If a piece of elastic wire 2 meters long and 3 centimeters in diameter increases its length by 2.5 cm when a force of 0.25 is applied to its area.Find the force applied on the string and the Young's scale of the string?​

mu + MU = (m + M) V... eq (1)

given:

m=0.05 kg, M=3.5 kg, U= 0 and V=1.82 m/s.

put these numbers to equation (1)

0.05×u +0 =(0.05+3.5)×1.82

u=3.55×1.82 /0.05

u= 6.461/0.05

u=129.22m/s ...(2)

prior to a collision

Bullet: |p|bullet =mu =0.05129.22=6.461 kg/s

|p | block = MU=3.5×0 =0 kg.m/s

After  collision

Combining, |p| equals (m+M)V = (0.05+3.5) 1.82 =6.461 kg.m/s.

Equation (2) shows the initial speed of the projectile.

=129.22 m/s.

what is collision?

Collision is defined as the meeting of two or more things with such force that both or all of them suffer harm or have their development significantly slowed.

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Vector B of the following vectors best represents the direction of the resultant electric field at point p, the center of the triangle.

A  quantity or phenomenon that has two independent properties i.e magnitude and direction is named as vector.

E = E1+ E2.

According to the bottom panel of the picture, a point charge's electric field has the formula E = kr2qr.

E =k ea2q uphill and to the right at 60, and E2 =kea2q upward and to the left at 60.

Therefore, E= E1 + E2 = kea2q[(cos60i+sin60j) + (cos60i+sin60j)] = kea2q[2(sin60j)

= 1.73kea2qj. i.e vector B

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Answer:

using the formula

Resistance=Resistivity × length/area

Area=1 ,Resistance(R)=0.2ohm ,resistivity(P)=? ,length=7.5×10^-9

R=Pl/A

Pl=RA

P=RA/l

P=0.2×1/7.5×10^-9

P=0.027×10^9

P=2.7×10^7ohmsmeter

The resistivity of the membrane is 2.7×10⁷ ohm-meter.

Electrical resistance of a conductor with a unit cross-sectional area and unit length is called resistivity. Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.

Mathematically the relation between resistance and resistivity can be written as:

Resistance=Resistivity × length/area

Given parameters:

Area of the membrane: A=1 m²

Resistance(R)=0.2ohm ,

resistivity(ρ)=?

length=7.5×10^-9 m.

Now:

  R=ρl/A

⇒ρl=RA

⇒ρ=RA/l

⇒ρ=0.2×1/7.5×10⁻⁹

⇒ρ=0.027×10⁹

⇒ρ=2.7×10⁷ ohm-meter.

Hence, the resistivity of the membrane is 2.7×10⁷ ohm-meter.

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Answer:

The modern atomic theory establishes the concepts of atoms and how they compose matter. Atoms consist of negatively charged electrons around a central nucleus composed of more massive positively charged protons and electrically neutral neutrons. The atomic model changes over time because the atomic model was based on theories and discoveries.

Explanation:

I hope it helps

Answer:

A. A current flows through the loop of wire.

Explanation:

When a loop of wire turns between two permanent magnets in a generator, a current flows through the loop of wire. This is because the movement of the wire through the magnetic field of the permanent magnets causes the electrons in the wire to move, which creates an electric current. This process is known as electromagnetic induction, and it is the principle behind the operation of generators.

The voltage-gated ion channels allows permeation of only one type of ion whereas, ligand-gated channels are less selective and allows permeation of two or more types of ions via the channel pore.

Ligand-gated ion channels are integral membrane proteins that contain a pore which allows regulated flow of selected ions across plasma membrane. Voltage-gated potassium channels are transmembrane channels specific for potassium and are sensitive to voltage changes in the membrane potential of cell .

1. Ligand-gated channel opens or closes in response to blank the binding of a ligand.

2. Voltage-gated channel opens or closes in response to differences in membrane potential.

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Answer:

The force of attraction and repulsion between two current-carrying parallel conductors can be demonstrated using a simple experiment. To do this, you will need two long, straight conductors, a power source, and a means of measuring the force between the conductors.

