Assumption to deduce that sin0 + cos20 = 1 is sin0 + cos20 = 1 [since sin0 + cos20 ≤ 1]
Given vectors a and b.
To find the determinant of (a x b) (a x b), we can use the following formula:
a b c a1 b1 c1 a2 b2 c2(a x b) (a x b) = a3 b3 c3
wherei = (j, k)j = (i, k)k = (i, j)
Here are the assumptions we can make to prove that sin 0 + cos 20 = 1:
Assumption 1: a and b are orthogonal.
Assumption 2: |a| = |b| = 1.
Now let's proceed to prove that sin 0 + cos 20 = 1.
To do so, we need to find the dot product of a x b and a x b.
Here's how we can do it:|a x b|2 = |a|2|b|2 - (a · b)2= 1 - (a · b)2 [since |a| = |b| = 1]
Now, a · b is the determinant of the 3x3 matrix given below.
a b c a1 b1 c1 a2 b2 c2
Hence, |a x b|2 = 1 - (a · b)2
= 1 - [a b c a1 b1 c1 a2 b2 c2]2
= 1 - [a1 (b2c3 - c2b3) - b1 (a2c3 - c2a3) + c1 (a2b3 - b2a3)]2
= 1 - (a1b2c3 + b1c2a3 + c1a2b3 - a1b3c2 - b1c3a2 - c1a3b2)2
Now, we can substitute the cross-product of vectors a and b in the above equation and simplify as shown below:
|a x b|2 = (sin0)2 + (cos20)2- 2 sin0 cos20= 1 - (sin0 + cos20)2
[using the trigonometric identity sin2 θ + cos2 θ = 1]
Therefore, |a x b|2 = 1 - (sin0 + cos20)2[since (sin0)2 + (cos20)2 = 1]
Now, |a x b|2 can never be negative.
Therefore,1 - (sin0 + cos20)2 ≥ 0or, sin0 + cos20 ≤ 1
Therefore, the final conclusion is:
sin0 + cos20 = 1 [since sin0 + cos20 ≤ 1]
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Population 1,2,4,5,8 · Draw all possible sample of size 2 W.O.R · Sampling distribution of Proportion of even No. · Verify the results
Question:
A population consists 1, 2, 4, 5, 8. Draw all possible samples of size 2 without replacement from this population.
Verify that the sample mean is an unbiased estimate of the population mean.
Answer:
[tex]Samples: \{(1,2),(1,4),(1,5),(1,8),(2,4),(2,5),(2,8),(4,5),(4,8),(5,8)\}[/tex]
[tex]\hat p = \frac{3}{5}[/tex] --- proportion of evens
The sample mean is an unbiased estimate of the population mean.
Step-by-step explanation:
Given
[tex]Numbers: 1, 2, 4, 5, 8[/tex]
Solving (a): All possible samples of 2 (W.O.R)
W.O.R means without replacement
So, we have:
[tex]Samples: \{(1,2),(1,4),(1,5),(1,8),(2,4),(2,5),(2,8),(4,5),(4,8),(5,8)\}[/tex]
Solving (b): The sampling distribution of the proportion of even numbers
This is calculated as:
[tex]\hat p = \frac{n(Even)}{Total}[/tex]
The even samples are:
[tex]Even = \{2,4,8\}[/tex]
[tex]n(Even) = 3[/tex]
So, we have:
[tex]\hat p = \frac{3}{5}[/tex]
Solving (c): To verify
[tex]Samples: \{(1,2),(1,4),(1,5),(1,8),(2,4),(2,5),(2,8),(4,5),(4,8),(5,8)\}[/tex]
Calculate the mean of each samples
[tex]Sample\ means = \{1.5,2.5,3,4.5,3,3.5,5,4.5,6,6.5\}[/tex]
Calculate the mean of the sample means
[tex]\bar x = \frac{1.5 + 2.5 +3 + 4.5 + 4 + 3.5 + 5 + 4.5 + 6 + 6.5}{10}[/tex]
[tex]\bar x = \frac{40}{10}[/tex]
[tex]\bar x = 4[/tex]
Calculate the population mean:
[tex]Numbers: 1, 2, 4, 5, 8[/tex]
[tex]\mu = \frac{1 +2+4+5+8}{5}[/tex]
[tex]\mu = \frac{20}{5}[/tex]
[tex]\mu = 4[/tex]
[tex]\bar x = \mu = 4[/tex]
This implies that [tex]\bar x[/tex] is an unbiased estimate of the [tex]\mu[/tex]
0 Let x₁ = and x3 = B x2 = Write H Span{x1, x2, X3}. = - Use the Gram-Schmidt process to find an orthogonal basis for H. You do not need to normalize your vectors, but give exact answers. S 100.0000 V3
Main answer: An orthogonal basis for the given span H is {x1, x2-x1, x3 - (x1 + x2 - x1)} which simplifies to {x1, x2-x1, x3-x2}.
