1. The fraction of the neutron's kinetic energy transferred to the atomic nucleus is 8% or 0.08.
2. The final kinetic energy of the neutron KE₂ (neutron), is 6.42 x 10⁻¹³ J.
What is kinetic energy?Kinetic energy is the energy possessed by a body by virtue of its motion.
The fraction of the neutron's kinetic energy that is transferred to the atomic nucleus is calculated as follows:
The final velocity of the atom is found using the principle of conservation of linear momentum.
initial momentum of the neutron = final momentum of the atom
m₁u₁ = m₂u₂
where;
m₁ = mass of the neutron
u₁ = initial velocity of the neutron
m₂ = mass of the atomic nucleus
u₂ = final velocity of the atomic nucleus
m₂ = 112.4 m₁
u₂ = m₁u₁ / m₂
u₂ = m₁u₁ / (12.4 m₁)
u₂ = 0.08 u₁
The initial kinetic energy of the neutron is determined as follows:
KE₁ = ¹/₂m₁u₁²
The final kinetic energy of the atomic nucleus is determined as follows:
KE₂ = ¹/₂m₂u₂²
KE₂ = ¹/₂(12.4 m₁)(0.08u₁)²
KE₂ = 0.08 (¹/₂m₁u₁²)
KE₂ = 0.08 (KE₁)
The fraction of the neutron's kinetic energy transferred to the atomic nucleus is determined as follows:
Fraction = 0.08 (KE₂) / KE₁
Fraction= 0.08
Fraction = 8 %
The final kinetic energy of the neutron is calculated as follows;
KE₂ (neutron) = (1 - 0.08) x (6.97 x 10⁻¹³ J)
KE₂ (neutron) = 6.42 x 10⁻¹³ J
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a person kicks a ball into the air with a force f0. the figure shows the position of the ball at various times. what is the net force on the ball and its acceleration at the highest point shown?
Answer:
force=mg+Fo
acceleration=0
Explanation:
A ladder with mass, m= 10.8 kg and length, L= 10.5 m is leaning against a frictionless wall. If the ladder makes an angle of 72 degrees with the ground, what is the horizontal force exerted by the ladder on the wall? Give the answer in newtons (N) and rounded to three significant figures.
430.9 N is the horizontal force exerted by the ladder on the wall
Torque=FLsinθ
m=10.8kg
L=10.5m
g=9.8 ms²
θ=72
Torque=FLsinθ
Torque=1111.32×sin 72
Torque=430.9 N
In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three principles of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the idea of force (1687).
Newton's first law states that unless a force is applied to a body, it will stay in either its resting or uniformly moving condition along a straight path. According to the second law, when an external force applies on a body, the body accelerates (changes velocity) in the force's direction.
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A wind turbine transfers energy from __________ energy stores. What one word completes the sentence?
A wind turbine transfers kinetic energy to mechanical energy from energy stores, which is then used to generate electricity.
What is wind energy?Wind energy is a type of renewable source of energy that can be used for converting it into electrical energy by the use of turbines that transform mechanical energy into electricity, which is then used for different purposes (both industrial and particular home usage).
Therefore, with this data, we can see that wind energy can be used to generate electricity by means of turbines that convert mechanical energy into electricity.
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A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving
at 20 m/s in a direction 30 o
south of west. After collision, the two vehicles
remain tangled together. Find the speed and state the direction of car.
Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.
Conservation of Linear MomentumIt states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.
Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.
The given parameters are;
M1 = 7500 kgU1 = 5 m/sM2 = 1500U2 = 20 sin 30 = 10 m/sV = ?The formula to find the speed will be
M1U1 - M2U2 = (M1 + M2)V
7500 × 5 - 1500 × 10 = (7500 + 1500)V
37500 - 15000 = 9000V
22500 = 9000V
V = 22500/9000
V = 2.5 m/s
Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.
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How long does it take a ball to fall 75.0m? (g = -9.81 m/s²)
O 15.3 m/s²
O 3.91 s
O 15.3 s
O 3.90 m/s²
Answer:
3.91 s
Explanation:
d = -75
a = -9.81
d = 1/2 at^2
-75 = 1/2 ( -9.81) (t^2)
75 = 1/2 ( 9.81) t^2 shows t = 3.91 s
A car accelerates from rest to 28 m/s in 3.5 seconds. What’s the acceleration
positive charge Q and a particle with a negative charge -Q. What will be the direction of the electric field at point P?
