Is 23.2 greater than 156

Answer: 5,040

Step-by-step explanation: The value of 7P6 is 5,040. To evaluate this, you can use the formula for permutations: nPr = n! / (n - r)!, where n is the total number of items and r is the number of items being selected. In this case, n = 7 and r = 6, so 7P6 = 7! / (7 - 6)! = 7! / 1! = 5,040.

The percentage change in the interest rate is -80%. This means that the interest rate needs to be reduced by 80% to achieve an increase in the amount of money by 25% in t/2 years time.

The interest on a loan or principal sum can be easily calculated using simple interest. Simple interest is a notion that is employed across a wide range of industries, including banking, finance, automobiles, and more.

Let the original sum of money be P.

According to the question, if P is deposited at a simple interest rate of r% p.a. for t years, it will be doubled. This means that the interest earned on P after t years is P, i.e.,

I = P

The formula for simple interest is I = (P * r * t) / 100. Substituting I = P, we get:

P = (P * r * t) / 100

Simplifying, we get:

r = 100 / t

Now, the question states that if the same amount of money (P) is increased by 25% in t/2 years time, the new amount becomes:

P' = P + (0.25P) = 1.25P

Let the new rate of interest be r'.

The formula for simple interest is I' = (P' * r' * t/2) / 100. Substituting P' = 1.25P, we get:

I' = (1.25P * r' * t/2) / 100

The interest earned on P' after t/2 years is 1.25P - P = 0.25P. Therefore, we have:

I' = 0.25P

Substituting the value of I' in the above equation, we get:

0.25P = (1.25P * r' * t/2) / 100

Simplifying, we get:

r' = 20 / t

The percentage change in the interest rate is given by:

((r' - r) / r) * 100%

Substituting the values of r and r', we get:

((20/t - 100/t) / (100/t)) * 100%

= -80%

Therefore, the percentage change in the interest rate is -80%. This means that the interest rate needs to be reduced by 80% to achieve an increase in the amount of money by 25% in t/2 years time.

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The margin of error for the duration of telephone calls directed by a local telephone company is approximately 0.511 minutes or 30.66 seconds, with a 98% confidence level.

Given the provided information, we can use the following terms to calculate the margin of error:

1. Standard deviation (s) = 4.5 minutes
2. Sample size (n) = 420 calls
3. Confidence level = 98%

First, let's find the critical value (z-score) for a 98% confidence level. Using a standard normal distribution table, we can determine that the critical value is approximately 2.33.

Next, we need to find the standard error. The standard error (SE) is calculated as follows:

SE = s / √n
SE = 4.5 / √420
SE ≈ 0.2195

Now that we have the critical value and standard error, we can calculate the margin of error (ME) using the formula:

ME = z-score * SE
ME = 2.33 * 0.2195
ME ≈ 0.511

Thus, the margin of error for the duration of telephone calls directed by a local telephone company is approximately 0.511 minutes or 30.66 seconds, with a 98% confidence level. This means that the true mean duration of telephone calls is likely to be within 0.511 minutes (or 30.66 seconds) of the sample mean.

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Recall that any non-zero number raised to the power of 0 is equal to 1. Therefore, 8^0 = 1.

To rewrite the expression using only positive exponents, we can use the following rules of exponents:

a^(-n) = 1 / a^n

a^0 = 1

Using these rules, we can rewrite the expression as:

4^(-2) x 8^0 x 5^6

= (1/4^2) x 1 x 5^6

= 1/16 x 5^6

Therefore, the expression 4 to the power of negative 2 times 8 to the power of 0 times 5 to the power of 6, rewritten using only positive exponents, is 1/16 x 5^6.

The area inside the quadrilateral with corners (1, 2), (2, 3), (5, 1), and (3, -1) is approximately 4.5 square units.


1. Sketch the quadrilateral with given vertices.

2. Divide the quadrilateral into three triangles:

  - Triangle 1: (1, 2), (2, 3), (3, -1)
  - Triangle 2: (1, 2), (3, -1), (5, 1)
  - Triangle 3: (2, 3), (3, -1), (5, 1)

3. For each triangle, find the equation of the line connecting its two points on the same vertical level (either x=1, x=3, or x=5).

4. Calculate the definite integral of each line equation over its respective x range.

5. Subtract the lower line's integral from the upper line's integral for each triangle to find each triangle's area.

6. Add the areas of the three triangles to find the total area of the quadrilateral.

Following these steps, the quadrilateral's area is approximately 4.5 square units.