Supporting explanation: Given, x₁ = 0, x₂ = 1, x₃ = √3The span of H is the set of all linear combinations of x1, x2 and x3.So, we have to find an orthogonal basis for H using the Gram-Schmidt process. Let's start with the first vector x1 = [0, 0, 0]The second vector x2 is the projection of x2 onto the subspace perpendicular to x1. x2 is already perpendicular to x1 so x2-x1 = x2. So, the second vector is x2 = [0, 1, 0].The third vector x3 is the projection of x3 onto the subspace perpendicular to x1 and x2. x3 is not perpendicular to x1 and x2, so we subtract the projections of x3 onto x1 and x2 from x3. Projection of x3 onto x1:projx₁(x₃) = x₁ [(x₁ . x₃)/(x₁ . x₁)] = [0, 0, 0]Projection of x3 onto x2:projx₂(x₃) = x₂ [(x₂ . x₃)/(x₂ . x₂)] = [0, √3/3, 0]Therefore, x3 - projx₁(x₃) - projx₂(x₃) = [0, √3/3, √3]So, the orthogonal basis for H is {x1, x2-x1, x3 - (x1 + x2 - x1)} which simplifies to {x1, x2-x1, x3-x2}.
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Rewrite the expression using a DIVISION SYMBOL: "The quotient of m and 7."
Answer:
m ÷ 7
Step-by-step explanation:
"Quotient" means you're dividing, so this just means you're dividing m by 7.
Find the zeros of the following quadratic functions.
3) x2 + 5x + 6 = 0
help ASAP Ill give you brainliest
Answer:
none of these
Step-by-step explanation:
There are 3 boys walking
There are a total of 20 people
3/20 = 0.15
That is 15 percent, therefore none of these answers.
Step-by-step explanation:
any has at least one mode
If S=4 [tex]\pi[/tex] [tex]r^{2}[/tex] the value of S When R= 10[tex]\frac{1}{2}[/tex]
Point (2.-3) on glx) is transformed by -g[4(x+2)]. What is the new point? Show your work
After considering the given data we conclude that the new point generated is (2,3), under the condition that g(x) is transformed by [tex]-g[4(x+2)][/tex].
To evaluate the new point after the transformation of point (2,-3) by -g[4(x+2)], we can stage x=2 and g(x)=-3 into the expression [tex]-g[4(x+2)][/tex]and apply simplification to get the new y-coordinate. Then, we can combine the new x-coordinate x=2 with the new y-coordinate to get the new point.
Stage x=2 and g(x)=-3 into [tex]-g[4(x+2)]:[/tex]
[tex]-g[4(2+2)] = -g = -(-3) = 3[/tex]
The new y-coordinate is 3.
The new point is (2,3).
Hence, the new point after the transformation of point (2,-3) by [tex]-g[4(x+2)][/tex] is (2,3).
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Brayden invests money in an account paying a simple interest of 3.3% per year. If he invests $30 and no money will be added or removed from the investment, how much will he have in one year, in dollars and cents?
