In case of a Crash the pilot of the plane jumped from it and opened his parachute after falling through 40m

Answer:

Sorry if I kwon the

answer I telling u

the answer sorry

The first two steps for finding the magnitude of the resultant vector is find the sum of the two horizontal vectors and the sum of the two vertical vectors.

The resultant of two vectors is determined from Pythagoras theorem is as shown below.

R² = a² + b²

Thus, the first two steps for finding the magnitude of the resultant vector is find the sum of the two horizontal vectors and the sum of the two vertical vectors.

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Answer:

6m/s

Explanation:

the original momentum = mass x velocity = 8x (60+10) = 560

momentum after = mass x velocity of the school bag + mass x velocity of the boy = 10x20 + 60x A

200+60A = 560

A=6

The net force performs a total amount of work equal to

(45 N) (0.80 m) = 36 J

on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have

W = ∆K = 1/2 mv²

since the bullet starts at rest, where m = its mass and v = its final velocity.

Solve for v :

36 J = 1/2 (0.0050 kg) v²   ⇒   v = 120 m/s

The option which most likely represent the forces acting on the object is  ← 63 N and → 73 N.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

When the  resulting net force of an object is →10 N

The forces must be in x and  -x direction to balance and give net force of 10 N in +x direction.

So, +73N -63 N = +10 N

Thus, the correct option is ← 63 N and → 73 N

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Answer:

the easy way to describe this is to use a light as an example.

Explanation:

Voltage is pretty much the loop used to help use a lightbulb to emit light. Without voltage, we would be unable to use lightbulbs. This applies to much more than a lightbulb, but it's the easiest way to describe how voltage works.

I hope this woll work.Best of luck.Sorry of the answer ia wrong

Answer:

wood

Explanation:

Based on the calculations, the kinetic energy of the model rocket at this point is equal to: A. 7,200 Joules.

Given the following data:

Mass = 1 kg.

Height = 500 m.

Velocity = 120 m/s.

Mathematically, kinetic energy can be calculated by using this formula:

K.E = 1/2 × mv²

Where:

Substituting the given parameters into the formula, we have;

K.E = 1/2 × 1 × (120)²

K.E = 1/2 × 1 × 14,400

K.E = 7,200 Joules.

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Answer:

[tex]46.482 cm[/tex]

Explanation:

[tex]Since 1 in = 2.54cm\\\\18.3 inches =(18.3 x 2.54) cm\\ =46.482cm[/tex]

The acceleration of the snail will be 7/13 m/sec². The acceleration is found as the rate of change of the velocity.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The given data in the problem is;

v(t)=1.4ln(1’t²) inches per minute

0<t<15 minute

Acceleration is found as;

[tex]\rm v('t)=1.4 \times \frac{1}{1+t^2} (2t)[/tex]

Acceleration at t= 5 minute;

[tex]\rm v'(5)=\frac{1.4(2)(5)}{1+5^2} =\frac{14}{26} \\\\ v'=\frac{7}{13}[/tex]

Hence, the acceleration of the snail will be 7/13 inch per square minute.

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Answer:

B. A measure of mass per unit volume

Explanation:

trust me

Answer:ITS C I PASSED THE TEST

Explanation:I DID THE PLATO

The times and distances are represented by the function are

The distance is the length of path travelled by a body when moving with some speed and taking time t.

Given function is

D (t) = 300t +125 for 0≤t<2.5

D (t) = 875  for 2.5 ≤t≤3.5

D(t)= 75t +612.5 for 3.5<t≤6

According to the given function, for 2 hours, the traveler will travel from home,

D (2) = 300x2 +125 = 725 miles.

For time between 2.5 to 3.5 hr, the distance is constant i.e. 875 miles.

For total time 6hr, the distance travelled will be

D(6) = 75 x 6 +612.5 = 1062.5 miles.

Thus, the correct options are picked up.

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Answer:

B, D, E

Explanation:

got it right on edge

The sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.

Kirchhoff's loop rule states that the algebraic sum of potential differences, as well as the voltage supplied by the voltage sources and resistances, in any loop must be equal to zero.

In a series RLCcircuit, the voltages are not added by scalar addition but by vector addition.

Kirchhoff's loop rule is not violated since the voltages across different elements in the circuit are not at their maximum values.

Therefore, the sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.

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The work John does is 680 J (joules).

To calculate the work done by John, we need to use the formula:

Work = Force * Distance * cos(theta)

where Force is the applied force, Distance is the displacement, and theta is the angle between the force and the displacement.

Substitute the given values into the formula:

Force = 60 N

Distance = 12 m

theta = 37 degrees

Convert the angle from degrees to radians:

theta_radians = 37 degrees * (pi/180)

Calculate the cosine of the angle:

cos(theta_radians) = cos(37 degrees * (pi/180))

Calculate the work done by John:

Work = 60 N * 12 m * cos(37 degrees * (pi/180))

Simplify the equation and calculate the numerical value:

Work ≈ 680 J (joules)

Therefore, the work done by John is approximately 680 joules.

