In a football game the running back is running up the field. He starts from rest and runs 4 seconds with an acceleration of 1.3m/s. What is the magnitude of his displacement

Answers

Answer 1

We are given:

initial velocity (u) = 0 m/s

time (t) = 4 seconds

acceleration (a) = 1.3 m/s²

displacement (s) = x m

Solving for the displacement:

from the second equation of motion

s = ut + 1/2 at²

replacing the variables with the given values

x = (0)(4) + 1/2 (1.3)(4)(4)

x = 1/2 * 20.8

x = 10.4 m


Related Questions

In June 21 are there more hours of daylight in San Francisco or the equator explain

Answers

Answer:

There would be more hours of sunlight at the equator

One car is traveling north at 80 km/h. A second car is traveling south at 80 km/h. Both cars have the same velocity
True
False

Answers

True because it is the same amount and same speed but just different directions and people

Answer: True

Explanation:

How frequently do most coastal areas experience high tides?

Answers

It doesn't matter where you are.  "Tides" happen twice (hi - lo - hi - lo) in about 24 hours and 50 minutes.  Anywhere.

If it doesn't do two complete cycles in 24 hours 50 minutes, then it's not tide.

Answer:

Twice a day

Explanation:

EDGE

When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racquet exerts a force of 443 N on the ball for 4.30 ms, giving it a final velocity of 45.7 m/s. Using these data, find the mass of the ball.

Answers

Answer:

0.041kg

Explanation:

Step one:

given data

initial velocity u= 0m/s

Force F= 443N

time t= 4.3 ms= 0.0043seconds

final velocity v= 45.7m/s

Step two:

Required

mass m

we know that the expression for impulse is given as

Ft=mv

make m subject of the formula

m=Ft/v

substitute we have

m=443*0.0043/45.7

m=1.90/45.7

m=0.04kg

The mass of the ball is 0.041kg

A soccer ball is kicked from the ground with a velocity of 30m/s directed at an angle of 45 degrees with respect to horizontal. Resolve this velocity vector into horizontal and Vertical components

Answers

Answer:

Vertical = 21.2 m/s

Horizontal = 21.2 m/s

Explanation:

For the vertical component:

sin (45) = v/30

sin (45) x 30 = v

21.2 m/s = v

For the horizontal component:

cos (45) = h/30

cos (45) x 30 = h

21.2 m/s = h

Which of these results in kinetic energy of an object? position motion mass volume

Answers

Answer:

Motion

Explanation:

I just took the test :)

P.S. Can I please get a brainliest (look at my account to see what i do with the points :p)

Kinetic energy is the energy that set an object or body in motion. Motion result in kinetic energy.

What is kinetic energy?

Kinetic energy is the energy required to set an object in motion.

It is the energy present in a moving body. This involve the movement of an object from one place to another as it is found in a moving ball or car.

Therefore, motion result in kinetic energy.

Learn more about kinetic energy from the link below.

https://brainly.com/question/8101588

How can a systematic error affect the reported data?

Answers

The decimal can be in the wrong place

Answer:

A systematic error may result in a high degree of precision.

A systematic error will likely result in poor accuracy

Explanation:

It's what my work gave me when I got it wrong

Dalton’s theory states that atoms are the smallest possible parts of elements. In a chemical reaction, atoms will

rearrange and form new substances with new properties.
change form into completely new atoms with new properties.
be destroyed and remade into new substances.
be turned completely into energy.
An atom’s emission of light with a specific amount of energy confirms that

Answers

Answer:

A.REARRANGED AND FORM NEW SUBSTANCES WITH NEW PROPERTIES

Explanation:

A force of 200N acts at an angle of 140° with respect to the positive x- direction. determine the components of this force in the x- and y- direction​

Answers

Answer:

The components of the force in the x and y-direction are -153.21 N and 128.56 N respectively.

Explanation:

Rectangular components of a vector

Given a vector [tex]\vec F[/tex] as an ordered pair (f,θ), where f is the magnitude of the vector and θ is the angle it forms with the positive x-direction, the rectangular components of the vector are given by:

[tex]F_x=f.\cos\theta[/tex]

[tex]F_y=f.\sin\theta[/tex]

The force of f=200N forms an angle of θ=140°. The components of the force are:

[tex]F_x=200.\cos 140^\circ[/tex]

Calculating:

[tex]F_x=-153.21~N[/tex]

[tex]F_y=200.\sin 140^\circ[/tex]

[tex]F_y=128.56~N[/tex]

The components of the force in the x and y-direction are -153.21 N and 128.56 N respectively.

