If there are 10.00 moles of ascorbic acid(C6H8O6), what is the mass of ascorbic acid?

Answers

Answer 1

Given

no of moles = 10 mol

we know that mass of 1 mole ascorbic acid is 176.12,

mass id 10 mole of ascorbic acid = 10× 176.12

= 1761.2 g

Answer - 1761.2 grams


Related Questions

sam was given the following equation to balance: H2O->H2+O2. she balanced it as follows: 2H2O->H2+O2. what did she do wrong? what is the correct way to balance the equation?

Answers

Answer:

2H2 in products

Explanation:

she should have added another 2 in H2

The edited equation does not balance the number of hydrogens. The correct balanced equation for the given reaction is written as follows:

[tex]\rm 2H_{2}O \rightarrow 2H_{2} +O_{2}[/tex].

What is balanced chemical equation?

The balanced chemical equation of a reaction represents the perfect stochiometric coefficients of all the reactants and products. Thus, each elements in the reaction have to be equal in both side.

According the mass conservation law, the total mass of the reactants is equal to the total mass of the products. Thus, all elements have to balanced on each side.

When water dissociates into hydrogen and oxygen molecules, 2moles of water undergoes dissociation to give two moles of H2 and one mole of O2. Thus the balanced equation is:

[tex]\rm 2H_{2}O \rightarrow 2H_{2} +O_{2}[/tex]

To find more on balanced reactions, refer here:

https://brainly.com/question/22064431

#SPJ2

I am one percent away from failing. I just need help. No false answers
How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?

Answers

Answer:

I did it in steps in the picture I just hope it helps you to understand:)

I'll give brainless! no l!nks!!!

1. Imagine a very warm 60 degree day in January with a steady rain. What type of air mass would you expect to be bringing in this weather pattern?

2. Imagine a very cold 20 degree day in January with lots of blue sunny skies. What type of air mass would you expect to be bringing in this weather pattern?

Answers

Answer:

Maritime tropical air mass

Continental polar air mass

please help asap i will mark you as brainly and give u 10 points ( don’t mind the answer i accidentally clicked )

Answers

Answer:

Negative 5

Explanation:

I am not 100% sure btw

i don’t know negative 5

what does Avogadro's law state and what is the formula​

Answers

The law is approximately valid for real gases at sufficiently low pressures and high temperatures. The specific number of molecules in one gram-mole of a substance, defined as the molecular weight in grams, is 6.02214076 × 1023, a quantity called Avogadro's number, or the Avogadro constant.

Answer:

Hello There!!

Explanation:

The answer is that it states that under the same pressure and temperature conditions, equal volumes of all gases contain the same number of molecules.

Formula:Vn=k

hope this helps,have a great day!!

~Pinky~

Which pair of formulas represents the empirical formula and the molecular formula of a compound?

Answers

Answer:

CH2O and C6H12O6

Explanation:

To find an empirical formula, take a molecular formula and divide the subscript of each element by the greatest common factor of all the subscripts. In this case, the only pair that works is CH2O,C6H12O6, which can be verified by dividing the coefficients of the molecular formula by 6.

Why might metamorphic rocks show signs of blending and distortion?

Answers

Answer:

because of heat and pressure

Which process requires energy for a nonspontaneous redox reaction to occur?

Answers

Answer: Electrolysis

Explanation: ‍♀️

Two hundred liters of helium at 2.00 atm and 28.0 °C is placed into a tank with an internal pressure of 5.92 atm. Find the volume of the helium
after it is creleased into the tank when the temperature of the tank.remains 28.0°C.
liters (Round to three sig figs)

Answers

Answer:

27*6 dkfkdh hshsnnsbssshs ss. hhshsns svs s ssjssgsyz

Explanation:

ysgshssbs

If I have 1.9 moles of gas held at a pressure of 5 atm and in a container with a volume of 100 liters, what is the temperature of the gas? 3205K

Answers

Answer:

T = 3206.89 K

Explanation:

Given that,

Number of moles, n = 1.9 moles

Pressure, P = 5 atm

Volume, V = 100 L

We need to find the temperature of the gas. Let the temperature is T. We know that,

PV = nRT

Where

R is gas constant, R = 0.08206 L-atm/mol-K

Put all the values,

[tex]T=\dfrac{PV}{nR}\\\\T=\dfrac{5\times 100}{1.9\times 0.08206 }\\\\T=3206.89\ K[/tex]

So, the temperature of the gas is 3206.89 K.

significant figures to 2.3 x 4.50

Answers

Answer:

10.35= 4 sig figs but change it to 2 since it's 2.3 is the lowest number

10.

hope this helps

have a good day :)

Explanation:

What type of element is fluorine

Answers

Answer:

It is a halogen element

Explanation:

hope this helps

have a great day/night

HI! I REALLY NEED HELP WITH THIS, THANK YOU!

