problem 7-16 determine the internal normal force, shear force, and moment at points c and d of the beam. given: w1
Answers
The internal Normal force is equal to
The internal Shear force is equal to
Moments at points between C and D is
Internal Normal force :
The normal force at any section of a structure is defined as the algebraic sum of the axial forces acting on either side of the section.
Shear force:
The shearing force (SF) is defined as the algebraic sum of all the transverse forces acting on either side of the section of a beam.
Bending moment
The bending moment (BM) is defined as the algebraic sum of all the forces’ moments acting on either side of the section of a beam.
let Ax and Ay be horizontal and vertical component of A .
we have given that W₁ = 200 N/m × 6 m = 1200 N
and W₂ = 1/2 × 200 N/m× 6m = 600 N ( for triangle)
the distance between B and W₂ (x₂) = 1/3×6 = 2m
the distance between B and C (x₁) = 1/2×6 = 3m
Forces act in horizontal direction (Fₓ) ,
summation Fₓ = 0 = > Aₓ= 0
now, for vertical direction as Ay act upward and W1 and W2 acting downward direction.
summation M = 0
=> - Ay × 6 + W₁× 3 + W₂× 2 = 0
=>- 6Ay + 3600 N-m + 1200 N-m = 0
=> -Ay× 6 = - 4800 => Ay = 800 Nm
As we know total sum of force acting free body
= 0
=> Aₓ + N꜀ = 0 where N꜀ is normal force on C
but Ax= 0 so, Nc = 0
for Shear forces , Summation Fy = 0
=> Ay - W₁ - W₂ - V꜀ = 0 , where V꜀ is shear force
V꜀ = 800 - 200× 3 - 200 × 3/2 = -100 N
sum of moments Mc = 0
=> M꜀ - Ay ×3 - W1 × 3/2 - W2×1/3 ×3 = 0
=> M꜀ - 2400 - 1200× 3/2 - 600 × 1 = 0
=> M꜀ = 4.8 kNm
Hence , Internal Normal force is zero
shear force is 100 N and moment of force between C and D is 4.8 kNm.
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Related Questions
part k what is the magnitude of e at the point (0.50 m , 0.50 m , 0.50 m )? express your answer with the appropriate units.
Answers
The values constants magnitude are A=-6 MathrmV cdot m-2 A=6 Vm. B = 4 mathrm V cdot m 3, B = 4 mathrm V m 3, C = 2 V m 6, C = -2 V cdot m 6, l = 2 mathrm V m 6, m = 3 mathrm V m 3, and n = 6 mathrm V n = 6.
How would you define magnitude?Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
What does force magnitude mean in physics?The amount that encapsulates the force's strength is known as its magnitude. Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10." Magnitude can be thought of as simply the "value" or "amount" of any physical quantity.
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bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum? check all that apply.
Answers
Equation A. P A i + P B i = P A f + P B f and D.ΔPA + ΔPB=0. correctly states the principle of conservation of momentum.
Momentum is the product of the mass and pace of an object. it's miles a vector quantity, owning a magnitude and a route. If m is an item's mass and v is its velocity, then the object's momentum is p.
Momentum is manufactured from the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both value and path. Isaac Newton's 2d regulation of motion states that the time price of trade of momentum is the same as the pressure performed at the particle. See Newton's legal guidelines of movement.
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Disclaimer:- your question is incomplete, please see below for the comlete question.
Bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum? check all that apply.
A. P A i + P B i = P A f + P B f
B. P A i + P A f = P B i + P B f
C. ΔPA = ΔPB
D. ΔPA + ΔPB=0
2. A ball is projected with a velocity of 50m/s at an angle of 53° to the horizontal
Calculate:
A. The time of flight of the ball.
B. The range and
C.The maximum height
Answers
The time of flight is 0.4 sec, The range is 1.6 m and maximum height is 3.2 meter.