Exercise to solve

1) Determine the magnitude of the electrostatic attractive force between two charges of 2 µc and -6 µC respectively if they are separated by a distance of 2 mm

2) Determine the magnitude of the electrostatic attractive force between two charges of 6 µC and -8uC respectively if they are separated by a distance of 8 cm

Briefly explain in a minimum of five lines and a maximum of 8 lines​

Answers

number 1 !! hope that helps

Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2 as F1 = 45 N 70degree And F2 = 75 N , 20 Degree (a) Find the magnitude and direction of the force that third person should exert to stop this cart. You can ignore the effects of friction. (b) If the third person exerts the force found in part (a), the cart accelerates at 200 m/S2 in the (+) x-direction. What is the weight of the cart​

Answers

Answer:

a)  F₃ = 109.5 N ,     θ₃ = 38.35,  b)   m = 0.429 kg

Explanation:

For this force addition exercise, let's decompose the forces into a coordinate system

strength 1

          cos 70 = F₁ₓ / F₁

          sin 70 = [tex]F_{1y}[/tex] / F₁

          F₁ₓ = F₁ cos 70

         F_{1y} = F₁ sin 70

          F₁ₓ = 45 cos 70 = 15.39 N

          F_{1y} = 45 sin70 = 42.29 N

Strength 2

         cos 20 = F₂ₓ / F₂

         sin 20 = F_{2y} / F₂

         F₂ₓ = F₂ cos 20

         F_{2y} = F₂ sin20

         F₂ₓ = 75 cos 20 = 70.48 N

         F_{2y} = 75 sin 20 = 25.65 N

a) in the first part we are asked to find the magnitude of force 3 so that the body is in equilibrium

       

X axis

         ∑ Fₓ = 0

          F₁ₓ + F₂ₓ + F₃ₓ = 0

          F₃ₓ = - F₁ₓ - F₂ₓ

          F₃ₓ = - 15.39 - 70.48

          F₃ₓ = - 85.87 N

Y Axis

         ∑ F_{y}  = 0

         F_{1y} + F_{2y} +F_{3y}  = 0

         F_{3y} = - F_{1y} -F_{2y}

         F_{3y} = - 42.29 - 25.65

         F_{3y} = - 67.94 N

the magnitude of this force can be found using the Pythagorean theorem

         F₃ = √ (F₃ₓ² + F_{3y}^2)

         F₃ = √ (85.87² + 67.94²)

         F₃ = 109.5 N

The direction of this force can be found using trigonometry

          tan θ =  F₃ = [tex]F_{3y}[/tex] / F₃ₓ

          θ₃ = Tan⁻¹ (67.94 / (85.87))

          θ₃ = 38.35º

since the two vectors are negative this angle is in the third quadrant, measured from the positive side of the x axis is

          θ₃ = 180 + 38.53

          θ₃ = 218.35º

b) I think you have an error in your statement, we have two possibilities:

1) If we eliminate the third force, what is the mass

it should say: "if we apply the third force force ...", they ask that we find the masses of the vehicle, let's use Newton's second law

X axis

       F₁ₓ + F₂ₓ = m a

       15.39 + 70.48 = m 200

        m = 85.87 / 200

        m = 0.429 kg

       

2) If the force F3 is in the first quadrant

        F1x + F2x + F3x = m a

         

        m = (15.39 + 70.48 + 85.87) / 200

        m = 0.8587 kg

A horizontal spring required a force of 1.0 N to compress it 0.1 m. How much work is required to stretch the spring 0.4 m?

Answers

Answer:

0.5J

Explanation:

given data

Force applied F= 1N

extension e= 0.1m

let us find the spring constant first

applying

F=ke

k=F/e

k=1/0.1

k=10N/m

Step two:

Required is the work done

we know that the expression/formula for the work done by a spring is given as

Wd=1/2kx^2

x=0.4m

substitute

Wd= 1/2*10*0.4^2

Wd=0.5*10*0.16

Wd=0.5J

A scientific ____ must be testable and capable of being proven false.

