One uranium atom has a diameter of 3. 5×10−8 centimeters. What is the sum of 1,000,000 uranium atoms’ diameters, in centimeters, written in standard notation?.

Answer:

Explanation:

Because dispersion is a property of refraction. A refractive medium is non-dispersive when waves of all frequencies pass at the same speed, otherwise there is a dispersion that is causing a distortion of waveforms.

Answer:

Explanation:

Given:

R = 18 Ohm

U = 9.0 V

__________

I - ?

Ohm's law:

I = U / R

I = 9.0 / 18 = 0.5 A

Hope this above expression for fringe width helps you.

Answer:

Explanation:

To obtain an expression for fringe width, we need to consider the phenomenon of interference in wave patterns, such as in the case of Young's double-slit experiment. In this experiment, a coherent light source, such as a laser, is passed through two closely spaced slits, creating an interference pattern of light and dark fringes on a screen placed behind them.

The fringe width (w) can be determined using the following expression:

w = λ * D / d

Where:

- λ represents the wavelength of the light used,

- D is the distance between the double-slit and the screen,

- d is the separation between the two slits.

The diagram accompanying this explanation would illustrate a coherent light source passing through the double slits, with the resulting pattern of light and dark fringes observed on the screen placed behind them. The distance D between the double-slit and the screen, as well as the separation d between the slits, would be indicated in the diagram.

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The taller individual must have reclined less than the smaller man because their shoes are the exact same size (leaning in terms of angle of body made with the ground). Bob's center of mass is consequently located closer to the ground.

what is centre of mass?

A position established in relation to an individual or group of items is the center of mass. It represents the system's average location as weighted by each component's mass. The center of mass for straightforward stiff objects with homogeneous density is found at the midpoint.

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The taller individual must have reclined less than the smaller man because their shoes are the exact same size (leaning in terms of angle of body made with the ground). Bob's center of mass is consequently located closer to the ground.

What is centre of mass?

In physics, the centre of mass of a distribution of mass in space (also known as the balancing point) is the unique location at which the weighted relative position of the dispersed mass accumulates to zero. This is the point at which a force can be applied to generate a linear acceleration without causing an angular acceleration. Calculations in mechanics are frequently simplified when expressed in terms of the centre of mass. It is a hypothetical point at which the entire mass of an item can be considered to be concentrated in order to visualise its motion. In other words, the centre of mass is the particle equivalent of a particular object for the purposes of applying Newton's equations of motion.

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The sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned below

1. First heart sound

2. Second Heart sound

3.  Third heart sound

4. Fourth heart sound

Therefore, the sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned above

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Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .

Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.

The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.

Given applied force = 60 N

weight of object = 50N;  friction force = 20N

As we know that, Coefficient of friction =  force of friction/normal force

= 20/50

Coefficient of friction = 0.4

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The magnitude of the average force exerted by the block on the bullet during that time is 202,304.147m N (m stands for bullet mass)

We got some values here,

v = 439 m/s

t = 2.17 ms = 2.17 × [tex]10^{-3}[/tex] s

First, we should find the acceleration of the car. We assume that final speed of bullet after impact is 0 m/s, so here we go

a = v/t

a = [tex]v_{1}[/tex] - [tex]v_{0}[/tex] / [tex]t_{1}[/tex]  - [tex]t_{0}[/tex]

a = 0 - 439 / 2.17 × [tex]10^{-3}[/tex]  - 0

a = -439 / 2.17 × [tex]10^{-3}[/tex]

a = -439,000 / 2.17

a = -202,304.147 m/[tex]s^{2}[/tex]

What actually happens when the result is negative is not the acceleration after the bullet hits the target, but the deceleration.

Now we got the amount of deceleration. We can found the force by the formula of: F = m.a but in the question there is no mass value of the bullet. So, we can answer this question by this way (we can ignore negative values)

F = m.a

F = m × 202,304.147 m/[tex]s^{2}[/tex]

F = 202,304.147m N

Acceleration (a) is the change of velocity (Δv) over the change of time (Δt), and here is the formula, a = Δv/Δt. This formula allows you to measure how quick velocity changes in meters per second squared (m/s. Acceleration is also a vector quantity, so it includes both magnitude and direction.

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Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.

A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.

what is geosynchronous orbit?

The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.

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Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.

What is geosynchronous orbit?

The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.

A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.

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For a frictionless pulley with mass connected by a light string, the acceleration for the system when released is equal to 6.5m/s²

Using the formula a = (m₂ - m₁)g/(m₁ + m₂)

Where a = acceleration, m = mass and g = gravity

m₁  = 2kg

m₂ = 10kg

g = 9.8m/s²

Applying to the formula, a = (m₂ - m₁)g/(m₁ + m₂) to find the acceleration of a frictionless pulley when released;

a = (10 - 2)(9.8)/(2 + 10)

a = 8(9.8)/12

a = 6.5m/s²

Therefore the system's acceleration 6.5m/s²

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Equation A. P A i + P B i = P A f + P B f and D.ΔPA + ΔPB=0. correctly states the principle of conservation of momentum.