Calculation:-
The initial vertical speed is u = 5m/s×sin53° = 4m/s
Time of flight = u/g
= 4/10
= 0.4 second
so if the final vertical velocity is v at a height h then v² = u² −2gh will give us v = [tex]\sqrt{16-20*0.45} = \sqrt{7} m/s[/tex]
The horizontal velocity remains constant and is given as Vx = 5m/s Cos53° = 3m/s
so the speed at the said instant will be V = [tex]\sqrt{v_{x} ^{2} +v^{2} } = \sqrt{9+7} = 4m/s[/tex]
Range = horizontal velocity× 0.4 second
= 4 × 0.4
= 1.6 m
Height = UT- 1/2at²
= 1.6 - 0.4 × 10 × 0.16
= 3.2 m
The horizontal velocity of the projectile is constant. There is the vertical acceleration due to gravity. Its value is 9.8 m/s/s, and the projectile's vertical velocity changes at 9.8 m/s per second. The horizontal movement of the projectile is independent of vertical movement. Horizontal acceleration is always zero because nothing accelerates the projectile horizontally.
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There are nine books in a stack, each with a weight of 6n. The coefficient of friction between all the books is 0. 1 as is the coefficient between the table and the bottom book. What horizontal push must i just exceed on the next to bottom book to start sliding the top eight books off the bottom one?.
Answers
The top five books must be pushed off the bottom one with 5 N of horizontal force.
The word "force" has a specific meaning in science. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. Each of the six books weighs five pounds, therefore we need to slide five of them.
them, where 55 = 25N
The following formula can then be used to get the friction force.
F = N μ
where F is the frictional force, N is the force, and is the static friction coefficient
F= (25 N) (0.2) (0.2)
F= 5 N
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if a 69.87 kg person ate 181 calories worth of sugar (about the calories in a typical energy drink and they converted all of that energy to heat immediately, what would be the change in temperature of that person?
Answers
If a 69.87 kg person ate 181 calories worth of sugar and they converted all of that energy to heat immediately, the change in temperature of that person is 3.609 ºC.
What is calorie?
Energy is quantified by calories. One calorie is equal to the amount of a heat energy needed to raise one gram of water's temperature by one degree Celsius.In reality, the term "calorie" refers to a kilocalorie, or one thousand actual calories.To heat one kilogram of water by one degree Celsius, one nutritional calorie is required.Through combustion in a bomb calorimeter, the number of calories in various food servings is calculated.To calculate the change in temperature resulted from the intake of food calories or energy generated in Joules we use the formula,
Energy(Joules) = mass of the body (g) x specific heat of the body(J/gºC.) x change in temperature (ºC)
Let us assume that the average specific heat of the person's body is 3.00 J/gºC.
Using the above formula we find the change in temperature as-
181 x 1000 cal/ 1cal x 4.18 J/1 cal = 69.87 x 1000 x 3.00 J/gºC. x ΔT
ΔT = 181 x 1000 x 4.18/ 69.87 x 1000 x 3
= 3.609
Hence, the change in temperature of that person is 3.609 ºC.
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Toy cars 1, 2, and 3 are launched horizontally with the trajectories shown below. Cars 1 and 2
are launched from a 15 m high cliff, while Car 3 is launched from a 30 m high cliff. We can
ignore air friction.
Answers
Initial launch speed of the cars are in order as Vcar 1 = Vcar 2< Vcar 3
Speed (often abbreviated as "s") is a scalar variable that describes how much an object's location changes over time or how much it changes per unit of time. The average speed of an item in a period of time is the distance traveled by the object divided by the duration of the period.
Time divided by distance are the speed-related metrics.. The meter per second (m/s) is the SI unit of speed, while the kilometer per hour (kph) is the most often used unit of speed in daily life.
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A 53 kg person is being dragged in their sleeping bag to the lake by a 476 N force at an angle of 40 degrees. If the coefficient of friction between the sleeping bag and the ground is 0.37:
a.) What is the force of gravity acting on the person?
b.) What is the normal force acting on the person? (Use net force in y-direction)
c.) What is the force of friction acting on the person?
d.) What is the acceleration of the person in the sleeping bag?
Answers
(a) The force of gravity acting on the person is 519.4 N.
(b) The normal force acting on the person is 519.4 N.
(c) The force of friction acting on the person is 192.18 N.
(d) The acceleration of the person in the sleeping bag is 3.25 m/s².
What is the force of gravity acting on the person?
