PROBLEM 1. Veldora walked around the circular pool. The circular pool has a
diameter of 3 meters. What is the distance that Veldora has walked?
Step 1 – Read and understand
What is asked in the problem? ____________________________
What do you know of the problem?________________________
Step 2 – Plan
What must be done to solve the problem? _________________
Step 3 – Solve and answer ___________________________
Carry out the plan & write the final answer. _______________
Step 4 – Check
Is the answer correct? _______________________
PROBLEM 2. How much greater is the circumference of the circle with a diameter of
12m than another circle with a radius of 5m?
Step 1 – Read and understand
What is asked in the problem? ____________________________
What do you know of the problem?_______________________
Step 2 – Plan
What must be done to solve the problem?_________________
Step 3 – Solve and answer ________________________
Carry out the plan & write the final answer._______________
Step 4 – Check
Is the answer correct?_________

Answers

Answer 1

Answer:

9.42m

Step-by-step explanation:

I took this on a test. Was extremely difficult, but I remembered the answer after my 4th retake


Related Questions

PLZ HELP WILL GIVE 50 POINTS - QUADRATIC APPLICATIONS

find how far away (ground distance) from the catapult will white bird be at its highest. (round to the nearest 2 decimal points)
h= -0.114x^2+2.29x+3.5


Answers

Answer:

The bird will be at a ground distance of 10.04 units away.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, y_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

[tex]y_{v} = -\frac{\Delta}{4a}[/tex]

Where

[tex]\Delta = b^2-4ac[/tex]

If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].

Equation for the height:

The height of the bird after x seconds is given by:

[tex]h(x) = -0.114x^2 + 2.29x + 3.5[/tex]

Which is a quadratic equation with [tex]a = -0.114, b = 2.29, c = 3.5[/tex].

When the bird is at its highest?

Quadratic equation with [tex]a < 0[/tex], and thus, at the vertex. The ground distance is the x-value of the vertex. Thus

[tex]x_{v} = -\frac{b}{2a} = -\frac{2.29}{2(-0.114)} = 10.04[/tex]

The bird will be at a ground distance of 10.04 units away.

The table shows the mean number of minutes spent on homework last weekend. The MAD for both sets of data is 5. Which number correctly completes the statement: The difference between the means is _______ times the value of the MAD of each set of data. (Subtract the two means and then divide that difference by 5.)

Answers

The answer is : 5
Explanation:

Over the course of one day, a store owner determined that 80% of customers bought a drink and 30% of customers bought a snack
If the store sold 120 snacks that day, how many more drinks than snacks did the store sell? Enter the answer in the box.
The store sold 40
more drinks than snacks.

Answers

Maybe 39 make sure i don’t know

A snail can travel 390 inches in 5 hours. How far does it travel in 10 minutes?

Answers

60 minutes in an hour so multiply that times 5 getting 300 now divide. You get 1.3 multiply by 10 for the amount of minutes needed so 13 inches in 10 minutes
The snail travels 13 inches in 10 minutes

5 hours = 300 minutes
390 inches/300 minutes = 1.3 inch per minute
1.3 inches x 10 minutes = 13 minutes

A small coffee shop sells bags of two types
of coffee. Bag A contains 24 ounces and
costs $15.60. Bag B contains 30 ounces
and costs $20.40. Which statement is true?


A. Bag A costs 3¢ less per ounce than Bag B.

B. Bag A costs 3¢ more per ounce than Bag B.

C. Bag A costs 2¢ less per ounce than Bag B.

D. Bag A costs 2¢ more per ounce than Bag B.

Answers

the answer to your question is B and D
To answer your question I would say most likely B & D are your best options

Which equation represents the parabola with focus (8, 4) and vertex (8, - 2)

Answers

Answer:

8.4 whic e querido representante the parábola 8.3

Which set of equations shows a way to find 771 - 468?

Answers

Answer:

The one that has 303 as the answer is the correct one

The number of gallons of water left in a swimming pool at time t minutes can be modeled by w(1) = -7t+B50. Find the y-intercept and explain what it represents in this situation.​

Answers

Answer:

I'm not really sure

Step-by-step explanation:

soooooooory

Why is a square also a rectangle? Use the drop-down menus to complete the explanation.

Answers

A square is also a rectangle because it possesses all the properties of a rectangle. Similar to a rectangle, a square has: interior angles which measure 90° each, opposite sides that are parallel and equal, and many more attributes as well. Keep in mind however that a square is a special type of rectangle because it posseses some additional properties which don't apply to normal rectangles like the fact that all four sides of a square are equal, and diagonals of a square bisect each other at right angles.