Momentum is the product of the mass and pace of an object. it's miles a vector quantity, owning a magnitude and a route. If m is an item's mass and v is its velocity, then the object's momentum is p.

Momentum is manufactured from the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both value and path. Isaac Newton's 2d regulation of motion states that the time price of trade of momentum is the same as the pressure performed at the particle. See Newton's legal guidelines of movement.

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Disclaimer:- your question is incomplete, please see below for the comlete question.

Bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum? check all that apply.

A. P A i + P B i = P A f + P B f

B. P A i + P A f = P B i + P B f

C. ΔPA = ΔPB

D. ΔPA + ΔPB=0

The values constants magnitude are A=-6 MathrmV cdot m-2 A=6 Vm. B = 4 mathrm V cdot m 3, B = 4 mathrm V m 3, C = 2 V m 6, C = -2 V cdot m 6, l = 2 mathrm V m 6, m = 3 mathrm V m 3, and n = 6 mathrm V n = 6.

Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

The amount that encapsulates the force's strength is known as its magnitude. Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10." Magnitude can be thought of as simply the "value" or "amount" of any physical quantity.

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(a) The force of gravity acting on the person is 519.4 N.

(b) The normal force acting on the person is 519.4 N.

(c) The force of friction acting on the person is 192.18 N.

(d) The acceleration of the person in the sleeping bag is 3.25 m/s².

The force of gravity acting on the person is calculated as follows;

W = mg

where;

W = 53 kg  x   9.8 m/s²

W = 519.4 N

The normal force acting on the person is calculated as follows;

Fn = W

where;

Fn = 519.4 N

The force of friction acting on the person is calculated as follows;

Ff = μFn

where;

Ff = 0.37 x 519.4 N = 192.18 N

The net force on the person is calculated as follows;

F(net) = F cosθ  -   Ff

where;

F(net) = 476 x cos(40)  -  192.18

F(net) = 172.46 N

The acceleration of the person in the sleeping bag is calculated as follows;

a = F(net) / m

a = (172.46) / (53)

a = 3.25 m/s²

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The correct answer of velocity is 0.66 m/s or 2 / 3m/s, at which the couple collide.

What is Collision concept?

A collision is a situation in which two or more objects.

Given data:

m1=5000kg

m2=10000kg

v1=2m/s

v2=0

An inelastic collision conserves momentum:

m1v1+m2v2 = (m1+m2) vboth

m1v1+m2v2 = (m1+m2) vboth

vboth =m1v2+m2v2m1+m2

vboth =(5000kg)(2m/s)+(10000kg)(0)  /   (5000kg+10000kg)

vboth= 10000 / 15000 = 2 / 3 m/s

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For an automobile to cover 400 miles in 5 hours and 20 minutes, it must travel at an average speed of 75 mph.

Calculating average speed involves dividing the whole distance traveled by the total time it took to cover that distance. Speed is the rate of movement of something at a specific time. Average speed refers to the average speed during the course of a journey.

Average In order to comprehend the pace of a journey, speed is crucial. On a travel, the speed could occasionally change. Finding the average speed then becomes crucial to getting an idea of how quickly the route will be finished.

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The time of flight is 0.4 sec, The range is 1.6 m and maximum height is 3.2 meter.

Calculation:-

The initial vertical speed is u = 5m/s×sin53° = 4m/s

Time of flight = u/g

= 4/10

= 0.4 second

so if the final vertical velocity is v at a height h then v² = u² −2gh will give us v = [tex]\sqrt{16-20*0.45} = \sqrt{7} m/s[/tex]

The horizontal velocity remains constant and is given as Vx = 5m/s Cos53° = 3m/s

so the speed at the said instant will be V = [tex]\sqrt{v_{x} ^{2} +v^{2} } = \sqrt{9+7} = 4m/s[/tex]

Range = horizontal velocity× 0.4 second

= 4 × 0.4

= 1.6 m

Height = UT- 1/2at²

= 1.6 - 0.4 × 10 × 0.16

= 3.2 m

The horizontal velocity of the projectile is constant. There is the vertical acceleration due to gravity. Its value is 9.8 m/s/s, and the projectile's vertical velocity changes at 9.8 m/s per second. The horizontal movement of the projectile is independent of vertical movement. Horizontal acceleration is always zero because nothing accelerates the projectile horizontally.

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The item is pushing against it with a force of 30.4 N in a downward direction.

Since there is no net gravitational pull in the earth's center, the weight will be zero but the mass will not change. Thus, 50 kg will be the mass of the earth's core.

