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PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS

Answers

Answer 1

Answer:

a no b yes c no d no e yes

Step-by-step explanation:


Related Questions

a rectangle with a length of 20 meters and a width of 11 meters is being dilated by a scale factor of 5. What is the length of the rectangle after the dilation?

Answers

Answer:

We meet again

Step-by-step explanation:

When a rectangle is dilated by a scale factor k, the length and width of the rectangle are both multiplied by k. In this case, the length of the rectangle is being dilated by a scale factor of 5. So the length of the rectangle after the dilation will be 20 * 5 = **100 meters**.

A teacher would like to estimate the mean number of steps students take during the school day. To do so, she selects a random sample of 50 students and gives each one a pedometer at the beginning of the school day. They wear the pedometers all day and then return them to her at the end of the school day. From this, she computes the 98% confidence interval for the true mean number of steps students take during the school day to be 8,500 to 10,200. If the teacher had used a 90% confidence interval rather than a 98% confidence interval, what would happen to the width of the interval?

It would increase by 8%.
It would decrease by 8%.
It would increase, but not necessarily by 8%.
It would decrease, but not necessarily by 8%.

Answers

Answer:

It would decrease, but not necessarily by 8%

If the teacher had used a 90% confidence interval rather than a 98% confidence interval, the width of the interval would decrease, but not necessarily by 8%.

Option D is the correct answer.

What is a confidence interval?

A confidence interval is a range of values that is likely to contain the true value of an unknown parameter, such as a population means or proportion, based on a sample of data from that population.

It is a statistical measure of the degree of uncertainty or precision associated with a statistical estimate.

We have,

The width of a confidence interval is determined by the level of confidence and the sample size.

A higher confidence level requires a wider interval, and a larger sample size typically results in a narrower interval.

Since the sample size is fixed in this case, changing the confidence level will result in a change in the width of the interval.

As the confidence level increases, the width of the interval also increases. This is because a higher confidence level requires a larger margin of error, which is added to the point estimate to create the interval.

Therefore,

If the teacher had used a 90% confidence interval rather than a 98% confidence interval, the width of the interval would decrease, but not necessarily by 8%.

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Can someone please help me please I really need help

Answers

Answer:

16 cans

Step-by-step explanation:

Hey,

I have to admit, this problem is pretty complicated. But I got you :).

To begin, we have to represent the small and large boxes with two separate variables. So...

y = large

x = small

(It really doesn't matter what variable you use, I just used these)

Now, we know that Estelle fills 3 large boxes and 5 small boxes and had a total of 170 cans in total. We can represent this by writing...

3y + 5x = 170

Then, we know that the boy worker filled 4 large boxes and 4 small boxes and had a total of 184 cans. We can represent this by writing...

4y + 4x = 184

As you can see, this is a system of equations.

3y + 5x = 170

4y + 4x = 184

We want to know how many cans each small box can hold, so we have to find a common number for x since x represents the small box.

To do this, we have to multiply the first equation by 4 and the second by 3. Here's what I mean...

4 (3y + 5x = 170)

3 (4y + 4x = 184)

When we do this you get...

12y + 20x = 680

12y + 12x = 552

Notice how the y's are now both 12. We had to do that in order to get rid of y, they had to equal the same number. Now, subtract...

8x = 128

Divide by 8...

x = 16

That means that...

YOUR ANSWER: Each small box can hold up to 16 cans.

I hope this helps :)

SOMEONE PLEASE HELP I'VE BEEN ASKING FOR DAYS NOW WITH SCALE FACTOR!!!!! I will give brainliest if right!!!!!!

Answers

Answer:

It has been answered for you

See this:

https://brainly.com/question/23012157

Help me plz!! I need help and NO FILES PLZZZZZZZ!

Answers

Answer:

1

EXPLAINATION:

y = mx +b

b = y intercept

Right answer will be marked brainlist .
Robert takes out a loan for $7200 at a 4.3% rate for 2 years. What is the loan future value?