I hope this helps! <3

Answer:

Step-by-step expl

A square is also a rectangle because it possesses all the properties of a rectangle. Similar to a rectangle, a square has: interior angles which measure 90° each, opposite sides that are parallel and equal, and many more attributes as well. Keep in mind however that a square is a special type of rectangle because it posseses some additional properties which don't apply to normal rectangles like the fact that all four sides of a square are equal, and diagonals of a square bisect each other at right angles.

O capital de R$ 12.000,00 foi aplicado a juros compostos à taxa de 60% ao ano durante 2 anos. Determine o montante? *

Answers

?Answer:

Step-by-step explanation:

In order to complete the square for the equation below, what value should be added to both sides of the equation?
x2 - 8x + ? = 42 + ?

Answers

Answer:

? = 16

Step-by-step explanation:

x2 - 8x + ? = 42 + ?

1. Take the coefficient of the middle term 8x, which is 8 and divide it by 2.  [tex]\frac{8}{2} = -4[/tex]. Then square it  [tex]-4^{2} = 16[/tex]

2. Take 16 and add it to both sides: [tex]x^2 - 8x + 16 = 42 + 16[/tex]

2. Take half of the coefficient 8 that you divided by 2, which is 4 and insert 4 into the equation [tex](x -4)^2 = 58[/tex]

3. ? = 16

Find all x-intercepts of the function.
y = x³ - 9x² + 18x

Answers

Answer:

Step-by-step explanation:

X-intercepts mean y=0 so we have

y = x³ - 9x² + 18x = 0

Factoring

x³ - 9x² + 18x = 0

x*(x² - 9x +18) = 0

x*(x-3)*(x-6) = 0

So x-intercepts are at x=0, x=3 and x=6

Answer:

Step-by-step explanation:

see plot, intercepts at 0, 3, 6

who’s tryna help me with
my im3 final pls !!

Answers

Answer:

Step-by-step explanation:

Wat

Yeah just post the questions

Which congruence statement correctly compares the two triangles shown?
A) AABD - ABDC
B) AABD - ACDB
C) ADBA - ADBC
OD) AADB - ABCD

Answers

Answer:

B) ABD=CDB

Step-by-step explanation:

Answer: B

Explanation: Because i am correct bestie

PLEASE HELP QUICK!!!
COMPOUND INTEREST!!!
$600 is deposited in an account that pays 7% annual interest, compounded continuously. What is the balance after 5 years?

Answers

9514 1404 393

Answer:

  $851.44

Step-by-step explanation:

The balance is given by the formula ...

  A = Pe^(rt) . . . . principal P, interest rate r, t years

Using the given numbers, we find the balance to be ...

  A = $600·e^(0.07·5) ≈ $851.44

Which equation is true when x = 1/2?

Answers

Answer:

D

Explanation:

6/ 1/2 = 6*2, 6*2 not equal to 3

half of 8 is 4, not 16

1/2+2 = 2 1/2

10/ 1/2 = 10*2 = 20

You can transform V to V' by translating it and then performing a dilation centered at V'. Find the translation rule and scale factor of the dilation.  Simplify the scale factor and write it as a proper fraction, improper fraction, or whole number.  Translation: (x, y) -> (___,___) Scale factor: ___​

Answers

Answer:

Translation rule → (x + 10, y + 1)

Scale factor = 4

Step-by-step explanation:

Coordinates of V → (-8, -2)

Coordinates of V' → (2, -1)

Therefore, point V has been translated from x = -8 to x = 2,

Translation on x-axis → 2 - (-8) = 10 units

Translation on y-axis → -1 - (-2) = -1 + 2

                                                  = 1 unit

If the point V is translated 10 units right and 1 unit upwards,

Rule for the translation → (x + 10, y + 1)

Radius of the circle V = 2 units

Radius of the circle V' = 8 units

Scale factor = [tex]\frac{\text{Dimension of the image}}{\text{Dimension of the original}}[/tex]

                    = [tex]\frac{\text{Radius of the image}}{\text{Radius of the original}}[/tex]

                    = [tex]\frac{8}{2}[/tex]

                    = 4

Therefore, circle V has been dilated by a scale factor of 4 to form circle V'.

A certain smart phone game app allows the player, once a day, to spin a wheel with 8 different sections. Seven of the sections contain a small prize and one of the sections is the grand prize, in which the player wins all of the other seven prizes. The makers of the game claim that the wheel has an equally likely probability of landing on each section. Andraya has played the game for several months and believes that the grand prize occurs less often than the game makers claim.