Answers

ig The right answer is -Give the reaction more time.

2Cr^3 + 3Zn(s) -> 2Cr(s) + 3Zn^2 + (aq) which reactant is reduced and which is oxidicided

Answers

Answer:

Cr is oxidised

and

Zn is reduced

[ Reduced reactant ] :

Cr^( + 3 ) + 3 e^( - 1 ) ===》 Cr^( 0 )

_____________________________

[ Oxidicided reactant ] :

Zn^(0) ===》Zn^( + 2 ) + 2 e^( - 1 )

21. What type of cells are found on the retina and provide signals to the brain about incoming light?
A photoreceivers
B optic cells
C photoreceptors
D retina cells​

Answers

the answer to this question is C

Answer:

Explanation:

have a good day

All of the following elements are metals EXCEPT?
A. Br B. Co C. Cu D. Zn

Answers

Answer:

Br

Explanation:

Help? s/o to itsdevilsj754

Answers

Explanation:

A geological process where materials of Earth are transported from one place to another by natural forces like wind or water is called erosion.

When materials of Earth are deposited over a certain landmark due to transportation by natural forces then this process is called deposition.

The four major causes of erosion and deposition are as follows.

Gravity - Force that is responsible for attracting an object towards the center of Earth.

Running water - Water present in the rivers, oceans or lakes is moving from one place to another. Also, along with it carries pebbles or other materials.

Wind Waves - This is basically air and it keeps on moving from one place to another all the time. Wind waves tend to carry dust particles or other materials along with it.

Glaciers - When a mass of ice that is formed by accumulation and compaction of snow over mountains or around the poles tends to move slowly is called glaciers.

08.04 MC) An unknown solution has a pH of 7.2. Which of these chemicals is likely to cause the greatest decrease in the pH of the solution when added to the solution? (5 points) a HF b KOH c NH3 d HNO3

Answers

Answer:

HNO3

Explanation:

i have the test

The correct answer that will decrease the PH is ( HNO3)

Since the unknown solution is containing a pH of 7.2, it means it is more basic not acidic, then to make it have  decrease in PH, then acidic substance needs to be added to it so as to reduce the PH from 7.2

KOH : potassium hydroxide is a base, if it is added to the substance, it will increase in PH value

NH3 : Ammonia is a base, if it is added to the substance, it will increase in PH value

HNO3 : Trioxonitrate (v) acid is an acid , adding it to the substance will make the PH to be acidic hence decrease in PH

When a substance  is neither acidic nor basic it can be regarded as   neutral.

The pH scale gives the measurements of  how acidic or basic a particular substance is.

The pH scale can be given in the  ranges starting from 0 to 14.

A pH of 7 is  considered neutral.

Therefore, decrease in PH can be achieved by adding acidic substance.

Learn more at : https://brainly.com/question/11936640?referrer=searchResults

What is the correct name for the chemical formula N408?

Answers

Answer:

molar mass (molar weight)

Explanation:

Which oxide is covalent?
A. AsO2 B. K2O
C. CuO D. ZnO

Answers

Answer:

A.

Cu Zn K is are metals which form ionic bond with oxygen

pls help me guys please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please​

Answers

5) B

6) C

7) B newland, law of octaves

8) A)

Anthony needs to make a solution with a concentration of 2.5m. He begins with 2.0 iters and a 8.0M solution. What final volume does he need. Tally and solve.

Answers

Answer:

The final volume is 6.4 L.

Explanation:

Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

Ci: initial concentration Vi: initial volume Cf: final concentration Vf: final volume

In this case:

Ci: 8 M Vi: 2 L Cf: 2.5 M Vf: ?

