Predict the shape of the molecule.....

Predict The Shape Of The Molecule.....

Answers

Answer 1

Answer:

bent

Explanation:


Related Questions

What is the number of moles in 546 g strontium nitrite?

A. 0.388 mol
B. 2.58 mol
C. 329 mol
D. 3.04 mol

Answers

The answer is 2.58 mol

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A man washes clothes in a stream using a detergent that contains phosphorus. Which type of pollution is this?

Question 2 options:

toxic


sediment


nutrient


bacterial

Answers

I think nutrient, hope it’s right!

Answer:

bacterial or toxic please

A solution is made from 0.5 moles of sodium dichromate. If the volume of the solution is 1 Liter, what is the molarity of the solution
2 M
0.5 M
4 M
1 M

Answers

Answer:

4 M

Explanation:

See the steps and explanation in the picture

How many molecules of CO2 at standard temperature and pressure in 5.4 moles of CO2

Answers

Answer:

3.25×10²⁴ molecules.

Explanation:

From the question given above, the following data were obtained:

Number of mole of CO₂ = 5.4 moles

Number of molecules of CO₂ =?

The number of molecules of CO₂ in 5.4 moles can be obtained as follow:

From Avogadro's hypothesis,

1 mole of CO₂ = 6.02×10²³ molecules

Therefore,

5.4 moles of CO₂ = 5.4 × 6.02×10²³

5.4 moles of CO₂ = 3.25×10²⁴ molecules

Thus, 5.4 moles of CO₂ contains 3.25×10²⁴ molecules.

Combustion Analysis of an unknown hydrocarbon resulted in the capture of 216.00 g of water vapor and 440.00 g of CO2. The total mass of the hydrocarbon before combustion was 144 g.

(1. How many moles of carbon dioxide are present after combustion?)

(2. What is the empirical formula for the unknown hydrocarbon?)

(3. How many water molecules does the water vapor trap capture?)

(4. The gram-formula mass for the unknown hydrocarbon was determined to be 72 g/mol. How many moles of the unknown hydrocarbon were present in the original sample?)

(5. infrared spectral analysis determines that the unknown hydrocarbon does NOT contain oxygen. How many moles of O2 are used in combusting the unknown sample?)

Answers

1: 10 mol CO2

2: C10H24

3: 12 mol H2O

4: 0.5 mol

5: 16 mol O2

The compound is C5H10.

From the information  available in the question;

Number of moles of carbon dioxide = 440.00 g/44 g/mol = 10 moles

Number of moles of water vapor = 216.00 g/18 g/mol = 12 moles

Mass of carbon = 10 moles × 12 g/mol = 120 g of carbon

Moles of hydrogen = 12 moles  × 2 g/mol = 24 g of hydrogen

Number of moles of carbon = 120 g/12 g/mol = 10 moles

Number of moles of hydrogen = 24 g/1 g/mol =24 moles

Divide through by the lowest number of moles =

C - 10/10   H - 24/10

C - 1          H - 2

The empirical formula is CH2

Molar mass of the compound = 72 g/mol

[12 + 2(1)]n = 72

14n = 72

n = 5

The compound is C5H10.

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Calculate AEfor a system that absorbs 599,0 kJ of heat from its surroundings
and does 3510 kJ of work on its surroundings.

Answers

Answer:

-2911 kJ

Explanation:

Step 1: Given data

Heat absorbed by the system (Q): 599.0 kJ (By convention, when the systems absorbs heat, Q > 0)Work done by the system on the surroundings (W): -3510 kJ (By convention, when the systems does work on the surroundings, W < 0)

Step 2: Calculate the change in the internal energy (ΔE)

We will use the following expression.

ΔE = Q + W

ΔE = 599.0 kJ + (-3510 kJ) = -2911 kJ

What is the correct sequence of chemical transformations with the correct phases?

Answers

Answer:

1. Cu(s) 2. Cu(NO3)2 (aq) 3. Cu(OH)2 (s) 4. CuO (s) 5. CuSO4 (aq)  6. Cu(s)

Explanation:

How much heat (in kJ) would need to be removed to cool 150.3 g of water from 25.60°C to -10.70°C?

Answers

Answer:

Q = -22.9 kJ

Explanation:

Given that,

Mass of water, m = 150.3 g

Water gets cool from 25.60°C to -10.70°C.

The specific heat of water, c = 4.2 J/g°C

The formula for heat needed is given by :

[tex]Q=mc\Delta T\\\\Q=150.3\times 4.2 \times (-10.7-25.6)\\\\Q=-22914.738\\\\or\\\\Q=22.9\ kJ[/tex]

So, 22.9 kJ of heat is needed to be removed to cool.