Answers

Answer: should be 7819.20

explanation:

7200 * .043 * 2 = 619.20

7200 + 619.20 = 7819.20

Stonewall receives ¢250 per year in simple interest from an amount of money he invested in

ADB, Barclays and GCB. Suppose ADB pays an interest of 2%, Barclays pays an interest of

4% and GCB pays an interest of 5% per annum and an amount of ¢350 more was invested in

Barclays than the amount invested in ADB and GCB combined. Also, the amount invested in

Barclays is 2 times the amount invested in GCB.

a) Write down the three linear equations and represent them in the matrix form AX = B.

b) Find the amount of money Stonewall invested in ADB, Barclays and GCB using Matrix

Inversion​

Answers

Answer:

The amount invested in ADB is ¢1363.[tex]\overline 3[/tex] =

The amount invested in Barclays is ¢3,427.[tex]\overline 3[/tex]

The amount invested in GCB is ¢1,713.[tex]\overline 3[/tex]

Step-by-step explanation:

The parameters of the investment Stonewall made are;

The amount in interest he receives from ADB, Barclays and GCB = ¢250

The amount of interest ADP pays = 2% per annum

The amount of interest Barclays pays = 4% per annum

The amount of interest GCB pays = 5% per annum

The amount invested in Barclays = The amount invested in ADB and GCB + ¢350

The amount invested in Barclays = 2 × The amount invested in GCB

a) Let 'x', represent the amount invested in ADB, 'y' represent the amount invested in Barclays, and 'z', represent the amount invested in GCB

We have;

y = x + z + 350

y = 2·z

0.02·x + 0.04·y + 0.05·z = 250

Therefore, we get the three linear equations as follows;

-x + y - z = 350...(1)

y - 2·z = 0...(2)

0.02·x + 0.04·y + 0.05·z = 250...(3)

Using Matrix inversion, we have;

[tex]\left[\begin{array}{ccc}-1&1&-1\\0&1&-2\\0.02&0.04&0.05\end{array}\right] \times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}350&0&250\end{array}\right][/tex]

The transpose of the 3 by  3 matrix [tex]M^T[/tex] is given as follows;

[tex]M^T = \left[\begin{array}{ccc}-1&0&0.02\\1&1&0.04\\-1&-2&0.05\end{array}\right][/tex]

The Adjugate Matrix is given as follows;

[tex]Adj = \left[\begin{array}{ccc}0.13&-0.09&-1\\-0.04&-0.03&-2\\-0.02&0.06&-1\end{array}\right][/tex]

The inverse of the matrix = Adj/Det where, Det = -0.15, is therefore;

[tex]M^{-1} = \left[\begin{array}{ccc}\dfrac{-13}{15} &\dfrac{3}{5} &\dfrac{20}{3} \\\\\dfrac{4}{15} &\dfrac{1}{5} &\dfrac{40}{3} \\\\\dfrac{2}{15} &-\dfrac{2}{5} &\dfrac{20}{3} \end{array}\right][/tex]

We therefore, get the solution as follows;

[tex]\left[\begin{array}{ccc}\dfrac{-13}{15} &\dfrac{3}{5} &\dfrac{20}{3} \\\\\dfrac{4}{15} &\dfrac{1}{5} &\dfrac{40}{3} \\\\\dfrac{2}{15} &-\dfrac{2}{5} &\dfrac{20}{3} \end{array}\right]\times \left[\begin{array}{c}350&0&250\end{array}\right] = \left[\begin{array}{c}\dfrac{4,090}{3} \\&\dfrac{10,280}{3} \\ & \dfrac{5,140}{3} \end{array}\right][/tex]

[tex]\begin{array}{c}x = \dfrac{4,090}{3} \\&y = \dfrac{10,280}{3} \\ & z = \dfrac{5,140}{3} \end{array}[/tex]

The amount invested in ADB, x = ¢4,090/3 = ¢1363.[tex]\overline 3[/tex]

The amount invested in Barclays, y = ¢10,282/3 = ¢3,427.[tex]\overline 3[/tex]

The amount invested in GCB, z = ¢5,140/3 = ¢1,713.[tex]\overline 3[/tex]

Why is it important to know "first term" and "common ratio" when dealing with geometric sequences?