The force of gravity acting on the person is calculated as follows;
W = mg
where;
m is the mass of the persong is acceleration due to gravityW = 53 kg x 9.8 m/s²
W = 519.4 N
The normal force acting on the person is calculated as follows;
Fn = W
where;
Fn is the normal force on the person acting upwardsW is the weight of the person acting downwardsFn = 519.4 N
The force of friction acting on the person is calculated as follows;
Ff = μFn
where;
μ is coefficient of frictionFn is normal forceFf = 0.37 x 519.4 N = 192.18 N
The net force on the person is calculated as follows;
F(net) = F cosθ - Ff
where;
F cosθ is the force applied along the horizontalFf is force of frictionF(net) = 476 x cos(40) - 192.18
F(net) = 172.46 N
The acceleration of the person in the sleeping bag is calculated as follows;
a = F(net) / m
a = (172.46) / (53)
a = 3.25 m/s²
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which of the statements below best describes longshore current? group of answer choices outgoing swash moves perpendicular to the beach. incoming backwash of water moves parallel to the beach. sand moves parallel to the beach. incoming swash of water moves parallel to the beach.
Answers
The statement which describes the longshore current is d.) incoming swash of water moves parallel to the beach.
What is a longshore current?
When the waves reach a beach, it liberates a large amount of energy that is usually generates a current and runs parallel to the shore. Such type of current is said to be longshore current.
Sea floor, shoreline features and depth of the water are the main factors on which the speed of the waves reaching the shore depends. The waves make their movement towards the beach where various segments of wave itself encounters before other and this results the segments to slow down. They do not reach the beach perfectly parallel to the shoreline. But when we talk about the longshore current, it moves parallel to the coastline or beach.
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Help, fast!
If you have an 18 Ohm light bulb connected to a 9.0 V cell, what is the current in the circuit?
Answers
Answer:
Explanation:
Given:
R = 18 Ohm
U = 9.0 V
__________
I - ?
Ohm's law:
I = U / R
I = 9.0 / 18 = 0.5 A
how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.
Answers
The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J
W = F d cos θ
W = Work done
F = Force
d = Displacement
θ = Angle between force and displacement vector
F = 14 N
d = 2 mm = 0.002 m
θ = 0
W = 14 * 0.002 * 1
W = 0.028 J
Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.
Therefore, the work done by tension on the laptop is 0.028 J
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A 10-kg mass and a 2.0-kg mass are connected by a light string over a massless, frictionless pulley. If g = 9.8 m/s2 , what is the acceleration of the system when released
Answers
For a frictionless pulley with mass connected by a light string, the acceleration for the system when released is equal to 6.5m/s²
How is the acceleration for a frictionless pulley calculated?Using the formula a = (m₂ - m₁)g/(m₁ + m₂)
Where a = acceleration, m = mass and g = gravity
m₁ = 2kg
m₂ = 10kg
g = 9.8m/s²
Applying to the formula, a = (m₂ - m₁)g/(m₁ + m₂) to find the acceleration of a frictionless pulley when released;
a = (10 - 2)(9.8)/(2 + 10)
a = 8(9.8)/12
a = 6.5m/s²
Therefore the system's acceleration 6.5m/s²
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When the temperature of a gas is increased from 27° the average speed of the molecules increases three-fold. Calculate the final temperature of the gas. (prove by calculation)
Answers
The final temperature of the gas is obtained as 2700 K or 2472° C.
What is the relationship between the speed of the gas and the temperature?We know that when the temperature of a gas is increased, the speed of the gas is also increased. Given that we have the initial temperature of the gas as 27° C or 300 K.
Given that;
[tex]V_{1}[/tex]/[tex]V_{2}[/tex] = √[tex]T_{1}[/tex]/[tex]T_{2}[/tex]
Where the [tex]V_{1}[/tex] and [tex]V_{2}[/tex] refers to the initial and the final velocities while the [tex]T_{1}[/tex] and the [tex]T_{2}[/tex] refer to the initial and the final temperatures.
[tex]V_{1}[/tex]/3 [tex]T_{1}[/tex] = √300/ [tex]T_{2}[/tex]
1/3 = √300/ [tex]T_{2}[/tex]
1/9 = 300/ [tex]T_{2}[/tex]
[tex]T_{2}[/tex] = 2700 K or 2472° C
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1. describe the sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length). begin with the aortic valve and compare others to it. this is a subjective description.
