Ken jumps 1 1/5 metres steve jumps 1.5 metres steve jumps further than ken how much further does steve jump than Ken?

Answer: 0.416666667 yards

Answer:

2/5 of a yard

Step-by-step explanation:

Hope this helps and have a wonderful day!!!!

Answer:

its c or a but i think its mostly a

Step-by-step explanation:

Answer:

The correct answer is A

Step-by-step explanation:

The Economy of Oceania largely depends on trade and tourism but trade specifically  

To determine the scale factor relationship between the pizzas based on their diameters, we need to compare the sizes of the pizzas. The scale factor represents the ratio between the corresponding measurements of two similar objects.

In this case, we would compare the diameters of the pizzas. The scale factor can be calculated by dividing the diameter of one pizza by the diameter of another pizza. For example, if Pizza A has a diameter of 12 inches and Pizza B has a diameter of 8 inches, the scale factor between them would be: Scale Factor = Diameter of Pizza A / Diameter of Pizza B = 12 inches / 8 inches = 1.5. Therefore, the scale factor relationship between the pizzas is 1.5. This means that the diameter of Pizza A is 1.5 times larger than the diameter of Pizza B.

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The correct answer we get from the Quantitative variable. i.e. "a. number of car in college per day".

The correct answer is "a. number of car in college per day".

Quantitative variable:

The quantitative variable is used to indicate a variable that takes on numerical values. It is a type of statistical variable that is numeric and uses an objective measure to determine its value.

The variable measures the count, amount, or size of something.

To find out which of the given options is an example of a quantitative variable, we need to understand what it is.

So, the given options are:

a. number of cars in college per day. (Quantitative variable)

b. Gender of students. (Non-quantitative variable)

c. College major. (Non-quantitative variable)

d. Type of favored food. (Non-quantitative variable)

Thus, option a. number of cars in college per day is an example of a quantitative variable.

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Answer:

1.78 > 0.88

Because you would always put the sign on the bigger number.

Answer:

1.78 > 0.88

Step-by-step explanation:

It is > hope this helped.

Based on a survey, 24% of 205 single women and 27% of 270 single men said they "definitely want to have children."

To construct a confidence interval for the difference between two proportions, we use the formula:

(p₁ - p₂) ± z * sqrt((p₁ * (1 - p₁) / n₁) + (p₂ * (1 - p₂) / n₂))

Here, p₁ represents the proportion of single women who want to have children, p₂ represents the proportion of single men who want to have children, n₁ is the sample size of single women, and n₂ is the sample size of single men. The z-value corresponds to the desired confidence level.

Substituting the given values (p₁ = 0.24, n₁ = 205, p₂ = 0.27, n₂ = 270) and the appropriate z-value for a 99% confidence level, we can calculate the lower and upper bounds of the confidence interval.

If the confidence interval includes 0, it suggests that the difference between the proportions is not statistically significant, indicating no evidence of a gender gap. On the other hand, if the confidence interval does not include 0, it suggests a statistically significant difference, indicating evidence of a gender gap.

Therefore, based on the 99% confidence interval estimate, if the interval includes 0 (option A), there is no evidence of a gender gap. If the interval does not include 0 (option B), there is evidence of a gender gap.

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Answer:

Is this an actual question

Answer:

definatly not infinitely it should be only one correct answer so false

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

-53 + 2+ 2x + 4 = ax + b

-47 + 2x = ax + b

Since there is 3 variables you need 3 equations which you don't have. After simplifying there is nothing else you can do.

Answer:

12870ways

Step-by-step explanation:

Combination has to do with selection

Total members in a tennis club = 15

number of men = 8

number of women = 7

Number of team consisting of women will be expressed as 15C7

15C7 = 15!/(15-7)!7!

15C7 = 15!/8!7!

15C7 = 15*14*13*12*11*10*9*8!/8!7!

15C7 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C7  = 15*14*13*12*11/56

15C7 = 6,435 ways

Number of team consisting of men will be expressed as 15C8

15C8 = 15!/8!7!

15C8 = 15*14*13*12*11*10*9*8!/8!7!

15C8 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C8 = 6,435 ways

Adding both

Total ways = 6,435 ways + 6,435 ways

Total ways = 12870ways

Hence the required number of ways is 12870ways

Answer:

Step-by-step explanation: so first you got to distribute the on both sides so like the 2 and the ten from there you just eliminate and do it like normal. I’m sorry I’m bad at at explaining it but I hoped it helped some how :)

Answer:

It will cost $36.38 to travel 8.9 miles.