Required:
What would be appropriate hypotheses for the Andraya to test?

Answers

Answer:

The appropriate hypothesis set for Andraya to test is:

[tex]H_0: p = 0.125[/tex]

[tex]H_1: p < 0.125[/tex]

Step-by-step explanation:

The makers of the game claim that the wheel has an equally likely probability of landing on each section.

That is, the makers claim that the probability of earning the grand prize is:

[tex]p = \frac{1}{8} = 0.125[/tex]

Andraya has played the game for several months and believes that the grand prize occurs less often than the game makers claim.

At the null hypothesis, we test if it happens as often as the makers claim, that is, the proportion is 0.125. So

[tex]H_0: p = 0.125[/tex]

At the alternate hypothesis, we test if it happens less ofter than the makers claim, that is, the proportion is less than 0.125. So

[tex]H_1: p < 0.125[/tex]

The appropriate hypothesis set for Andraya to test is:

[tex]H_0: p = 0.125[/tex]

[tex]H_1: p < 0.125[/tex]

A measuring cylinder of radius 3cm contains water to a height of 49cm.if this water is poured into a similar cylinder of radius 7cm, what will be the height of the water column​

Answers

Answer:

9 cm.

Step-by-step explanation:

Volume of a cylinder == pi r^2 h.

The volume of the water is constant so:

pi * 3^2 * 49 = pi * 7^2 h

9 *49 = 49 h

h = 9 cm.

What is the name of the following net?

Answers

the answer is square pyramid

Answer:

[tex]\large\colorbox{gold}{sǫᴜᴀʀᴇ ᴘʏʀᴀᴍɪᴅ}[/tex]

Match the correct word with it's definition

Answers

Answer:

Rule by a small group : Oligarchy

Rule by Citizens : Democracy

Rule by No one Anarchy

Rule by king or Queen : Monarchy

A square pyramid has a volume of 1350 ft3. If the base is a square with side
lengths 15 feet, what is the height?

Answers

Height = 6 ft

Explanation:
Area of square base = 15 x 15 = 225 ft2

Volume of pyramid = Area of square base x Height
1350 = 225 x Height
1350/225 = Height
Height = 6

Wat is the average between 1,000, 2300,1000,2600

Answers

Answer:

1180.2

Step-by-step explanation:

The average of 1,000,2300,1000,2600 is 1180.2

Write an explicit formula for am, the nth term of the sequence 5, 30, 180, ....

Answers

Answer:

Am = 5 * 6^(m-1)

Step-by-step explanation:

30/5 = 6

180/30 = 6

Am = 5 * 6^(m-1)

What is the solution of log; (3x+2) = log: (4x-6)?

Answers

Answer:

x = 8

Step-by-step explanation:

Answer:

x = 8

Step-by-step explanation:

Cancel the log from both sides and you'll get:

[tex]3x + 2 \: = 4x - 6 \: \\ 6 + 2 = 4x - 3x \: \\ x = 8[/tex]

The
exact solusion of the IVP

Answers

Answer:

[tex]\displaystyle y = \sqrt{2}e^{\frac{1}{2} ln|2 + x^2|}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Algebra I

|Absolute Value|FunctionsFunction NotationExponential Rule [Multiplying]:                                                                        [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex]

Algebra II

Logarithms and Natural LogsEuler's number e

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Differential Equations

Separation of Variables

Antiderivatives - Integrals

Integration Constant C

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

U-Substitution

Logarithmic Integration

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y' = \frac{xy}{2 + x^2}[/tex]

[tex]\displaystyle y(0) = 2[/tex]

Step 2: Rewrite

Separation of Variables

Rewrite Derivative Notation:                                                                            [tex]\displaystyle \frac{dy}{dx} = \frac{xy}{2 + x^2}[/tex][Division Property of Equality] Isolate y's:                                                       [tex]\displaystyle \frac{1}{y} \frac{dy}{dx} = \frac{x}{2 + x^2}[/tex][Multiplication Property of Equality] Rewrite Derivative Notation:                [tex]\displaystyle \frac{1}{y} dy = \frac{x}{2 + x^2} dx[/tex]

Step 3: Find General Solution Pt. 1

Integration

[Equality Property] Integrate both sides:                                                        [tex]\displaystyle \int {\frac{1}{y}} \, dy = \int {\frac{x}{2 + x^2}} \, dx[/tex][1st Integral] Integrate [Logarithmic Integration]:                                            [tex]\displaystyle ln|y| = \int {\frac{x}{2 + x^2}} \, dx[/tex]