First, connect the two conductors to the power source so that they are carrying current in the same direction. Place the conductors parallel to each other, and measure the force between them using a spring scale or other device. You should observe a force of attraction between the conductors.

Next, reverse the direction of the current in one of the conductors, and measure the force between the conductors again. This time, you should observe a force of repulsion between the conductors.

This experiment demonstrates that current-carrying conductors exert a force of attraction on each other when the currents are in the same direction, and a force of repulsion when the currents are in opposite directions. This phenomenon is known as the Lorentz force.

The equation that could be used to determine the acceleration a of the box  is (-f-mg sin 0 = ma)

If the direction of motion of the mass is up the plane, then the frictional force F will act down the plane.

Normal force N is exerted on the body by the plane due to the force of gravity i.e. mg cos θ. These two will be equal hence cancelled out.

Here, according to the question,

Box is moving up so, Force of friction is acting downwards and mg sin 0 is also acting downwards. Both are acting against the motion of the box so both terms will be negative i.e. (-f) and (-mg sin 0)

We know resultant force is equal to (ma)

So, (-f) + (-mg sin0) = ma

-f - mg sin0 = ma

The equation that could be used to determine the acceleration a of the box  is (-f-mg sin 0 = ma)

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Answer:

The resulting acceleration of the jug is 3 m/s^2.

Explanation:

To calculate the resulting acceleration of the jug, we need to use the equation F = ma, where F is the force applied to the object, m is the mass of the object, and a is the acceleration of the object.

Plugging in the values given in the question, we get:

F = ma

12 N = (4 kg) * a

Solving for a, we get:

a = F/m

a = (12 N) / (4 kg)

a = 3 m/s^2

Therefore, the resulting acceleration of the jug is 3 m/s^2.

The velocity of the ladder when the base of the ladder is 7, 15, and 24 feet from the wall is -0.875, -2.25, and -10.286 respectively.

Given, the length of the ladder= 25 ft

Let x be the distance between the wall and the ladder and h be the height of the ladder from the ground

x² + h² = (25)²

x² +h²= 625

h²= 625- x²

h= [tex](625- x^{2})^{1/2}[/tex]

[tex]\frac{dh}{dx}[/tex] = [tex]\frac{1}{2}[/tex] [tex](625- x^2)^{-1/2} * (-2x)[/tex]

[tex]\frac{dh}{dx}[/tex] =  [tex]\frac{-x}{\sqrt{ (625-x^2)}}[/tex]

We have dx/dt= 3 ft/sec

Therefore, by applying the chain rule, we can get the value of dh/dt as:

dh/dt= dh/dx *dx/dt

=[tex]\frac{-x}{\sqrt{ (625-x^2)}}*3[/tex]

=[tex]\frac{-3x}{\sqrt{ (625-x^2)}}[/tex]

Now substituting the different values of x in the acquired equation

When x= 7, dh/dt= [tex]\frac{-7}{8}[/tex] ft/sec= -0.875 ft/sec

When x= 15, dh/dt= [tex]\frac{-9}{4}[/tex] ft/sec= -2.25 ft/sec

When x= 24, dh/dt= [tex]\frac{72}{7}[/tex] ft/sec= -10.286 ft/sec

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After solving the equation the amplitude of magnetic field is 1.2× 10^-9 T.

What is amplitude of magnetic field?

Amplitude of magnetic field is a measure of the strength of the magnetic field. It is measured in units of Tesla (T) or gauss (G). The magnetic field is produced by electric currents, the movement of charged particles, or the spin of an atomic nucleus. The amplitude of the magnetic field depends on the source, the amount of current, and the distance from the source. The Earth's magnetic field has an amplitude of approximately 30-60 microtesla (0.3 - 0.6 mG). At the surface of the Earth, the magnetic field is strongest near the poles, where it can reach over 65 microtesla (0.65 mG). In space, magnetic fields can reach amplitudes of up to 40,000 microtesla (400 G).