Answers

Answer:

Each term of a geometric sequence increases or decreases by a constant factor called the common ratio. The sequence below is an example of a geometric sequence because each term increases by a constant factor of 6. Multiplying any term of the sequence by the common ratio 6 generates the subsequent term.

Step-by-step explanation:

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Step-by-step explanation:

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During Year 3, Vernon Corporation reported after the net come of $3,595.000 During the year the number of shares of stock outstanding remained constant at 10.000 of $100 par 9 percent prefered stock and 399,000 shares of common stock. The company's kotel stockholders equity is $19,600,000 at December 31. Year 3. Vernas Corporation's common stock was selling at $54 per share at the end of is scal year. All clvidends for the year have been paid, including $4.20 per share so common stockholders.
Required

3. Compute the earings per share, (Round your answer to 2 decimal places.)

b. Compute the books te of common stock (Round your answer to 2 decimal places.) c. Compute the price warning Mic Round intermediate calculations and final answer to 2 decimal places) d. Compute the dividend yield (Round your percentage answer to 2 decimal places, fe, 0.2345 should be entered as 23.45).)

Answers

a The net income is $3505000

b The number of common shares outstanding is 399,000

c Earnings per share is $8.79

d Book value of common stock is $46.62

e. Price-earnings ratio (P/E ratio) is 6.14

How to calculate the value

a. Net income available to common stockholders:

Net income = $3,595,000

Dividends to preferred stockholders = (Number of preferred shares * Par value * Dividend rate) = (10,000 * $100 * 0.09) = $90,000

Net income available to common stockholders = Net income - Dividends to preferred stockholders

= $3,595,000 - $90,000

= $3,505,000

b. Weighted average number of common shares outstanding:

Number of common shares outstanding = 399,000

c. Earnings per share: EPS = Net income available to common stockholders / Weighted average number of common shares outstanding

= $3,505,000 / 399,000

≈ $8.79

d. Book value of common stock:

Total stockholders' equity = $19,600,000

Preferred stock equity = Number of preferred shares * Par value = 10,000 * $100 = $1,000,000

Common stock equity = Total stockholders' equity - Preferred stock equity

= $19,600,000 - $1,000,000

= $18,600,000

Book value of common stock = Common stock equity / Number of common shares outstanding

= $18,600,000 / 399,000

≈ $46.62

e. Price-earnings ratio (P/E ratio):

Price-earnings ratio = Price per share / Earnings per share

= $54 / $8.79

≈ 6.14

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Find the measure of the exterior 1.
A. 144°
B. 56°
C. 36°
D. 136°

Answers

the exterior is B 56

Write all your steps leading to the answers.) X and Y have joint density function f_(XY)(x,y)=B(1+xy), |x|<1,|y|l; zero, otherwise.
(1) Find B so that f_(XY) (x,y) is a valid joint density function.
(2) Prove or disprove X, Y are uncorrected.
(3) Prove or disprove X, Y are independent.
(4) Prove or disprove X^2 and Y^2 are independent.

Answers

(1) To find the value of B that makes f_(XY)(x,y) a valid joint density function, we need to ensure that the total probability over the entire domain is equal to 1. In this case, the domain is |x|<1 and |y|<1.