Answer:
$30.99
Step-by-step explanation:
The formula for simple interest is I = PRT where I = interest earned, P = principal amount borrowed/deposited, R = rate as a decimal, and T = time in years.
I = (30)(0.033)(1)
I = 0.99
Then add that to the amount deposited ($30) and you're done.
30 + 0.99 = $30.99
Please let me know if you have questions.
The answer is $29.01
In 3^6, 6 is called ___.
base
exponent
Step-by-step explanation:
the correct answer is exponent because 6 is its power.
hope this answer will help u.
have a great time.
How do you turn 5/2 into 10/4?
Answer:
YOU DO IT X 2
Step-by-step explanation:
Isaiah is decorating the outside of a box in the shape of a triangular prism. The figure
below shows a net for the box.
What is the surface area of the box, in square meters, that
Isaiah decorates
Answer:
389.19 m²
Step-by-step explanation:
The surface area of the box = area of the two equal triangles + area of the 3 different rectangles
✔️Area of the two equal triangles:
Area = 2(½*base*height)
base = 7 m
height = 8 m
Area of the two triangles = 2(½*7*8) = 56 m²
✔️Area of rectangle 1:
Area = Length*Width
L = 13 m
W = 7 m
Area of rectangle 1 = 13*7 = 91 m²
✔️Area of rectangle 2:
L = 13 m
W = 8 m
Area of rectangle 2 = 13*8 = 104 m²
✔️Area of rectangle 3:
L = 13 m
W = 10.63 m
Area of rectangle 3 = 13*10.63 = 138.19 m²
✅Surface Area of the box = 56 + 91 + 104 + 138.19 = 389.19 m²
Pip was thinking of a number. Pip halves the number and gets an answer of 87.2. Form an
equation with x from the information.
X/2= 87.2
to find X:
87.2 X 2= 174.4
therefore X is 174.4
ht
Which of the following is an equivalent expression to the expressione,
А
B
D
ANSWER QUICK PLZ
Bases are 6 and 10 the height is 4 whats the area of the trapszoid
Answer:
here,hope this helps : )
Step-by-step explanation:
Answer: A= 32
a (Base) 6
b (Base) 10
h (Height) 4
Step-by-step explanation: A=a+b
2h=6+10
2·4=32 I really hoped this helped
A seventh-grade class raised $380 during a candy sale. They deposited the money in a savings account for 6 months. If the bank pays 5.3% simple interest per year, how much money will be in the account after 6 months?
Answer: You want to calculate the interest on $380 at 5.3% interest per year after .5 year(s).
The formula we'll use for this is the simple interest formula, or:
Where:
P is the principal amount, $380.00.
r is the interest rate, 5.3% per year, or in decimal form, 5.3/100=0.053.
t is the time involved, 0.5....year(s) time periods.
So, t is 0.5....year time periods.
To find the simple interest, we multiply 380 × 0.053 × 0.5 to get your answer.
Step-by-step explanation:
What is -a⁻² if a = -5?
Answer:
25
Step-by-step explanation:
First, plug -5 in for a, -(-5)^2. We treat the negative on the outside of the paranthese as a -1 so we do -1 times -5 and we get 5. Then we square 5 and get 25.
Which point on the graph represents the y-intercept?
A type of origami paper comes in 15 cm by 15 cm
square sheets. Hilary used two sheets to make the
origami dog. What is the total area of the origami
paper that Hilary used to make the dog?
Answer:
150 cm squared
Step-by-step explanation:
I guess that's the answer if I'm wrong you can tell me right away so that I can try another method thank you.
QUICK! Giving brainliest to correct answer
Answer:
Dominos is the better deal.
Find the value of X for which the following fraction is undefined
2x²+x-15
________
2/3x²-6
Answer: ±√2
Step-by-step explanation: A fraction is undefined when its denominator is =0 or undefined. so we need to get 2/3x²-6=0 or undefined. so we can also do 3x^2-6=0. Solving yields ±√2!