Answers
The sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned below
1. First heart sound
Heard dull. Described as LUB.At the beginning of the ventricular systole Frequency: 30-80 cpsVaries from 0.09 to 0.16 second.2. Second Heart sound
Sharp, described as DUBAt the end of ventricular systole Duration 0.11 secFrequency- 150 to 200 cps.Due to closure of semilunar valves.3. Third heart sound
Heard often. Weak and rumbling in nature. Frequency below 40 cpsDuration 0.04secHeart as lub-dub-ta4. Fourth heart sound
Weak and rumbling. When atria contracts Frequency- 20cpsTherefore, the sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned above
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A wooden block resting on a table is given a push. Which of the following describe the motion of the block a moment after the push
Continues at a constant speed for a while, then slows down
O Slows down gradually to a stop
Accelerates at a positive, constant rate
O Moves at a constant speed
Answers
Acceleration will be constant while speed will not. The third option describes the motion.
What is Force ?Force can simply be defined as a pull or push. It is the product of mass and velocity and it is measured in Newton.
If a wooden block resting on a table is given a push, the block of mass m will accelerate with acceleration a and stop due to friction
One of the following options that describe the motion of the block a moment after the push is the third option. That is, accelerates at a positive, constant rate.
Since the block will be accelerating, the speed of the block can never be constant.
Therefore, accelerates at a positive, constant rate is the option that describe the motion of the block a moment after the push.
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A 20 gram bullet traveling at 250m/s strikes a block of wood that weighs 2kg. With what velocity will the block and bullet move after the collision?.
Answers
The conservation of momentum can be used to determine the final velocity. The block and bullet system's velocity after the collision will be 2.5 m/s.
For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). Using the momentum principle,
Where,
= bullet weight, 20 g, or 0.2 kilogram
250 m/s is the bullet's speed before colliding.
= block weight = 2 kg
= velocity following impact =?
Fill out the formula with the values,
Therefore, the block and bullet system's velocity following the collision will be 2.5 m/s.
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which of the following would be the closest estimate to the number of times the sun has orbited the galactic center?
Answers
The closest estimate to the one times the sun has orbited the galactic center.
The Milky Way galaxy's rotational and barycenters are located at the Galactic Center . The Sagittarius A supermassive black hole, a compact radio source that is almost exactly at the galactic rotational center, is the object's central massive object. It has a mass of about 4 million solar masses. The Galactic Center is frequently referred to as a type of "cosmic homing signal" by astrologers. Far away on one of the spiraling arms of the galaxy, it is the hub around which our tiny solar system slowly revolves. It is enormous and unknowable. Whatever process produced the Milky Way is represented by the GC. The most difficult conditions for star formation can be found in the Galactic Center, which has more than 80% of the Milky Way Galaxy's dense molecular gas, high temperatures, significant turbulence, complex magnetic fields, and a powerful gravitational potential well.
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3. What group of elements found on the periodic table are NOT used when determining the number of
valence electrons a group has?
Answers
Answer: Transition metals
Explanation:
kinetic energy depends on both the mass of an object and on its speed. using the ratio k1k2 to see how changing one or both of these parameters changes the kinetic energy. match each case with the correct value of k1k2.
Answers
The effect on K₁/K₂ on changing the quantities are :
a)If the mass of 1 is double the mass of 2, and the speeds are the same, then ratio is 2 times
b)If the speed of 1 is double the speed of 2, and the masses are the same, then ratio becomes 4 times.
c)If The mass of 2 is double the mass of 1, and the speeds are the same, then ratio becomes half.
d)If The speed of 2 is double the speed of 1, and the masses are same, then ratio becomes 1/4 times.
e)If The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1,then ratio becomes half.
We know that kinetic energy of any body is given by (1/2)mv² where m is the mass of the body and v is the velocity of the body.