The integral of f_(XY)(x,y) over the given domain should be equal to 1:

∫∫ f_(XY)(x,y) dx dy = 1

∫∫ B(1+xy) dx dy = 1

To solve this integral, we integrate with respect to x first and then with respect to y:

∫(∫ B(1+xy) dx) dy

∫[Bx + B(xy^2)/2] dy, integrating with respect to x

Bxy + B(xy^2)/2 + C, integrating with respect to y

Now, evaluate the integral over the given domain:

∫[-1,1] [Bxy + B(xy^2)/2 + C] dy

[Bxy^2/2 + B(xy^3)/6 + Cy] evaluated from -1 to 1

[B/2 + B/6 + C] - [-B/2 - B/6 - C]

(B/2 + B/6 + C) - (-B/2 - B/6 - C)

2B/3 = 1

Solving for B:

B = 3/2

Therefore, the value of B that makes f_(XY)(x,y) a valid joint density function is B = 3/2.

(2) To determine if X and Y are uncorrelated, we need to calculate the covariance between X and Y. If the covariance is zero, then X and Y are uncorrelated.

Cov(X, Y) = E[XY] - E[X]E[Y]

To calculate E[XY], we need to find the joint expectation:

E[XY] = ∫∫ xy f_(XY)(x,y) dx dy

E[XY] = ∫∫ xy (3/2)(1+xy) dx dy

Integrating over the domain |x|<1 and |y|<1, we can calculate E[XY].

Similarly, we need to calculate E[X] and E[Y] to determine Cov(X, Y).

If Cov(X, Y) is found to be zero, then X and Y are uncorrelated.

(3) To prove or disprove independence between X and Y, we need to check if the joint probability density function (pdf) can be factorized into the product of the marginal pdfs of X and Y.

If f_(XY)(x,y) = f_X(x)f_Y(y), then X and Y are independent.

To determine if this factorization holds, we need to compare the joint pdf f_(XY)(x,y) with the product of the marginal pdfs f_X(x) and f_Y(y). If they are equal, then X and Y are independent. Otherwise, they are dependent.

(4) To prove or disprove the independence between X^2 and Y^2, we follow a similar approach as in (3). We compare the joint pdf of X^2 and Y^2 with the product of their marginal pdfs. If they are equal, X^2 and Y^2 are independent. Otherwise, they are dependent.

By examining the factorization of the joint pdfs and comparing them with the product of the marginal pdfs, we can determine the independence relationships between the variables X, Y, X^2, and Y^2.

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Y’all NLE Choppa is in jail. Sending prayers and love

Answers

Answer:

NLE Choppa noooooooooooooooooo

Step-by-step explanation:

THE BEST RAPPPERRR!!!!!!!!!

Answer:

He wasnt in jail? I dont think cuz he was makin new music

Step-by-step explanation:

Please answer and not give me links that make me download a whole bunch of stuff then just turn out to be an inappropriate picture (Yeah that's happened to me twice on here :/)

Answers

Answer:

3

Step-by-step explanation:

12/4=3

PLEASE HELP ME and the first person that answers correctly will get... BRAINLIEST I promise.

Answers

Step-by-step explanation:

V≈75.4

A≈100.53

PLSS HELP IMMEDIATELY!!! i’ll give brainiest if u don’t leave a link!

Answers

Answer:

it's arm will regenerate and grow back

plz mark me as brainliest

Answer:

B. The arm will regenterate

Leo flips a paper cup 50 times and records how the cup landed each time. The table below shows the results. RESULTS OF FLIPPING PAPER CUP Outcome Right-side UP Upside Down On its Side Frequency 10 18 22 Based on the results, how many times can he expect the cup to land on its side if it is flipped 1,000 times? 333 440 550 786​

Answers

Answer:

The answer is 440

Step-by-step explanation:

I just took the test and got that question right

Help please I’ll mark brainiest

Answers

Answer:

V≈7853.98

Step-by-step explanation:

V=πr2h

r=10

h=25

Solution

V=πr2h=π·102·25≈7853.98163

Joe wants to rent a boat and spend less than $33. Boat cost $7 per hour, and Joe has a discount coupon for $9 off. What are the possible numbers of hours Joe could rent the boat? Use t for the number of hours. Write your answer as an inequality solved for t.

