PLEASE HELP a current of 0.5 A flows with a resistance of 50 ohms what is the e.m.f applied NEED HELP ASAP AND BRAINLIEST​

Answers

Answer 1

Answer:

25 volts

Explanation:

voltage = current × resistance

[tex]v = i \times r \\ v = 0.5 \times 50 \\ v = 25v[/tex]


Related Questions

Classify each characteristic as either a metal or a nonmetal.
shiny surface
dull surface
good conductor of electricity
good conductor of heat
poor conductor of electricity
poor conductor of heat
malleable
brittle

Answers

Answer:

metal, non, metal, metal, non, non, metal, non

Explanation:

knowledge


An object has an initial velocity of 15 m/s and a constant acceleration of 4 m/s2. How long will it take before its final velocity is equal to three times its initial velocity?

Answers

Based on the calculations, it would take 7.5 seconds before the final velocity of this object would be equal to three times its initial velocity.

Given the following data:

Initial velocity = 15 m/s.Constant acceleration = 4 m/s².Final velocity = 3 × 15 = 45 m/s.

How to calculate the acceleration of an object?

Mathematically, acceleration can be calculated by using the first equation of motion:

v = u + at

Where:  

v is the final velocity.u is the initial velocity.t is the time measured in seconds.

Making t the subject of formula, we have:

t = (v - u)/a

Substituting the given parameters into the formula, we have:

t = (45 - 15)/4

t = 30/4

t = 7.5 seconds.

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Of the following, which is the best reason for why a woman's risk for cardiovascular disease increases after menopause?

Answers

Answer:

The best reason for the increased risk of cardiovascular diseases in women after menopause is the significant decrease in the levels of Estrogen in the body.

Detailed answer:

Due to the approach of menopause the estrogen levels in the blood decrease drastically. Estrogen helps in relaxing the vessels and keeping them in their natural diameter. But due to a drastic decrease in its level due to menopause, there is a high chance of cholesterol building up on the walls of the artery in the heart, which can cause many cardiovascular diseases.

When a force of 450N pushes on a 20kg box as
shown, the acceleration of the box up the incline is
0.70m/s2. Find the coefficient of sliding friction
between the box and the incline.

Answers

Answer:

ma+mgsinh0​+f=F∴(25)(0.75)+(25)(10)sinh0​+μk​N=F∴18.75+(250)(0.6h)+μk​(mgcosh0​=F⟹18.75+150+μk​((25)(10)(0.76))=500∴168.75+μk​(190)=500⟹μk​(190)=331.25⟹μk​=1.74

Explanation:

Friction can only occur between solids and ________

Answers

Friction can only occur between solids, liquids and gas.

What is friction?

Friction can be defined as the force that a moving object encounters when sliding over a surface.

The various phases of matter include solid, liquid and gases and friction occurs in all the three phases of matter.

Therefore, Friction can only occur between solids, liquids and gas.

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In the video, the students create two charged tapes, a "pointy" tape and a "square" tape. The pointy tape is first placed on top of the square tape, and the two are pulled apart. After pulling them apart, the students observed the behavior of the tapes when they were brought near each other, but not touching each other.

Answers

The two pointy tapes repel. This shows they have the same type of charge.

Attraction of two charges

The attraction of two charges occurs when the two charges have opposite charges.

Repulsion of two charges

The repulsion of two charges occurs when the two charges have similar charges.

Thus, since the two pointy tapes will have the same charge, we can conclude that they will repel each other when brought near each other.

The complete question is below:

How did the pointy tapes behave when brought near each other, and what does this demonstrate about their charges?

Two pointy tapes repel. This shows they have opposite types of charge.

Two pointy tapes attract. This shows they have opposite types of charge.    

Two pointy tapes repel. This shows they have the same type of charge.

Two pointy tapes attract. This shows they have the same type of charge.

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Fluid Dynamics links the concept of viscosity to the fluid flow. Mention how the contact angle, surface tension, capillarity governs the flow?

Answers

Fluid Dynamics is an area of ​​research that started a long time ago, along with Calculus. It combines techniques of Mathematical Analysis and of Dynamical Systems, such as Bifurcation Theory, among others.

What is surface tension?

