Light containing two different wavelengths passes through a diffraction grating with 1,250 slits/cm. On a screen 17.5 cm from the grating, the third-order maximum of the shorter wavelength falls midway between the central maximum and the first side maximum for the longer wavelength. If the neighboring maxima of the longer wavelength are 8.44 mm apart on the screen, what are the wavelengths in the light

Answer:

Answer: Oxygen

Explanation:

Oxygen would not be considered as a pollutant

Answer:

Hey there the answer is C. Oxygen

Explanation:

Oxygen is the chemical element with the symbol O and atomic number 8. It is a member of the chalcogen group in the periodic table, a highly reactive nonmetal, and an oxidizing agent that readily forms oxides with most elements as well as with other compounds. After hydrogen and helium, oxygen is the third-most abundant element in the universe by mass. At standard temperature and pressure, two atoms of the element bind to form dioxygen, a colorless and odorless diatomic gas with the formula O 2. Diatomic oxygen gas constitutes 20.95% of the Earth's atmosphere. Oxygen makes up almost half of the Earth's crust in the form of oxides. Hope this helps! Have a great day!

Answer:

The speed of the bird is 1.00% of the speed of sound.

Explanation:

The speed of the bird can be found by using the Doppler equation:

[tex] f = f_{0}(\frac{v - v_{r}}{v - v_{s}}) [/tex]

Where:

v: is the speed of sound = 343 m/s

f₀: is the frequency emitted = 1490 Hz

f: is the frequency observed = 1505 Hz

[tex]v_{r}[/tex]: is the speed of the receiver = 0 (it is stationary)

[tex]v_{s}[/tex]: is the speed of the source =?

The minus sign of [tex]v_{s}[/tex] is because the source is moving towards the receiver.

By solving the above equation for [tex]v_{s}[/tex] we have:

[tex] v_{s} = v - \frac{f_{0}*v}{f} = 343 - \frac{1490*343}{1505} = 3.42 m/s [/tex]

The above speed in terms of the speed of sound is:

[tex]\% v_{s} = \frac{3.42}{343}\times 100 = 1.00 \%[/tex]

Therefore, the speed of the bird is 1.00% of the speed of sound.  

I hope it helps you!

Answer:

Option C

Explanation:

Options for the question are as follows -

A. At a faucet close to entrance valve

B. At a faucet away from the entrance valve

C. It will be the same at all faucets

D. There will be no increase in the pressure at the faucets

Solution -

The static force will be the same at all faucets and also the area of the faucets be same.

Thus, the pressure created at all faucets will be the same.

Thus, option C is correct

1. third law

2. first law

3. third law

4. second law

The work done by the force on the block is approximately 311.2 Joules.

To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.

The horizontal component of the force can be calculated using trigonometry:

F_horizontal = F * cos(angle)

            = 45 N * cos(30 degrees)

            = 45 N * (√3 / 2)

            ≈ 38.9 N

Now, we can calculate the work done by the force using the equation:

Work = Force * Distance * cos(theta)

where theta is the angle between the force and the displacement.

Work = F_horizontal * Distance * cos(0)

     = 38.9 N * 8 m * cos(0)

     = 38.9 N * 8 m

     = 311.2 Joules

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Answer:

4.25 rad/s

Explanation:

Given that.

Mass, m = 51.9 kg

Radius, r1 = 2.4 m

Moment of inertia, I = 215.24 kgm^2

Angular velocity, ω = 2.1 rad/s

Radius, r2 = 0.864 m

To start with, we are going to use the Conservation of angular momentum to solve the question, which is

l(initial) = l(final)

[I₁ + I₂](initial)*ω(initial) = [I₁ + I₂](final)*ω(final)

Making ω(final) the subject of formula, we have

ω(final) = [I₁ + I₂](initial)*ω(initial) / [I₁ + I₂](final)

ω(final) = [215.24 + (51.9)(2.4)²](2.1) / [215.24 + (51.9)(0.864)²]

ω(final) = [215.24 + 298.944]2.1 / [215.24 + 38.74]

ω(final) = 514.184 * 2.1 / 253.98

ω(final) = 1079.786 / 253.98

ω(final) = 4.25 rad/s

= 5.273 rad/s

Answer:

the electric field strength inside the resistor is 2.57 V/m

Explanation:

