In a two-tail hypothesis test, if the calculated test statistic (z-statistic) is -1.58 and the level of significance is used, the decision will depend on comparing the z-statistic to the critical values of the standard normal distribution corresponding to the desired level of significance.
Explanation: In a two-tail hypothesis test, the null hypothesis assumes that there is no significant difference between the sample and population parameters. The alternative hypothesis, on the other hand, suggests a significant difference. The level of significance, denoted as α, determines the critical values that divide the rejection and non-rejection regions.
If the calculated test statistic, in this case -1.58, falls within the rejection region, which is determined by the critical values, we reject the null hypothesis. If the test statistic falls outside the rejection region, we fail to reject the null hypothesis.
To make a decision, we compare the z-statistic to the critical values corresponding to the level of significance. If the z-statistic of -1.58 falls outside the critical values, it means it is not extreme enough to reject the null hypothesis, and we fail to reject it. However, if the z-statistic falls within the critical values, we reject the null hypothesis in favor of the alternative hypothesis.
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555555555555 plzzz help
[Help asap, question is in image, will mark brainliest]
Answer:
V = 339.12
Step-by-step explanation:
Volume of a cone:
V = πr²(h/3)
Given:
r = 6
h = 9
Work:
V = πr²(h/3)
V = 3.14(6²)(9/3)
V = 3.14(36)(3)
V = 113.04(3)
V = 339.12
Drag the correct steps into order to solve the equation 5x5 + 5 = 10 for x
Answer:
x = 1
Step-by-step explanation:
5x^5 + 5 = 10
Start the solution by subtracting 5 from both sides:
5x^5 = 5
Dividing both sides by 5 yields x^5 = 1.
Taking the 5th root of both sides, we get x = 1
On January 1, 2020, Maris Enterprises issued 9%, 5-year bonds with a face amount of $800,000 at par. Interest is payable annually on January 1.
Answer:
A. Jan 1
Dr cash $800,000
Cr Bonds payable $800,000
B. Dr Interest expense $72,000
Cr Interest Payable $72,000
Step-by-step explanation:
Preparation of the entries to record the issuance of the bonds and the first annual interest accrual on December 31
A. Preparation of the entries to record the issuance of the bonds
Jan 1
Dr cash $800,000
Cr Bonds payable $800,000
(Being to record issuance of the bonds)
B. Preparation of the Journal entry to record first annual interest accrual on December 31
Dec 31
Dr Interest expense $72,000
Cr Interest Payable $72,000
($800,000*9%)
(Being to record the first year interest expense accrued)
I got correct on this question but I wrote some of the numbers in a different order, is it okay if I wrote it in a different order on every question similar like this?
Answer:
however it works for you along as you get the right answer
Step-by-step explanation:
Answer:
Yeah you will most likely get the same answer
Step-by-step explanation:
as long as you don't mix up (for this example of course) the service call fee (which is the constant) and the fee for each hour of labor (the coefficient of the variable), you are good
Has anyone done the Alg1B Portfolio - Unit 6 for connections academy
Answer:
I have
Step-by-step explanation:
Amad collected 42 plates in February for a project he plans to make. He had collected a total of 91 plates by the end of March. Which equation can be used to find the number of plates Amad collected in March? A. 42 * p = 91 b. P - 91 = 42 c. 91 / p = 42 d. P + 42 = 91
Answer:
Option D: P + 42 = 91
Step-by-step explanation:
Plates collected in February = 42
Total Plates collected = 91
Plates in February + Plates in March = total plates
42 + P = 91 or
P + 42 = 91
Part A:
A group of students are going on an overnight camping trip. One tent holds 7 students, and 4 tents hold 28 students. Determine how many students fit in six, nine, and ten tents.
Part B:
Create a table of values to represent the relationship between the number of tents and the number of students.
Part C:
Write the equation to represent the relationship between the number of tents and the number of students.
Part A:
Six Tents Holds 42 People
Nine Tents Holds 63 People
10 Tents Holds 70 People
Part B:
Number of tents|||Number of people
1 |||7
6 |||42
9 |||63
10 |||70
Part C:
Tents=x
1x=7 people
PLZ HELP ME, ASAP I WILL CROWN BRAINLIEST!!!!
Find the height of a prism whose volume is 108 cm3
and the area of the base is 15 cm2.
