If f(x) = 6x³ + 5x, g(x) = 3x² +5, and h(x) = 9x² - 8, What is the degree of f(g(h(x)))?

a)2
b)3
c)7
d) 12

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

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that is :-

[tex]{ \boxed{✠\underline{ \boxed{ \sf{ \red✰Cost \: price =100 \times \frac{selling \: price}{100 + profit\%} }}}✠}}[/tex]

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[tex]\rm{➾x = 100 \times \frac{690}{100 + 15}} \\\rm{➾x \frac{100 \times 690}{100 + 15}~~~~~~~~~~~~~~~ } \\ \rm{➾x = \frac {100 \times \cancel{ 690}}{ \cancel{115}}}~~~~~~~ \\ \rm{➾x = 100 \times 6}~~~~~~~~~~~~~~~ \\ \rm{➾x =106}~~~~~~~~~~~~~~~[/tex]

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➣ Hence "x" (Cost price) of the item

[tex] \large{ \boxed{✠\underline{ \boxed{ \sf{ Rs.106\green✓}}}✠}}[/tex]

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Hope it helps !

Answer:

4

Step-by-step explanation:

(3 × 14) × 3 = 126

7 × 18 = 126

Boubacar will have to increase each dimension by 4 ft so that its area is triple.

The area of a rectangle is given by -

A[R] = L x B

where -

L is Length of rectangle

B is Breadth or width of rectangle.

Given is a deck that measures 3 feet by 14 feet. Boubacar wants to increase each dimension by equal lengths so that its area is tripled.

Assume that he increases the dimensions by x ft.

Initial Area = [A] = 3 x 14 = 42 ft².

Final Area = [A'] = 3[A] = 3 x 42 = 126 ft²

Initial dimensions = (L x B) = 3 feet x 14 feet

Final dimensions = (L' x B') = (3 + x) × (14 + x)

Now -

(L' x B') = 126

(3 + x)(14 + x) = 126

3(14 + x) + x(14 + x) = 126

42 + 3x + 14x + x² = 126

x² + 17x - 84 = 0

Solving the equation, we get -

x = 4  [ non negative number ]

Therefore, Boubacar will have to increase each dimension by 4 ft so that its area is tripled.

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Answer-10x+46

Step-by-step explanation: hope this helps

Answer: Answer-10x+46

Answer:

Part A:

In order to find a coterminal angle, or angles of the given angle, simply add or subtract 360 degrees of the terminal angle as many times as possible.

Part B:Simply put, coterminal angles start at 0° and end at the same place, though in different directions and multiple times around (you're probably going to want to make that sound a little more formal). Since each time around is 360°, boom

Part C: 75° is in Quadrant II, right? If I go one more time around, 75 + 360 = 435°. I can also go "backward. Starting at 0 and going clockwise, I'm going 75 fewer degrees than all the way around, so 360-75 = 285° but since I'm going "backward" 75 - 360 = -285°. One more is on you.

Step-by-step explanation:

Answer:

First answer:

A

Second answer:

I think A

Answer:

A and B

Step-by-step explanation:

1

the volume (V) of a rectangular prism is calculated as

V = lwh ( l is length, w is width, h is the height )

  = Bh ( B is the area of the base )

2

the volume of a cone is [tex]\frac{1}{3}[/tex] the volume of a cylinder with the same base area (B) and height (h)

[tex]\dfrac{5-i}{4+3i}=\dfrac{(5-i)(4-3i)}{(4+3i)(4-3i)}=\dfrac{20-15i-4i-3}{16+9}=\dfrac{17-19i}{25}=\dfrac{17}{25}-\dfrac{19}{25}i[/tex]

Answer:

3x³ + 12x

Step-by-step explanation:

3x(x² + 4)

3x³ + 12x

Step-by-step explanation:

once the level of medicine reaches a value, where 30% are 23mL (so, whatever is lost, is immediately replaced again), that is then the long run value for the amount of the drug in the patient's body.

so,

30% = 23 mL

1% = 30%/30 = 23/30 = 0.766666666...