Step-by-step explanation:

In order to get how much it will cost to travel 8.9 miles, you need to first set up a linear equation (in slope-intercept form, which is [tex]y=mx+b[/tex] ). You can do this with what the problem has given us. Since there's a flat fee of $3, that is the y-intercept or the [tex]b[/tex] slope-intercept form. Then there is $3.75 added for every additional mile traveled, making it the slope or the [tex]m[/tex] in slope-intercept form. That makes the equation look like:

[tex]y=3.75x+3[/tex]

The [tex]x[/tex] in that equation represents how far you traveled. Therefore in order to find out 8.9 miles, plug in 8.9 for [tex]x[/tex].

[tex]y=3.75(8.9)+3[/tex]

Simply solve the equation and you will have how much it will cost to travel 8.9 miles.

[tex]y=33.375+3[/tex]

Now add the like terms:

[tex]y=36.375[/tex]

Since it needs to be rounded to the nearest cent, you will round to the nearest tenth:

[tex]y=36.38[/tex]

Therefore, it will cost $36.38 to travel 8.9 miles.

Answer:

x=-20

Step-by-step explanation:

3x+178=6x+238

-3x=60

x=-20

Answer:

160 days

Step-by-step explanation:

800 divided by 5 equal 160

Answer:

your answer is 160 days

Step-by-step explanation:

800÷5=160 days

I hope this helps

have a nice day/night

mark brainliest, please :)

Answer:

Step-by-step explanation:

a) Probability that the mouse weighs less than 405 grams: 0.8461

b) Probability that the mouse weighs more than 461 grams: 0.0062

c) Probability that the mouse weighs between 406 and 461 grams: 0.8302

d) It is not unlikely that a randomly chosen mouse would weigh less than 405 grams.

Using normal distribution;

a) Probability that the mouse weighs less than 405 grams:

To find this probability, we need to calculate the area under the normal curve to the left of 405 grams. We can use the z-score formula to standardize the value.

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation.

For 405 grams:

z = (405 - 359) / 33

Using a standard normal distribution table or calculator, we can find the probability associated with the z-score.

The probability that the mouse weighs less than 405 grams is approximately 0.8461.

b) Probability that the mouse weighs more than 461 grams:

Similarly, we need to calculate the area under the normal curve to the right of 461 grams.

For 461 grams:

z = (461 - 359) / 33

Using the standard normal distribution table or calculator, we find the probability associated with the z-score.

The probability that the mouse weighs more than 461 grams is approximately 0.0062.

c) Probability that the mouse weighs between 406 and 461 grams:

To find this probability, we calculate the area under the normal curve between the z-scores for 406 and 461 grams.

For 406 grams:

z₁ = (406 - 359) / 33

For 461 grams:

z₂ = (461 - 359) / 33

We can then find the probability associated with each z-score and subtract them to get the desired probability.

The probability that the mouse weighs between 406 and 461 grams is approximately 0.8302.

d) Is it unlikely that a randomly chosen mouse would weigh less than 405 grams?

To determine if it is unlikely, we compare the probability from part (a) with the significance level or threshold value. Let's assume a significance level of 0.05 (5%).

The probability from part (a) is 0.8461, which is greater than 0.05. Therefore, it is not unlikely that a randomly chosen mouse would weigh less than 405 grams.

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Answer:

First find the sum of 15 n-1

Step-by-step explanation:

then you can continue to 2n-1

Answer:

10

Step-by-step explanation:

Using $A^2 + B^2 = C^2$, we know that $A = 6$ and $B = 8$. $8^2 = 64$ and $6^2 = 36$. $64 + 36 = 100$, and $√100 = 10$.

Answer:

Step-by-step explanation:

use the pythagorean theorem.

a^2+b^2=c^2

6^2+8^2=c^2

36+64=100

√100=10

***IMPORTANT. don't forget to square root the answer you get from a^2+b^2. you are putting the answer in squared form which isn't going to be correct, so don't forget to root it before you enter.

Answer:

Step-by-step explanation:

4

Answer:

The son is 10, and the father is 50.

Step-by-step explanation:

10 times 5 would be 50, and 50+10 is 60.

Answer:

Father: 50

Son: 10

Step-by-step explanation:

Son's age: S

Father's age: F

F=5S

F+S=60.

Substitute.

5S+S=60

6S=60

S=10

F=50. As a check, 10+50=60 and 50/5=10.

Hope this was helpful.

~cloud

Answer:

8/3

Step-by-step explanation:

1. 2 ÷ 3 = .66

.66 · 4 = 2.6

2. 4 × 2/3 =

4/1 × 2/3 = 8/3

good luck, i hope this helps :)

Answer:

a

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

A trapezoid with two right angles is a quadrilateral with two right angles.  

Answer:

120

Step-by-step explanation:

The polygon shown is a parallelogram with a base length of 15 and a height of 8

The area of a parallelogram can easily be calculated by multiplying the height by the base length

So A = 15 * 8

15 * 8 = 120

Hence, the area of the polygon is 120 square units

The vector x in terms of the basis B is [x]B = [a].