Answers

Inequality: 7t - 9 < 33
Solve the inequality
7t < 42
t < 6

$7 per hour plus $9 off

$7x5=$35-$9 discount=$26

$26+$7=$33

6hours=$42-$9=$33

Joe could rent the boat for 6 hours

consider recurrence (and no such that for every non negative integer ny 2 an = 400-1 - 5an-2 +200-3 suppose recurrence (an) has the following initial value a=1 a2=2 in what follows, let a (n) dehote term an for each nonnegative integern write an explicit formula for a(n)

Answers

The given recurrence relation is an = 400 - 5an-2 + 200-3, with initial values a0 = 1 and a1 = 2. We need to find an explicit formula for a(n).

To find an explicit formula for a(n), we will first solve the recurrence relation and then generalize the pattern. Let's expand the relation for a few terms to observe the pattern:

a2 = 400 - 5a0 + 200-3 = 400 - 5(1) + 200-3 = 397

a3 = 400 - 5a1 + 200-3 = 400 - 5(2) + 200-3 = 388

a4 = 400 - 5a2 + 200-3 = 400 - 5(397) + 200-3 = -9603

a5 = 400 - 5a3 + 200-3 = 400 - 5(388) + 200-3 = -1260

From the given examples, we can observe that the recurrence relation alternates between positive and negative values. This suggests that the relation might have a periodic pattern. Since the given recurrence is a second-order relation (in terms of n), it is reasonable to assume that the pattern repeats every two terms.

Based on this observation, we can establish the following explicit formula for a(n):

a(n) = (-1)^(n mod 2) * (200n - 5^(n/2) + 200-3)

In this formula, the term (-1)^(n mod 2) alternates between -1 and 1 depending on the parity of n, ensuring the alternating pattern. The other terms account for the linear and exponential components of the recurrence relation.

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Find the value of x that makes the equation true:

16 - x = 4

x = 18
x = 20
x = 14
x = 12

Answers

16 - x = 4
16 - 12 = 4
x = 12
Find the value of x that makes the equation true:

16 - x = 4


x = 12

Can someone please help me with this page

Answers

Answer:

2. there is no E it would be AB=CD

A school is planning for an addition in some open space next to the current building. The existing building ends at the origin. The graph represents the system of equations that can be used to define the space for the addition. What is the system of equations that matches the graph?

y ≤ 3x
y > –2x – 1
y > 3x
y ≤ –2x – 1
y < –3x
y ≥ 2x – 1
y > –3x
y ≤ 2x – 1

Answers

Equation system that corresponds to the graph:

1. y ≤ 3x 2. y > –2x – 1

To find the system of equations that corresponds to the provided graph, we must first analyze it and locate the regions that fulfil the specified requirements.

1. Begin by locating the darkened region underneath the line y 3x. This line has a slope of 3 and intersects the origin (0,0). Shade the area beneath the line.

2. After that, locate the darkened region above the line y > -2x - 1. The slope of this line is -2, while the y-intercept is -1. The area above the line should be shaded.

3. The solution space that meets both requirements is represented by the overlapping shaded region between the two lines. The common area is located below y 3x and above y > -2x - 1.

4. The equation system that corresponds to this common area is: - y 3x - y > -2x - 1

The space for the addition in the open area next to the present building is defined by these two formulae.

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34.607 to the nearest whole number

Answers

I know the answer is 35

Help help help help help

Answers

Answer:

6 ft

Step-by-step explanation:

The triangle CDE is half of the size of triangle ABC, so if you match up the corresponding sides, DE is half of AC. AC is 12 so DE is 6.

hope is helped!

6ft is the correct answer

Justin completes 8 extra credit problems on the first day and then 4 problems each day until the worksheet is complete. There are 28 problems on the worksheet. Write and solve an equation to find how many days it will take Justin to complete the worksheet after the first day.

Answers

Answer:

28-8-4x=0

x=5

5 days

Step-by-step explanation:

28-8=20 problems left

then 4 each day

i need help i will give branliest please !!!