Determine the m/v% of a solution where 5 g of sugar is dissolved in enough water to yield 250 mL of total solution

Answers

Answer:

2 %m/v

Explanation:

Step 1: Given data

Mass of sugar (solute): 5 gVolume of solution: 250 mL

Step 2: Calculate the %m/v of sugar in the solution

We will use the following expression.

%m/v = mass of sugar/volume of solution × 100%

%m/v = 5 g/250 mL × 100% = 2 %m/v

This means that there are 2 grams of sugar every 100 milliliters of solution.

Which of the following would form a spontaneous reaction at 298 K?
O A. AH = 28 kJ/mol, AS = 0.109 kJ/(mol-K)
B. AH = 31 kJ/mol, AS = 0.093 kJ/(mol-K)
C. AH = 8.7 kJ/mol, AS = 0.008 kJ/(mol-K)
D. AH = 205 kJ/mol, AS = 0.210 kJ/(mol-K)

Answers

Answer:

A

∆H = 28 kJ/mol, ∆S = 0.109 kJ/(mol-k)

Explanation:

A P E X

The spontaneous reaction at 298 K is the one having

ΔH = 28 kJ/mol, ΔS = 0.109 kJ/(mol-K)

We know the formula of Gibb's free energy as-

ΔG = ΔH - TΔS

ΔG = 28 - (298 × 0.109)

ΔG = -4.48

If a reaction is spontaneous, change in Gibb's free energy is negative and change in entropy is positive.

Therefore, The spontaneous reaction at 298 K is the one having

ΔH = 28 kJ/mol, ΔS = 0.109 kJ/(mol-K)

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cell and chromosome characteristics? ​

Answers

Answer:

hope the inserted image will help :)

Explanation:

Answer:  Both are centered inside the nucleus.

Explanation: The characteristics between cells and chromosomes are that they both are centered inside the nucleus (which is a cell). This characteristic applies to both plant and animal cells.

Please help me
5. Where is potential energy decreasing?
А B C D

Answers

Answer:

D

Explanation:

I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.

B it is goin down hill and that means it decreased

Consider this chemical equation:
2AgNO3(aq) + Cu(s) → Cu(NO3)2(aq) + 2Ag(s)
Which substances dissolve in solution? Select all
that apply.
AgNO3
Cu
Cu(NO3)2
Ag
Answer is:AgNO3 and Cu(NO3)2

Answers

Answer:

the answer is very correct as AgNO3 and Cu(NO3)2

Answer:

A,C

Explanation:

the person above me is correct

3. How many particles are present in 13.4 moles of carbon dioxide?
8.07. 1024 particles
04.49. 1022 particles
6.02. 1024 particles
6.02. 1023 particles

Answers

Answer:

[tex]\boxed {\boxed {\sf 8.07 *10^{24} \ particles}}[/tex]

Explanation:

To convert from moles to representative particles, Avogadro's number: 6.02*10²³ is used. This number tells us the amount of particles in 1 mole of a substance. We can use it as a ratio.

[tex]\frac {6.02*10^{23} \ particles}{1 \ mol \ CO_2}}[/tex]

Multiply by the given number of moles.

[tex]13.4 \ mol \ CO_2 *\frac {6.02*10^{23} \ particles}{1 \ mol \ CO_2}}[/tex]

The moles of carbon dioxide will cancel out.

[tex]13.4 *\frac {6.02*10^{23} \ particles}{1}}[/tex]

The denominator of 1 can be ignored and this becomes a simple multiplication problem.

[tex]13.4 * {6.02*10^{23} \ particles[/tex]

[tex]8.0668*10^{24} \ particles[/tex]

The original number of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us round the 6 to a 7.

[tex]8.07 *10^{24} \ particles[/tex]

13.4 moles of carbon dioxide has approximately 8.07*10²⁴ particles.

Without these we would not be able to bend our arms or legs. A. Levers B. Bones C.Joints

Answers

Answer:

Joints

Explanation:

Without joints we would not be able to bend our arms or legs. Hence option C is correct.

What is bending?

Bending is defined as the behavior of a thin structural element under an external load that is applied perpendicular to the element's longitudinal axis. Plants and their parts are thought to bend as a result of a flexure process in which the curvature of the plant part changes. The plant organs' collenchyma gives them flexibility and elasticity, preventing them from breaking when bent.

The force required to bend, straighten, and support joints is applied by muscles to the bones. Muscles act in pairs of flexors and extensors because they may pull on bones but not put them back into place. The extensor muscle relaxes and stretches as the flexor muscle contracts to bend the joint.

Thus, without joints we would not be able to bend our arms or legs. Hence option C is correct.