When two objects of mass M1 and M2 are separated by R, the gravitational force between them is expressed as follows:

F = G*(M1*M2)/R^2

G = 6.674*1(-11) m3/(kg*s2), where G is the gravitational constant.

M1, the object's mass, is 50 kg, and R is its distance, in.

F = G*(M1*M2)/R^2

G = 6.674*1(-11) m3/(kg*s2), where G is the gravitational constant.

M1, the object's mass, is known to be 50 kg.

This distance, R, is 25,600 kilometers.

However, keep in mind that this should be stated in meters and

1km = 1000m

Consequently, 25,600km equals (25,600*1000)m, or 25,600,000 m.

M2 is the equivalent of 5.972*10(24) kg, which is the mass of the Earth.

F = (6.674*1(-11) m3/(kg*s2))*(50kg*5.972*10(24) kg)/ (replacing all of those in the force equation) ( 25,600,000 m)

^2\sF = 30.4 N

Given that the gravitational force is attracting, it will act in a manner that is favorable to the 50 kg item.

Consider the following as the second Newton's law:

F = M*a

Accordingly, the acceleration brought on by the item on Earth is 30.4N = 5.972*10(24) kg*a

a = 30.4N/((5.972*10(24) kg)) = 5.09*10(-24) m/s

Nearly everyone can feel the acceleration.

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The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ  would be -366 KJ

What is the internal energy of the system?

Internal energy can be defined as the property that defines the energy of a substance in the absence of effects due to capillarity,  external electric and magnetic fields

In the above case

Let Change in internal energy ΔU = 246 kJ

Let Heat gained by the system (q) = 612 kJ

Using the  First law of thermodynamics

ΔU = q + w

Where:

ΔU  represent  change in internal energy

q represents  heat added to the system

and w is work done.

Let plug in the formula

246 kJ = 612 kJ + w

w = 246 kJ - 612 kJ

w= - 366 kJ

Here the negative sign means  that work is done by the system.

Therefore, The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ  would be -366 KJ

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The final temperature of the gas is obtained as 2700 K or 2472° C.

We know that when the temperature of a gas is increased, the speed of the gas is also increased. Given that we have the initial temperature of the gas as  27° C or 300 K.

Given that;

[tex]V_{1}[/tex]/[tex]V_{2}[/tex] = √[tex]T_{1}[/tex]/[tex]T_{2}[/tex]

Where the [tex]V_{1}[/tex] and [tex]V_{2}[/tex] refers to the initial and the final velocities while the [tex]T_{1}[/tex] and the [tex]T_{2}[/tex] refer to the initial and the final temperatures.

[tex]V_{1}[/tex]/3 [tex]T_{1}[/tex]   = √300/ [tex]T_{2}[/tex]

1/3 = √300/ [tex]T_{2}[/tex]

1/9 = 300/ [tex]T_{2}[/tex]

[tex]T_{2}[/tex] = 2700 K or 2472° C

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The core of a red giant is contracting, but the outer layers are expanding as a result of hydrogen fusion in a shell outside the core

Nuclear fusion of hydrogen to form helium happens evidently in the solar and different stars. It takes area best at extremely high temperatures. Scientists are attempting to find methods to create controlled nuclear fusion reactions on earth.

Researchers at Lawrence Livermore countrywide Laboratory's country-wide Ignition Facility in California have spent over a decade perfecting their method and the feature now showed that the landmark test conducted on eight August 2021 did, in fact, produce the primary-ever successful ignition of a nuclear fusion reaction.

People had been capable of cause fusion, but in methods that might be uncontrolled, like in thermonuclear guns sometimes called hydrogen bombs. Fusion has additionally been proven in laboratories, but below conditions that eat a long way, extra strength than the reaction produces.

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The statement which describes the longshore current is d.)  incoming swash of water moves parallel to the beach.

What is a longshore current?

When the waves reach a beach, it liberates a large amount of energy that is usually generates a current and runs parallel to the shore. Such type of current is said to be longshore current.

Sea floor, shoreline features and depth of the water are the main factors on which the speed of the waves reaching the shore depends. The waves make their movement towards the beach where various segments of wave itself encounters before other and this results the segments to slow down. They do not reach the beach perfectly parallel to the shoreline. But when we talk about the longshore current, it moves parallel to the coastline or beach.

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The calculated velocity is 7295 rpm. Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path.

According to Faraday's law of induction, an induced electromotive force is produced when a magnet rotates inside a coil. Alternatively said, mechanical energy is changed into electrical energy. Electrical generators are built on the principles of this physical phenomenon. Let's calculate the coil cross section's area A.

A=π 4 d 2 \s= 5.0265 × 10 − 3 m2

Step 2

The following equation describes the greatest induced electromotive force (or peak voltage) in a coil:

ε p=N A B ω

Step 3

Let's use the equation above to calculate the angular velocity. Recall that 1 rpm is equal to 0.10472 radians per second, and 1 tesla is equal to 1 volt per second divided by 1 square meter.

