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The statement fourth "The spread between the lower quartile and the median is greater than the spread between the upper quartile and the median" is correct.

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

The box plot is missing.

The box plot is shown (please refer to attached picture)

The given options are:

As we know the property of box plot the difference between the lower and higher quartiles is greater than the difference between the upper and lower quartiles.

The spread between the lower quartile and the median:

= 15 - 9 = 6

= 19 - 15 = 4

Thus, the statement fourth "The spread between the lower quartile and the median is greater than the spread between the upper quartile and the median" is correct.

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Answer:

0.01

Step-by-step explanation:

so i divided 5 by 365 because 365 days or in a year so 5/365=0.01369863013 and usually just said as 0.01

Hope This Helped

Answer z=2

See picture attached for the math

Done!

Answer:

[tex](f+g)(x)=3x^3-2x^2+10x-12[/tex]

Step-by-step explanation:

Given:

[tex]\begin{cases}f(x)=3x^3-2x^2+4x-5\\g(x)=6x-7 \end{cases}[/tex]

[tex]\begin{aligned}(f+g)(x) & = f(x)+g(x)\\& = (3x^3-2x^2+4x-5)+(6x-7)\\& = 3x^3-2x^2+4x-5+6x-7\\& = 3x^3-2x^2+4x+6x-5-7\\& = 3x^3-2x^2+10x-12\end{aligned}[/tex]

Answer:

[tex]m\angle A = 91^{\circ}[/tex]

Step-by-step explanation:

All angles in a quadrilateral must add up to [tex]360^{\circ}[/tex], so [tex]\angle A + \angle B + \angle C + \angle D = 360^{\circ}[/tex]

We can now solve for [tex]\angle A[/tex] by substituting [tex]\angle B, \angle C, \angle D[/tex] for the correct values.

[tex]\angle A + \angle B + \angle C + \angle D = 360\\\angle A + 72 + 130 + 67 = 360\\\angle A + 269 = 360\\\\\boxed{\angle A = 91^{\circ}}[/tex]

That is the answer

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The interquartile range of the data that is represented on the dot plot is: 2 chocolate chips.

Interquartile range (IQR) = upper quartile - lower quartile.

Upper quartile (Q3) = center of the second half of the data = 5

Lower quartile (Q1) = center of the first half of the data = 3

Interquartile range (IQR) = 5 - 3

Interquartile range (IQR) = 2 chocolate chips.

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Answer: The answer is True .

The statement is false, these two ratios don't make a proportion.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

here, we have,

5/9, 56/99

we know, that, two ratios make a proportion if, a:b=c:d

but, here,

5/9= 5:9

56/99 = 56: 99

Hence, The statement is false, these two ratios don't make a proportion.

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The statement that completes the definition is (d) down payment

From the question, we have the following highlights:

When a part payment is made to procure an item, the part payment is referred to as a down payment

The down payment fits the highlights (1) and (2) stated above

Hence, the statement that completes the definition is (d) down payment

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Answer:

3 Cups of flour.

Step-by-step explanation:

Answer:

25 = b

26 = c

Step-by-step explanation:

From the information provided, Jenna's taxable income is zero. See the explanation below.

The formula for taxable income is given as:

Gross Income Less Standard Deduction.

Since the current effective standard deduction for singles is $12,950 Jenna doesn't need to file a tax return since tax cannot be a negative figure.

it is to be noted that the rate payable for individual single taxpayers in 2022 is $10% up to $10,275.

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Por razones trigonométricas, encontramos que las alturas de la torre y el edificio son de aproximadamente 11.548 metros y 31.548 metros, respectivamente.

En esta pregunta debemos utilizar conceptos de trigonometría para determinar la altura de los dos edificios. A continuación, tenemos las siguientes expresiones trigonométricas:

Diferencia entre las alturas del edificio y el torre

20 = r₁ · sin 60°

r₁ ≈ 23.094 m

Ahora determinamos el valor de r₂ mediante identidades trigonométricas:

r₂ = r₁ · (cos 60°/cos 45°)

r₂ = (23.094 m) · (cos 60°/cos 45°)

r₂ ≈ 16.330 m

Finalmente, obtenemos las alturas de cada edificio:

Torre

h = (16.330 m) · sin 45°

h ≈ 11.548 m

Edificio

h' = h + 20 m

h' = 11.548 m + 20 m

h' = 31.548 m

Por razones trigonométricas, encontramos que las alturas de la torre y el edificio son de aproximadamente 11.548 metros y 31.548 metros, respectivamente.

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Answer:

Mean = 2.2

Median = 1

Mode = 0 and 1

Range = 9

Step-by-step explanation:

First arrange the number of calls from least to greatest.

0, 0, 0, 1, 1, 1, 2, 3, 5, 9

Mean is the average. Add the numbers together and divide by 10 since there are 10 numbers in total.

0 + 0 + 0 + 1 + 1 + 1 + 2 + 3 + 5 + 9 = 22

22/10 = 2.2

Mean = 2.2

Median is the middle number. Since there is an even amount of numbers, take the 5 and 6 number in the list, add them together and divide by 2. You are taking the average of the two numbers.

