Let f(x)=5x^4 and g(x)=e^2x+x. If h is the function defined by h(x)=f(g(x)), which of the following gives a correct expression for h′(x)?

Let F(x)=5x^4 And G(x)=e^2x+x. If H Is The Function Defined By H(x)=f(g(x)), Which Of The Following Gives

Answers

Answer 1
Look it up on quizzes
Answer 2

The values of h'(x) is h'(x) = 20 [tex](e^{2x} + x) ^{3}[/tex]  (2[tex]e^{2x}[/tex] + 1 ).

Option C is the correct answer.

Given,

f(x)=5x^4 and g(x)=e^2x+x.

If h is the function defined by h(x)=f(g(x)),

We need to find h′(x).

What is the differentiation formula for the following?

We have,

dx/dx = 1

d[tex]x^{n}[/tex]/dx = n[tex]x^{n-1}[/tex]

d[tex]e^{x}[/tex]/dx = [tex]e^{x}[/tex]

d[tex]e^{n}[/tex]/dx = [tex]ne^{n}[/tex]

d(cx)/dx = c(dx/dx) = c

We have,

- f(x)=5[tex]x^{4}[/tex] ______(1)
- g(x)=[tex]e^{2x}[/tex]+x ______(2)

- h(x)=f(g(x)) _______(3)

Now,

h(x) = f ( [tex]e^{2x}[/tex]+x )

From (1)

h(x) = 5[tex](e^{2x} + x) ^{4}[/tex] ______(4)

Now,

Differentiate (4)

h'(x) = 5 d[tex](e^{2x} + x) ^{4}[/tex]/dx

h'(x) = 5 x 4 [tex](e^{2x} + x) ^{3}[/tex] d [tex](e^{2x} + x)[/tex] / dx

h'(x) =20 [tex](e^{2x} + x) ^{3}[/tex] ( d[tex]e^{2x}[/tex]/dx + dx/dx )

h'(x) = 20 [tex](e^{2x} + x) ^{3}[/tex]  (2[tex]e^{2x}[/tex] + 1 )

Thus the values of h'(x) is h'(x) = 20 [tex](e^{2x} + x) ^{3}[/tex]  (2[tex]e^{2x}[/tex] + 1 ).

Option C is the correct answer.

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Step-by-step explanation:

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Answer:

when you divide you get -11/12

if you have a calculator you could add the 5/8 and 3/4

then add the -2/3 and the -5/6

then divide the first answer by the second answer

Answer:

[tex] \frac{( \frac{5}{8} + \frac{3}{4}) }{( - \frac{ 2}{3} - \frac{5}{6} )} \\ \\ \\ \frac{( \frac{5}{8} + \frac{6}{8}) }{( - \frac{4}{6} - \frac{5}{6} ) } \\ \\ \\ \frac{ (\frac{5 + 6}{8}) }{( \frac{ - 4 - 5}{6} )} = \frac{( \frac{11}{8} )}{( - \frac{9}{6} )} \\ \\ \\ \frac{11}{8} \div ( - \frac{9}{6} ) \\ \\ \\ \frac{11}{8} \times ( - \frac{6}{9} ) \\ \\ \\ \frac{11}{8} \times ( - \frac{2}{3} ) \\ \\ \\ \frac{11}{4} \times ( - \frac{1}{3} ) \\ \\ \\ = - \frac{11}{12} \\ \\ \\ = - 0.91666[/tex]

I hope I helped you^_^

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total: 13,800

Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

d/t

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T= Time

Step-by-step explanation:

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The formula to find average speed ~

[tex] \mathrm{ \dfrac{total \: \: distance \: \: covered}{total \: \: time \: \: taken} }[/tex]

Formula for Instantaneous speed ~

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Answer:

not enough information

Step-by-step explanation:

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Answers

2/8

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Answers

Answer:

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Step-by-step explanation:

x = (7+4√3)

x^2 =  x = (7+4√3)^2

= 49 + 48 + 56√3

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Answer:

21

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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if you need help with algbrea
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Answer:

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------------------------

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-----------------

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---    ------

7       7

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Step-by-step explanation:

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х
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os
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2
.
5
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о
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3
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D

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A

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here it is plz mark me as brainliest

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Answers

Answer: c.2*1

Step-by-step explanation: in the picture

You need to remember two definitions.

First, the dimensions of a matrix are the number of rows by the number of columns. If a matrix has a row and b columns, it's an a*b matrix.

Second, before computing the product of two given matrices, you need to check an important condition.

If a matrix A has i row and j columns. And a matrix B has k row and l columns we can not apply the product AB only if j = k. In other words the numbers of columns of A (j) must be equal to the number of rows of B (k).

If this condition is checked, than the new matrix will be of dimensions : ixl

In our case i = 2, j = 3, k = 3, l = 1

So the dimensions will be 2x1 so the answer is C.

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