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The correct answers are Using fast modular exponentiation, we can compute a^m mod b in order of log(n) steps, The lcm of two distinct prime numbers is their product, The Euclidean algorithm always terminates because the remainders are integers, get smaller with each step, and are bounded below by 0, You can block convert a binary number to octal by grouping the binary digits into blocks of 3 and converting each block into an octal digit and If p and q are distinct primes, then the lcm of p and q and pq^2 is pq. The correct answers options are  B, D, F, G, and H.

Option B is true because fast modular exponentiation is a technique that can be used to compute a^m mod b in O(log n) time complexity. Option D is true because the LCM of two distinct prime numbers is their product since they do not have any common factors other than 1.

Option F is true because the Euclidean algorithm is guaranteed to terminate because each remainder is smaller than the divisor in each step, and the remainders are non-negative integers. Option G is true because binary numbers can be grouped into blocks of 3 digits, and each block can be converted into a single octal digit.

Option H is true because the LCM of p and q and pq^2 is pq since the prime factors of pq^2 are already included in the prime factorization of pq. So, Statements that are true are B, D, F, G, and H.

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Answer:

[tex]a. \quad \dfrac{\boxed{1}}{\boxed{3}}} \cdot \dfrac{\boxed{1}}{\boxed{2}}} = \dfrac{\boxed{1}}{\boxed{6}}}\\\\\\\\b. \quad \dfrac{\boxed{1}}{\boxed{3}}} \cdot \dfrac{\boxed{1}}{\boxed{3}}} = \dfrac{\boxed{1}}{\boxed{9}}}\\\\\\\\c. \quad \dfrac{\boxed{21}}{\boxed{26}}} \cdot \dfrac{\boxed{5}}{\boxed{26}}} = \dfrac{\boxed{105}}{\boxed{676}}}\\[/tex]

Step-by-step explanation:

a.

When rolling a die(number cube) the sample space which is the set of all possible outcomes is {1, 2, 3, 4, 5, 6}

The probability of getting any single number on the face is the same = 1/6

For the first cube
P(3) = 1/6 and P(4) = 1/6
P(3 or 4) = P(3) + P(4) = 1/6 + 1/6 = 2/6 = 1/3

For the second cube
P(odd) = P(1 or 3 or 5) = P(1) + P(3) + P(5) = 1/6 + 1/6 + 1/6 = 3/6 = 1/2

So the combined probability that the first cube shows 3 or 4 and the second an odd is given by
1/3 · 1/2 = 1/6

b.
There are three coins a penny, dime and quarter

Probability of selecting a penny = number of pennies/total number of coins = 1/3

Since we are replacing the selected coin for the second draw, the probability of selecting a penny is just the same as before = 1/3

P(selecting 2 pennies with replacement) = 1/3 · 1/3 = 1/9

c.

There are a total of 26 letters in the alphabet
There are 5 vowels in the alphabet: A, E, I, O, U

Therefore there are 26 - 5 = 21 consonants

P(drawing a consonant) = 21/26

P(drawing a vowel) = 5/26

Since we are replacing the first drawn letter, these probabilities do not change with successive draws.

Therefore
P(consonant first draw and vowel second draw)

= P(consonant) · P(vowel)

= 21/26 · 5/26

=105/676

y''(0) = 2.

To find y''(0) for the given function y=7x^4+x^3+x^2+cx+, we need to take the second derivative of the function and then evaluate it at x=0.

First, we find the second derivative of y:

y'(x) = 28x^3 + 3x^2 + 2x + c

y''(x) = 84x^2 + 6x + 2

Now, we evaluate y''(x) at x=0:

y''(0) = 84(0)^2 + 6(0) + 2

y''(0) = 2

Therefore, y''(0) = 2.

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The line passes through the point (4, 5), has its equation of the line to be y = 5/4x

From the question, we have the following parameters that can be used in our computation:

Point, (x, y) = (4, 5)

The equation of a straight line is represented as

y = mx + c

Assuming c = 0,

So, we have

y = mx

This means taht

5 = 4m

So, we have

m = 5/4

Recall that

y = mx

So, we have

y = 5/4x

Hence, the equation of the line is y = 5/4x

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The measure of <RWY is 60 degree.