Replacing:

8 M* 2 L= 2.5 M* Vf

Solving:

[tex]Vf=\frac{8 M* 2 L}{2.5 M}[/tex]

Vf=6.4 L

The final volume is 6.4 L.

does neutrons have a orbit outside the atom​

Answers

Answer:

No because it's located inside the nucleus of the atom

hope this helps

have a good day :)

Explanation:

The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm without changing the temperature, what would be the new volume of the gas

Answers

Answer:

[tex]V_2=10mL[/tex]

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

[tex]P_2V_2=P_1V_1[/tex]

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL[/tex]

Regards!

How many grams of magnesium are in sample containing 9.12+ 10 ^23atoms

Answers

Answer: There are 1.51 moles present in [tex]9.12 \times 10^{23}[/tex] atoms.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in one mole of every substance.

Hence, moles present in [tex]9.12 \times 10^{23}[/tex] atoms are calculated as follows.

[tex]Moles = \frac{9.12 \times 10^{23}}{6.022 \times 10^{23}}\\= 1.51 mol[/tex]

Thus, we can conclude that there are 1.51 moles present in [tex]9.12 \times 10^{23}[/tex] atoms.

How can the coefficients in a balanced chemical reaction be used to convert from moles of a reactant to moles of a product?

Answers

The coefficients in a balanced equation can be used as molar ratios, which can act as conversion factors to relate the reactants to the products. These conversion factors state the ratio of reactants that react but do not tell exactly how much of each substance is actually involved in the reaction.

which statement is an example of diffusion
Answer
(A) A kitchen towel soaks up some split milk
(B) ice cream melts in a warm room
(C) pollen from flowers is blown by the wind
(D) the smell of cooking spreads through a house ​

Answers

D is the answer I think

Answer:

(C) pollen from flowers is blown by the wind.

I think this is the correct answer friend

How many liters are 1.20 g of oxygen?

Answers

Answer:

The required volume is 0.84 L

Explanation:

Given,

Mass of O2 gas = 1.20 g

We know,

At STP, molar volume of all gases is 22.4 L

and Molar mass of O2 gas is 32 g

Now,

Number of moles = mass/molar mass

                              = 1.20/32

                              = 0.0375

Again,

At STP,

Number of moles = Volume/Molar volume

or, Volume = Number of moles X Molar Volume

or Volume = 0.0375 X 22.4

∴ Volume = 0.84 L

So, the required volume is 0.84 L

A metal object with mass of 29.0 g is heated to 97.0 °C and then transferred to an insulated container containing 95.8 g of water at 20.5 °C. The water temperature rises and the temperature of the metal object falls until they both reach the same final temperature of 23.7 °C. What is the specific heat of this metal object? Assume that all the heat lost by the metal object is absorbed by the water.

Answers

Answer:

0.603J/g°C is the specific heat of the metal object

Explanation:

To solve this question we must know the heat given by the metal is equal to the heat absorbed by the water. The change in heat follows the equation:

Q = m*S*ΔT

Where Q is heat in Joules, m is the mass of the substance, S its specific heat and ΔT change in temperature

The equation to solve the problem is:

m(Object)*S(Object)*ΔT(Object) = m(Water)*S(Water)*ΔT(Water)

Where:

m(Object) = 29.0g

S(Object) = ??

ΔT(Object) = (97.0°C - 23.7°C = 73.3°C)

m(Water) = 95.8g

S(Water) = 4.184J/g°C

ΔT(Water) = (23.7°C - 20.5°C = 3.2°C)

29.0g*S(Object)*73.3°C = 95.8g*4.184J/g°C*3.2°C

S (Object) * 2125.7g°C = 1282.6J

S(Object) = 0.603J/g°C is the specific heat of the metal object

3. How is the equilibrium position of this reaction affected
by the following changes?
2802 (g) + O2 (g) <-------------→ 2 S03(g) + heat
a. Lowering the temperature.
b. Decreasing the pressure
c. Removing oxygen
d. Adding sulfur trioxide (SO3).

Answers

Answer:

Explanation: a) Reaction is exothermic because heat is released

                       If temperature is lowered, amount of products is increased,

                      equilibrium transfers to right

b) If pressure decreases, equilibrium transfers to direction in which amount of gas moles is greater, also in left (reactants)

c) If Oxygen is removed, reaction which produces more oxygen is favoured, also balance changes to reactansts (left)

d) Adding product causes equilibrium transfer to left (reactansts)

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