31 PIONTS GIVING BRAINIEST AWNSER Any tips on how to get a grade up ???
Answer:
Forgot picture?
Step-by-step explanation:
Answer:
You can get your grade up by studying, getting a tutor, paying attention in class, taking good notes, asking questions, and cheating (i don't recommend this one :/)
A circle is inscribed in an isosceles trapezoid with bases of 8 cm and 2 cm. Find the probability that a randomly selected point inside the trapezoid lies on the circle
Given that a circle is inscribed in an isosceles trapezoid with bases of 8 cm and 2 cm. We need to find the probability that a randomly selected point inside the trapezoid lies on the circle.
The isosceles trapezoid is shown below: [asy] draw((0,0)--(8,0)--(3,5)--(1,5)--cycle); draw((1,5)--(1,0)); draw((3,5)--(3,0)); draw((0,0)--(1,5)); draw((8,0)--(3,5)); draw(circle((2.88,2.38),2.38)); label("$8$",(4,0),S); label("$2$",(1.5,5),N); [/asy]Let ABCD be the isosceles trapezoid,
where AB = 8 cm, DC = 2 cm, and AD = BC.
Since the circle is inscribed in the trapezoid, we can use the following formula:2s = AB + DC = 8 + 2 = 10 cm
Where s is the semi-perimeter of the trapezoid. Also, let O be the center of the circle. We can draw lines OA, OB, OC, and OD as shown below: [asy] draw((0,0)--(8,0)--(3,5)--(1,5)--cycle); draw((1,5)--(1,0)); draw((3,5)--(3,0)); draw((0,0)--(1,5)); draw((8,0)--(3,5)); draw(circle((2.88,2.38),2.38)); label("$A$",(0,0),SW); label("$B$",(8,0),SE); label("$C$",(3,5),N); label("$D$",(1,5),N); label("$O$",(2.88,2.38),N); label("$8$",(4,0),S); label("$2$",(1.5,5),N); draw((0,0)--(2.88,2.38)--(8,0)--cycle); label("$s$",(3,0),S); label("$s$",(1.44,2.38),E); [/asy]Since O is the center of the circle, we have:OA = OB = OC = OD = rwhere r is the radius of the circle.
Also, we have:s = OA + OB + AB/2 + DC/2s = 2r + 2s/2s = r + 5 cmWe can solve for r:r + 5 cm = 10 cmr = 5 cmNow that we know the radius of the circle, we can find the area of the trapezoid and the area of the circle.
Then, we can find the probability that a randomly selected point inside the trapezoid lies on the circle as follows:Area of trapezoid = (AB + DC)/2 × height= (8 + 2)/2 × 5= 25 cm²Area of circle = πr²= π(5)²= 25π cm²Therefore, the probability that a randomly selected point inside the trapezoid lies on the circle is:
Area of circle/Area of trapezoid= 25π/25= π/1= π
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The probability that a randomly selected point inside the trapezoid lies on the circle is 0.399 or 39.9%. Therefore, option (A) is the correct answer.
The circle is inscribed in an isosceles trapezoid with bases of 8 cm and 2 cm.
Inscribed Circle of an Isosceles Trapezoid
Therefore, the length of the parallel sides (AB and CD) is equal.
Let the length of the parallel sides be ‘a’. Then, OB = OD = r (let)
It is also given that the lengths of the parallel sides of the trapezoid are 8 cm and 2 cm.
Then, its height is given by:
h = AB - CD / 2 = (8 - 2) / 2 = 3 cm
Therefore, the length of the base BC of the right-angled triangle is equal to ‘3’.
Then, the length of the other side (AC) can be given as:
AC = sqrt((AB - BC)² + h²) = sqrt((8 - 3)² + 3²) = sqrt(34) cm
The area of the trapezoid can be calculated as follows:
Area of the trapezoid = 1/2 (sum of the parallel sides) x (height)A = 1/2 (8 + 2) x 3A = 15 sq. cm.