We have,

YMX = (YM) + (MX)

YMX = (4x-49) + (3x+4)

(YMX) = 7x - 45

Now, (YMX - TN) /2 = <TKN

(7x- 45 - 43)/2 = <TKN

5x -77 = 7x - 88 /2

10x - 154 = 7x-88

x=22

Now, (RY) = 6x-82 = 50

and, (MX) = 3x+4 = 70

So, the measure of <RWY

= (50+70)/2 = .60

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There might be a typo in the interval you provided, as it should be written in ascending order, such as [a, b] with a < b. I'll assume you meant the interval [2, 14]. Now, let's analyze the function f(x) = 1/ln(3x) and find its absolute maximum and minimum on the interval [2, 14].

Step 1: Find the critical points
To find the critical points, we need to find the derivative of the function f(x) and set it equal to zero.

f(x) = 1/ln(3x)
Using the chain rule, we find the derivative:
f'(x) = -1/(ln(3x))^2 * (1/x)

Now, we need to find when f'(x) = 0 or when f'(x) is undefined. Since the derivative is a fraction, it is never equal to zero. However, the function is undefined when the denominator is zero. In this case, there's no value of x in the interval [2, 14] that makes the denominator zero.

Step 2: Analyze the endpoints
Since there are no critical points within the interval, we only need to check the values of the function at the endpoints.

f(2) = 1/ln(6)
f(14) = 1/ln(42)

Step 3: Determine the absolute maximum and minimum
Compare the values at the endpoints:
f(2) > f(14) as ln(6) < ln(42)

Thus, the function f(x) has an absolute maximum at x = 2 and an absolute minimum at x = 14 within the interval [2, 14].

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By Cavalieri's Principle, the volume of that slanted cylinder will be the same volume of a non-slanted cylinder with the same altitude.

so we have a cylinder with a radius of 3 and a height of 7 and a cone hitching a ride on it, with a radius of 3 and a height of 3, so let's simply get the volume of each.

[tex]\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h=7\\ r=3 \end{cases}\implies V=\pi (3)^2(7) \\\\[-0.35em] ~\dotfill\\\\ \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h=3\\ r=3 \end{cases}\implies V=\cfrac{\pi (3)^2(3)}{3} \\\\[-0.35em] ~\dotfill\\\\ \pi (3)^2(7)~~ + ~~\cfrac{\pi (3)^2(3)}{3}\implies 63\pi +9\pi \implies 72\pi ~~ \approx ~~ \text{\LARGE 226.19}~in^3[/tex]

The estimated regression functions for the four regions using the first-order regression model (1.1) are appropriate.

a. To estimate the regression functions, the first-order regression model (1.1) is used for each region. This model assumes a linear relationship between the predictor variable and the response variable. The estimated regression functions are obtained by fitting a straight line to the data points in each region that best represents the relationship between the predictor and response variables.

b. The estimated regression functions may or may not be similar for the four regions. This depends on the data and the specific characteristics of each region. The estimated regression functions will differ in terms of the slope and intercept values, which represent the magnitude and direction of the relationship between the predictor and response variables.

c. To calculate the mean squared error (MSE) for each region, the residuals (the differences between the observed response values and the predicted response values from the estimated regression functions) are squared and averaged. MSE is a measure of the variability around the fitted regression line, with a lower value indicating less variability.

d. If the MSE values are similar for the four regions, it indicates that the variability around the fitted regression line is approximately the same across all regions. If the MSE values are different, it suggests that the variability around the fitted regression line varies across the regions.

Therefore, the estimated regression functions are appropriate for each region using the first-order regression model (1.1). The similarity of the estimated regression functions and the variability around the fitted regression line can be determined by calculating the MSE values for each region and comparing them.

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The value of p3 for which the set s is linearly dependent is p3 = 1

To find the value of p3 for which s is linearly dependent, we need to find values of p3 such that at least one of the vectors in the set s can be written as a linear combination of the other vectors in the set.

Let's start by setting up the linear combination equation:

c1(t − t^2) + c2(t^2 − t^3) + c3(1 − t t^3) = 0

where c1, c2, and c3 are constants that represent the coefficients of the linear combination.