Answers

We need to know her fastest time

Use synthetic division to determine whether the number is a zero of the polynomial function.
3i;g(x) = x^3 - 4x^2 + 9x - 36

Answers

The last entry in the synthetic division table is not zero, 3i is not a zero of the polynomial function g(x) = x³ - 4x² + 9x - 36.

To determine if 3i is a zero of the polynomial function g(x) = x³ - 4x² + 9x - 36, we can use synthetic division.

First, we set up the synthetic division table:

   3i | 1   -4   9   -36

Performing the synthetic division:

      | (1)  (-4)   (9)   (-36)

   3i |        3i    9i²   27i

      | (1)  (-4 + 3i)   (9 + 9i²)   (-36 + 27i)

Simplifying the last row, we have:

      | (1)  (-4 + 3i)   (9 - 9)   (-36 + 27i)

      | (1)  (-4 + 3i)   (0)   (-36 + 27i)

Therefore, the last entry in the synthetic division table is not zero, 3i is not a zero of the polynomial function g(x) = x³ - 4x² + 9x - 36.

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let R be the region bounded by the functions f(x)=-x^2 and g(x)=-9 as shown in the diagram below. find the exact area of the region R. write your answer in the simplest form. zoom in photo

Answers

What do you mean need more information


please write all the steps... write clearly thanks
Determine the inverse Laplace transforms of: (b) 1 3s²+5s+1

Answers

The inverse Laplace transform of 1 / (3s² + 5s + 1) is f(t) = 1/2 × [tex]e^{(-t)[/tex]- 1/2 × [tex]e^{(-t/3)[/tex].

To find the inverse Laplace transform of the function F(s) = 1 / (3s² + 5s + 1), we can use partial fraction decomposition and reference tables for Laplace transforms.

Step 1: Factorize the denominator

Factorize the denominator of the function 3s² + 5s + 1 to find its roots:

3s² + 5s + 1 = (s + 1)(3s + 1)

Step 2: Write the partial fraction decomposition

Write the function F(s) as a sum of partial fractions:

F(s) = A / (s + 1) + B / (3s + 1)

Step 3: Determine the values of A and B

To find the values of A and B, we can multiply both sides of the equation by the common denominator and equate the numerators:

1 = A(3s + 1) + B(s + 1)

Expand the right side and collect like terms:

1 = (3A + B)s + (A + B)

By equating the coefficients of s and the constant terms on both sides, we get a system of equations:

3A + B = 0

A + B = 1

Solving this system of equations, we find A = 1/2 and B = -1/2.

Step 4: Write the inverse Laplace transform

Using the partial fraction decomposition, we can now write the inverse Laplace transform:

F(s) = 1/2 × (1 / (s + 1)) - 1/2 × (1 / (3s + 1))

Referring to Laplace transform tables, we find that the inverse Laplace transform of 1 / (s + a) is [tex]e^{(at)[/tex], and the inverse Laplace transform of 1 / (s - a) is [tex]e^{(at)[/tex]. Therefore, applying these results, we have:

f(t) = 1/2 × [tex]e^{(-t)[/tex] - 1/2 × [tex]e^{(-t/3)[/tex]

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What's the slope and y intercept of 3x - y = 7

Answers

Answer:

the slope is 3

the y intercept is (0,-7)

Step-by-step explanation:

3x-y=7 solve for y

add y to both sides

3x=7+y

subtract 7 from both sides

y=3x-7

y=mx+b

m=slope

b=y-intercept

3=slope

-7=y-intercept

Hope that helps :)

