please help me and make it fast.

Answer:

[tex]Accept = 69.44\%[/tex]

[tex]Reject = 11[/tex]

Step-by-step explanation:

Given

See attachment for dataset

Solving (a): Percentage to accept

The percentage to accept are flea collars that range between 14mg to 16mg (inclusive)

From the attachment, we have:

[tex]Total = 36[/tex]

[tex]n(14mg-16mg) =25[/tex] --- Number of 14mg to 16mg

So, the percentage to accept is:

[tex]Accept = \frac{n(14mg-16mg)}{Total} * 100\%[/tex]

[tex]Accept = \frac{25}{36} * 100\%[/tex]

[tex]Accept = 0.6944 * 100\%[/tex]

[tex]Accept = 69.44\%[/tex]

Solving (b): Collars to reject

In (a), we have:

[tex]n(14mg-16mg) =25[/tex]

The number to reject is then calculated by subtracting the collars to accept from the total (this is called complement rule)

So, we have:

[tex]Reject = Total - n(14mg - 16mg)[/tex]

[tex]Reject = 36 - 25[/tex]

[tex]Reject = 11[/tex]

11 will be rejected

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