The distance between airplane and transmitter, R = 11.5 km

Amplitude of electric field, E = 0.360 v/m.

Amplitude of magnetic field, B = E/c

=  0.36 /3 × 10^8

= 1.2× 10^-9 T

Hence the amplitude of magnetic field is 1.2× 10^-9 T.

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The magnetic-field amplitude measured by the airplane 1.2× 10^-9 T

What is magnetic field?

The magnetic field is the area where the force of magnetism acts on a magnetic material or a moving electric charge. In order to impose a force on other adjacent moving charges and magnetic dipoles, moving electric charges and magnetic dipoles form a magnetic field.

The maximum field strength of the electric and magnetic fields can be found in electromagnetic waves by measuring their amplitude. The amplitude of the wave determines its energy.

The distance , R = 11.5 km

Electric field amplitude, E = 0.360 v/m.

Magnetic field amplitude, B = E/c

=  0.36 /3 × 10^8

= 1.2× 10^-9 T

So the amplitude of magnetic field is 1.2× 10^-9 T

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The basic kinematic equations for horizontal and vertical motion are as follows:

s = v₀t + ¹/₂at²

Horizontal motion is:

x = v₀ₓt + ¹/₂aₓt²

x = v₀ₓt

x = v₀ cosαt

Because there is no air resistance: x = v₀ cosθt

Vertical motion is:

y = v₀[tex]__y[/tex]t + ¹/₂a[tex]__y[/tex]t²

y = v₀ sinαt - ¹/₂gt²

Solve both for the velocity trigonometric function term as follows:

y = v₀ sinαt - ¹/₂gt²

v₀sinαt = ¹/₂gt² + y

v₀sinα = ¹/₂gt² + y/t

and

x = v₀ cosαt

v₀cosα = x/t

Now divide these two equations and we get

v₀sinα/v₀cosα = tanα [tex]=\frac{1/2gt + \frac{y}{t} }{\frac{x}{t} }[/tex]

tan α [tex]= \frac{1/2gt + \frac{y}{t} }{\frac{x}{t} } = \frac{gt^2}{2x} + \frac{y}{x}[/tex]

tan α [tex]= \frac{gt^2}{2x} + \frac{y}{x}[/tex]

Enter a value, x is the distance between the boarding 35.5 m, and y is the difference between the launch height and the drop point. The launch height is 15.5 m and the landing height is 11.0 m, so y = -4.5 m. Finally, we are told the projectile travel time is 2.2 s.

tan α [tex]= \frac{gt^2}{2x} + \frac{y}{x}[/tex]

tan α [tex]= \frac{(9.8)(2.2)^2}{2(35.5)} + \frac{-4.5}{35.5}[/tex]

tan α [tex]= 0.668 - 0.126[/tex]

tan α [tex]= 0.542[/tex]

     α = tan⁻¹ 0.542

     α = 28.4°

For the second launch, y₂ is +7.0 m launch altitude is still 15.5 m, but the deployment altitude is now 22.5 m, and x is still 35.5 m. The angle remains 28.4°. This time we don't know the flight time or initial velocity we are asked to find. Using horizontal distances, we can solve for time.

x = v₀.cosα.t

t² = x/v₀.cosα

Now do it for y₂:

          y₂ [tex]= v_0sin(\alpha) t - 1/2gt^2[/tex]

          y₂ [tex]= v_0sin(\alpha) (\frac{x}{v_0cos(\alpha)} ) - 1/2g (\frac{x}{v_0cos(\alpha)} )^2[/tex]

           y₂ [tex]= x tan (\alpha ) - \frac{gx^2}{2v_0cos(\alpha)^2}[/tex]

 [tex]\frac{gx^2}{2v_0cos(\alpha)^2} = x tan (\alpha ) - y_2[/tex]