100% = 1%×100 = 0.766666666... × 100 = 76.666666...

so, once the level reaches 76.666666... mL in the body, it will remain constant, as the daily filtered out 30% are 23 mL, and the daily add-on is also 23 mL.

so, the answer is

76.667 mL

Answer: 16-30 because it has the most numbers in between

Step-by-step explanation: brainliest?

The interval that has the highest frequency is 16-30. That is option A.

To determine the class interval with the highest frequency, the following steps should be taken as follows;

The class interval taken are:

0-15 = 13, 14

16-30= 17,28,22,25

31-45= 37,33,41

46-60 = 0

61-75 = 61

Therefore,the class interval with the highest number of animals weight = 16-30.

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Answer:

  B; (-4, -8)

Step-by-step explanation:

The given forms of the equation are standard form, vertex form, and intercept form.

__

It is not surprising that the vertex form yields the vertex most quickly.

  B) m(x) = 2(x +4)² -8

Compare this to the generic vertex form ...

  f(x) = a(x -h)² +k . . . . . . . . . vertex (h, k)

We see that the vertex is (h, k) = (-4, -8).

Answer:

-18 + x = 11

x = 29

Step-by-step explanation:

To solve this, you can use the formula of a + b = c

[tex]-18 + x = 11\\-18 = 18\\11 + 18 = 29\\x = 29[/tex]

Answer:

29

Step-by-step explanation:

Your equation can be -18+x=11. Since we don't know the number, we can use x. We are trying to find out a number that when it's added to -18, the answer will be 11.

Now, we solve the equation:

-18+x=11

x=11+18

x=29. Answer

To check this answer:

we can use our equation and substitute 29 for x.

-18+x=11

-18+(29)=11

11=11.

They are equal. Therfore, the answer is correct.

Answer:

x=3

13x-5=1+11x

(ADD 5 TO BOTH SIDES)

13x-5+5=1+11x+5

SIMPLIFY

13x=11x+6

SUBTRACT 11x FROM BOTH SIDES

13x-11x=11x+6-11x

SIMPLIFY

2x=6

DIVIDE BOTH SIDES BY 2

2x/2 = 6/2

SIMPLIFY TO GET FINAL ANSWER

x=3

Answer:

x = -20/9

Step-by-step explanation:

First we need to distribute this equation 4(4x+1) = 3x-4(6-x)+8. After distributing we get 16x+4 = 3x-24+4x+8. Next we add like terms to get 16x+4 = 7x-16. Now subtract 7x on both sides to get 9x+4 = -16. Now subtract -4 on both sides to get 9x = -20. Now divide by 9 on both sides to get x= -20/9.

Hope that helps! :)

I assume by f¹, you actually mean f⁻¹ as in the inverse of f. I also assume you are asked to find f(x) (as in the inverse of f⁻¹) and f⁻¹(4).

Given that

[tex]f^{-1}(x+2) = \dfrac{x-1}{x+1}[/tex]

with x ≠ 1, we can find f⁻¹(x) by replacing x + 2 with x :

[tex]f^{-1}(x + 2) = \dfrac{x-1}{x+1} = \dfrac{(x+2) - 3}{(x + 2) - 1} \implies f^{-1}(x) = \dfrac{x-3}{x-1}[/tex]

Then when x = 4, we have

[tex]f^{-1}(4) = \dfrac{4-3}{4-1} = \dfrac13[/tex]

Of course, we also could have just substituted x = 2 into the definition of f⁻¹(x + 2) :

[tex]f^{-1}(4) = f^{-1}(2+2) = \dfrac{2-1}{2+1} = \dfrac13[/tex]

To find f(x), we fall back to the definition of an inverse function:

[tex]f^{-1}\left(f(x)\right) = x[/tex]

Then by definition of f⁻¹, we have

[tex]f^{-1}\left(f(x)\right) = \dfrac{f(x)-3}{f(x)-1} = x[/tex]

Solve for f :

[tex]f(x) - 3 = x (f(x) - 1)[/tex]

[tex]f(x) - 3 = x f(x) - x[/tex]

[tex]f(x) - x f(x) = 3 - x[/tex]

[tex](1 - x) f(x) = 3-x[/tex]

[tex]f(x) = \dfrac{3-x}{1-x} = \dfrac{x-1}{x-3}[/tex]

There are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have the total number of students = 18

The number of ways the club send 4 students to the next debate is:

= C(18, 4)

[tex]= \rm \dfrac{18!}{4!(18-4)!}[/tex]

= 3060

Thus, there are 3060 ways the club send 4 students to the next debate if there are 18 students on the debate club.