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From the calculation, the wavelength of the waves is about 264 nm and belongs to the ultraviolet spectrum.

The term photoelectric effect can be used to describe the loss of electron from the surface of a metal. Given that; KE = E - W, where;

KE = kinetic energy of the emitted photoelectron

E = energy of the photon

W = work function of the metal

[tex]2= E - 2.71\\E = 2 + 2.71\\E = 4.71ev or 7.5 * 10^-19 J[/tex]

λ= hc/E

λ= [tex]6.6 * 10^-34 * 3 * 10^8/7.5 * 10^-19[/tex]

λ= [tex]2.64 * 10^-7 m[/tex] or 264 nm

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#21

According to first equation of kinematics

#22

#a

The order is

#b

for speed find absolute velocity

So order is

S1<S3<S2

Answer:

See below ~

Explanation:

Question 21 :

⇒ v = u + at

⇒ v = 5 + 1.3 (2)

⇒ v = 5 + 2.6

⇒ v = 7.6 m/s

=============================================================

Question 22 : At t = 3

Subpart (a)

⇒ Object 1 : v = 2 + 3(3) = 11 m/s

⇒ Object 2 : v = -8 - 4(3) = -20 m/s

⇒ Object 3 : v = 1 - 5(3) = -14 m/s

⇒ Hence, their velocities are in the order : Object 2 < Object 3 < Object 1

Subpart (b)

⇒ Object 1 : v = | 2 + 3(3) | = 11 m/s

⇒ Object 2 : v = | -8 - 4(3) | = 20 m/s

⇒ Object 3 : v = | 1 - 5(3) | = 14 m/s

⇒ Hence, their speeds are in the order : Object 1 < Object 3 < Object 2

Five locations are marked on the world map. The spot that is prone to hurricane mostly A.

A hurricane is a cyclone with winds of 74 miles (119 kilometers) each hour or more prominent that is typically joined by downpour, thunder, and lightning, and that occasionally moves into calm scopes.

The locations on the world map spot A, B, C, D, E are regions with country prone to hurricane.

The SPOT A, is GULF of Mexico, a sea bowl nearer to the Atlantic sea, encompassed with the North American landmass, the Hawaiian island is likewise inside that locale.

The SPOT B, is the southern Pacific sea with nations like BRAZIL, PERU, ECUADOR, CHILE, in that equivalent locale. This is likewise visited by the tropical storm.

The SPOT C, is inside the locales of AFRICA, nations at the edge are likewise impacted by typhoon.

The SPOT D, is Asian landmass with Russia at the edge. They are likewise inclined to typhoon.

The SPOT E, is the North Pacific sea locale situated at the upper left hand side of the world guide, with nations like Canada, Alaska and co. Near the artic circle.

Thus, location A is the most prone to hurricanes.

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I believe the answer is A. a

I've done the test, 16/16

Answer:

According to Oxford Dictionaries "Precision" means "the quality, condition, or fact of being exact and accurate."

Explanation:

Hope this helps! :)

Answer:

A. 0.502

B. 0.753

Explanation:

A. The angular acceleration of the flywheel is equal to the change in angular velocity divided by the change in time, which is equal to (4.6-2.09)/5 which is 0.502.
B. Angular acceleration is equal to the net torque divided by the rotational inertia. If you rearrange the equation, torque is equal to angular acceleration times rotational inertia, which is 0.502 times 1.5 which is 0.753.

Answer:

Assumption: the angular acceleration of this flywheel is constant.

Angular acceleration: [tex]0.502\; {\rm rad\cdot s^{-2}}[/tex].

Net torque on this flywheel: [tex]0.753\; {\rm kg \cdot m^{2} \cdot s^{-2}[/tex] (or, equivalently, [tex]0.753\; {\rm N \cdot m}[/tex].)

Explanation:

Change in the angular velocity of this flywheel:

[tex]\begin{aligned}\Delta \omega &= \omega_{1} - \omega_{0} \\ &= 4.6\; {\rm rad \cdot s^{-1}} - 2.09 \; {\rm rad \cdot s^{-1}} \\ &= 2.51\; {\rm rad \cdot s^{-1}}\end{aligned}[/tex].

Divide this change in angular velocity [tex]\Delta \omega[/tex] with the duration [tex]t[/tex] of the acceleration to find the average angular acceleration of this flywheel:

[tex]\begin{aligned}\alpha &= \frac{\Delta \omega}{t} \\ &= \frac{2.51\; {\rm rad \cdot s^{-1}}}{5\; {\rm s}} \\ &= 0.502\; {\rm rad \cdot s^{-2}}\end{aligned}[/tex].

By Newton's Second Law for Rotation, the net torque on this flywheel would be the product of the angular acceleration and the moment of inertia of this flywheel, [tex]I[/tex]:

[tex]\begin{aligned}\tau_{\text{net}} &= I\, \alpha \\ &= 1.5\; {\rm kg \cdot m^{2}} \times 0.502\; {\rm s^{-2}} \\ &= 0.753\; {\rm kg \cdot m^{2} \cdot s^{-2}} \\ &= 0.753\; {\rm (kg \cdot m \cdot s^{-2}) \cdot m} \\ &= 0.753\; {\rm N \cdot m}\end{aligned}[/tex].

The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and  m₂ will be u₁=5 and u₂=0 m/s respectively,

According to the law of conservation of momentum

Momentum before collision =Momentum after collision

m₁u₁+m₂u₂=(m₁+m₂)v

M×5+3M×0=[M+3M]v

The final velocity is found as;

V=51.25 m/s

The velocity of block A is found as;

[tex]\rm V_f=\frac{(m_1-m_2)u_1}{m_1+m_2} +\frac{2m_2u_2}{m_1+m_2} \\\\ V_f=\frac{(M-3M)5+2\times3M\times0}{m_1+m_2} \\\\ V_f=2.5 m/s[/tex]

Hence, the final velocity of the block A will be 2.5 m/sec.

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The information being conveyed by an object about the important events, advancements, and people of a specific time period is known as: C. historical significance.

Historical significance can be defined as an information that is being conveyed by an artistic object about the important events, advancements, technology, phenomenon, and people that have existed and occurred over a specific time period

This ultimately implies that, historical significance refers to the information that an object conveys with respect to the important events, advancements, technology, and people of a specific time period.

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The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

The energy stored in a capacitor is an electrostatic potential energy.

It is related to the charge(Q) and voltage (V) between the capacitor plates.

It is represented as 'U'.

Formula:

Potential difference, V is the ratio of the charge to the capacitance of a capacitor.

It is calculated using:

V = Q ÷ C

Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9

Substitute the values into the equation

Potential difference, V = 5 × 10∧-5 ÷  10∧-9 = 5 × 10∧4 volts

Formula:

Energy, U = 1 ÷ 2 (QV)

Where Q= charge and V = potential difference across the capacitor

Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)

= 0.5 × 25 × 10∧-1

= 0.5 × 2.5

= 1. 25 Joules

Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

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A new wave created by the destructive interference of two waves is produced. The new wave is accurately described in statement A. Its amplitude is greater than that of the waves that produced it.

Destructive interference happens when the maxima of two waves are 180° out of phase; a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

Two or more waves combining to produce a wave with a smaller displacement is called destructive interference.

Two waves overlap producing a new wave that exhibits destructive interference. It has a larger amplitude than the waves that overlapped to produce it.

Hence, statement A correctly describes the new wave.

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The density of the metal sphere is 2 times the density of the liquid as proved.

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ --- proved

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

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Answer:

5.775 m/s

Explanation:

radial acceleration = velocity / radius

=> velocity = radial acceleration * radius

=> v = 3.5 * 1.65 = 5.775 (m/s)

Out of the given equations,

241Am 23Np + 4He

18F → 180+ °C

14C → 14N+_e

152 Dy → 15. Dy+y

The first equation shows the alpha decay which is ₉₅Am²²⁴ →  ₉₃Np²³⁷ + ₂He⁴

Alpha particles are emitted in the form of radiations when radioactive decay occurs.  The atom of heavy nucleus emit the alpha particles that consist of two proton and two neutrons, also called helium nuclei.

The properties of alpha radiations are:

The Americium with atomic weight  224 undergo alpha decay and produce ₉₃Np²³⁷ . The alpha particle is helium nuclei.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Thus, the first equation represents alpha radiation.

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Potassium will have the greatest atomic size because of its number of shells, followed by sodium which 1 valence electron compared to magnesium the same number of shells but 2 valence electrons.

The relative size of the atoms is determined from the number of shells and valence electron contained in the atom.

Sodium, 11 ----> 2, 8, 1

Magnesium, 12 ----> 2, 8, 2

Potassium, 19, -----> 2, 8, 8, 1,

Potassium will have the greatest atomic size because of its number of shells, followed by sodium which 1 valence electron compared to magnesium the same number of shells but 2 valence electrons.

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Answer:

I don't really understood the question

The final temperature of the seawater-deck system is 990°C.

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

The deck of a small ship reaches a temperature Ti= 48.17°C seawater on the deck to cool it down. During the cooling, heat Q =3,710,000 J are transferred to the seawater from the deck. Specific heat of seawater= 3,930 J/kg°C.

Suppose for 1 kg of sea water, the heat transferred from the system is given by

3,710,000 = 1 x 3,930 x (T - 48.17)

T = 990°C  to the nearest tenth.

The final temperature of the seawater-deck system is 990°C.

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