Answer:17
Step-by-step Experlation: The volume is 108 cm. 3,2,15.a square prism with a base edge of 9.5 inches and a height of 17 ... amount for a landowner
please help help help help !!!!! ASAP
Factorise
3у^2 - 54y + 243
Answer:
3(y-9)^2
Step-by-step explanation:
Answer:
See in the picture mark brainliest if correct
Let C denotes any closed contour lying in the open disk |z| < 3. Consider the function f(z) : = (8²-16)5* Calculate the contour integral of the function f(z) over the contour C. 2622
The contour integral of the function f(z) over the contour C is zero because the function f(z) is analytic inside and on the contour C.
How to determine contour integral?In this case, the function f(z) = (8² - 16)5 = 64 × 5 = 320 is a constant function. Constant functions are always analytic within their domain. Therefore, f(z) is analytic within the region enclosed by the contour C.
According to Cauchy's Integral Formula, the contour integral of a function over a closed contour C is given by:
∮C f(z) dz = 2πi × sum of the residues of f(z) at its isolated singularities within C.
Since f(z) is a constant function, it does not have any singularities. Therefore, all the residues of f(z) are zero.
Hence, the contour integral of f(z) over the contour C is zero:
∮C f(z) dz = 0.
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Find the radian measure of an angle of -340
Answer:
-1.889 rad
Step-by-step explanation:
180 degrees = [tex]\pi[/tex]
-340 x [tex]\frac{\pi }{180}[/tex]
-340[tex]\pi[/tex]/180
-34[tex]\pi[/tex]/18
-1.889 rad
Please help!! I'm super confused:(
Answer: Singing
Mode: The value that appears the most in a list
Also by the way, the frequency table is most likely just a table of every single value and how many times they appear in the list. Its super easy all you have to do is count them
It is assumed that the average Triglycerides level in a healthy person is 130 unit. In a sample of 20 patients, the sample mean of Triglycerides level is 122 and the sample standard deviation is 20. Calculate the test statistic value.
The test statistic value can be calculated using the formula (sample mean - population mean) / (sample standard deviation / sqrt(sample size)).
To calculate the test statistic value, we use the formula (sample mean - population mean) / (sample standard deviation / sqrt(sample size)). In this case, the sample mean is 122, the population mean is 130, the sample standard deviation is 20, and the sample size is 20.
Test Statistic Value = (122 - 130) / (20 / sqrt(20))
= (-8) / (20 / 4.47)
= -8 / 4.47
≈ -1.79
Therefore, the test statistic value is approximately -1.79.
The test statistic value (t) measures the difference between the sample mean and the assumed population mean in terms of the standard error. It helps us determine the likelihood of obtaining such a sample mean if the population mean is indeed equal to the assumed value.
In this case, the test statistic value is -1.79, indicating that the sample mean is 1.79 standard errors below the assumed population mean of 130. The negative sign indicates that the sample mean is lower than the assumed value.
To determine the significance of this difference, we would compare the test statistic to critical values from the t-distribution or calculate the p-value associated with the observed test statistic. This would allow us to make conclusions about the statistical significance of the difference between the sample mean and the assumed population mean.
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Max is mixing oil and gas for his moped. He uses 3.75 liters of gas and 1.5 liters of oil. How many liters of gas are used per liter of oil?
Answer:
2.5 liters of gas is used with per liter of oil
Step-by-step explanation:
Max is missing oil and gas for his moped.
Amount of gas used = 3.75 liters
Amount of oil required = 1.5 liters
Ratio in which gas and oil are mixed = [tex]\frac{3.75}{1.5}[/tex]
= [tex]\frac{2.5}{1}[/tex]
That means if he uses 1 liter of oil then the gas required for the mixture = 2.5 liters
Therefore, 2.5 liters of gas is used per liter of oil.
Determine volume of a cylindre r2 + y2 = 4 inside a sphere r2 + y2 +22 = 16
The volume of the cylinder inside the given sphere is 8 cubic units.
How to determine the volume of the cylinder inside the given sphere?To determine the volume of the cylinder inside the given sphere, we need to find the limits of integration and set up the integral.
Let's analyze the equations:
Cylinder equation:[tex]r^2 + y^2 = 4[/tex]
Sphere equation: [tex]r^2 + y^2 + 2^2 = 16[/tex]
From the equations, we can see that the cylinder is centered at the origin (0, 0) with a radius of 2 and an infinite height along the y-axis. The sphere is centered at the origin as well, with a radius of 4.