Hence, the ratio of K₁/K₂ is changing on changing one or both of these parameters
a) when mass of first body is doubled then K₁ becomes 2 times of initial kinetic energy, then ratio will become twice of the initial value.
b)when speed of first object is doubled then kinetic energy of first object will becomes 4 times of initial energy ,therefore the ratio becomes 4 times of initial ratio.
c) If The mass of 2 is double the mass of 1, and the speeds are the same then in that kinetic energy of 2nd object will become twice of initial kinetic energy, therefore ratio will become half.
d) If The speed of 2 is double the speed of 1, and the masses are same then ratio becomes 1/4 times of initial ratio.
e) If The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1, then in that case ratio becomes half of initial ratio,
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(Complete question) is:
Kinetic energy depends on both the mass of an object and on its speed. Ki the kinetic energy. Using the ratio K₁/K₂ to see how changing one or both of these parameters changes the kinetic energy. Match each case with the correct value of ratio K₁/K₂. 1) The mass of 1 is double the mass of 2, and the speeds are the same.2) The speed of 1 is double the speed of 2, and the masses are the same. 3) The mass of 2 is double the mass of 1, and the speeds are the same. 4) The speed of 2 is double the speed of 1, and the masses are the same. 5) The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1.
a compound microscope has objective and eyepiece focal lengths of 6.0 mm and 1.6 cm , respectively. if the lenses are 8.6 cm apart, what is the magnification of the instrument?
Answers
To learn about the focal length and magnification to solve this problem.
What is focal length?
The focal length of a narrow lens in air is measured from the lens's center to its primary foci, also known as focal points. The focal length of a converging lens, such as a convex lens, is positive and determines how far a collimated light beam must travel to focus on a single point.
What is magnification?
The size of a picture in relation to the size of the item that created it is known as magnification in optics. The term "linear" magnification—also referred to as "lateral" or "transverse" magnification—describes the ratio of image length to object length as measured in planes perpendicular to the optical axis.
Given U₀ = 3cm, f₀= 2.5cm, v₀=mage distance for objective lens
1/f₀= 1/v₀- 1/u₀
1/v₀=1/f₀+1/u₀=1/2.5-1/3
v₀= 3*2.5/3-2.5= 15cm
Object distance for eye piece =20−15=5cm
Given Ue= -5cm, Fe= 6cm, Ve = image formed by eye piece
1/Ve= 1/Fe +1/ Ue= 1/6-1/5
Ve=-30cm
magnification m = -L/F₀*25/Fe
where L is the length of the microscope
here L= 20 cm
m= -20/25*25/6= -33.33
Therefore, the focal length is 15cm and the magnification is 33.33 cm.
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an satellite is said to be in geosynchronous orbit if the period of its orbit is equal to the period of rotation of the star or planet. for a satellite in geosynchronous orbit around the neutron star, what is its distance from the surface of the star?
Answers
Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.
A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.
what is geosynchronous orbit?
The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.
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Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.
What is geosynchronous orbit?
The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.
A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.
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please match the luminosity class to the description. not all answers will be used.-these extremely luminous stars are among the largest ever observed and represent the very short-lived old age phase of high mass stars.-these luminous stars represent the short-lived old age phase of low mass stars. when our sun hits this phase, it could become large enough to engulf the earth.-this phase represents the longest stage of a star's life. this luminosity class has stars with a large range in temperature (hottest to coolest) and luminosity (brightest to dimmest), but they are all bound by one common trait: they are powered by hydrogen fusion only in the core of the star.
Answers
The core of a red giant is contracting, but the outer layers are expanding as a result of hydrogen fusion in a shell outside the core
Nuclear fusion of hydrogen to form helium happens evidently in the solar and different stars. It takes area best at extremely high temperatures. Scientists are attempting to find methods to create controlled nuclear fusion reactions on earth.
Researchers at Lawrence Livermore countrywide Laboratory's country-wide Ignition Facility in California have spent over a decade perfecting their method and the feature now showed that the landmark test conducted on eight August 2021 did, in fact, produce the primary-ever successful ignition of a nuclear fusion reaction.
People had been capable of cause fusion, but in methods that might be uncontrolled, like in thermonuclear guns sometimes called hydrogen bombs. Fusion has additionally been proven in laboratories, but below conditions that eat a long way, extra strength than the reaction produces.
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12. Define aerobic capacity. How does it relate to cardiorespiratory endurance?
Answers
What is the average speed in mph for a car that travels 400 miles in 5 hours and 20 minutes?.
Answers
For an automobile to cover 400 miles in 5 hours and 20 minutes, it must travel at an average speed of 75 mph.