Step 4: Identify Variables

Identify variables for u-substitution for 2nd integral.

u = 2 + x²

du = 2xdx

Step 5: Find General Solution Pt. 2

[2nd Integral] Rewrite [Integration Property - Multiplied Constant]:             [tex]\displaystyle ln|y| = \frac{1}{2}\int {\frac{2x}{2 + x^2}} \, dx[/tex][2nd Integral] U-Substitution:                                                                           [tex]\displaystyle ln|y| = \frac{1}{2}\int {\frac{1}{u}} \, du[/tex][2nd Integral] Integrate [Logarithmic Integration]:                                         [tex]\displaystyle ln|y| = \frac{1}{2} ln|u| + C[/tex][Equality Property] e both sides:                                                                     [tex]\displaystyle e^{ln|y|} = e^{\frac{1}{2} ln|u| + C}[/tex]Simplify:                                                                                                             [tex]\displaystyle |y| = e^{\frac{1}{2} ln|u| + C}[/tex]Rewrite [Exponential Rule - Multiplying]:                                                        [tex]\displaystyle |y| = e^{\frac{1}{2} ln|u|} \cdot e^C[/tex]Simplify:                                                                                                             [tex]\displaystyle |y| = Ce^{\frac{1}{2} ln|u|}[/tex]Back-Substitute:                                                                                               [tex]\displaystyle |y| = Ce^{\frac{1}{2} ln|2 + x^2|}[/tex]

Our general solution is  [tex]\displaystyle |y| = Ce^{\frac{1}{2} ln|2 + x^2|}[/tex].

Step 6: Find Particular Solution

Substitute in point:                                                                                           [tex]\displaystyle |2| = Ce^{\frac{1}{2} ln|2 + 0^2|}[/tex]Evaluate |Absolute Value|:                                                                               [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln|2 + 0^2|}[/tex]|Absolute Value| Evaluate exponents:                                                            [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln|2 + 0|}[/tex]|Absolute Value| Add:                                                                                      [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln|2|}[/tex]|Absolute Value| Evaluate:                                                                               [tex]\displaystyle 2 = Ce^{\frac{1}{2} ln(2)}[/tex][Division Property of Equality] Isolate C:                                                         [tex]\displaystyle \sqrt{2} = C[/tex]Rewrite:                                                                                                             [tex]\displaystyle C = \sqrt{2}[/tex]Substitute in C [General Solution]:                                                                  [tex]\displaystyle y = \sqrt{2}e^{\frac{1}{2} ln|2 + x^2|}[/tex]

∴ Our particular solution is  [tex]\displaystyle y = \sqrt{2}e^{\frac{1}{2} ln|2 + x^2|}[/tex].

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Differential Equations

Book: College Calculus 10e

hellp plsssss i need it

Answers

uhhhh obama told me to tell you that your moms friends daughters teachers husbands friends sons has the same question as you

13) A rectangular garden has an area of 45 square meters. The garden will be 4 meters longer than its width Write and sowe an equation to find the dimensions in meters.​

Answers

Answer:

9m ×5m

Step-by-step explanation:

Area of a rectangle= length ×width

Let the width be W meters and the length be L meters.

2 equations can be written from the given information:

45= WL -----(1)

L= W +4 -----(2)

Substitute (2) into (1):

45= W(W +4)

Expand:

45= W² +4W

-45 on both sides:

W² +4W -45= 0

Factorise:

(W +9)(W -5)= 0

W+9=0 or W-5=0

W= -9 or W= 5

(reject)

Substitute W= 5 into (2):

L= 5 +4

L= 9

∴ The dimensions of the garden is 9m ×5m.

Help me please will be appreciated thx

Answers

Answer:

-6 +8d -2c

Step-by-step explanation:

[tex]\frac{-2}{5} (15 -20d +5c) = \frac{-2}{5} \times 15 - \frac{-2}{5}\times20d +\frac{-2}{5}\times5c = -6 + 8d -2c[/tex]

Kyle needs to fill the wooden platform he made to make it more stable. What is the volume of the platform?

Answers

Answer:

720 in³

Step-by-step explanation:

v = l * w * h

Break into two parts:

Bottom

v = 12 * 6 * 5

v = 360 in³

Top

v = 8 * 5 * 9

v = 360 in³

Total

v = 360 + 360

v = 720 in³

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