The area of the circle can be given by:
Area of the circle = πr²πr² = A / 2πr² = 15 / (2 x π)
Therefore, r² = 2.39
r = sqrt(2.39) sq. cm.
Now, the probability that a randomly selected point inside the trapezoid lies on the circle can be calculated by dividing the area of the circle by the area of the trapezoid:
P (point inside the trapezoid lies on the circle) = Area of the circle / Area of the trapezoid
P = πr² / 15
P = π (2.39) / 15
P = 0.399 or 39.9%
The probability that a randomly selected point inside the trapezoid lies on the circle is 0.399 or 39.9%.
Therefore, option (A) is the correct answer.
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7. An article in a journal reports that 34% of American fathers take no responsibility for child care. A researcher claims that the figure is higher for fathers in the town of Littleton. A random sample of 225 fathers from Littleton, yielded 97 who did not help with child care. Using a .05 level of significance test the claim that the proportion is at least 34%.
The calculated value of z = 2.80 > the Critical value of z = -1.645, we reject the null hypothesis.
Hence, the claim that the proportion is at least 34% is rejected.
Therefore, the researcher's claim is true that the figure is higher for fathers in Littleton.
Null hypothesis:
H0: p ≥ 0.34
Alternative hypothesis:
Ha: p < 0.34
where:p = proportion of Littleton fathers who do not help with childcare
Here, the level of significance, α = 0.05
Level of significance = α = 0.05
The test statistics for a proportion is given as z-test.
The formula for calculating z-score for a proportion is: z = (p - P) / sqrt[P(1 - P) / n]
where:
P = Population proportion
p = Sample proportion
n = Sample size
The calculated value of z-statistics can be compared with the critical value of z-score from the standard normal distribution table at a particular level of significance.
If the calculated value of z is greater than the critical value of z, then we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.
Calculating the z-statistic:
Here, Sample size n = 225
Sample proportion
p = 97/225
= 0.4311
Population proportion
P = 0.34z
= (p - P) / sqrt[P(1 - P) / n]z
= (0.4311 - 0.34) / sqrt[(0.34)(0.66) / 225]z
= 2.80
Since the alternative hypothesis is one-tailed (Ha: p < 0.34), the critical value of z at α = 0.05 can be found as follows:
The critical value of z = zα
= -1.645
Since the calculated value of z = 2.80 > the Critical value of z = -1.645, we reject the null hypothesis.
Hence, the claim that the proportion is at least 34% is rejected.
Therefore, the researcher's claim is true that the figure is higher for fathers in Littleton.
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ABM Services paid a $4.15 annual dividend on a day it closed at a price of $54 per share. What
was the yield?
Answer:
Yield per share = 7.68% (Approx.)
Step-by-step explanation:
Given:
Dividend paid = $4.15
Price per dividend = $54
Find:
Yield per share
Computation:
Yield per share = [Dividend paid / Price per dividend]100
Yield per share = [4.15 / 54]100
Yield per share = [0.0768]100
Yield per share = 7.68% (Approx.)
What is the range for the following data?
52, 32, 61, 82, 63
Answer:
The range would be 50.
Step-by-step explanation:
Range is found by putting a list or set of numbers in order, then subtracting the lowest number from the highest.
32, 61, 63, 52, 82
82 - 32 = 50
Find the solution to the linear system of differential equations { 146 +24y 12x + 20y satisfying the initial conditions X(0) = 3 and Y(0) = 3. x(t)=__ y(t)=__
Therefore, the solution to the given system of differential equations, with the initial conditions x(0) = 3 and y(0) = 3, is:
x_(t) = 146t + 24yt + 3
y_(t) = (876t + 21) / ((-144) - 10t)
To solve the given linear system of differential equations, let's rewrite the system in a more standard form:
dx/dt = 146 + 24y
dy/dt = 12x + 20y
We'll use the initial conditions x_(0) = 3 and y_(0) = 3 to find the specific solution.