Surface Tension is a phenomenon that occurs in all liquids, it is characterized by the formation of a kind of elastic membrane at its ends.

How to calculate the contact angle?

Contact angles in powders can be measured using the sessile drop measurement in the compressed powder or using the force tensiometer with the Washburn method.

In fluid dynamics, the variables of surface tension, viscosity and contact angle are treated. When dealing with viscosity we have  fluid can be viscous or a real fluid. In general, fluids are viscous.

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The graph below shows the conservation of energy for a skydiver jumping out
of a plane and landing safely on the ground. Which energy is represented by
line C?

Answers

Answer:

Kinetic energy

Explanation:

what is difference between heat engine and carnot engine

Answers

Answer: A heat engine uses temperature differences which cause pressure changes to exert force on a moving part. A Carnot Process is a theoretical explanation of a process involving pressure and temperature changes during ,amongst other things, phase changes.

Explanation:

Answer: The difference is a heat engine uses temperature differences which cause pressure changes to exert force on a moving part, A Carnot engine is only a theoretical explanation of a process involving pressure and temperature changes during or amongst other things.

Explanation:

Two large parallel metal plates carry opposite charges. They are separated by 0.20 m and the p.d. between them is 500 V. What is the magnitude of electric field, if it is uniform, in the region between them.​

Answers

Hi there!

We can use the following relationship between the Potential Difference and the Electric field:

[tex]V = E d[/tex]

V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)

We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]

Plug in the given values.

[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]

If a 75 resistor is connected to a 18 V battery, how much current passes
through the resistor?

Answers

Answer:

0.24 A

Explanation:

Voltage is given by the equation :

V = I × R

Voltage = Current × Resistance

Rearrange to make Current/I the subject :

18 = I × 75

I = 18÷75

I = 0.24 A

Hope this helped and brainliest please

Define 1 volt. Express it in terms of SI unit of work and charge calculate the amount of energy consumed in carrying a charge of 1 coulomb through a battery of 3 V.​

Answers

Answer:

Work done =3 joules

Explanation:

1 volt is the same as 1 Coulomb and 1 Joule

V=W/Q

1=W/3

W=3 x 1

W=3 Joules

Discuss the role of oxygen in air supply.

Answers

T he role of oxygen in air supply is to keep all the ling beings live and healthy.

What is Oxygen?

Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.

Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.

Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.

Thus, the air supply needs oxygen on the majority.

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Sunlight hits the black asphalt pavement on a sunny,
summer day. The pavement becomes excessively hot.
What wave behavior is demonstrated by this
phenomenon?

Answers

It is radiation (don’t mind this part just to fill 20 characters)

Why is digital forensics important?

Answers

Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.

A sewing machine uses 1.6kWh of electricity in one day. If electricity costs 9p per unit, what is the total cost in pence of using the sewing machine that day? Give your answer to 3 significant figures.

Answers

Answer:

[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]

Explanation:

Since,

1 kWh = 1 unit

So,

1.6 kWh = 1.6 units

If,

1 unit = 9p

1.6 units = 9p × 1.6

1.6 units = 14.4p

[tex]\rule[225]{225}{2}[/tex]

You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using electric fields. The physical setup is shown in the figure below.

Answers

You are working for a manufacturing company, which is mathematically given as

[tex]m=3\sqrt{2}[/tex][tex]m=\frac{15\sqrt{5}}{16}[/tex]x=0.747a[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]

What is the value of m that will place the movable bead in equilibrium at x-a a ....?

a)

Generally, the equation for the force of equilibrium is mathematically given as

F=2fcos\theta

Therefore

[tex]K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3[/tex]

[tex]m=3\sqrt{2}[/tex]

b)

By force equilibrium

[tex]K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}[/tex]

Therefore

[tex]n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\[/tex]

[tex]m=\frac{15\sqrt{5}}{16}[/tex]

c)

[tex]K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}[/tex]

x^2+a^2=(14/3)^{2/3}x^2

x=a/1.338

x=0.747a

d)

By force equilibrium

[tex]K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}[/tex]

[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]

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An object of volume 2.0×10^4cm³ is under water .calculate the buoyant force of water on the object (Density of water=1000kg/m³)

Answers

An object of volume 2.0×10^4cm³ is underwater, the buoyant force of the water on the object  

Fb= 1.962 *10^7N

What is the buoyant force?