The vector x can be written as a linear combination of the basis vectors V₁ and V₂ as shown below:

[x]B = a₁V₁ + a₂V₂

Since B is a basis of R², every vector in R² can be represented as a linear combination of V₁ and V₂.

Using the coordinates of x with respect to B, we have:[x]B = a₁V₁ + a₂V₂ = [8; 3]

We can represent V₁ and V₂ in terms of the standard basis of R² as follows:V₁ = [1; 0] and V₂ = [0; 1]

Therefore,[x]B = a₁[1; 0] + a₂[0; 1] = [a₁; a₂]Hence, we can conclude that a = [8; 3] with respect to the standard basis of R².

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a. The parallelogram R is degenerate, consisting of a single point (4, 0).

b. The integral ∬_R (x - 2y) dA over the degenerate parallelogram R evaluates to 0.

a. To evaluate the integral ∬_R (x - 2y) dA, where R is the parallelogram enclosed by the lines -2y = 0, x - 2y = 4, 3x + y = 1, and 3x + y = 8, we can make an appropriate change of variables to simplify the integral. Here's how to do it step by step:

Identify the vertices of the parallelogram R by finding the intersection points of the given lines. Solving the system of equations:

-2y = 0 (equation 1)

x - 2y = 4 (equation 2)

3x + y = 1 (equation 3)

3x + y = 8 (equation 4)

From equation 1, we have y = 0. Substituting this into equation 2, we get x = 4. Therefore, one vertex of the parallelogram is (4, 0).

Next, solving equations 3 and 4, we find another intersection point by equating the expressions for y:

1 - 3x = 8 - 3x

-3x + 1 = -3x + 8

1 = 8

This is a contradiction, so equations 3 and 4 are parallel lines that do not intersect. Therefore, the parallelogram R is degenerate and only consists of a single point (4, 0).

b. Make an appropriate change of variables to simplify the integral. Since the parallelogram R is degenerate and consists of a single point, we can use a change of variables to transform the integral to a simpler form. Let's introduce new variables u and v, defined as follows:

u = x - 2y

v = 3x + y

The Jacobian determinant of the transformation is calculated as follows:

|Jacobian| = |∂(x, y)/∂(u, v)|

= |∂x/∂u ∂x/∂v|

= |1 -2|

= 2

c. Express the integral in terms of the new variables. We need to find the limits of integration in terms of u and v. Since the parallelogram R is degenerate and consists of a single point, the limits of integration are u = x - 2y = 4 - 2(0) = 4 and v = 3x + y = 3(4) + 0 = 12.

The integral becomes:

∬_R (x - 2y) dA = ∫∫_R (x - 2y) |Jacobian| dudv

= ∫∫_R (x - 2y) (2) dudv

= 2∫∫_R (u) dudv

Evaluate the integral. Since R is degenerate and consists of a single point (4, 0), the integral becomes:

2∫∫_R (u) dudv = 2u ∫∫_R dudv = 2u(Area of R)

The area of a degenerate parallelogram is zero, so the integral evaluates to:

2u(Area of R) = 2(4)(0) = 0.

Therefore, the value of the integral ∬_R (x - 2y) dA over the given degenerate parallelogram R is 0.

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Answer:

HCF of 868,372,and 992 is 124

LCM of 868,372,and 992 is 20832

hope this answer helps you...

In a group of 700 people, there must be at least two individuals who have the same first and last initials.

What is combinatorics?

Combinatorics is a branch of mathematics that focuses on counting, arranging, and organizing objects or elements in a systematic and discrete manner. It deals with the study of combinations, permutations, and other mathematical structures related to discrete objects.

To determine whether there must be two people with the same first and last initials in a group of 700 people, we can use the Pigeonhole Principle.

The Pigeonhole Principle states that if we have more pigeons than pigeonholes, then at least one pigeonhole must contain more than one pigeon. In this case, the pigeons represent individuals with different initials, and the pigeonholes represent the unique combinations of first and last initials.

In the given scenario, we have [tex]700[/tex] people and a finite number of possible combinations of first and last initials. Let's consider the number of possible combinations of initials. Since we have 26 letters in the English alphabet, there are 26 choices for the first initial and 26 choices for the last initial. This gives us a total of [tex]26 * 26 = 676[/tex] possible combinations.

Now, since we have 700 people, and the number of possible combinations (676) is less than the number of people, it is not possible for each person to have a unique combination of initials. By the Pigeonhole Principle, at least one combination of initials must be shared by more than one person.

Therefore, in a group of 700 people, there must be at least two individuals who have the same first and last initials.

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