Answers

Answer:

hypothesis

Explanation: a hypothesis is a guess or a thought meaning it can be true but it might not be

Answer:

capable of being proven wrong.

Explanation:

You can't not be right all the time

If a point on the edge of a wheel 2 m in radius is accelerating at 2 m/s2, what is the angular acceleration of the wheel?

Answers

Answer:

[tex]\alpha =1\ rad/s^2[/tex]

Explanation:

It is given that,

The radius of a wheel, r = 2 m

Tangential acceleration of the wheel, [tex]a=2\ m/s^2[/tex]

We need to find the angular acceleration of the wheel. We know that the relation between angular and tangential acceleration is given by :

[tex]a=\alpha r\\\\\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{2}{2}\\\\\alpha =1\ rad/s^2[/tex]

So, the angular acceleration of the wheel is [tex]1\ rad/s^2[/tex].

When the force at the ends of a bar pushes rather than pulls, the bar experiences

Answers

Answer:

Compression

Explanation:

Force is defined as a push or pull on any object. Now, Force could either be in Compression or tension which are the push and pull that allow overhead bridges to remain erect after many years.

Now, Compression is a force that compresses objects together. Meanwhile, Tension is the opposite of compression and it is the force that pulls objects apart.

When an astronaut with a mass of 55 Kg goes from Earth to the Moon, how much does their weight change? Answer in N OR in Pounds. gmoon= 1.62m/s2, gearth = 9.8m/s2

Answers

PHYSICS

mass = 55 kg

gravitation earth = 9,8 m/s²

gravitation moon = 1,62 m/s²

Weight Change = ______?

Answer :

1) Earth

[tex]w = m \times g[/tex]

w = 55 × 9,8

w = 539 N

2) Moon

[tex]w \: = m \times g[/tex]

w = 55 × 1,62

w = 89.1 N

Assuming a release of 173 MeV per fission reaction, calculate how many reactions must occur per second to produce a power output of 170 MW .

Answers

Answer:

The number of reaction that must occur is 6.142 x 10¹⁸ reactions / second

Explanation:

Given;

energy released by the fission reaction, E = 173 MeV

power output, P = 170 MW

Convert the energy released by the fission reaction to Joules;

= 173 x 10⁶ x 1.6 x 10⁻¹⁹ J = 2.768 x 10⁻¹¹ J

Convert the output power to joules per second;

= 170 x 10⁶ J/s

The number of reactions per second that must occur is given by;

[tex]= \frac{170*10^6 \ J/s}{2.768*10^{-11} J/reaction} = 6.142 *10^{18} \ reaction/second[/tex]

Therefore, the number of reaction that must occur is 6.142 x 10¹⁸ reactions / second

What is a half-life?
A. the amount of time it takes for 25% of a radioactive isotope sample to decay
B. half of the time it takes for an organism to die
C. the amount of time it takes for a radioactive isotope to become stable
D. the amount of time it takes for half of a radioactive isotope sample to decay

Answers

Answer:

option D is correct

Explanation:

Answer: “ D ”

the amount of time it takes for half of a radioactive isotope sample to decay

The diagram shows our solar system. name planet 4

Answers

Answer:

mars

Explanation:

it is the fourth planet of the solar system

it would be mars, it’s goes mercury, venus, earth, mars, jupiter, saturn, uranus, neptune

I WILL MARK YOU AS BRAINLIEST IF RIGHT The fastest pitch ever recorded in MLB was thrown by Aroldis Chapman at 5 points 105.1 mph . If the 0.145 kg baseball accelerated 96 m/s / s , how much force did Chapman apply to the ball? Round your answer to the nearest whole number

Answers

Answer: The force was 13.92 Newtons.

Explanation:

First, let's recall the second Newton's law:

The net force is equal to the mass times the acceleration, or:

F = m*a

where:

F = force

m = mass

a = acceleration.

When the player hits the ball with the bat, he applies a force that accelerates the ball for a small period of time, that increases greatly the speed of the ball.

In this case, we know that:

the mass of the ball is 0.145 kg

The acceleration of the ball is 96m/s^2

Then we can input those values in the above equation to find the force.

F = 0.145kg*96m/s^2 = 13.92 N

The force was 13.92 Newtons.