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3. Which of the following describes the author's purpose in the text? R1.6
A.
to encourage students not to think about money when they're
choosing a degree or career to pursue
B. to stress the importance of viewing college as a way to develop jobs
skills, as well as determine what is important to you
C. to discourage students from pursuing careers in business, as people
are generally dissatisfied with their lives
D. to encourage students to pursue careers that help other people, as
they are usually the most enjoyable and meaningful

Answers

Answer:

B

Explanation:

I took the assessment

Advantages and disadvantages of using tidal energy instead of non-renewable energy sources.​

Answers

Advantages of using tidal energy:

-Environment-friendly

-A highly predictable energy source

-High energy density

-Operational and maintenance costs are low

-An inexhaustible source of energy

Disadvantages of using tidal energy:

-High tidal power plant construction costs.

-Negative influence on marine life forms.

-Location limits.

-The variable intensity of sea waves.

Listed below are characteristics that serve as evidence of shared ancestry between fish and reptiles. Select the option that applies only to embryos rather than adults (1 point)
Ogill slits that turn into gills
O hatch from and lay eggs
O scales as a form of skin
Ospines and tails

Answers

i’m not sure but it’s either B or A

Answer:

Its option A

Explanation:

It cant be option B because the adults lay the eggs, option A is correct because they embryos gill slits turn into gills.

Select all of the following statements that are true. Multiple answers are possible
Cells are made of cells

All living things are made of cells

Cells are the smallest living thing.

Only prokaryotic organisms have cells

Answers

the statements that are true are all living things are made of cells & cells are the smallest living thing. hopes that helps!! :)

If Jonathan went skateboarding from 4:00 PM to 4:30 PM and traveled 450 meters, what was his average speed?

Answers

20 m Increase by five

NEED A AWNSER ASAP PLEASE!!!!

Answers

Last one cuz it stay in the air for a while then swings making it kinetic

Answer:

2. the second one is the answer

Because it shows both potential and kinetic energy

Which simple machine is best used to split apart an object

A. A screw

B. A lever

C. A wedge

D. A pulley

Answers

Answer:

its A screw :))) your welcome

A screw, hope that helps.;)

describe one similarity and one difference between amylopectin and glycogen?

Answers

Answer: The main difference between amylopectin and glycogen is that amylopectin is an insoluble form whereas glycogen is a soluble form. The 1,4-alpha glycosidic bonds form the linear chain of both amylopectin and glycogen while 1,6-alpha glycosidic bonds form the branches.

Explanation:

how many core electrons does magnesium ion have​

Answers

Answer:

10 core electrons

Explanation:

Answer:

Magnesium has 10 core electrons

Which affects both deep water and surface currents in the ocean? the wind the temperature of the water the Coriolis effect None of the above​

Answers

Answer:

the wind and the temperature of water both drive ocean currents

Answer:

B. Write 'T' for true or 'F' for false statements :

1. Publisher works only with document in fixed shapes and sizes.

2. Viewing tools are only for editing purpose.

3. Text box icon is found in Styles group.

4. Publisher does not allow you to add images to your document.

5. Margin guides are blue lines that mark the edges.

Help guys
Please

Please help me if u know

Answers

Because they don’t have the same elements i guess, what is question 1?
They have different density

The table shows the rate of reaction for two unknown time intervals during a chemical change.

Reaction Rates
Time Intervals (s) Rate (M/s)
T1 1.8 x 10−6
T2 1.0 x 10−6

Which of the following is true for the two time intervals? (5 points)

Select one:
a. T1 is longer than T2, and the concentration of reactants at the end of T1 is lower than that of T2.
b. T1 is longer than T2, and the concentration of products at the end of T1 is lower than that of T2.
c. T1 is shorter than T2, and the concentration of reactants at the end of T1 is higher than that of T2.
d. T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.

Answers

Answer:

i think a is the right answer

does anyone know the answer to this​

Answers

It’s Tetracarbon dioxide :)

For the reaction shown, drsw the major(s) expected product.​

Answers

Answer:

2

Explanation:

Ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.

Answers

The given question is incomplete. The complete question is:

Ammonium phosphate [tex](NH_4)_3PO_4[/tex] is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid [tex]H_3PO_4[/tex] with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 1.7 mol of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.  

Answer: 0.57 moles of ammonium phosphate are produced by the reaction of 1.7 moles of liquid ammonia

Explanation:

The balanced chemical equation is:

[tex]H_3PO_4+3NH_4OH\rightarrow (NH_4)_3PO_4+3H_2O[/tex]

According to stoichiometry:

3 moles of liquid ammonia [tex](NH_4OH)[/tex] produces = 1 mole of ammonium phosphate [tex](NH_4)_3PO_4[/tex]

Thus 1.7 moles of liquid ammonia [tex](NH_4OH)[/tex] produces = [tex]\frac{1}{3}\times 1.7=0.57[/tex] mole of ammonium phosphate [tex](NH_4)_3PO_4[/tex]

Thus 0.57 moles of ammonium phosphate are produced by the reaction of 1.7 moles of liquid ammonia

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