Other Questions
The latent consequences of employment according to your text include:___________ liana amiri, single and no dependents has the following transactions in 2022:long term capital gain $22,000long term capital loss (8,000)short term capital gain 19,000short term capital loss (23,000)what is liana's net cap;ital gain or loss for 2022?$22,000 net long term capital gain$10,000 net long term capital gain$10,000 net short term capital gain$23,000 net long term capital loss In preparing the above trial balance, the following additional information was extracted from one of the law firms operating bank accounts at the First National State Bank. The December 31, 2021 bank statement shown below disclosed a balance of$128,328.First National State Bank20, High Street, Queenstown.Customer Account Number: 777-222-5140Bank Statement for the month of December 01 - 31, 2021DateDescriptionDebitCreditBalance01-12Previous balance103,230.0001-12Cheque # 5975,520.0097,710.0002-12Cheque # 5952,825.0094,885.0006-12Cheque # 5917,240.0087,645.0007-12Deposit15,455.00103,100.0010-12Cheque # 5941,285.00101,815.0013-12NSF cheque2,415.0099,400.0015-12Deposit13,530.00112,930.0018-12Cheque # 5994,810.00108,120.0020-12Cheque # 5922,620.00105,500.0022-12Deposit9,875.00115,375.0023-12Service charges120.00115,255.0024-12Cheque # 5932,875.00112,380.0024-12Cheque # 6032,402.00109,978.0024-12Customer note andinterest15,500.00125,478.0024-12Service fee on note50.00125,428.0027-12Cheque # 6003,635.00121,793.0028-12Deposit7,850.00129,643.0030-12Cheque # 5981,480.00128,163.0030-12Interest earned165.00128,328.0031-12Statement Totals37,277.0062,375.00128,328.00On the same date, December 31, 2021, the cash account in the general ledger of the firm indicated a balance of $117,113. A comparison of the bank statement and cash account revealed the following:The firms records showed a deposit of $9,320 made on December 31 that is not reflected on the bank statement.The accounting records indicate three cheques written but not yet reflected on the bank statement. These three cheques are as follows:Cheque # 596 - $1,450 Cheque # 601 - $2,230 Cheque # 602 - $3,415The deposit of $15,500 on the bank statement on December 24 was the collection of a note with interest. The value of the note was $15,000 and the other $500 was interest. A fee of $50 was charged by the bank to collect the customers note. The statement notifies the firm that the note with interest has been collected.The bank statement reflected service charges of $120 for December 31, 2021.An entry on December 31 on the bank statement shows interest earned of$165 on the bank account during December.A review of the cancelled cheques returned with the bank statement detected an error that the firm made. The firms records indicated that cheque #598 was paid to Andy John for plumbing services and was recorded incorrectly by the firms accountant as $1,840. The cheque was actually written for $ 1,480 and reflected as such on the bank statement.A NSF cheque for $2,415 from a client, Ann Hardy, was returned with the statement.(i) Prepare the bank reconciliation statement as at December 31, 2021.Prepare the entries in journal form necessary to adjust the accounts.Determine the cash balance as at December 31, 2021. Which of the following are ways that organizational structure determines your role as a project manager? Select all that apply.Organizational structure determines your career growth Organizational structure determines where you fit in Organizational structure determines how frequently to communicate Organizational structure determines who you should communicate with Read the following case and answer the questions that follow about rating errors in performance appraisal.At the end of every semester at Columbus State University, students fill out performance measures to evaluate the quality of instruction in each of their courses. Suppose that Professor Young, a white female, knew that students' evaluations were often subject to several errors in rating bias, so she decided to investigate to see if any of these errors were occurring on her own evaluations. In addition to completing an evaluation of Professor Young's performance, students were asked to fill out a brief demographic survey. Then, she conducted several random interviews with students to find out more information on why they rated her as they did. After gathering all of her data, Professor Young analyzed the information to see if she could identify any trends. What she found was quite interesting. First, after reviewing the evaluations, she discovered that students who thought her tests were difficult tended to rate her negatively in all other areas. After she interviewed some of the students, she also discovered that some students rated all their professors very