To find the limits of integration, we need to determine where the cylinder intersects the sphere. By substituting the cylinder equation into the sphere equation, we can solve for the values of r and y:
[tex](2^2) + y^2 + 2^2 = 16\\4 + y^2 + 4 = 16\\y^2 = 8[/tex]
y = ±√8
We can see that the cylinder intersects the sphere at y = √8 and y = -√8. Since the cylinder has infinite height, the limits of integration for y will be from -√8 to √8.
Now we can set up the integral to calculate the volume of the cylinder:
V = ∫∫∫ dV
= [tex]\int_0^ 2 \int_{\sqrt -8} ^ {\sqrt 8}\int _{\sqrt-(16 - r^2 - y^2)} ^{\sqrt (16 - r^2 - y^2)} dz dy dr[/tex]
Since the integrand is equal to 1, we can simplify the integral to:
V = [tex]\int_0 ^ 2 \int _{-\sqrt8} ^ {\sqrt8} 2\sqrt{(16 - r^2 - y^2)}[/tex] dy dr
Evaluating this integral will give us the volume of the cylinder inside the sphere.
To evaluate the integral and calculate the volume, we can integrate the given expression with respect to y first and then with respect to r.
[tex]\int_0 ^ 2 \int _{-\sqrt8} ^ {\sqrt8} 2\sqrt{(16 - r^2 - y^2)}[/tex]
Let's begin by integrating with respect to y:
[tex]\int_{-\sqrt8} ^ {\sqrt8} 2\sqrt(16 - r^2 - y^2) dy[/tex]
We can simplify the integrand using the trigonometric substitution y = √8sinθ:
dy = √8cosθ dθ
y = √8sinθ
Replacing y and dy in the integral:
[tex]\int _{-\pi /2} ^{\pi/2} 2\sqrt(16 - r^2 - (\sqrt 8sin\theta)^2) \sqrt 8cos\theta d\theta[/tex]
= 16[tex]\int _{-\pi /2} ^ {\pi /2} \sqrt(1 - (r/4)^2 - sin^2\theta)[/tex]cosθ dθ
To simplify the integral further, we can use the trigonometric identity [tex]sin^2\theta + cos^2\theta = 1:[/tex]
16[tex]\int _{-\pi /2} ^ {\pi /2} \sqrt(1 - (r/4)^2 - sin^2\theta)[/tex]cosθ dθ
= 16 [tex]\int _{-\pi /2} ^ {\pi /2} \sqrt(r^2/16)[1 - cos^2\theta][/tex]cosθ dθ
= 4r[tex]\int _{-\pi/2} ^ {\pi/2}[/tex] sinθ cosθ dθ
= 4r [tex][ -cos^2\theta/2[/tex] ]| [-π/2 to π/2 ]
= 4r [ [tex]-cos^2(\pi/2)/2 + cos^2(-\pi/2)/2[/tex] ]
= 4r [ -1/2 + 1/2 ]
= 4r
Now, we can integrate with respect to r:
[tex]\int_0 ^ 2[/tex] 4r dr
= 2[tex]r^2[/tex]| [0 to 2]
= 2[tex](2^2 - 0^2)[/tex]
= 2(4)
= 8
Therefore, the volume of the cylinder is 8 cubic units.
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Assume f : A → B and g : B → A are functions such that
f ◦ g = idB . Then g is injective and f is surjective.
f: A → B and g: B → A are functions such that f∘g=idB. It is true that g is injective and f is surjective.
Let y1, y2 ∈ B such that g(y1) = g(y2).
We need to show that y1 = y2.
To do this, we use the following facts;
f(g(y1)) = y1 (since f∘g=idB).
f(g(y2)) = y2 (since f∘g=idB).
Now, f(g(y1)) = f(g(y2)).
Since f is a function, g(y1) = g(y2) ⟹ f(g(y1)) = f(g(y2)).
So, we have y1 = y2 as required. Therefore, g is injective.
Let b ∈ B be arbitrary. We need to show that there exists an element a ∈ A such that f(a) = b.
Since f∘g=idB, we know that for any element y ∈ B,f(g(y)) = y.
Now, we can use b ∈ B to obtain the element g(b) ∈ A.
Then, f(g(b)) = b as required. Therefore, f is surjective.
So, the functions f and g satisfy the following properties:
if f: A → B and g: B → A such that f∘g=idB, then g is injective and f is surjective.