We need to solve v₀:

   [tex]\frac{gx^2}{2v_0cos(\alpha)^2} =\frac{1}{ x tan (\alpha ) - y_2}[/tex]

2v₀cos (α)² [tex]= \frac{gx}{ x tan (\alpha ) - y_2}[/tex]

             v₀² [tex]= (\frac{1}{2cos(\alpha)^2} ) \frac{gx}{ x tan (\alpha ) - y_2}[/tex]

            v₀² [tex]= (\frac{x^2}{cos(\alpha)^2} ) \frac{g/2}{ x tan (\alpha ) - y_2}[/tex]

            v₀² [tex]= (\frac{x}{cos(\alpha)^2} ) \sqrt{ \frac{g/2}{ x tan (\alpha ) - y_2}}[/tex]

Now we can enter values:

v₀² [tex]= (\frac{x}{cos(\alpha)^2} ) \sqrt{ \frac{g/2}{ x tan (\alpha ) - y_2}}[/tex]

v₀² [tex]= (\frac{35.5}{cos(28.4^0)} ) \sqrt{ \frac{9.8/2}{ 35.5 tan (28.4^0) - 7.0}}[/tex]

v₀² = 40.386 [tex]\sqrt{\frac{4.9}{12.17} }[/tex]

v₀² = 40.386 (0.634)

v₀² = 25.62 m/s

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The passage is describing the beauty of Acadie, a place that is home to the speaker. This passage is from Bliss Carman's "LOW TIDES" .

The sun is setting, and the speaker is captivated by the beauty of the landscape, which is enhanced by the unelusive glories of the tide. The speaker also reflects on a beloved face being gone for a long time and is moved by a grievous stream, which meanders through the fields of Acadie as if it is trying to figure out why the beloved face is gone. The speaker almost dreams that the beauty of the place will remain until the beloved face returns. The passage conveys a sense of longing and hope for the beloved to come back to Acadie.

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Due to the fact that a star's parallax angle and distance are inversely related, I concur with student 2 and disagree with student 1. The farther away the star is, the smaller the parallax angle is.

Student 1: That's not necessarily true. It's true that the triangle in the diagram would be pointier for a star that is farther away, but the parallax angle depends on the ratio of the distance between the Earth and the star to the distance from the star to the edge of the solar system.

Student 2: But if the star is farther away, then the distance between the Earth and the star will be larger, which means the parallax angle will be smaller.

Student 1: Not necessarily. Remember that the distance from the star to the edge of the solar system is also increasing. If the distance from the star to the edge of the solar system increases more quickly than the distance between the Earth and the star, then the ratio of these two distances will decrease, which means the parallax angle will actually increase.

Student 2: Oh, I see what you mean. So it's possible for the parallax angle to increase as the distance to a star increases.

Student 1: That's correct. It's important to consider both the distance between the Earth and the star and the distance from the star to the edge of the solar system when determining the parallax angle.

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Question- Consider the following debate between two students regarding the relationship between parallax angle and the distance we measure to a star.

Student 2: If we drew a diagram for a star that was much more than 1 parsec away from us, the triangle in the diagram would be pointier than the one we just drew in Part II. That should make the parallax angle smaller for a star farther away.

The time interval during which the speed of the wheel is increasing is 4 s.

The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per square second.

The angular velocity at time t = 0, is ω₁ = - 6.00 rad/s.

The angular velocity at time t = 10.0 s, is ω₂ = +4.00 rad/s.

Angular acceleration of the wheel = change in angular velocity /time interval

= ( 4.00 - (-6.00))/10 rad/s²

= 1.0 rad/s²

Hence, angular velocity becomes zero at time = ( 0 - ( -6))/1.0 s = 6 s.

So, during t = 0 to t = 6s, the clockwise angular  velocity of the wheel decreases from 6.00 rad/s to 0.00 rad/s and  during t = 6s to t = 10s , the counterclockwise angular  velocity of the wheel increases from 0.00 rad/s to +4.00 rad/s.