Given;

current flowing through the wire, I = 1.10 A

resistance of the wire, R = 7.00 Ω

length of the wire, L = 3.00 m

The emf created inside the resistor is calculated as;

V = IR

V = 1.10 x 7

V = 7.7 V

The electric field strength inside the resistor is calculated as;

E = V/L

E = 7.7 / 3

E = 2.57 V/m

Therefore, the electric field strength inside the resistor is 2.57 V/m

Answer:

20.0N

Becuase It's the largest

Answer:

20.0

Explanation:

It's the biggest number

Answer:

The drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires. According to the ideal gas law, this leads to a decrease in tire pressure. The low tire pressure light in vehicles is triggered when the pressure falls below a certain threshold, alerting the driver to check and adjust the tire pressure.

Explanation:

The ideal gas law, represented by the equation PV = nRT, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of an ideal gas. In this case, we can analyze how the drop in temperature affects the tire pressure.

When the temperature drops, according to the ideal gas law, the pressure of a gas will decrease if the volume and the number of moles remain constant. This is because the decrease in temperature causes a decrease in the average kinetic energy of the gas particles, leading to less frequent and less forceful collisions with the tire walls, resulting in a decrease in pressure.

In the context of the tire pressure, the air inside the tires behaves as an ideal gas. When the temperature drops overnight, the air inside the tires also cools down, causing a decrease in its temperature. As a result, the average kinetic energy of the air molecules decreases, leading to a decrease in pressure inside the tires.

The low tire pressure light comes on as a result of this drop in pressure. The tire pressure monitoring system in modern vehicles is designed to detect significant deviations from the recommended tire pressure. When the pressure drops below a certain threshold, typically due to temperature changes or a puncture, the light is triggered to alert the driver to check and adjust the tire pressure.

Therefore, the drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires, resulting in a decrease in tire pressure, which triggers the low tire pressure warning light.

Hope this helps!

Answer:

The border is 8km above sea level.

Explanation:

We know that:

Density = 1.25 kg/m^3

Pressure = 10^5 N/m^2

g = 10m/s^2

Now, suppose that we have a virtual rectangle, such that its bases have an area of 1m^2 and the rectangle has a height equal to H.

This virtual figure has a volume V = 1m^2*H, and it is filled with air (which we know that has a density 1.25 kg/m^3)

Then the total mass inside that volume is:

M = (1.25 kg/m^3)*V = (1.25 kg/m^3)*(1m^2*H)

The weight of this mass is:

W = g*M = (10m/s^2)*(1.25 kg/m^3)*(1m^2*H)

And if we divide the weight in a given surface, let's say 1 m^2, we get the pressure per square meter, which we know is equal to  10^5 N/m^2

then:

P = 10^5 N/m^2 = (10m/s^2)*(1.25 kg/m^3)*(1m^2*H)*(1/m^2)

Whit this equation we can find the value of H.

10^5 N/m^2 = (10m/s^2)*(1.25 kg/m^3)*(1m^2*H)*(1/m^2)

10^5 N =  (10m/s^2)*(1.25 kg/m^3)*(1m^2*H)

(10^5 N)/(10 m/s^2) = (1.25 kg/m^3)*(1m^2*H)

(10^4 kg) = (1.25 kg/m^3)*(1m^2*H)

(10^4 kg)/( 1.25 kg/m^3) = 1m^2*H

8,000 m^3 = 1m^2*H

(8,000 m^3)/(1m^2) =H

8,000 m = H

And we want this answer in km, knowing that 1,000m = 1km

8,000m = 8km = H

The border is 8km above sea level.

Height of boundaries is 8.2 km

Normal density = 1.25 kg/m³

1 atm = 101325 N/m²

Height of boundaries

Pressure = Height × Density × Gravitational acceleration

101325 = Height × 1.25 × 9.8

101325 = Height × 12.25

Height of boundaries = 101325 / 12.25

Height of boundaries = 8271.42 m

Height of boundaries = 8.2 km

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T

Answer:

the velocity is a second final to initial velocity of 39

Explanation:

Entrepreneurs are not wild risk takers but are instead calculating risk takers. They appear to be risk takers because they see the market differently than the rest of us do. 3. ... Entrepreneurs tend to be optimistic about their chances for success, and usually their optimism is based in reality.