0, 0, 0, 1, 1, 1, 2, 3, 5, 9

1 + 1 = 2

2/2 = 1

Median = 1

Mode is the number that occurs the most.

0, 0, 0, 1, 1, 1, 2, 3, 5, 9

In the list the numbers 0 and 1 both occur 3 times.

Mode = 0 and 1

Range is the biggest number (9) minus the smallest number (0).

0, 0, 0, 1, 1, 1, 2, 3, 5, 9

9 - 0 = 9

Range = 9

Answer:

noncollinear

Step-by-step explanation:

my guess sorry if im wrong

Answer:

a) 7 b) 24 c) 8.5 d) 11.4 (i think)

Step-by-step explanation:

Answer:

[tex]\sf x=1+i\sqrt{\dfrac{2}{3}} \ \quad and \quad \:x=1-i\sqrt{\dfrac{2}{3}}[/tex]

Explanation:

Given Expression:

Use the Quadratic Formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ when \ \ ax^2 + bx + c = 0[/tex]

insert coefficients

[tex]\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}[/tex]

[tex]\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}[/tex]

[tex]\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}[/tex]

[tex]\Longrightarrow \sf x =1 \pm i\dfrac{\sqrt{6} }{3}[/tex]

[tex]\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}}, \quad 1-i\sqrt{\dfrac{2}{3}}[/tex]

Use quadratic formula

[tex]\\ \rm\Rrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{6\pm \sqrt{36-60}}{6}[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{6\pm\sqrt{-24}}{6}[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{6\pm2\sqrt{6}i}{6}[/tex]

[tex]\\ \rm\Rrightarrow x=1\pm \dfrac{sqrt{2}i}{\sqrt{3}}[/tex]

[tex]\\ \rm\Rrightarrow x=1\pm\sqrt{\dfrac{2}{3}}i[/tex]

AYEEE SAME WOOOO!!! HOPE YOU'RE HAVING A GREAT DAY :D

Answer:

[tex]\frac{2B}{1m} =h[/tex]

Step-by-step explanation:

[tex]B =\frac{1hm}{2}[/tex]

Multiply both sides by 2.

[tex]2B = 1hm[/tex]

To make h as the subject divide both sides by 1m.

[tex]\frac{2B}{1m} =\frac{1hm}{1m}[/tex]

Therefore,

[tex]\frac{2B}{1m} =h[/tex]

Answer:

Step-by-step explanation:

Remark

The deck is divided into 4 different kinds of cards

clubs

diamonds

Hearts

Spades

Each kind of card has a 2

So there are 4 twos in a standard deck of cards.

Answer:

The appropriate journal entries related to the investment during 2021 is: Debit Investment in Carne shares $78 million; Credit Cash $78 million.

January 2, 2021

Debit Investment in Carne shares $78 million

Credit Cash $78 million

January 12, 2021

Debit Cash $12,000,000

($2 per shares  x 6,000,000)

Credit Investment in Carne shares  $12,000,000

December 21, 2021

Debit  Investment in Carne shares $7,000,000

Credit Investment revenue $7,000,000

(25% x $28,000,000)

December 31, 2021

Debit Investment revenue $1,000,000

Credit Investment in Carne shares $1,000,000

[25% x ($48,000,000 ÷ 12 years)]

December 31, 2021

No journal entry for changes in fair value when using equity method.

Therefore the appropriate journal entries related to the investment during 2021 is: Debit Investment in Carne shares $78 million; Credit Cash $78 million.

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Answer:

24/5

Step-by-step explanation:

x is 4.8, improper simplified is 24/5

Answer:

Step-by-step explanation:

Answer:

2.953

Step-by-step explanation:

Following the order of operations, work from left to right for addition/subtraction.

Subtraction:

[tex]\begin{array}{r r r r r} ^0\diagup\!\!\!\!1 &. & ^10 & ^0\diagup\!\!\!\!1&^1 2\\ -\quad0&.&8&0&9\\\cline{1-5}0&.&2&0&3\\\cline{1-5} \end{aligned}[/tex]

Addition:

[tex]\begin{array}{r c c c r} 0 & . & 2&0&3\\ + \:\:2 &.& 7 & 5\\\cline{1-5}2&.&9&5&3\\\cline{1-5} \end{aligned}[/tex]

Therefore, the solution is 2.953

Let's see

2.75 can be written as 2.750

Answer:

120m²

Step-by-step explanation:

Area¹ = (6*5) = 30*2 surfaces = 60m²

Area² =(6*6) = 36m²

Area of Triangle =(1/2*4*6) = 12* 2 surfaces = 24m²

Total surface area = 60 + 36 + 24 = 120m²

=/120m²

The expression, the company can use to predict the value of the car is v =32000 (0.8)^t

The company which provides term life or accidental or death insurance in terms of money when one subjects to any of the conditions.

Given is an insurance company estimates that the value of a car depreciates by 20% each year (That also means it retains 80% of its value each year). The company used an exponential function to predict the value of a car, v, as a function of time, t, in years.

The rate of interest r in percentage = 100 - 20 = 80%

If the value of a brand new car is  P =$32,000.00.

The value of car will be

value =  P x r^t

v = $32,000 x(0.8)^t

Thus, this is the expression insurance company uses to find the value of car.

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