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i cant help you with that bc there is no graph so...

Answer:

Rhombus

Step-by-step explanation:

Sides are parallel but have no right angles.

Answer:

  parallelogram

Step-by-step explanation:

Opposite sides of the figure have the same slope (0 or 5/2), so are parallel. The product of the slopes is not -1, so the angles are not right angles. Adjacent sides are different lengths, so the figure is not a rhombus.

__

The figure is a parallelogram.

_____

Additional comment

The slope is the "rise" (change in y-coordinate) of the segment divided by its "run" (change in x-coordinate). The left and right sides have a rise of 7-2 = 5, and a run of 6-4 = 2 -0 = 2. Their slope is 5/2.

The top and bottom sides have a rise of 0, so a slope of 0.

When the product of the slopes of different segments is -1, those segments are perpendicular. The perpendicular to a horizontal line has "undefined" slope, so the product of the slopes would be (0)×(undefined). This is a special case of perpendicular lines where the product of slopes is not -1.

The given figure is quadrilateral, parallelogram, and a  rhombus but not a square. So brett is not correct.

A square is a quadrilateral with all the sides equal and all the four sides are perpendicular to each other.

We know that it is a quadrilateral as a quadrilateral is having four sides and the sum of the angles is 180 degrees.

The given figure is a parallelogram as opposite sides of the figure are parallel and equal.

The given figure is a rhombus as all the sides are parallel and equal.

The given figure can not be a square as in the square all the four sides are perpendicular to each other.

Therefore given figure is quadrilateral, parallelogram, and a  rhombus but not a square. So brett is not correct.

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Answer:

x = -2

Step-by-step explanation:

Given :

[tex]\frac{8}{x+1} = \frac{-16}{x+4}[/tex]

=============================================================

Cross multiplying the terms :

⇒ 8 (x + 4) = -16 (x + 1)

⇒ 8x + 32 = -16x - 16

⇒ 24x = -48

⇒ x = -2

Answer:

[tex](x+1-i)(x+1+i)[/tex]

Step-by-step explanation:

[tex](x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2[/tex]

Answer:

11,800 lb

Step-by-step explanation:

dnt worry i got my wayz :)

Answer:

11,800 lbs

Step-by-step explanation:

5.9x2,000=11,800

Answer:

2 months

Explanation:

50 - 40 = 10

25-20 = 5

10/5 = 2

The months for which Joey have to belong to each before the costs are the same are 2 months.

Equation modelling is a method of writing a mathematical relation from a mathematical statement for mathematical analyses of the problem given.

Given is different fees structure of two gyms →  Gym A has a $40 sign up fee and it costs $25 per month. Gym B has a $50 sign up fee and costs $20 per month.

Assume that the months for which Joey have to belong to each before the costs are the same be x.

Then -

For Gym A -

Total cost for x months = C[A] = 25x + 40

For Gym B -

Total cost for x months = C[B] = 20x + 50

For same cost -

C[A] = C[B]

25x + 40 = 20x + 50

25x - 20x = 50 - 40

5x = 10

x = 2

Therefore, the months for which Joey have to belong to each before the costs are the same are 2 months.

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Answer: 17.2

Step-by-step explanation:

By the Pythagorean theorem,

[tex]10^{2}+14^{2}=(AC)^{2}\\\\(AC)^{2}=296\\\\AC=\sqrt{296} \approx \boxed{17.2}[/tex]

prolly 4.36 just use the Pythagorean theorem