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According to a recent survey, women chat on their mobile phones more than do men (CNN.com, August 25, 2010). To determine if the same patterns also exist in colleges, Irina takes a random sample of 40 male students and 40 female students in her college. She finds that female students chatted for a sample average of 820 minutes per month, with a sample standard deviation of 160 minutes. Male students, on the other hand, chatted for a sample average of 760 minutes per month, with a sample standard deviation of 240 minutes. It is not reasonable to assume equal population variances. Test the hypothesis whether women chat on their phones more than men at the 5% significance level.
A report on a study in which each of 6 workers was provided with both a conventional shovel and a shovel whose blade was perforated with small holes.
Worker: 1 2 3 4 5 6
Conventional: .0011 .0014 .0018 .0022 .0017 .0016
Perforated: .0011 .0010 .0019 .0013 .0011 .0015
Do these data provide convincing evidence that the mean energy expenditure using the conventional shovel exceeds that using the perforated shovel? Test the relevant hypotheses using a significance level of 0.05?
Based on the given data, the hypothesis test results show that there is not enough evidence to conclude that women chat on their phones more than men at the 5% significance level.
For the hypothesis test comparing the chat times of male and female students, we can use a two-sample t-test since we have two independent samples with unequal variances. The null hypothesis (H0) assumes that there is no difference in chat times between men and women, while the alternative hypothesis (Ha) suggests that women chat more than men.
Calculating the test statistic and degrees of freedom using the provided sample data and formulas, we find that the test statistic is approximately 1.03. Comparing this with the critical value at a 5% significance level (t-critical value), we find that it does not fall in the rejection region.
Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim that women chat on their phones more than men at the 5% significance level.
For the second scenario comparing energy expenditure using conventional and perforated shovels, we would need more information, such as the sample sizes, means, and standard deviations, to perform the relevant hypothesis test. The provided data alone does not allow us to conduct the hypothesis test.
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please help :c
Angela bought a total of 3 dozen cookies for Easter. Each cookie was 0.65 (INCLUDING TAX!) Of the cookies, 3/4 of them were shaped like Easter eggs. What was the cost of the Easter egg shaped cookies?
please add the work along with the question
Answer: $17.55
Step-by-step explanation:
36 x 0.65 = $23.40 total for all cookies
($23.40/1) x (3/4) = (70.2/4)
70.2 divided by 4 = $17.55
or
$23.40 x .75 = $17.55
Which sequences are geometric? Check all that apply. –2, –4, –6, –8, –10, … 16, –8, 4, –2, 1 –15, –18, –21.6, –25.92, –31.104, … 4, 10.5, 17, 23.5, 30, … 625, 125, 25, 5, 1, …
Answer:
16,-8,4,-2,1
-15,-18,-21.6,25.92,-31.104...
625,125,25,5,1
Step-by-step explanation:
Answer: 16, –8, 4, –2, 1. has a common ratio,r = (-1/2)
-15, –18, –21.6, –25.92, –31.104 has a common ratio, r = (1.2)
625, 125, 25, 5, 1 has a common ratio, r= (1/5)
Step-by-step explanation: just took the test
Ben weighs 41.9 kg. His older brother weighs 57.6 kg. How much more does his older brother weigh?
Step-by-step explanation:
[tex]57.6 - 41.9 = 5.7[/tex]
Question 6: Integration (12 marks) a. Which of the following definitions best describes the result of integrating a positive function f(x)? A The value of f(x) when == 0 B. The area between the curve of f(x) and the x-axis. C. The difference between the minimum of f(x) and the maximum of f(x). D. The gradient of f () at the point where x = 0. (1 mark) b. Which of the following is the general antiderivative of the function f(x) = 23+8x?? A 10x4 + 24x2 B. 2x° (x2 + 4) C. 2x6 + 8x4 D. 32° +2x4+C (1 mark) Which of the following statements is true for an odd function 9(2) ? 1 C. A. B. В S 0-2500 S = g(x) = 0 5 (2) = 0 Soo-a C. D (1 mark) d. By using the substitution 4x + 2 = u, show that the expression below is true. 1 +1 dx +C (4x + 2) 1600 + 8 (5 marks) e. Find the volume of the solid obtained when the area bounded by the curves below is rotated about the x-axis. Use the result shown in part (e) to assist you. Sa+gads 1 O x 1 = 0 (4 marks)
(a) The area between the curve of f(x) and the x-axis best describes the result of integrating a positive function f(x).