Answer:

question #1 is A

Question #2 is C

Explanation:

Answer:

true

Explanation:

with increased temperature particles move faster as they gain kinetic energy

Answer:

The human body carries out its main functions by consuming food and turning it into usable energy. Immediate energy is supplied to the body in the form of adenosine triphosphate (ATP). Since ATP is the primary source of energy for every body function, other stored

Explanation:

this what teacher explain to us

Answer:

I believe it is true, but our brains don’t do it, I think it is the lenses in our eyes that do it. I might be wrong tho

Explanation:

Answer:

Yes it is true that our eyes form upside-down images, which are flipped right-side-up by our brain.

The final angular velocity of the carnival ride at a displacement of 6.3 rad is 25.2 rad/s.

The final angular velocity of the carnival ride is determined by applying third kinematic equation as shown below;

ωf = ωi + 2αθ

where;

ωf = 0 + 2(2.0) x 6.3

ωf = 25.2 rad/s

Thus, the final angular velocity of the carnival ride at a displacement of 6.3 rad is 25.2 rad/s.

​

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Answer: 5.0 rad/s

Explanation: Because that’s what khan said so try it out.

Increased driving can lead to higher vehicle maintenance and repair expenses, increased fuel costs, potential increases in auto insurance premiums, and additional parking fees, all of which should be considered when estimating the overall impact on your expenses.

The expenses that are likely to change based on how much you drive can be broadly categorized into two main areas: vehicle-related expenses and fuel-related expenses.

1. Vehicle-related expenses: The more you drive, the more wear and tear your vehicle will experience, leading to increased maintenance and repair costs. Regular oil changes, tire replacements, brake pad replacements, and other routine maintenance tasks will be required more frequently.

2. Fuel-related expenses: It's intuitive that the more you drive, the more fuel you'll consume, resulting in higher fuel expenses. Fuel prices can vary, but regardless of fluctuations, increased mileage will directly impact your fuel budget. Fuel-efficient vehicles may mitigate some of these costs, but the overall impact on your expenses will still be noticeable.

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Answer: A

Explanation:

Because someone who is aggressive, stubborn, or proud of theirselves are more likely to think they're above everyone else and be a bully. However someone who is willing to compromise is better since you can generally make everyone happy that way

HOPE THIS HELPS ^^

Answer:

Explanation:

stress = ?

length =5 m

area of cross section = 0.04 cm or 0.0004m

force = 20 × 10 = 200 N ( w = mg) g = 10

formula : stress = force / cross-sectional area

stress = 200 / 0.0004

stress = 500,000 Nm^-2

Answer:

The correct answer is "6666.67 N".

Explanation:

The given values are:

Mass,

m = 0.100

Relative speed,

v = 4.00 x 10³

time,

t = 6.00 x 10⁻⁸

As we know,

⇒  [tex]F=m(\frac{\Delta v}{\Delta t} )[/tex]

On substituting the given values, we get

⇒      [tex]=0.100\times 10^{-6}(\frac{4\times 10^3}{6\times 10^{-8}} )[/tex]

⇒      [tex]=6666.67 \ N[/tex]

Answer: 2.67

Explanation: it said he went from 0 to 8 in 3 seconds so if we divide eight By three we get 2.67 rounded to the nearest hundredth so you accelerated that 2.67 m/s

Answer:

v = 248.8 m/s

Explanation:

Given that,

Charge, q = [tex]6.47\ \mu C[/tex]

Electric field, E = 1300 N/C

Magnetic field, B =1.33 T

The force acting on the particle, [tex]F=6.27\times 10^{-3}\ N[/tex]

We need to find the magnitude of the particle's velocity. The net force on the particle is given by :

[tex]F=qE+qvB\\\\6.27\times 10^{-3}=6.47\times 10^{-6}\times 1300+6.47\times 10^{-6}\times 1.33v\\\\6.27\times 10^{-3}-6.47\times 10^{-6}\times 1300=6.47\times 10^{-6}\times 1.33v\\\\-0.002141=6.47\times 10^{-6}\times 1.33v\\\\v=\dfrac{0.002141}{6.47\times 10^{-6}\times 1.33}\\\\v=248.8\ m/s[/tex]

So, the magnitude of the particle's velocity is 248.8 m/s.