What is the typical speed?Calculating average speed involves dividing the whole distance traveled by the total time it took to cover that distance. Speed is the rate of movement of something at a specific time. Average speed refers to the average speed during the course of a journey.
What drives us to determine average speed?Average In order to comprehend the pace of a journey, speed is crucial. On a travel, the speed could occasionally change. Finding the average speed then becomes crucial to getting an idea of how quickly the route will be finished.
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a system gains 612 kj of heat, resulting in a change in internal energy of the system equal to 246 kj. how much work is done?
Answers
The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ would be -366 KJ
What is the internal energy of the system?
Internal energy can be defined as the property that defines the energy of a substance in the absence of effects due to capillarity, external electric and magnetic fields
In the above case
Let Change in internal energy ΔU = 246 kJ
Let Heat gained by the system (q) = 612 kJ
Using the First law of thermodynamics
ΔU = q + w
Where:
ΔU represent change in internal energy
q represents heat added to the system
and w is work done.
Let plug in the formula
246 kJ = 612 kJ + w
w = 246 kJ - 612 kJ
w= - 366 kJ
Here the negative sign means that work is done by the system.
Therefore, The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ would be -366 KJ
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If a 50 kg object is at a location 25,600 km from Earth's center, what is the gravitational force exerted by the object on earth? In what direction does that force act?
Answers
The item is pushing against it with a force of 30.4 N in a downward direction.
What would the weight of a 50 kilogram object be at the Earth's core?Since there is no net gravitational pull in the earth's center, the weight will be zero but the mass will not change. Thus, 50 kg will be the mass of the earth's core.
When two objects of mass M1 and M2 are separated by R, the gravitational force between them is expressed as follows:
F = G*(M1*M2)/R^2
G = 6.674*1(-11) m3/(kg*s2), where G is the gravitational constant.
M1, the object's mass, is 50 kg, and R is its distance, in.
F = G*(M1*M2)/R^2
G = 6.674*1(-11) m3/(kg*s2), where G is the gravitational constant.
M1, the object's mass, is known to be 50 kg.
This distance, R, is 25,600 kilometers.
However, keep in mind that this should be stated in meters and
1km = 1000m
Consequently, 25,600km equals (25,600*1000)m, or 25,600,000 m.
M2 is the equivalent of 5.972*10(24) kg, which is the mass of the Earth.
F = (6.674*1(-11) m3/(kg*s2))*(50kg*5.972*10(24) kg)/ (replacing all of those in the force equation) ( 25,600,000 m)
^2\sF = 30.4 N
Given that the gravitational force is attracting, it will act in a manner that is favorable to the 50 kg item.
Consider the following as the second Newton's law:
F = M*a
Accordingly, the acceleration brought on by the item on Earth is 30.4N = 5.972*10(24) kg*a
a = 30.4N/((5.972*10(24) kg)) = 5.09*10(-24) m/s
Nearly everyone can feel the acceleration.
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if the sun had been born with a smaller, lower-mass companion star, would that star be a red dwarf today or would it already be dead?it would still be a red dwarf today regardless of how much less mass than the sun it has, since its lifetime would be inherently longer than the sun'sit would be a red dwarf today only if it had much less mass than the sun (for example, a star with 20% msun)it would be dead by today only if if it had a little less mass than the sun (for example, a star with 90% msun)it would be dead today only if it had much less mass than the sun (for example, a star with 20% msun)it would be a red dwarf today only if it had a little less mass than the sun (for example, a star with 90% msun)
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If the Sun had been born with a smaller, lower-mass companion star, would that star be a red dwarf today or would it already be dead, it would still be a red dwarf today regardless of how much less mass than the Sun it has, since its lifetime would be inherently longer than the Sun's.
Stars sparkle and shine—they appear to have an incandescence of their own even when they are bathed in the spotlight—so it stands to reason that they are stars. However, they are "stars" in a much more specific sense because they are a product of the long-standing Western cultural tendency to equate humanity with the heavenly.
Not all celebrities live alone. About half of all stars in our galaxy, the Milky Way, have a companion and journey through space in a binary system.
Now, the long-lost partner of the Sun could be found anywhere in the Milky Way. According to a team of Harvard astronomers, our solar system was once a binary system because the Sun formerly had a companion star.