) A friend of yours complains that he often has lower back pain. One day while he picks up a package, you notice he bends at his hips rather than keeping his back straight and bending his knees. Assume he pivots at the hips so that his spine is horizontal. His back muscles then exert a force at 48 cm away from the hips at 13.5 degrees above the horizontal (directed slightly up and to the left in the picture shown). The weight of his upper body is 560 N, and his center of mass is 38 cm from the hips. Draw a force diagram of the spine. What total force is exerted by the back muscle when he picks up a 10 kg package at 82 cm from the hips? Extra credit: Find the force exerted by the hips on the spine/pelvis

Answers

Answer:

Explanation:

Please see the figure attached for free body diagram .

Taking torque about the hip joint ,

560 x 38 + 100 x 82 = F sin13.5 x 48

21280 + 8200 = 11.2 F

F = 2632.14 N .

Force exerted by the hip on the spine = 2632.14 N .

Which atmospheric gas is used by plants and given off by animals? A. Carbon dioxide. B. Nitrogen C. Oxygen D. Argon​

Answers

Answer:

A

Explanation:

Answer:

i think it is B

Explanation:

plants and humans have a cycle thing humans breath out carbon dioxide and plants absorb that and released it as oxygen and animals and humans breath in

An object has an acceleration of 18 m/s/s. If the mass of this object were tripled (with no change in its net force), then its new acceleration would be

Answers

Answer: 6

If the mass of this object were tripled (with no change in its net force) =>Its acceleration will decrease by 3 times

=> the new acceleration would be: 18/3 = 6(m/s²)

Explanation:

A car travels at a constant speed up a ramp making an angle of 28 degrees with the horizontal component of velocity is 40 kmh^-1, find the vertical and horizontal component of velocity.

Answers

Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

[tex]v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h][/tex]

In order to find the vertical component, we must use the sine function of the angle.

[tex]V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h][/tex]

Which are true of gamma radiation?
Check all that apply.
A. It has no charge.
B. It has a mass of 0.0005 amus.
C. It causes transmutation.
D. It usually occurs with other types of radioactive decay.

Answers

Answer:

B and D

Explanation:

Why does the weather change during an eclipse? help me

Answers

Answer:

here`s your answer

Winds often slow down during an eclipse as the atmosphere temporarily settles. Heating causes the atmosphere to mix and bubble, just like a pot of water on the stove. As it warms, the water level in the pot rises because warm objects, including water, expand. In the case of the atmosphere, it also expands when heated.

Explanation:

how much heat is necessary to warm 500g of water from 20°c to 65°c​

Answers

Explanation:

so sorry

don't know but please mark me as brainliest please

for f(x)=2x1 and g (x)=x2-7,find (f-g)(x)

Answers

Your f(x) value is a little ambiguous, so I am assuming the value of f(x)=2x-1

Answer:

(f-g)(x) = 2x-x²+6

Explanation:

f(x)=2x-1

g(x)=x²-7

(f-g)(x)=f(x)-g(x)

          = (2x-1)-(x²-7)

          = 2x-1-x²+7

          = 2x-x²+6

Therefore,

(f-g)(x) = 2x-x²+6

Why does everyone trust gravity?(Explained)(Will Give Brainliest)

Answers

Answer:

Because gravity makes you able to stand and move around

Gravity can't fail

it can fail only in astronuts camp and in space

Explanation:

✌❤

Yh....

:)

Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50meters above the surface.

1080 J
2 00 J
1 00 J
10. J

Answers

Answer:

1080J

Explanation:

Given parameters:

Mass of object  = 2kg

Velocity  = 10m/s

Height  = 50m

Unknown:

Total energy  = ?

Solution:

The total energy of the moving object is obtainable by summing the kinetic and potential energy;

       Total energy  = P.E + K.E

P.E is the potential energy  = mgh

K.E is the kinetic energy = [tex]\frac{1}{2}[/tex]mv²

 Now insert the parameters and solve;

    Total energy  = mgh +  [tex]\frac{1}{2}[/tex]mv²

m is the mass

g is the acceleration due to gravity

h is the height

v is the velocity

  Total energy  = (2 x 9.8 x 50) +  ( [tex]\frac{1}{2}[/tex] x 2 x 10²)

  Total energy  = 980 + 100 = 1080J

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