(b) The general antiderivative of the function f(x) = 23 + 8x is 2x³ + 4x² + C.
Hence, option (C) is the correct answer.
(c) An odd function satisfies f(-x) = -f(x). Thus, for an odd function f(x), the integral from -a to a is equal to zero because f(x) and -f(x) will have opposite signs, and the areas will cancel each other out. Hence, option (A) is the correct answer.
(d) To use the substitution u = 4x + 2, we need to find dx in terms of du.du = d/dx (4x + 2) dx= 4dxIntegrating both sides gives ∫du/4 = ∫dx/ (4x + 2). Therefore, the given expression becomes, ∫ 1/(4x + 2) dx = (1/4)∫du/u= (1/4)ln|u|+C= (1/4) ln|4x + 2| + C. Hence, (1/4) ln|4x + 2| + C is true by using the substitution 4x + 2 = u.
(e) The given function can be graphed as below: [tex]\int_0^1 (x^2 + 1) dx = \frac{4}{3}[/tex] We need to use the disk method to find the volume of the solid generated by rotating the region bounded by the curves about the x-axis. We need to consider an elemental area, find its volume, and integrate it over the region of interest. We know that the volume of the disk is given by V = πr²h, where r is the radius and h is the height of the disk. Let us consider an elemental area, A of the region rotated about the x-axis. If we rotate this area through a small angle, θ, then the area of the sector generated is given by d A = πr²dθ/2π = r²dθ/2. The radius of the disk is x, and the height is given by g(x) - f(x). Thus, V = ∫[g(x) - f(x)]²πx²dx.In this case, we have g(x) = x + 1 and f(x) = x². Substituting these values, V = π∫(x + 1 - x²)² x² dx. The limits of integration are from 0 to 1.
Therefore, V = π∫[x⁴ - 2x³ + x² + 2x + 1]dx= π[x⁵/5 - x⁴/2 + x³/3 + x² + x]₀¹= π[(1/5) - (1/2) + (1/3) + 1 + 1]
The volume of the solid obtained is, V = π[(8/15) + 2] = (14π/15).
Hence, the volume of the solid obtained when the area bounded by the curves below is rotated about the x-axis is (14π/15).
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PLEASEEEEE ILL MARK BRAINIEST
Answer:
5. 18 that is what i think the answers are
6. 13.75
5 2 11 8 35 32
Evaluate the function at the given value.
h(x) = 1/3.6^x
what is h(2)?
Answer:
h(x)=6^x/3 is what I got hope I could help
simplify this number 300mm:9m
Answer:
1 : 30
Step-by-step explanation:
300mm:9m
We need to change the meters to mm
1 meter is 1000 mm
so 9 m is 9000 mm
300mm:9000mm
Divide both sides by 300
300mm/300 : 9000/300
1 : 30
Mrs, carp's class has 11 boys and 17 girls. what is the probability that she will randomly chose a girl first and then a boy?
Possible answers ⇒
0.18
0.24
0.33
0.48
WILL GIVE BRAINLIST
Find the volume and total area of the right circular cone.
To find the volume and total area of the right circular cone, we will use the formulas below. Volume of the right circular cone: $$V = \frac{1}{3}πr^2h$$
Total surface area of the right circular cone:$$A = πr^2 + πrl$$, Where r is the radius, l is the slant height and h is the height of the cone.π (pi) is a mathematical constant that is approximately equal to 3.14159 and is used to calculate the circumference and area of a circle. The radius of the right circular cone is 3.5 cm and its height is 7 cm. To calculate the slant height, we will use the Pythagorean theorem which states that the square of the hypotenuse (l) is equal to the sum of the squares of the other two sides:$$l^2 = r^2 + h^2$$$$l = \sqrt{r^2 + h^2} = \sqrt{3.5^2 + 7^2} \approx 7.98\ cm$$
Volume of the right circular cone:$$V = \frac{1}{3}πr^2h = \frac{1}{3}π(3.5)^2(7) \approx 89.75\ cm^3$$. Total surface area of the right circular cone:$$A = πr^2 + πrl = π(3.5)^2 + π(3.5)(7.98) \approx 91.86\ cm^2$$. Hence, the volume of the right circular cone is approximately 89.75 cm³ and the total surface area is approximately 91.86 cm².
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Find the value of x.
hello i know its wrong but lol. i tried to help.
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Answer:
One solution
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