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if it took 2.17 ms for the bullet to change speed from 439 m/s to the final speed after impact, then what was the magnitude of the average force (in n) exerted by the block on the bullet during this time?
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The magnitude of the average force exerted by the block on the bullet during that time is 202,304.147m N (m stands for bullet mass)
We got some values here,
v = 439 m/s
t = 2.17 ms = 2.17 × [tex]10^{-3}[/tex] s
First, we should find the acceleration of the car. We assume that final speed of bullet after impact is 0 m/s, so here we go
a = v/t
a = [tex]v_{1}[/tex] - [tex]v_{0}[/tex] / [tex]t_{1}[/tex] - [tex]t_{0}[/tex]
a = 0 - 439 / 2.17 × [tex]10^{-3}[/tex] - 0
a = -439 / 2.17 × [tex]10^{-3}[/tex]
a = -439,000 / 2.17
a = -202,304.147 m/[tex]s^{2}[/tex]
What actually happens when the result is negative is not the acceleration after the bullet hits the target, but the deceleration.
Now we got the amount of deceleration. We can found the force by the formula of: F = m.a but in the question there is no mass value of the bullet. So, we can answer this question by this way (we can ignore negative values)
F = m.a
F = m × 202,304.147 m/[tex]s^{2}[/tex]
F = 202,304.147m N
What is acceleration?Acceleration (a) is the change of velocity (Δv) over the change of time (Δt), and here is the formula, a = Δv/Δt. This formula allows you to measure how quick velocity changes in meters per second squared (m/s. Acceleration is also a vector quantity, so it includes both magnitude and direction.
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Look at the diagram below. What is the total resistance of the resistors in this circuit?
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The total resistance of the resistors in the circuit from the diagram is 20 Ω.
What is resistance?Resistance is a measure of the opposition to current flow in an electrical circuit.
To calculate the total resistance of the resistors in parallel, we use the formula below.
Note: Both resistors are connected in series.
Formula:
For series connection
R = R₁+R₂................ Equation 1Where:
R = Total resistance of the resistor in the circuit.From the diagram,
Given:
R₁ = 10 ΩR₂ = 10 ΩSubstitute these values into equation 1
R = 10+10R = 20 ΩHence, the total resistance is 20 Ω.
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30. An applied force of 60 N is used to accelerate a 50 N object to the right across a frictional surface. The object
encounters a 20 N of friction. Determine the coefficient of friction
a. 0.4
b. 2.5
c. 0.83
d. 3
Mu'
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Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .
What do you mean by frictional force ?Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.
The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.
Given applied force = 60 N
weight of object = 50N; friction force = 20N
As we know that, Coefficient of friction = force of friction/normal force
= 20/50
Coefficient of friction = 0.4
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400 turn circular coil with a radius of 0.3 m is rotated through a quarter turn in 0.417 ms (this corresponds to 60 revolutions per second). suppose the plane of the loop was initially perpendicular to a uniform magnetic field. if the average induced voltage is 10 kv, what is the magnitude of the magnetic field?
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Bohr atomic model can not predict spectra for multielectron atom.
What is Bohr atomic model?
The Bohr model postulates that the electrons are orbit the nucleus at fixed energy if levels. Orbits further from to the nucleus to exist at highest energy levels.
Sol-
Bohr’s theory was unable to explained the followings observations :
i) Bohr’s model could not explain the spectra of atoms containing more than one of electron.
ii) It never not explain the Zeeman effect.
In presence of the magnetic of field, each of spectral line gets split up to into fine lines, the phenomenon is known as Zeeman effect.
iii) It could not explain the to Stark effect.
In presence of the electric of field, each spectral line gets split up into fine lines, the phenomenon is known as as the Stark effect.
iv) The main objection to the Bohr’s model was raised by Heisenberg’s uncertainty principle.
According to the Heisenberg’s uncertainty principle, it is impossible to determine the simultaneously the exact position and the momentum of a small moving particle like an electron.
But, according to Bohr’s model electron moves in well-defined orbits around the nucleus, and hence its position, as well as momentum, can be determined simultaneously, which is against the of uncertainty principle.
So, electron moves in well-defined orbits around to the nucleus is impossible.
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