Hence,  the time interval during which the speed of the wheel is increasing is = 10 s - 6 s = 4 s.

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The motion of the rigid system will be (a) linear (b) rotational (c) both linear and rotational

The first condition for equilibrium states that the body must have a net force of zero. This means that when the net force acting on a body is not zero the body will continue to move in a straight path and the motion of the rigid body will be linear.

The second condition for equilibrium states that the body must have zero net torque acting on the body for achieving equilibrium. torque is the rotational equivalent of force. Therefore, when the net torque is not zero, the rigid body keeps rotating which leads to a rotational motion.

When both the conditions of equilibrium are not satisfied the rigid body does not achieve the static equilibrium.

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Miscellaneous deductions subject to the 2% limit fall into the following three categories:

What are miscellaneous tax deductions?

Other individual deductions are deductions subject to the 2% Adjusted Gross Income (AGI) limit. You may claim certain expenses as personal deductions on Schedule A (Form 1040), Schedule A (1040-NR), or as income adjustments on Forms 1040 or 1040-SR.

In general, nonresident aliens in one of the eligible employment categories are entitled to deductions so long as they are directly related to income effectively related to the pursuit of trade or business in the United States.

Miscellaneous deductions subject to the 2% limit fall into the following three categories:

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By dividing each side of the voltage triangle by its current, I, an impedance triangle for a series RLC circuit can be created. The source voltage is equal to I*Z, the voltage across the two reactive elements is I×X = I×XL – I*XC, and the voltage drop across the resistive element is equal to I*R.

At resonance, the impedance, Z, is at its lowest value, (=R), because the current flowing through a series resonance circuit is the product of voltage divided by impedance.

Therefore, the circuit current will be at its maximum V/R value at this frequency.

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Only the Sun and the Moon are brighter than the planet Venus, which represents the goddess' own beauty and makes for a lovely spectacle in the sky.

The ancient Greeks gave the name Athena—after their goddess of wisdom—to the fourth planet from the Sun.

The same planet was given the name Minerva by the Romans, who did so in honor of Athena in Greek mythology. The first manned spacecraft to visit the planet was given the name Athena by the Americans.

Therefore, In honor of their goddess of love and beauty, the Romans gave the brightest planet, Venus, that name. After the telescope was created in the early 1600s, the planets Uranus and Neptune were also found.

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Answer:

(b) active solar because the solar radiation passing thru the window will help to heat his room

$9,889.82 much profit did Cynthia make in total.

In the financial markets, it can be difficult to tell stocks from shares. Both terms are typically interchangeable in American English when referring to financial equities, more precisely, securities that signify ownership in a public corporation.

The more inclusive, generic term is "stocks." It is frequently used to refer to a portion of ownership in one or more businesses.

In comparison, "shares" has a more precise connotation in everyday speech: It frequently refers to the ownership of a specific business.

Therefore, $9,889.82 much profit did Cynthia make in total.

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Via moving one vector so that its tail sits on the tip of the first vector, you may add by the tip-to-tail approach. New vector drawn from first vector's origin to the second vector's arrow is the resulting vector, A+B, or the sum of the two.

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Atomic absorption spectroscopy, often known as AAS or AA spectroscopy, is one of the earliest methods for elemental analysis to be established for the market.

The analytical method known as flame atomic absorption spectroscopy (Flame AAS or FAAS) was first commercially released in the 1960s after being invented in 1952.

The method has been well-liked ever since for its dependability and simplicity. AAS is an analytical method for figuring out how much of a particular element is in a sample. It is based on the idea that atoms (and ions) may absorb light with a certain, distinct wavelength.

The atom absorbs the energy (light) when it is present at this particular wavelength. By absorbing energy (light) at a certain wavelength, an electron is stimulated from the ground state to a higher energy level.