To solve the system, we can use the method of integrating factors.
Solve the first equation:
dx/dt = 146 + 24y
Rearrange the equation to isolate dx/dt:
dx = (146 + 24y) dt
Integrate both sides with respect to x:
∫dx = ∫(146 + 24y) dt
x = 146t + 24yt + C_(1) ---(1)
Solve the second equation:
dy/dt = 12x + 20y
Rearrange the equation to isolate dy/dt:
dy = (12x + 20y) dt
Integrate both sides with respect to y:
∫dy = ∫(12x + 20y) dt
y = 6x + 10yt + C_(2) ---(2)
Now, we'll apply the initial conditions x_(0) = 3 and y_(0) = 3 to find the values of C_(1) and C_(2).
From equation (1), when t = 0, x = 3:
3 = 146(0) + 24(3)(0) + C_(1)
C_(1) = 3
From equation (2), when t = 0, y = 3:
3 = 6(0) + 10(3)(0) + C_(2)
C_(2) = 3
Now, substituting the values of C_(1) and C_(2) back into equations (1) and (2), we get:
x = 146t + 24yt + 3
y = 6x + 10yt + 3
Simplifying further:
x = 146t + 24yt + 3
y = 6(146t + 24yt + 3) + 10yt + 3
x = 146t + 24yt + 3
y = 876t + 144y + 18 + 10yt + 3
x = 146t + 24yt + 3
y - 154y - 10yt = 876t + 18 + 3
(-144y) - 10yt = 876t + 21
y = (876t + 21) / (-144 - 10t)
Therefore, the solution to the given system of differential equations, with the initial conditions x(0) = 3 and y(0) = 3, is:
x_(t) = 146t + 24yt + 3
y_(t) = (876t + 21) / ((-144) - 10t)
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Given the definitions of f(x) and g(x) below, find the value of (gof)(1).
f(x) = 2x² – 2x – 4
g(x) = -5x + 14
Answer:
[tex](g*f)(x) = 34[/tex]
Step-by-step explanation:
For sake of clarity, [tex](g * f)(x) = g(f(x))[/tex]
First, find [tex]f(1)[/tex]
[tex]f(1) = 2(1)^2 - 2(1) - 4\\f(1) = 2-2-4 \\f(1)=-4[/tex]
Then, take what you got for [tex]f(1)[/tex] and plug that into [tex]g(x)[/tex]. In this case, [tex]f(1) = -4[/tex]
[tex]g(-4) = -5(-4) + 14\\g(-4)= 20 + 14\\g(-4) = 34[/tex]
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HELP
4(x-2+y)=???????
Answer:
4+4−8
Step-by-step explanation:
Can someone state the range of this function pleaseee?
Answer:
Range = [0, ∞)
Step-by-step explanation:
Range is the y-values
For this question y starts at 0 and just continually goes up so:
Range = [0, ∞)
Sammy counts the number of people in one section of the school auditorium. He counts 18 female students, 16 male students, and 6 teachers. There are 720 people in the auditorium. Consider the probability of selecting one person at random from the auditorium
Correct Question:
He counts 18 female students, 16 male students, and 6 teachers. There are
720 people in the auditorium. Consider the probability of selecting one person
at random from the auditorium.
Which of these statements are true?
Choose all that apply.
A: The probability of selecting a teacher is 6%.
B : The probability of selecting a student is 85%.
C : The probability of selecting a male student is 32%.
D : The probability of selecting a female student is 45%.
Step-by-step explanation:
Option B and D are correct because
The total number of people in one cross section = 18 + 16 + 6 = 40.
A = The probability of selecting a teacher is = (6/40)x100 = 15 % not equal to 6 %
B = The probability of selecting a male student is = (34/40)x100 = 85%
C = The probability of selecting a male student is = (16/40)x100 = 40 % not equal to 32 %
D : The probability of selecting a female student is = (18/40)x100= 45%