= = p N A = 7295 r pm

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Initial launch speed of the cars are in order as  Vcar 1 = Vcar 2< Vcar 3

Speed (often abbreviated as "s") is a scalar variable that describes how much an object's location changes over time or how much it changes per unit of time. The average speed of an item in a period of time is the distance traveled by the object divided by the duration of the period.

Time divided by distance are the speed-related metrics.. The meter per second (m/s) is the SI unit of speed, while the kilometer per hour (kph) is the most often used unit of speed in daily life.

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If the Sun had been born with a smaller, lower-mass companion star, would that star be a red dwarf today or would it already be dead, it would still be a red dwarf today regardless of how much less mass than the Sun it has, since its lifetime would be inherently longer than the Sun's.

Stars sparkle and shine—they appear to have an incandescence of their own even when they are bathed in the spotlight—so it stands to reason that they are stars. However, they are "stars" in a much more specific sense because they are a product of the long-standing Western cultural tendency to equate humanity with the heavenly.

Not all celebrities live alone. About half of all stars in our galaxy, the Milky Way, have a companion and journey through space in a binary system.

Now, the long-lost partner of the Sun could be found anywhere in the Milky Way. According to a team of Harvard astronomers, our solar system was once a binary system because the Sun formerly had a companion star.

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The total resistance of the resistors in the circuit from the diagram is 20  Ω.

Resistance is a measure of the opposition to current flow in an electrical circuit.

To calculate the total resistance of the resistors in parallel, we use the formula below.

Note: Both resistors are connected in series.

Formula:

For series connection

Where:

From the diagram,

Given:

Substitute these values into equation 1

Hence, the total resistance is 20 Ω.

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Acceleration will be constant while speed will not. The third option describes the motion.

Force can simply be defined as a pull or push. It is the product of mass and velocity and it is measured in Newton.

If a wooden block resting on a table is given a push, the block of mass m will accelerate with acceleration a and stop due to friction

One of the following options that describe the motion of the block a moment after the push is the third option. That is, accelerates at a positive, constant rate.

Since the block will be accelerating, the speed of the block can never be constant.

Therefore, accelerates at a positive, constant rate is the option that describe the motion of the block a moment after the push.

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Since a bar of length L₀ with a thermal expansion coefficient would experience a length fluctuation ΔL when the temperature changes ΔT, the equation of linear thermal expansion ΔL = ∝LΔT must be used.

The linear thermal expansion equation tells us that a ΔT = (ΔL/∝L₀) = 22.14° based on the following values: ΔL = 0.481 foot, L₀ = 1671 feet, and ∝ = 0.000013 per centigrade degree (this is simply the linear thermal expansion of steel that must be found in a table). As previously stated, these degrees are centigrades (Celsius or Kelvin, it makes no difference as this is merely a variation), and the foot units cancel on the equation, demonstrating that no additional conversion was required.

Our new temperature must be T = T₀  + ΔT = 35.14°C because our last reading on a chilly spring day was 13.0°C.

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More than 30 N force needs to be in order to get the object to start moving across the floor.

F=μN

μ= 0.15

N= 200 N

F=200 N×0.15

F=30 N

In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three principles of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the idea of force (1687).

Newton's first law states that unless a force is applied to a body, it will stay in either its resting or uniformly moving condition along a straight path. According to the second law, when an external force applies on a body, the body accelerates (changes velocity) in the force's direction.

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The work done by the constant force of 167 N, given that the block is displaced at 59 m is 8715.97 J

We know that work done is defined as:

Work done (Wd) = force (F) × distance (d)

Wd = fd

Since angle projection is involved, the work done is defined as:

Wd = FdCosθ

With the above formula, we can detertmine the work done as illustrated follow:

Wd = FdCosθ

Wd = 167 × 59 × Cos 27.8

Wd = 9853 × 0.8846

Wd = 8715.97 J

Therefore, we can conclude from the calculation made above that the work done is 8715.97 J

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The closest estimate to the one  times the sun has orbited the galactic center.

The Milky Way galaxy's rotational and barycenters are located at the Galactic Center . The Sagittarius A supermassive black hole, a compact radio source that is almost exactly at the galactic rotational center, is the object's central massive object. It has a mass of about 4 million solar masses. The Galactic Center is frequently referred to as a type of "cosmic homing signal" by astrologers. Far away on one of the spiraling arms of the galaxy, it is the hub around which our tiny solar system slowly revolves. It is enormous and unknowable. Whatever process produced the Milky Way is represented by the GC. The most difficult conditions for star formation can be found in the Galactic Center, which has more than 80% of the Milky Way Galaxy's dense molecular gas, high temperatures, significant turbulence, complex magnetic fields, and a powerful gravitational potential well.

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