The direction of the electric field at a given point is determined by the relative magnitudes and positions of the charges involved. The electric field lines always point away from positive charges and towards negative charges. The strength of the electric field is greater when the charges are closer together.
At point P, the direction of the electric field created by a positive charge Q and a particle with a negative charge -Q will depend on the relative positions of the charges. Let's consider two scenarios:
1. If the positive charge Q is closer to point P than the negative charge -Q:
In this case, the positive charge Q will exert a stronger electric field compared to the negative charge -Q at point P. The electric field vectors will point away from the positive charge Q and towards the negative charge -Q. Therefore, the overall direction of the electric field at point P will be towards the negative charge -Q.
2. If the negative charge -Q is closer to point P than the positive charge Q:
In this scenario, the negative charge -Q will exert a stronger electric field compared to the positive charge Q at point P. The electric field vectors will point away from the negative charge -Q and towards the positive charge Q. Consequently, the overall direction of the electric field at point P will be towards the positive charge Q.
It's important to note that the direction of the electric field is independent of the charge of the test particle at point P. The electric field exists irrespective of the presence of a test charge, and its direction is determined solely by the configuration and positions of the charges creating the field.
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20pts!
Alex slides a 170 g hockey puck across a sheet of ice. The coefficient of kinetic friction between the puck and the ice is 0.09. What is the puck's rate of acceleration as it slides across the ice?
-0.88 m/s2
−1.74 m/s2
−1.16 m/s2
−2.09 m/s2
The rate of acceleration of the hockey puck with a mass of 170 g is 0.88 m/s².
What is acceleration?Acceleration can be defined as the rate of change of velocity.
To calculate the acceleration of the puck, use the formula below.
Formula:
a = gμ................ Equation 1Where:
a = Acceleration of the puckg = Acceleration due to gravityμ = Cofficient of kinetic frictionFrom the question,
Given:
g = 9.8 m/s²μ = 0.09Substitute these values into equation 1
a = 9.8×0.09a = 0.88 m/s²Hence, puck's rate of acceleration is 0.88 m/s².
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A rescue helicopter is lifting two people upwords as shown in the diagram below. The tension in the cable is 1205.4 N while the helicopter ascends at a Constant Speed ignore are resistance.
Explanation:
Let
T
be the tension of the cable and m
g
be the force of gravity. If the upward direction is positive, then Newton’s second law is T−mg=ma, where a is the acceleration. Thus, the tension is T=m(g+a). We use constant acceleration kinematics (Table 2-1) to find the acceleration (where v=0 is the final velocity, v
0
=−12m/s is the initial velocity, and y=−42m is the coordinate at the stopping point). Consequently, v
2
=v
0
2
+2ay leads to
a=−
2y
v
0
2
=−
2(−42m)
−12m/s
=1.71m/s
2
We now return to calculate the tension:
T=m(g+a)
=(1600kg)(9.8m/s
2
+171m/s
2
)
=1.8×10
4
N
The maximum force that wire A can withstand without breaking is 2000 N. Wire B is made of the same material as wire A but has twice the diameter.
What is the maximum force that wire B can withstand?
The maximum force that wire B can withstand is same as A.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.
For wire diameter do not effect the force it can withhold so, A and B and have same force 2000 N.
The maximum force that wire B can withstand is same as A.
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Monkey Joe is trying to prove how strong he is by pulling a 5000 kg truck. He applies a force of 6000N at an angle of 30 below the horizontal. The coefficient of kinetic friction is 0.01.
Then I need help with all the parts to the question seen in the picture.
(h) The net force equation for y-direction is F(net)_y = F sinθ
(i) The normal force acting on the truck is 490,000 N.
(j) The force of friction acting on the truck is 490 N.
(k) The net force equation for the x - direction is F(net)_x = Fcosθ - Ff.
(l) The acceleration of the truck is 0.94 m/s².
What is free body diagram?A free body diagram (FBD) is a sketch of all the forces acting on object, indicating the direction of the applied force.
↑ N
Ff → Ф ← F
↓W
where;
N is the normal force on the blockW is the weight of the blockFf is the force of frictionF is the applied forceThe net force equation for y-direction is calculated as follows;
F(net)_y = F sinθ
The normal force acting on the truck is calculated as follows;
Fn = mg
where;
Fn is the normal force on the truck acting upwardsm is mass of the truckg is acceleration due to gravityFn = 5000 x 9.8
Fn = 49,000 N
The force of friction acting on the truck is calculated as follows;
Ff = μFn
where;
μ is coefficient of frictionFn is normal forceFf = 0.01 x 49,000 N
Ff = 490 N
The net force equation for the x - direction is written as;
F(net)_x = Fcosθ - Ff
where;
F cosθ is the force applied along the x-directionFf is force of frictionF(net) = 6000 x cos(30) - 490
F(net) = 4,706.15 N
The acceleration of the truck in the sleeping bag is calculated as follows;
a = F(net) / m
a = (4,706.15) / (5000)
a = 0.94 m/s²
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A person who is high in comfort with closeness and high in anxiety over abandonment in Bartholomew's attachment model would be called
A person who is high in comfort with closeness and high in anxiety over abandonment in Bartholomew's attachment model is known as a generalized anxiety disorder
What is meant by generalized anxiety disorder?An individual is said to be suffering from a generalized anxiety disorder when he or she worries too much, gets worried constantly or excessively and subjects the person to being abandoned to his problem or situation. It is on this premise that such individuals are usually in Bartholomew's attachment model.
So therefore, we can now confirm and deduce from the simple note given above that a generalized anxiety disorder have great negative impact on our wellness.
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Which of the following choices is an example of gathering evidence? OA. Forming opinions. OB. Taking measurements OC. Asking questions. OD. Drawing conclusions. SUB
The following choice is an example of gathering evidence in Taking measurements. Option B.
The scientific method is the process of objectively establishing facts through testing and experimentation. The basic process is to make observations, form hypotheses make predictions conduct experiments and finally analyze the results. Accurate readings are evidence-based.
Without evidence the author just states his opinion. So writing an essay begins with gathering evidence long before writing it. The advantage of naturalistic observation is that the researcher can directly observe the subject in its natural environment. This method gives scientists direct insight into social behavior and helps them realize things they might not have encountered in a laboratory setting.
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Jason Bourne drives his stolen Audi A6 at 25 m/s across the roof of a parking garage and off the edge. The lower parking deck is 18.6 m below.
A. How far out from the edge will he land?
B. With what speed will he hit (magnitude and direction)?
A. The distance from the edge that the car will lad is 48.75 m.
B. The velocity it hit the ground with, v is 19.1 m/s in the forward direction.
What distance from the edge will the car travel at a velocity of 25 m/s?The distance from the edge will the car traveling at a velocity of 25 m/s is calculated as follows:
Distance = velocity * timeTime taken = √(2h/g)
where h is the height = 18.6 m
g is the acceleration due to gravity = 9.8 m/s²
t = √(2 * 18.6/9.8)
t = 1.95 seconds
Distance = 25 * 1.95
Distance = 48.75 m
The velocity it hit the ground with, v is calculated as follows:
v²= u² + 2gh
where;
u is initial vertical velocity = 0
g = 9.8 m/s²
h = 18.6 m
v = √2gh
v = √(2 * 9.8 * 18.6)
v = 19.1 m/s in the forward direction.
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A 2.0 kg block is pushed 2.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 30.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2
.
For a 2.0 kg block is pushed 2.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 30.0, the work done is 8.3 J
What is Work Done?This refers to the term that shows the product of the displacement of an applied force in a given direction.
Hence, the calculations are:
The work done by a force pushing an object is given by:
W= Fdcos[tex]\alpha[/tex]
where
F is the magnitude of the forced is the displacement of the object[tex]\alpha[/tex] is the angle between the direction of the force and of the displacementd= 1m
[tex]\alpha[/tex] = 63 degrees
W= (18.3)(1)(cos 63 degrees)
=8.3J
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A 2.0 kg block is pushed 1.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 27.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2.
If the coefficient of kinetic friction between
the block and the wall is 0.40, find
a) the work done by the force on the block.
Water flows over a waterfall 16 m high, at the rate of 3,000 × 104 kg/s. If this water powers an electric generator with a 35% efficiency, how much electric power can be supplied? Present your answer in megawatts.
The amount of electric power supplied by the water that flows over a waterfall 16 m high at the rate of 3.00×10⁴ kg/s is 1646400 W.
What is electric power?Electric power is the rate at which electric energy is consumed in an electric circuit or system.
To calculate the electric power supplied by the water, we use the formula below.
Formula:
P = 0.35M'gh.............................. Equation 1Where:
P = Electric powerM' = Falling rate of the waterg = Acceleration due to gravityh = HeightFrom the question,
Given:
M' = 3.00×10⁴ kg/sh = 16 mg = 9.8 m/s²Substitute these values into equation 1
P = 0.35×16×9.8×30000P = 1646400 WHence, the amount of electric power supplied is 1646400 W.
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3. An airplane accelerates from rest down a runway at 3.20 m/s² for 42.5 s until it finally lifts
off the ground. Determine how far the plane traveled before takeoff.
a. 1721.34 m
b.
968.26 m
c.
2205.47 m
d. 1115,14 m
e.
2890 m
e option is the correct answer - 2890m
Initial velocity(u) = 0[tex]m/s[/tex]
Accelaration(a) = 3.20[tex]m/s^{2}[/tex]
time(t) = 42.5s
The equation S = u t + 1 2 a t 2 is newton's second equation of motion. Here, 'S' represents the displacement of a body, 'u' represents the initial velocity of a body, 't' represents the time taken by the body to cover the displacement in t time(seconds), and 'a' represents the constant acceleration of a body throughout the movement.
[tex]s = ut + 1/2at^{2}[/tex]
[tex]s = 0(t) + 1/2(3.20)(42.5^{2}) \\s = 1/2(5780)\\s = 2890m[/tex]
The value of s is 2890m.
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Question 12 of 34
A water faucet has a circular handle with radius 2.5 cm attached to a central
shaft with radius 0.50 cm. What is the mechanical advantage of the faucet
handle?
OA. 0.20
OB. 1.3
OC. 5.0
OD. 2.0
Answer:
C: 5
Explanation:
MA = radius of wheel/ radius of axle
MA =2.5/0.5
MA = 5.0
A person with body resistance between his hands of 10k accidentally grasps the
terminals of a 14-kV power supply. If the power supply is to be made safe by increasing
its internal resistance, what should the internal resistance be for the maximum current in
the above situation to be 1.00 mA or less?
14 mΩ should the internal resistance be for the maximum current in
the above situation to be 1.00 mA or less .
What is internal resistance ?
Internal resistance refers to the resistance to current flow provided by the cells and the battery itself, resulting in heat generation. Internal resistance is measured in ohms. The relationship between the internal resistance (r) and electromotive force (e) of cell s is given by
e = I (r + R)
where e = EMF, or H. electromotive force (volts), I = current (A), R = load resistance, r is the internal resistance of the cell, measured in ohms.
Rearranging the above formula, we get: e = IR + Ir or e = V + Ir
In the above equation, V is the potential difference (clamp) across the cell when current (I) is flowing through the circuit.
r = E-Ir/I
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Forces
A cyclist cannot reach terminal velocity going downhill.
Answer:
Air resistance
PLEASE GIVE BRAINLIEST THANK YOU!!!
Moving electric charges, or currents, give rise to?
A. Magnetic fields
B. Stored energy
C. Decreases in temperature
D. Potential energy
Answer:
A =Magnetic fields
Explanation:
Which of the following objects
transforms chemical energy into
mechanical energy?
A. Battery powered clock
B. Cell phone
C. Washing machine
D. Windmill
Battery-powered clocks and Washing machines are objects that transform chemical energy into mechanical energy.
What are chemical energy and mechanical energy?Chemical energy is a type of energy that is stored in the bonds of a chemical. It is converted into thermal energy when people burn wood or burn gasoline in the engine of a car. Mechanical energy is a type of energy that is stored in objects by tension. Compressed springs and stretched bands are examples of mechanical energy.
Mechanical energy i.e. kinetic energy or potential energy is the energy that is present in an object in motion or the energy that is stored in objects due to their position. Mechanical energy is a type of renewable energy.
So we can conclude that options A and C are the correct answers.
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You are the commander of an exploratory mission
to a black hole. You launch a robotic probe on
a trajectory that will take it into the black hole.
The probe has an internal clock and sends a radio pulse back to your ship at a fixed interval, in
the reference frame of the probe. What effects do
you observe in the signals from the probe as it approaches the black hole? What might you observe
if the hole is rotating?
With increasingly long delays due mostly due to the increasing gravitationally time dilation affecting the probe when a trajectory that will take it into the black hole.
A black hole is a celestial object with a gravitational pull so powerful that nothing, not even light, can escape. A black hole can develop as a result of the death of a massive star. When its internal thermonuclear fuels run out at the end of its life, the center of such a star gravitationally collapses inward into itself, obliterating the star's outer layers.
The crushing weight of component matter crashing in from all directions causes the dying star to be crushed to a point with zero volume and infinite density known as the singularity. Black holes are often hard to observe directly due to their small size and the lack of any visible light from them.
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The helicopter now starts to accelerate upwords at 2,25m.s-2. calculate the tension in the cable if the tension of the cable is 1205,4 N
Answer:
1205.4N
Explanation:
given. "if the tension of the cable is 1205.4N)
PLEASE HELP, THE QUESTION IS IN THE IMAGE.
The weight of the container on Mars is 296 N.
The weight of the container on Uranus is 696 N.
The mass of the container on both Mars and Uranus is constant.
What is weight of an object?
The weight of an object is the measure of effect of gravitational force on an object.
The weight of an object changes with change in acceleration due to gravity.
Mathematically, weight of an object is given as;
W = mg
where;
m is mass of an objectg is acceleration due to gravityThe mass of an object is defined as the quantity of stuff contained in an object.
The mass of an object does not change with gravity.
The weight of the container on Mars is calculated as follows;
W = mg
where;
m is mass of then container = 80 kgg is acceleration due to gravity of Mars = 3.7 m/s²W = 80 x 3.7
W = 296 N
The weight of the container on Uranus is calculated as follows;
W = mg
where;
m is mass of then container = 80 kgg is acceleration due to gravity of Uranus = 8.7 m/s²W = 80 x 8.7
W = 696 N
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Answer:
he weight of the container on Mars is 296 N.
The weight of the container on Uranus is 696 N.
The mass of the container on both Mars and Uranus is constant.
Explanation:
A 500 kg roller coaster car pauses at the top of a 40 m hill before rolling without friction to the bottom. Determine the speed of the car at the bottom of the hill
Answer:
v = 28 m/s
Explanation:
Since energy is conserved:
Eg = Ek
mgh = 1/2mv^2
masses cancel
gh = 1/2v^2
(9.8)(40) = 1/2v^2
(2)(40)(9.8) = v^2
v = sqrt(784)
v = 28 m/s
Should the air temperature be less or greater than the temperature in the pool to avoid condensation in an indoor swimming pool?
The temperature in the pool to avoid condensation in an indoor swimming pool is cooler than air temperature.
Temperature :
Temperature is the degree to which an object is hot or cold.Its SI unit is kelvin (K).Humidity:
The amount of water vapour in the air is known as humidity.
The humidity will be high if there is a lot of water vapour in the atmosphere. It feels wetter outside as the humidity
In indoor pools, the relative humidity should be kept between 50 and 55 percent at a temperature of around 26 degrees in the winter and 23 degrees in the summer.
The temperature in the pool to avoid condensation in an indoor swimming pool is cooler than air temperature.
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pls help me thx ......................................................................
The work done by the cat is 500J and the force with which the frog hit the lily pad is 5N.
The definition of work includes both the force that is applied to the body and the displacement of the body.
Think about a block that is resting on a horizontal, frictionless floor. A constant force F acts on this block. The result of this force is to move the body d meters in a straight line in the force's direction.
Work done = Force * displacement
Work done = 50N * 10m
Work done = 500Nm
Thus, the work done by the cat is 500J.
Force = Work done / displacement
Force = 10J / 2m
Force = 5N
Thus, the force with which the frog hit the lily pad is 5N.
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(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?
The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.
The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.
Is there a timepiece on the ISS?For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.
Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.
Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.
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A particle of charge +2 q is placed at the origin and particle of charge - q is placed on the x - axis at x = 2a. Where on the x - axis can a third positive charg e be placed so that the net electric force on it is zero?
The answer is 6.8 how do I get this?
Particles with the like charges attract while opposites repel therefore the third charge has to be placed on the right side of -q charge for the electric force to be zero at a distance of 6.8 from the origin.
How is distance from origin calculated?Electric force is measured = (kq₁q₂)/r²
Where k is a constant,
q₁ is charge of the particle at the origin, +2,
q₂ is the charge of the particle on the x-axis, -q
r is the distance from origin
2a is the distance from -q
e is electric force, 0
Let distance of particle from -q be x and +2q be y
y - x = 2a
x = y - 2a
kqe/x² = k2qe/(x + 2a)²
((x + 2a)/x)² = 2
(1 + 2a)/x = √2 cross multiply
x = 2a/(√2 - 1) = 4.8284a
x = 4.8284a
y = x + 2a
y = 4.8284a + 2a
y = 6.8284a approximately 6.8a
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