Generally, the equation for buoyant force   is mathematically given as

Fb = g * p * V

Therefore

Fb=9.81* 2.0*10^4 *1000

Fb= 1.962 *10^7N

In conclusion,  the buoyant force

Fb= 1.962 *10^7N

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Is the ability to discriminate between two close objects.

Answers

Answer:

resolution

Explanation:

  That is the definition of resolution

An infinitely long line of charge has a linear charge density of 8.00*10^−12 C/m. A proton is at distance 19.0 cm from the line and is moving directly toward the line with speed 1200 m/s. How close does the proton get to the line of charge?

Answers

Hi there!

To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.

For this, we can use the work-energy theorem to solve.

Recall the following equations:
[tex]W = \Delta KE[/tex]

[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]

We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.

The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]

For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]

**λ = Linear charge density (C/m)

To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]

Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]

[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]

Now, we can begin solving for 'a'.

Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]

Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]

It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.

What is the meaning of the safety symbol shown below?

Answers

Answer:

D. Poison

Explanation:

In-Class Problem #2
at
at
A 79.5 kg defensive end tackles a 60 kg
running back going north at 5 m/s. After the
hit both players move together at 2.5 m/s
south. How fast was the defensive end
running before the tackle?
on
ne ta
EAOLES
62
v = 8.16 m/s south
-0
362

Answers

Answer:

8.16m/s south

Explanation:

North is the negative direction.

60kg*(-5m/s)+79.5kg*v=(79.5kg+60kg)*(2.5m/s)

-300kgm/s+79.5kg*v=348.75kgm/s

79.5kg*v=648.75kgm/s

v=8.16m/s

you can only apply a 200n force but u need to make a 20 kg wagon of mulch travel at a speed of 10 m/s. How long do you have to push the wagon before its speed reaches 10m/s if it starts at rest

Answers

Time for which the wagon is pushed before it speed reaches 10m/s from rest.

What is momentum?

The momentum is the product of mass of an object and its velocity.

Let the impact force is applied for time t. The impulse is equal to the change in momentum.

F.t = m(Vf -Vi)

where Vf =10 m/s, Vi =0 m/s, m =20kg and F =200N, then time for the force applied will be

200 x t = 20 x (10)

t =1s

Thus, the time for which the wagon is pushed before it speed reaches 10m/s from rest is 1s.

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Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate .
An employee will display by adhering to professional standards of the workplace and encouraging co-workers to do the same.

Answers

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

Who is a leader?

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.

Hence, self-representation and leadership skills are the correct answer.

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when solving for t you used sin theta instead of cos theta?

Answers

Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse . No matter the size of the triangle, the values of sin(θ) and cos(θ) are the same for a given θ, as illustrated below.

Mark as brainlest answer!


You drive a car east on the highway at 26 m/s. Another car passes you moving east traveling at 32 m/s. How fast do you view the car passing you?

Answers

The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

Relative velocity of the car

The speed of the car passing you is determined by applying relative velocity principle as shown below;

Vr = Va - Vb

Vr = 26 m/s - 32 m/s

Vr = -6 m/s

Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

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the frequency of a pendulum has a period of 1.13 seconds is?

A) 0.88
B) 1.13
C) 1.27
D) 11.3

Answers

Answer:

A 0.88

Explanation:

frequency=1/period

=1/1.13=0.88

how much force is required to accelerate an 8.6kg wagon by 15 m/s ?

Answers

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

What is force?

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

Mass of the rock m = 8.6kgAcceleration a = 15m/s²Force F = ?

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

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Why is it important to to find information about if if crabs can or can't see the plankton, they eat near the ocean floor

Answers

Answer:

One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.


(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire

Answers

From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is  6.4 * 10^7 .

What is Hookes law?

According to Hooke's law, the force is directly proportional to the extension of the wire.

Given that;

F = Ke

F = 240N

e = 0.8 mm or 0.0008m

K = F/e

K = 240N/0.0008m

K = 3.0 * 10^5 N/m

Now;

Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3

= 6.4 * 10^7

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