx + c \\\\\sf \implies y = 1(x) + 0 \\\\\sf \implies \boxed{\pink{\frak{ y = x }}}[/tex]

Answer:

x = 1, y = 1

x = -2, y = -8

x = 3, y = 7

Step-by-step explanation:

Answer:

m<b=107º

Step-by-step explanation:

180-41-32=107

D and B are congruent

Answer:

x = 14

Step-by-step explanation:

10x-30+5x = 180

Combine like terms

* 15x-30 = 180

Add 30 from both sides

* 15x 30+-30 = 180+30

Divide 15 both sides

* 15x/15x = 210/15x

x = 14

Hope this helps :)

none of these i guess

Answer:

x equals 375

Step-by-step explanation:

75+0.70x=0.90x

Hello Carousel!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex]

First, let's take I as ⇨ [tex]\tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex].

[tex]\tt \:I = \int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x +1}} \: dx \\\tt \: I =\int \: \frac{ x + 2 }{( {x}^{2} + 2x + 1 + x + 2) \sqrt{x + 1}} \: dx \\ \tt \:I =\int \: \frac{ x + 2 }{( ({x + 1}^{2}) + x + 2) \sqrt{x + 1}}[/tex]

Let, x + 1 = m² => dx = 2mdm.

[tex]\tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: m} 2mdm \\ \tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: \bcancel{ m}} 2 \bcancel{m}dm \\ \tt \: I = \: \int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 } 2dm[/tex]

Now, divide the numerator & denominator by m²....we'll get it as...

[tex]\tt \:I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{ {m}^{2} + 1 + \frac{1}{ {m}^{2} } } \: dm \\\tt \: I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{( {m}^{2} + \frac{1}{ {m}^{2} } - 2) + 3} \: dm \\\tt \: I =2\int \: \frac{ (1 + \frac{1}{ {m}^{2} }) \: dm }{ ({m} - \frac{1}{ m } ) ^{2} + 3} [/tex]

Now, let m - 1/m be t => (1 + 1/m²) dm = dt

[tex]\tt \:I =2\int \: \frac{ dt}{ {t}^{2} + 3 } \\ \tt \:I = 2\int \: \frac{ dt}{ {t}^{2} + ( \sqrt{3}) ^{2} }[/tex]

We know, [tex]\tt \:\int \: \frac{dx}{ {x}^{2} + a ^{2} } = \frac{1}{a} tan ^{ - 1} (\frac{x}{a} ) + c[/tex]...therefore...

[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{t}{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 1}[/tex]

Now, substitute the value of 't' in eq. 1..we'll get..

[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{m - \frac{1}{m} }{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 2}[/tex]

Now, substitute the value of 'm' in eq. 2...we'll get...

[tex] \tt \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{ \sqrt{x + 1} - \frac{1}{ \sqrt{x - 1} } }{ \sqrt{3} } ) + c \\ \tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x + 1 - 1}{ \sqrt{3} \sqrt{x - 1} } ) + c \\ \boxed{\boxed{ \bf \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x }{ \sqrt{3 (x - 1} )} ) + c }}[/tex]

__________________

__________________

Hope it'll help you!

ℓu¢αzz ッ

Answer:

AA   as the angles are similar the sides are not similar so AA is the answer

Step-by-step explanation: