In a game of shuffleboard (played on a horizontal surface), a puck is given an initial speed of 6. 0 m/s. It slides a distance of 9. 0 m before coming to rest. What is the coefficient of kinetic friction between the puck and the surface?.

Answers

Answer 1

The coefficient of kinetic friction between the puck and surface id 0.20.

What is coefficient of kinetic friction?

Coefficient of kinetic friction is the ratio between frictional force present in the motion of two surfaces that are in contact to the normal force that presses the two surface together.

It is calculated mathematically as: μ = F/N, where

F= frictional force and N= normal force.

v2 = u2 +2as

0= 62 + 2a9

18a + 36= 0

18a = -36

a= -2

friction =  μ × normal force

or friction =ma

ma=  μN

ma=  μ(mg)

μ = a/g where g = 9.8 N

μ= -2/9.8

⇒0.20.

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Related Questions

why or how do neutrons help to reduce the repulsion between protons and stabilize the atoms nucleus?

Answers

Since the neutrons have no charge they don't add to the repulsion already present, and they help separate the protons from each other so they don't feel as strong a repulsive force from any other nearby protons.
I hope it answers your question.

A family in a car with the ma of 1400 kg. In an accident it hit a wall and goe from a peed of 27 m/ to a tandtill in 1. 5 econd. Calculate the force involved

Answers

The force involved is F₁.₅=-25.2KN when the car hit a wall and goes from a speed of 27m/s

What is meant by force?

A force is an influence in physics that can modify the velocity of an object. A force can modify the velocity of a mass item. A force is a vector quantity since it has both magnitude and direction. It is measured in newtons, the SI unit of mass (N). The sign F represents force.

In its original form, Newton's second law states that the net force acting on an object equals the rate at which its momentum varies with time.

We know that,

Force=ma

F=ma

F=m((v-u)/t)

Given, t=1.5 second

Velocity v=0m/s at stand still

And mass m=1400kg

Speed u=27m/s

F₁.₅=1400((0-27m/s)/1.5)

F₁.₅=-25.2KN

Therefore, the force involved is F₁.₅=-25.2KN

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a car is towing a boat on a trailer. the driver starts from rest and accelerates to a velocity of 11.0 m/s in a time of 27.2 is. the combined mass of the boat and trailer is 514 kg. the frictional force acting on the trailer can be ignored. what is the tension in the hitch that connects the trailer to the car?

Answers

The correct answer is 207 Newton Tension in the hitch that connects the trailer to the car.

What is Newton's second law of motion?

The relationship between the force applied to an object with mass and its net acceleration is described by Newton's second law of motion. This relationship is mathematically precisely proportional, which means that a greater force will produce a greater acceleration.

Given,

Initial Velocity = u = 0 m/s

Final Velocity = v = 11 m/s

Time = 27.2 Sec (Unit of time is not given, we consider Second as unit of time)

Mass = 514 Kg i.e., combined mass of boat and Trailer

Force = Mass x Acceleration (As Acceleration= Velocity / Time)

         = 514 x (11 / 27.2) = 207 N

Hence Tension is 207 N in the hitch that connects the trailer to the car (Frictional force is neglected here).

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Bumps, Blemishes and Beyond
Imagine that you are working in either a cosmetic surgery clinic or a medical spa, and you
are meeting a client for the first time. They have come to you for a simple procedure, but
when you're doing the consultation with the person, you notice some suspicious-looking
lesions on their skin. You explain to the client that you are concerned about them, and you'd
like them to see their healthcare provider before you can proceed with treatment. They ask
you to write your findings down so that they can share them with their primary care provider.
You are going to search for images of two different types of lesions online and imagine them
to be what your client is presenting with. Using the terminology that you learned about
lesions, describe them in enough detail that someone could picture the areas in their mind
without the images. You will be expected to submit the images to the dropbox to support
your written work. You will need to include the type, shape, distribution, color, size, and
presence of drainage in your descriptions for it to be considered complete.

Answers

Benzoyle peroxide

This chemical helps to eliminate excess oil from the skin, kills acne-causing bacteria, and removes dead skin cells that can block pores. Products containing benzoyl peroxide are sold over the counter in strengths ranging from 2.5% to 10%.

Can blemishes be removed with Vaseline?

He continues by saying that the petroleum jelly itself is ineffective at treating the zit. By creating a seal over the skin, it actually aids in protecting the skin barrier as the zit heals.

Do skin imperfections disappear?

Scars from acne do not completely disappear on their own. With age, depressed acne scars frequently grow more obvious due to collagen loss in the skin. But there are numerous procedures that might lessen the prominence of acne scars. hyperpigmentation following inflammation or Within a few months, redness could naturally.

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while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever.

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Using the theories of fulcrum ,we got that it is true that while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever.

A fulcrum is the stationary point of a lever while a lever arms connect the fulcrum to the points on the lever arms that are actually vertically aligned with the centers of mass

Hence, while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever is true.

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(Complete question) is:

while doing pushups, the toes are the point around which rotation occurs. thus, they form the fulcrum of the lever, Select true : false.

A 70. 0-kg man jumps 1. 00 m down onto a concrete walkway. His downward motion stops in 0. 0200 seconds. If he forgets to bend his knees, what force is transmitted to his leg bones?.

Answers

The force transmitted to the man's leg bones during his downward motion is 14,945 N

State the equations of motion

The fundamentals of an object's motion, such as its position, velocity, or acceleration at different periods, are described by kinematics equations of motion or Newton’s equations of motions.

An object's motion in 1D, 2D, and 3D is controlled by these three equations of motion-

First law of equation: v = u + at

Second law of motion: s = ut + at^2/2

Third law of motion: v^2=u^2 + 2as.

In the question, the following informations are given,

Mass of the man, m = 70kg

Height the man jumps, h = 1.00 m

Time taken to reach the ground, t = 0.02 seconds

Using the 3rd equation of motion we find out the velocity with which the man comes down as-

v^2 = u^2 +2gh

v^2 = 0 + 2 x 9.8 x 1

v^2 = 19.6

v = √19.6

  = 4.27 m/s

Since force is determined by both time and acceleration therefore using the formula of force we find out the velocity as-

F = mass x acceleration

  = mass x velocity/time

  = 70 x 4.27/ 0.02

  = 14,945 N

Hence, the force transmitted to his leg bones is 14,945 N

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The weight of the atmosphere results in P_0 at the surface of the oil layer. Then the weight of the oil and the weight of the water combine to create the pressure at the bottom. Why does air pressure decrease with increasing altitude? (Select all that apply.) Less air above pushes down. Hot air rises. The weight of the air above is smaller. Colder air is less dense. There is more air below to push up more strongly. The weight of the air below is smaller. Use the worked example above to help you solve this problem. In a huge oil tanker, salt water has flooded an oil tank to a depth of h_2 = 4.75 m. On top of the water is a layer of oil h_1 = 8.40 m deep, as in the cross-sectional view of the tank as shown in the figure. The oil has a density of 0.700 g/cm^3. Find the pressure at the bottom of the tank. (Take 1,025 kg/m^3 as the density of salt water.) Calculate the pressure on the top lid of a chest buried under 3.80 meters of mud with density 1.75 x 10^3 kg/m^3 at the bottom of a 11.5-m-deep lake.

Answers

Air pressure decreases with altitude because the weight of the air below is smaller.The pressure at the bottom of the oil tank in the salt water is 2.05 x 10⁵ PaThe pressure on the top lid of the crate buried under the mud is 2.81 x 10⁵ Pa

The pressure at the bottom of the oil layer is given by,

P₁ = P₀ + ρgh₁ = (1.01 x 105 Pa) + (7 x 102 kg/m³) (9.8 m/s2) (8.4 m)

P₁ = (1.01 x 105 Pa) + (576.2 x 102 Pa)

P₁ = 1.58 x 105 Pa

Now, the pressure at the bottom of the tank which will be given using a formula, we have

P[tex]__{bottom}[/tex] = P1 + \rho g h2 = (1.58 x 105 Pa) + (1.025 x 103 kg/m3) (9.8 m/s2) (4.75 m)

P[tex]__{bottom}[/tex] = (1.58 x 105 Pa) + (47.7 x 103 Pa)

P[tex]__{bottom}[/tex] = 2.05 x 105 Pa

The pressure under mud will be given as

P₁ = P₀ + ρgh₁ = (1.01 x 105 Pa) + (1.75 x 103 kg/m3) (9.8 m/s2) (3.8 m)

P₁ = (1.01 x 105 Pa) + (65.1 x 103 Pa)

P₁ = 1.66 x 105 Pa

Now, the pressure on the top lid of a chest buried will be given as:

P[tex]__{top}[/tex] = P1 + \rho g h2 = (1.66 x 105 Pa) + (1.025 x 103 kg/m3) (9.8 m/s2) (11.5 m)

P[tex]__{top}[/tex] = (1.66 x 105 Pa) + (115.5 x 103 Pa)

P[tex]__{top}[/tex] = 2.81 x 105 Pa

The question is clearer in the picture

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while underway in fog you hear a whistle signal consisting of one prolonged blast followed immediately by two short blasts. which vessels are required to sound this signal in fog?

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In this case, blast at intervals of not more than two minutes is the signal which will be  used by power-driven vessels when underway. One long  blast plus two short blasts at intervals of not more than two minutes is the signal used by sailing vessels.

Why do vessels sound signals in fog?

Heavy fog leads to severe issues  that lead to reduction in the signal-to-noise ratio to levels which may even affect the communication system.  It leads to Restricted Visibility. Therefore various methods are used including Foghorns , fog signals that warn vehicles of hazards or rocky coastlines , and some other boats in foggy conditions.

Apart from this certain other methods including prolonged blast, fog signals, communication with the satellite can be used. The whole process is undertaken to reduce the amount of harmful impacts, issues that may be faced by the vessels

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Power-driven vessel underway making way are required to sound this signal in fog.

What is Power-driven vessel?The term "power driven vessel" means any vessel propelled by a machine. The term "sailing vessel" signal a vessel under sail, provided that no propulsion machinery is  used.Power-driven vessel include sailing vessels operated by engine power. Here are the lights you need: Red and green sidelights are visible from  at least two miles away on a dark, clear night.Mechanical vehicles in motion must give way to uncommand vehicles. For purposes of  Rule 3(b), the term "engine craft" means any machine-powered craft. Power-driven vessel means a vessel propelled by an engine, fuel, rocket, or similar device.

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5. the 1200-turn coil in a dc motor has an area per turn of 1.1x10-2 m2. the design for the motor specifies that the magnitude of the maximum torque is 5.8 nm. when the coil is placed in a 0.20-t magnetic field. what is the current in the coil?

Answers

The rotating equivalent of force is torque. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect.

A coil's torque is determined by:

equals niABsin

where I is the coil's current

Area of the coil equals A.

Magentic field = B

n is the coil's total number of turns.

and = angle between the field B and area vector A

The maximum torque would occur at 900, where sinθ = 1.

Maximum torque therefore equals niAB.

alternatively 5.8N-m = (1200) i(1.1x10-2m2) (0.20-T)

or the coil's current, I is 2.196A

The formula for torque is rF=rFsin(r). To put it another way, the cross product of the distance vector and the force vector, where 'a' is the angle between r and F, is what is known as torque (the distance between the pivot point and the place where force is applied).

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A baeball i thrown vertically into the air. What i the velocity and acceleration
of the ball at it highet point

Answers

The correct answer is velocity and acceleration at highest point of the ball is 0 m/s and 9.8 m/s² respectively.

How velocity and acceleration is related?

The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.

When a body is thrown vertically upward, it will travel along a route determined by the Earth's gravitational pull. Projectile motion is described as the motion. The gravitational pull and the air drag force both work against the ball when it is in motion.

Thus, velocity and acceleration at highest point will be 0 m/s and 9.8 m/s² respectively.

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✓= √219.8113) ✓=5.8 m/s RE=1/6/240)100.07²: / 44,946.75
Suzie Lavtaski (m=56 kg) is skiing at Bluebird Mountain. She is moving at 16 m/s across the crest of a ski hill
located 34 m above ground level at the end of the run.
+719
775
a. Determine Suzie's kinetic energy.
b. Determine Suzie's potential energy relative to the height of the ground at the end of the run.
c. Determine Suzie's total mechanical energy at the crest of the hill.
d. If no energy is lost or gained between the top of the hill and her initial arrival at the end of the run, then
what will be Suzie's total mechanical energy at the end of the run?
e. Determine Suzie's speed as she arrives at the end of the run and prior to braking to a stop.
• Audio Guided Solution
• Show Answer

Answers

a.) Kinetic energy = 1/2 × mv^2

=1/2 × 56 × 16^2

=7168 J

b.) Potential energy = m .g. h

=56 ×9.8 ×34

=18,678.24 J

c.) Total energy = kinetic energy + potential energy

=7168+18,678.24

=25,846.24 J

d ) Because no energy is lost or gained between the top of the hill and her initial arrival at the end of the run, then the total mechanical energy at the top of the hill or any place across the crest and the bottom of the crest .

Thus , Total mechanical energy = 25,846.24 J

e) As we know, total energy = potential energy + kinetic energy

but at the end of the run it's potential energy is zero.

So, Total energy = 1/2 ×m ×v^2

25,846.24= 1/2 ×56 ×v^2

V= 30.38 m/s

Hence, Suzie's speed as she arrives at the end of the run is 30.38 m/s

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a cart starting from rest rolls down a hill and at the bottom has a speed of 4 m/s. if the cart were given an initial push. so its initial speed at the too of the hill was 3 m/s. what would x be its speed at the bottom?

Answers

The correct answer of speed at 5 m/s at the bottom.

What is the connection between speed and kinetic energy?

A moving object's kinetic energy is inversely related to its mass and to the square of its velocity. Accordingly, an item with identical mass and speed will have twice the kinetic energy as one with double the mass and speed will have four times the kinetic energy.

When starting from rest, the cart’s PE is changed into KE:

Change in PE  =  Change in KE = 1/2m(4)²

When starting from 3 m/s, the

final KE is: KEf=     KEi+    Change in KE= 1/2 m(3) ²+ 1/2m(4) ²=  1/2 m(25)

=  1/2 m(5) ²

Speed is not the same as kinetic energy

Hence the answer of speed is 5 m/s.  

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p8.26 a coastal power plant takes in cooling water through a vertical perforated manifold, as in fig. p8.26. the total volume flow intake is 110 m/s. currents of 25 cm/s flow past the manifold, as shown. estimate (a) how far downstream and (b) how far normal to the paper the effects of the intake are felt in the ambient 8-m-deep waters.

Answers

Here, the sink strength is related to the volume flow to the depth into the flat surface.

m = 271 b

where,

Q→ Total volume flow rate

b→ Ambient Depth of water

Given, Q value as 110m²/s & bas 8m. Substitute, 110 m²/sec for a 8 m for b

Now,

m = 110 m = 2.1895 m²/s

a) The distance of the downward stream,

a = m/u∝

Here,

The velocity of water currents Substitute 0.25 m/s for U∝,

2.1895 m²/s for m

= 2.1895/0.25

a = 8.758 m

The distance of the downward stream a = 8.758 m.

b) The far normal to the paper the effect of intake left on each side.

L = Па

We have, a value of 8-758

So, substitute a = 8.758 frew above

L = π X 8.758 L = 27.5m

The for normal to the paper the effect of intake left on each side,

L =27.5m.

Towards or near the mouth of a stream swimming downstream. is two miles downstream.  At the end of the normal industrial process or at a post-manufacturing stage. Those that migrate downstream migrate from points further upstream towards the estuary.

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If another object (a can of beans) was dropped from 12 meters in free fall, how long will it take for that object to fall to the ground?

Answers

The time it takes the object to fall to the ground from a height of 12 m is 1.56 seconds.

What is time?

Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.

To calculate the time it takes the object to fall to the ground, we use the formula below.

Formula:

H = ut+gt²/2.............. Equation 1

Where:

H = Heightg = Acceleration due to gravityt = Timeu = Intial velecity

From the question,

Given:

u = 0 m/s (drop from height)g = 9.8 m/s²H = 12 m

Substitute these values into equation 1 and solve for t.

12 = (0×t)+(9.8t²)/29.8t² = 12×2t² = 12×2/9.8t² = 2.45t = √2.45t = 1.56 seconds.

Hence, the time it takes the object to fall to the ground is 1.56 seconds.

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if the tmt and e-elt get built as planned, what is one exciting potential discovery that astronomers hope to be able to make with them?

Answers

One exciting potential discovery that astronomers hope to be able to make with the E-ELT and TMT is life on other planets.

TMT and E-ELT are (currently) proposed telescopes. TMT (short for Thirty Meter Telescope) is a very large telescope composed of many small mirrors each about 1,4m in size. E-ELT (short for European Extremely Large Telescope) is going to be around 39m in diameter.

These proposed telescopes have very high resolution and sharper detection. They will be able to detect any exoplanet's atmosphere while it's transiting its star. In that detection, these telescopes may search for any biomarker molecules to detect the presence of life and habitability of the exoplanet.

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approximately how many times greater is the atmospheric pressure in jupiter's core than on earth's surface?

Answers

Approximately 100 million times greater is the atmospheric pressure in jupiter's core than on earth's surface.

The average  atmospheric pressure at sea level at 15 degrees Celsius is the unit of measurement known as an atmosphere. 1,013 millibars is equal to 760 millimeters of mercury, or 29.92 inches, in one atmosphere. When the bulb is pressed, air from the tube and bulb escapes as bubbles. The liquid's surface does, however, experience atmospheric pressure. The water moves inside the tube when we release the bulb. The pressure that the air around us puts on us is known as air pressure, whereas the pressure that the atmosphere puts on the earth is known as atmospheric pressure. Mercury barometer is used to measure atmospheric pressure, while tore gauges are used to measure air pressure. Since our internal pressure is roughly equal to the external atmospheric pressure, we are not affected by the pressure of the atmosphere around us.

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if the electric field emitted by a radio tower has an amplitude of 239 v/m, what is the amplitude of the corresponding magnetic field?

Answers

If the electric field emitted by a radio tower has an amplitude of 239 v/m,  the amplitude of the corresponding magnetic field will be H = 0.64 A/m

E / H = [tex]\sqrt{mu0 / epsilon 0 }[/tex]

238 / H = [tex]\sqrt{4*3.14*10^{-7} / 8.85 * 10^{-12} }[/tex]

238 / H = 374

H = 0.64 A/m

The amplitude of the corresponding magnetic field will be H = 0.64 A/m

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the work required to carry a particle with a charge of 6.0 c from a 5.0-v equipotential surface to a 6.0-v equipotential surface and back again to the 5.0-v surface is:

Answers

The work required to carry a particle with a charge of 6.0 c from a 5.0-v equipotential surface to a 6.0-v equipotential surface and back again to the 5.0-v surface is zero.

What are the properties of equipotential surface?

The electric field present around the surface is perpendicular to an equipotential surface.

Two equipotential surface can never met or intersect.

The direction is always from high potential to low potential.

If there is an isolated point charge, then the equipotential surface is a sphere.

Equipotential points are those points in an electric field that has same electric potential. If these points are connected by any line or curve, it is said to be equipotential line and the surface on which it lies is the equipotential surface.

The work done between two points in an equipotential surface is always zero. It is calculated in the following manner:

If any charge moves from point Va to Vb in an equipotential surface, then work done in moving charge

W= q0 (Va- Vb)

As (Va- Vb) = 0 so the total work is equal to zero.

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two objects in thermal equilibrium with a third object are in thermal equilibrium with each other."" which law of thermodynamics is this?

Answers

The zeroth law of thermodynamic states that if two systems are in thermal equilibrium in equilibrium. with a third system, they are. with each other".

One of the four fundamental laws of thermodynamics is the zeroth law. It offers a stand-alone definition of temperature that excludes the second law's concept of entropy. Ralph H. Fowler created the law in the 1930s, many years after the first, second, and third laws had gained widespread acceptance.

According to the zeroth law, if two thermodynamic systems are in thermal equilibrium with one another and with a third system separately, then all three systems are in thermal equilibrium with one another.

The mathematical representation of thermodynamics depends on the zeroth law. It mathematically transforms the relationship between systems' thermal equilibrium into an equivalence relation, which can symbolize the equality of a particular quantity related to each system.

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the speed of the incoming water is 15 cm/s and the cross-sectional area of the hose carrying the water is 4.0 cm2. 1) determine the time required for a 30-l container to be filled with water. (express your answer to two significant figures.)

Answers

The time required to fill a 25 liter container  with water is 8.3 minutes.

What is time?Time can be described in mathematics as an ongoing and continuous series of events that take place one after another, from the past through the present, and into the future. The duration of events or the gaps between them can be measured, compared, or even ordered using time.It is possible to define time as the dimension on which any system evolves.Its length can be expressed in terms of milliseconds, seconds, minutes, hours, days, weeks, months, and years.It is a quantity that is a part of several measurements that are used to compare the length of events or the gaps between them, to compare how long they last, to order events, and to measure how quickly things change in the real world or in our conscious experience.

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Complete the following statement: when a net torque is applied to a rigid object, it always produces a.

Answers

When a net torque is given to a rigid object, it always causes an angular velocity change.

What exactly is meant by torque?

Torque is defined as a force that causes an object to revolve around an axis. In linear kinematics, force causes an item to accelerate; in rotational kinematics, torque causes an object to accelerate. Torque is a vector quantity.

Based on the vector values involved, we must predict what will happen when a net torque is applied to a rigid object.

As a result, when a net torque is applied to the rigid item, the rate of rotation changes.

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borgmann provides the example of running as a focal practice and distinguishes it from running on a treadmill in what significant way?

Answers

Borgmann provides the example of running as a focal practice and distinguishes it from running on a treadmill in that running (outside) engages the mind and body, while running on a treadmill only engages the body.

Focal practice is human activity that demands patience, skill, and attentiveness. They make life feels meaningful not because of what they produce, but because of what they are. These activities are not accomplished effortlessly. They require focus, engagement, and commitment to achieve their goal.

Some examples of focal practice activities are meditation, gardening, hiking, preparing a meal, tending a fire, and learning a musical instrument.

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on its highest power setting, an 880-watt microwave oven heats a bowl of spaghetti. (a) find the intensity of the microwaves, given they are absorbed over a circular area 16 cm in diameter. w/m2 (b) what is the peak electric field strength of the microwave? v/m (c) what is its peak magnetic field strength? t

Answers

The intensity is 4400 w/m2 , strength of the microwave is 1820 V/m  and magnetic field strength is606.66× 10-8 T .

What is intensity?

The power transferred per unit area is known as the intensity or flux of radiant energy, where the area is measured on a plane perpendicular to the direction of the energy's propagation. It is measured in watts per square metre (W/m2) in the SI standard.

a.) Average intensity=I

I=P/A where, P= power

A= area of the circle

= π r2

As we are given the diameter and r= d/2 , so area= π d2/4

d= 16cm= 0.16 m

area = 3.14× (0.16)×2 /4 = 0.20

P= 880W

I= 880/0.2= 4400 w/m2

b.) I =0.5 c e0 Emax2

Where c = speed of light = 3 108 m/s

e0= 8.85×10-12

Emax= peak of electric field =√ 2I / c ×e0

= √2×4400/(3×108)×8.85 ×10 -12

⇒1820 V/m  

Bmax= peak of magnetic field strength

Bmax = Emax/ c

          ⇒1820/ 3× 108

          ⇒606.6 ×10 -8 T

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some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. what force (in n) must a 64.0 kg grouper exert to stay submerged in salt water if its body density is 1003 kg/m3?

Answers

The force (in n) must a 64.0 kg grouper exert to stay submerged in salt water if its body density is 1003 kg/m3 will be 15.6 newtons.

The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. Therefore, we have the mass of the fish times g times the ratio of densities minus 1, which is 85.0 kilograms times 9.80 newtons per kilogram times 1.025 times 10 to the 3 kilograms per cubic meter (density of seawater) divided by 1015 kilograms per cubic meter (density of the fish) and equals 8.21 newtons.

F= d/a

=1003 /64

=15.6 N

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A 1.5 kg mass is pulled at a constant speed with a force of 6N. What is the constant of friction between the surface and the mass

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The constant of friction between the surface and the mass of 1.5 kg being pulled with a force of 6 N is 0.408.

What is friction?

Friction is a force that oppose the motion between two bodies in contact.

To calculate the constant of friction between the surface and the mass, we use the formula below.

Formula:

μ = F/mg.......... Equation 1

Where:

μ = Contant of frictionF = Forcem = Massg = Acceleration due to gravity.

From the question,

Given:

F = 6 Nm = 1.5 kgg = 9.8 m/s²

Substitute these values into equation 1

μ = (6)/(1.5×9.8)μ = 6/14.7μ = 0.408.

Hence, the constant of friction between the surface and the mass is 0.408.

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if buoyant force push things upwards, why don't hot air balloons and planes get pushed into outer space

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Answer:

I think that's because the force of gravity is greater than the buoyant force, and for the hot air balloons, they can increase/decrease the temperature of the air in the balloon in order for it to rise/fall for more control. For planes, they use aerodynamics as well as the help of a couple of engines to thrust the plane forward. I hope this helps.

If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant? express your answer in kilogram-meters squared per second squared.

Answers

The net torque applied to the item equals the rate of change of angular momentum.

The net torque is equal to the weight "mg" times the angle between the weight's line of action and the origin (x dL/dt = mgx = mgrCos) (36.8)

Alternatively, it is composed of the weight perpendicular to the position vector times its magnitude, r dL/dt = mgCos(36.8).

clearly the same equation.

Just enter the values because everything is already provided. Finding L's rate of change does not require knowledge of particle velocity.

what is angular momentum?

The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.

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The net torque is equal to the weight "mg" times the angle between the weight's line of action in  angular momentum and the origin (x dL/dt = mgx = mgrCos) (36.8)

What is angular momentum?

The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.

The net torque applied to the item equals the rate of change of angular momentum. Alternatively, it is composed of the weight perpendicular to the position vector times its magnitude, r dL/dt = mgCos(36.8).

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in what direction will the seesaw rotate, and what will the sign of the angular acceleration be? in what direction will the seesaw rotate, and what will the sign of the angular acceleration be? the rotation is in the clockwise direction and the angular acceleration is positive. the rotation is in the clockwise direction and the angular acceleration is negative. the rotation is in the counterclockwise direction and the angular acceleration is positive. the rotation is in the counterclockwise direction and the angular acceleration is negative.

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The rotation is in the counterclockwise direction and the angular acceleration is positive.

What is angular acceleration?

The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.

A rigid body's points all share the rotating velocity and acceleration.

Therefore, The rotation is in the counterclockwise direction and the angular acceleration is positive.

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The angular acceleration is positive and the rotation is counterclockwise.

Angular acceleration:

In physics, angular acceleration is the temporal rate of change of angular velocity. Because there are two types of angular velocity, spin angular velocity as well as orbital angular velocity, there are two types of angular acceleration, spin angular acceleration as well as orbital angular acceleration. Spin angular acceleration is the angular acceleration of a rigid body as to its centre of rotation, whereas orbital angular acceleration is the angular acceleration of a point particle around a fixed origin. Therefore, = d d t.

A rigid body's points all share the rotating velocity and acceleration.

Therefore, The rotation is in the counterclockwise direction and the angular acceleration is positive.

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What type of interference occurs when the crests of one wave overlaps with the crests of another wave?.

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Constructive interference occurs when crests of one wave overlap the crests of the other wave.

What are the properties of constructive interference?

The two waves must travel through the same medium along with the  properties of the waves must be the same. They should have same amplitude and wavelength. The amplitude of the wave is the height of the crest or trough.  Upward displacement occurs when the waves undergo constructive interference; hence, the upward displacement of the medium is greater than the displacement of the two interfering pulses.

It occurs when the phase difference between the two waves is an even multiple of π (180°).

Example:  When we see two speakers right next to each other, we can experience constructive interference when the distance from each speaker to the observer is the same. The path difference should be equal to zero.

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a pressure sensor was used to measure the unsteady pressure in a cylinder. the sensor output was acquired for 8 seconds at a rate of 269 hz and spectral analysis was performed using fft. is zero padding or truncation needed? type your answer as a number where: 1

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In the analysis of measuring the unsteady pressure in the cylinder using the FTT method, a zero-padding required to 2¹²= 4096 or a truncation required to 2¹¹ = 2408 points.

Answer 1

The "Fast Fourier Transform" (FFT) is an important measurement method in the science of audio and acoustic measurements. It converts the signal into individual spectral components and thus provides frequency information about the signal. FFT is used for fault analysis, quality control, and machine or system condition monitoring.

Find the total data points:

N = Frequency x time

N = (259) (8)

N = 2152

The total number of data points is 2152

It is required to use the powers of 2 data points in the FTT algorithm. The nearest powers of 2 values for data points are:

2¹¹= 2408

2¹² = 4096

Therefore, there is a zero-padding required to 2¹²= 4096 or a truncation required to 2¹¹ = 2408 points.

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