high, very low, or right down the middle. These students were consistently using only one part of the rating scale, regardless of a professor's effectiveness or lack of effectiveness. Other students tended to compare Professor Young to other instructors. One student even told Professor Young in the interview, "It's not like you are a bad professor, it's just that I had Dr. Ink this quarter and he is great!" The interviews also provided Professor Young with information on why some students rated her very highly. For example, one student told her that he was planning on taking another course from her and thought if he gave her a high evaluation, she would be more lenient in grading his work, even though he knew the evaluations were anonymous. Finally, in analyzing the demographic data, Professor Young saw that the white females were giving her higher ratings than other students. Professor Young had certainly learned quite a bit in analyzing her performance evaluations! She decided that next semester she would discuss rating errors with her class before having them evaluate her instruction.Questions (Pick best option in brackets): describe and give an example of Temperate deciduous forest It can most reasonably be inferred from the use of theword "fancied" in line 85 that Sokol:F.was delusional and near death.G.was pleased to be able to stand one last time.H.had been admired, earlier in life, by many.J.enjoyed a burst of youthful energy. Adjusting Entries for Accrued Salaries Garcia Realty Co. pays weekly salaries of $29,000 on Friday for a five-day workweek ending ending on that day. a. Journalize the nary adjusting entry at the end of the accounting period assuming that the period ends on Wednesday. Salaries Expense 23,200 X Salaries Payable 5,800 X Feedback Check My Work Learning. b. Journalize the necessary adjusting entry at the end of the accounting period assuming that the period ends on Thursday. Salaries Expense Salaries Payable Feedback Check My Work Some types of services used in earning revenues are paid for after the service has been performed. In such cases, the expense is increased. When does the accounting period and? what color on a slide actually reduces someones ability to think clearly? decompose into partial fractions:[tex]\frac{x^5-2x^4+x^3+x+5}{x^3-2x^2+x-2} \\ \\ \\ \frac{4x^2-14x+2}{4x^2-1}[/tex] A nurse is obtaining the genetic history of a pregnant client by eliciting historical information about her family members. which question is most appropriate for the nurse to ask? Which of the following is a good condition for bottom-up estimating?A. Strategic decision makingB. Internal, small projectC. Fixed price contractD. High uncertaintyE. Both C and D are good conditions for bottom-up estimating Find z1 - z in polar form. z1 = 2cis(50), z2= 5cis(300) Find the largest value of x that satisfies: logo () - logs (+ 5) = 5 = Which of the following CR cassette sizes will provide the greatest recorded detail?a. 8 x 10 inchb. 10 x 12 inchc. 14 x 17 inchd. All sizes would have equal recorded detail. question 9.9 which band combination(s) is(are) best for separating urban areas from other forms of land cover (i.e., vegetation, trees, etc.)? why? a) Use the van der Waals equation of state to calculate the pressure of 3.20 mol of hcl at 499 K in a 4.90-L vessel.b) Use the ideal gas equation to calculate the pressure under the same conditions. Select the correct answer. Circle has radius of 24 units. Arc located on the circle has a central angle of . What is the area of the associated sector, in square units? A. B. C. D. In 2010, the binder industry was perfectly competitive. The market demand curve for binders was: QD=3172-42P where P was the price of a binder (in dollars per binder) and Qp was the quantity of binders demanded per month. The market supply curve for binders was: Qs 100+150P where Qs was the quantity of binders supplied per month. a) Solve for the short run equilibrium price and output of binders (show your work).b) If a representative binder seller has long-run total cost given by: TC= 1 + 2q +0.0625q where q is the monthly output of the individual binder seller, what is the long-run, profit maximizing level of output of this firm? Explain your answer. Hint: In the long run, firms produce where ATC is at a minimum. c) What is the long-run equilibrium price charged in the market for binders? d) What is the long-run equilibrium output of the binder industry?(Hint: Assume that the firms will meet the demand at the long run price.) e) Approximately how many binder sellers will there be in the long-run equilibrium (round your answer to the nearest whole number)? : Which type of lymphocyte produces and secretes antibodies?1) Memory B-lymphocyte 2) Memory T-lymphocyte 3) Natural killer cell 4) Plasma cell 5) Cytotoxic T-lymphocyte