Next, we can expand the terms and group them by powers of t:

(c1 − c2)t^2 + (-c1 + c2 + c3)t + (c3) = 0

For this equation to have a non-trivial solution (i.e., not all c1, c2, and c3 are zero), the determinant of the coefficient matrix must be zero:

det

|1 -1 0|

|-1 1 1|

|0 -1 p3|

= 0

Expanding the determinant, we get:

1(1-p3) - (-1)(-p3) + 0(1) = 0

Simplifying this equation, we get:

p3 - 1 = 0

Therefore, the value of p3 for which the set s is linearly dependent is p3 = 1

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The equivalence classes are, [0]={0,3,-3,6,-6}, [1]={1,4,-2,-5}, [2]={2,5,-1,-4}, [3]={3,6,-3,0}, and R has 4 distinct equivalence classes: {[0]}, {[1], [4], [-2], [-5]}, {[2], [5], [-1], [-4]}, and {[3], [6], [-3], [0]}.

An equivalence relation is a mathematical concept that relates objects or elements in a set based on a certain property or characteristic they share. In this case, the relation R on set A relates elements x and y if their difference is divisible by 3. This means that the elements in each equivalence class of R share this same property.

The set-roster notation expresses the equivalence classes of R as sets of elements in A that are related to each other under R. In this case, there are four distinct equivalence classes of R, each containing elements that differ by multiples of 3. This concept is important in various areas of mathematics, including algebra, topology, and geometry.

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The value of the missing angle x is 114 degrees

From the question, we have the following parameters that can be used in our computation:

The kite

The value of x can be calculated using the following equation

x + 78 + 78 + 90 = 360 ---- sum of angles in a quadrilateral

When the like terms are evaluated, we have

x + 246 = 360

So, we have

x = 114

Hence, the value of x is 114 degrees

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The arc length is approximately 20.5744 units.

To find the arc length from (0, 4) clockwise to (3, 7) along the circle[tex]x^2 + y^2 = 16.[/tex]

We need to first find the angle between the positive x-axis and the line connecting the center of the circle to the point (3, 7), since the arc length is a fraction of the circumference of the circle.

The center of the circle is at (0, 0), and the line connecting (0, 0) to (3, 7) has a slope of (7-0)/(3-0) = 7/3.

Therefore, the angle between the positive x-axis and this line is given by:

θ = arctan(7/3) ≈ 1.1659045 radians

Since we are traveling clockwise from (0, 4) to (3, 7), we are traversing an angle of 2π - θ, which is approximately 5.1766375 radians.

The circumference of the circle is given by 2πr, where r is the radius of the circle. In this case, the radius is 4, so the circumference is 8π.

The fraction of the circumference that we travel along is the ratio of the angle we traverse to the total angle around the circle, which is 2π.

Therefore, the arc length is:

(5.1766375 radians / 2π) × 8π = 20.5744

Rounding to four decimal places, the arc length is approximately 20.5744 units.

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For a population with an original σ=5, the standard error of the mean (SEM) for a sample size of n=4 is approximately 2.5 points, for a sample size of n=9 it is approximately 1.67 points, and for a sample size of n=16 it is approximately 1.25 points.

In question 9, with a population σ of 10, the SEM for a sample size of n=4 is approximately 5 points, for a sample size of n=9 it is approximately 3.33 points, and for a sample size of n=16 it is approximately 2.5 points. The difference between the SEM in questions 8 and 9 is due to the difference in population σ. A larger population σ will result in a larger SEM, which means more error is expected in the sample mean.

Increasing sample size (comparing a, b, c) will decrease the SEM, resulting in less error expected in the sample mean. This is because as sample size increases, the sample mean becomes a better representation of the population mean.

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Answer:

It's 84

Step-by-step explanation:

To calculate the area of a triangule you need to use this formula:

B * H / 2

So:

12 * 14 / 2 = 84

Hope this helps :)

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The system of linear functions for the graph below is given as follows:

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

For the first line, we have that:

Hence the equation is:

y = -0.5x + 1.

For the second line, we have that:

Hence the equation is:

y = -4x - 6.

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The length of the curve r = 4θ², 0≤θ≤2√3, is 38.786 units.

To find the length of the curve, we can use the formula for arc length:
[tex]L = \int_{a}^{b}\sqrt{(1 + (dy/dx)^2)} dx[/tex]

In this case, we have the polar equation r = 4θ², which we can convert to Cartesian coordinates using x = r cos(θ) and y = r sin(θ):

x = 4θ² cos(θ)
y = 4θ² sin(θ)

To find dy/dx, we can use the chain rule:

dy/dx = (dy/dθ)/(dx/dθ)

= (4θ² cos(θ) + 8θ sin(θ))/(8θ cos(θ) - 4θ² sin(θ))

Simplifying this expression, we get:

dy/dx =(4θ) (θ cos(θ) + 2 sin(θ))/(2 cos(θ) - θ sin(θ))

Now we can substitute this expression and the expression for x into the arc length formula:
[tex]L = \int_{0}^{2\sqrt{3}}\sqrt{(1 + ((4\theta)(\theta cos(\theta) + 2sin(\theta))/(2cos(\theta) - \theta sin(\theta)))^2)} d\theta[/tex]

This integral is difficult to solve analytically, so we can use numerical methods to approximate the value. Using a calculator or computer program, we get:

L ≈ 38.786

So the length of the curve is approximately 38.786 units.

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We can use the Taylor series formula to find the fourth-degree Taylor polynomial for f about x = 2.  The answer is d. 18

[tex]f(2) = f(2) = 405[/tex]

[tex]f'(2) = 29[/tex]

[tex]f''(2) = 28[/tex]

[tex]f'''(2) = 168[/tex]

The fourth-degree Taylor polynomial is:

P4(x) [tex]= f(2) + f'(2)(x-2) + (f''(2)/2!)(x-2)^2 + (f'''(2)/3!)(x-2)^3 + (f''''(c)/4!)(x-2)x^{2}[/tex]^4

where c is some number between 2 and x.

Using the given third derivative, we can find the fourth derivative:

[tex]f''''(x) = (4x + 1) ^6 * 4[/tex]

Plugging in x = c, we have:[tex]f''''(c) = (4c + 1) ^6 * 4[/tex]

Therefore, the coefficient of [tex](x-2)^4[/tex] in the fourth-degree Taylor polynomial is:[tex](f''''(c)/4!) = [(4c + 1) ^6 * 4] / 24[/tex]

We need to evaluate this at c = 2:[tex][(4c + 1) ^6 * 4] / 24 = [(4*2 + 1) ^6 * 4] / 24 = 18[/tex]

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The correct answer is: t = 2.293, p-value < 0.01, reject the null hypothesis, and conclude that the mean weight of the citizens has increased.

To test the hypothesis, we need to use a one-sample t-test since we are comparing the mean weight difference of the sample to zero (no change). The sample mean weight difference is 3.51, and the sample standard deviation is 7.44. Since we do not know the population standard deviation, we use the t-distribution.

The null hypothesis is that the mean weight difference is equal to zero (no change), and the alternative hypothesis is that the mean weight difference is greater than zero (increase in weight).

Using a significance level of 0.01, the critical t-value for a one-tailed test with 40 degrees of freedom is 2.704. The calculated t-value is (3.51-0)/(7.44/sqrt(41)) = 2.293. The p-value associated with this t-value is less than 0.01 (found using a t-distribution table or calculator).

Since the p-value is less than the significance level, we reject the null hypothesis and conclude that the mean weight of the citizens of Pawnee significantly increased after drinking the new candy bar milkshake for a week. Therefore, the correct answer is: t = 2.293, p-value < 0.01, reject the null hypothesis, and conclude that the mean weight of the citizens has increased.

The 95% confidence interval for the mean difference in weight (1.163 , 5.857) also supports this conclusion since it does not include zero.

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a. Numerical form of f(3): When x=3, the denominator of the function becomes 3-3=0, which makes the function undefined. Therefore, f(3) does not exist. This is known as a "point of discontinuity."

b. Graph of f(x): To plot the graph of f, we need to find the values of f(x) for different values of x. We can use algebraic techniques to simplify the function:

f(x) = (4x^2-17x+15)/(x-3)

= (4x-3)(x-5)/(x-3) (factoring the numerator)

= 4x - 3 (canceling out the common factor of (x-3))

Now, we can see that the function is undefined at x=3, but for all other values of x, it is equal to 4x-3. Therefore, the graph of f(x) is a straight line with slope 4 and y-intercept -3, except for a hole at x=3. To sketch the graph, we can draw a dotted line at x=3 to indicate the point of discontinuity, and draw the straight line with a break at x=3,

c. Limit of f(x) as x approaches 3:

As x approaches 3, the denominator of the function gets closer and closer to zero, but the numerator also approaches a specific value. We can use algebraic techniques to evaluate the limit:

lim x→3 (4x^2-17x+15)/(x-3)

= lim x→3 [(4x-3)(x-5)/(x-3)] (factoring the numerator)

= lim x→3 (4x-3) (canceling out the common factor of (x-3))

= 7

Therefore, the limit of f(x) as x approaches 3 is 7.

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The probability that the weight of 36 babies born at the hospital will be between 7.4 and 6.5 pounds is approximately 0.9089 or 90.89%.

a) The values of the parameters are:

Mean (μ) = 7.3 pounds

Standard deviation (σ) = 0.65 pounds

b) As we don't have the sample data, we can't calculate the sample mean (μx) and sample standard deviation (σx or s).

c) To find the probability that the weight of 36 babies will be between 7.4 and 6.5 pounds, we need to use the central limit theorem as the sample size is large enough (n=36).

First, we need to standardize the values using the formula:

z = (x - μ) / (σ / sqrt(n))

where x is the value we want to find the probability for, μ and σ are the population mean and standard deviation respectively, and n is the sample size.

For 7.4 pounds:

z1 = (7.4 - 7.3) / (0.65 / sqrt(36)) = 1.38

For 6.5 pounds:

z2 = (6.5 - 7.3) / (0.65 / sqrt(36)) = -2.46

Next, we need to find the probability of z-values using a standard normal distribution table or calculator.

Using the standard normal distribution table, the probability of z1 = 1.38 is 0.9157, and the probability of z2 = -2.46 is 0.0068.

Finally, we can find the probability that the weight of 36 babies will be between 7.4 and 6.5 pounds by subtracting the probability of z2 from the probability of z1:

P(6.5 ≤ x ≤ 7.4) = P(z2 ≤ z ≤ z1) = P(z ≤ 1.38) - P(z ≤ -2.46) = 0.9157 - 0.0068 = 0.9089

Therefore, the probability that the weight of 36 babies born at the hospital will be between 7.4 and 6.5 pounds is approximately 0.9089 or 90.89%.

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The value of x in each case:

(a) x = 7 units

(b) x = 5√2 units

(c) x = 4√3 units

In this question we use some basic formula of trigonometry.

(a) Consider sine of angle 30 degrees

sin(30) = opposite side/hypotenuse

1/2 = x/14

x = 14/2

x = 7 units

(b) Consider cosine of angle 45 dgrees

cos(45) = adjacent side/ hypotenuse

1/√2 = 5/x

x = 5√2 units

(c) Consider tangent of angle 60 degrees.

tan(60) = opposite side/ hypotenuse

√3 = x/4

x = 4 × √3

x = 4√3 units

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Here the length of VT is equal to (x-1) which is equal to 6 and SC is equal to (2x-17) which is equal to 3.

So x=7, VT=6 and SC=3.

Explain length

Length is a fundamental physical quantity used to measure the size of an object or the distance between two points. It is expressed in units such as meters, centimetres, or feet and is used in various fields such as mathematics and physics. The length of a straight line is calculated by finding the distance between its endpoints, while the length of two-dimensional shapes such as rectangles is measured by their perimeter.

According to the given information

We can use the following steps to find x:

Find the length of ST using Pythagoras' theorem as follows:

SV = RV + RS = RV + RT = 6 + (2x - 17) = 2x - 11

UT = UV + VT = 12 + (x - 1) = x + 11

ST² = SV² + UT²

(2x - 11)² + (x + 11)² = ST²

Find the length of VT using Pythagoras' theorem as follows:

TV² = UT² - UV²

TV² = (x + 11)² - 12²

Substitute TV² into the equation in step 1 and solve for x.

After solving for x, we get x=7.

Therefore, VT is equal to (x-1) which is equal to 6 and SC is equal to (2x-17) which is equal to 3.

So x=7, VT=6 and SC=3.

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The probability that the average height of 9 randomly chosen people is over 70 inches is approximately 0.0478, or 4.78%.

1. Identify the given values: mean (µ) = 68 inches, standard deviation (σ) = 3 inches, and sample size (n) = 9.

2. Calculate the standard deviation of the sample mean using the formula σ/√n: 3/√9 = 3/3 = 1.

3. Determine the z-score for 70 inches using the formula (X - µ)/(σ/√n): (70 - 68)/1 = 2.

4. Find the probability of a z-score greater than 2 by referring to a z-table or using a calculator, which is approximately 0.0228.

5. Since the question asks for the probability over 70 inches, subtract the probability from 1: 1 - 0.0228 ≈ 0.9772.

6. The probability that the average height is over 70 inches is 1 - 0.9772 = 0.0478, or 4.78%.

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