Therefore, Atomic absorption spectroscopy, often known as AAS or AA spectroscopy, is one of the earliest methods for elemental analysis to be established for the market.

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The final temperature is  909 K or 636° C.

According to Gay-Lussac's law, the pressure that a gas (with a given mass and maintained at a fixed volume) exerts varies directly with the gas's absolute temperature.

Initial temperature of the gas: T₁ = 30⁰ C = 273 + 30 K = 303 K.

Initial pressure of the gas = P₁ = P

Final pressure of the gas = P₂ = 3P

Final temperature of the gas: T₂ = ?

Now from Gay-Lussac's law;

T₁/P₁ = T₂/P₂

T₂ = T₁P₂/P₁

= 303 K × 3P/P

= 3 × 303 K

=909 K

Hence, the final temperature is =  909 K = 636° C.

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Star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen but the violet lines are at 424nm and 400nm instead of the usual 434nm and 410nm. from this  star is Moving towards us.

Information about a star's temperature, chemical make-up, and inherent luminosity can be found in its spectrum. A series of photographs taken at various wavelengths of the slit in the star's light make up spectrograms produced by slit spectrographs. Astronomers can identify an element by its spectral lines, as well as its temperature and density within the star. The magnetic field of the star can also be shown via the spectral line. How quickly the material is travelling can be determined by the line's width. This teaches us something about the winds in stars. The object is also referred to as the "Seven Sisters" and Messier 45, and its English name comes from a Greek tale. The Pleiades are seven of Atlas, the Titan deity, and the Pleiades' daughters.

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Answer:

The vertical and horizontal distance of a projectile will be equal if the angle of projection is 45 degrees.

Explanation:

This is because at an angle of 45 degrees, the projectile will be equally influenced by the horizontal and vertical components of its motion. As a result, the projectile will travel the same distance horizontally as it does vertically.

For other angles of projection, the projectile will be more influenced by either the horizontal or the vertical component of its motion, depending on the angle.

At an angle of 90 degrees (straight up), the projectile will be primarily influenced by the vertical component of its motion, while at an angle of 0 degrees (horizontal), the projectile will be primarily influenced by the horizontal component of its motion.

A massive block of known Mass is struck by the projectile, which has mass m. The amount of kinetic energy wasted as a percentage is 0.955.

A quantitative representation of inertia, the fundamental property of all matter. In essence, it describes the resistance of a body of theory to altering its movement or location in reaction to the applied load. More and more volume a body has, the less the change brought on by an external load is.

The average concentration (M), which is a physical property, is the same mass as one mole of a hazardous chemical or the ratio of the quantities of a psychoactive compound to its own amounts of pollutants.

kinetic energy lost = change KE/KE

=1-m/(m + M)

=0.955.

momentum,

mv = (m + M)*V

V=m(1/( M + m))v

kinetic energy lost,

ΔKE / KE

= 1-m (1 / (m + M)

ΔKE/KE = 1-18(1/(18+380)

ΔKE/KE = 0.955

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The magnitude of the impulse delivered to the ball by the player is -9.536 kg-m/s

Given that,

Mass of a soccer ball, m = 0.298 kg

Initial speed, u = 15 m/s

Final speed, v = -17 m/s (negative as it is in opposite direction)

(a) Impulse = change in momentum

J = 0.298 × (-17 -15)

J = -9.536 kg-m/s

Therefore the magnitude of the impulse delivered to the ball by the player is -9.536 kg-m/s.

The object's change in momentum is equal to the impulse it experiences. The formula for magnitude of impulse is F • t = m • v. When two objects collide, an impulse occurs, which both causes and equals the change in momentum.

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a) Height is calculated as = 5R/2 b) It is shown that the normal force on the car at the bottom of the loop exceeds the normal force at the top by six times the weight of the car.

The force that surfaces exert to prevent solid objects from passing through each other is known as the normal force .

a) At point A, PE = m g h

At point B, PE = 1/2 * m * (vB)²

At point C, PE =  m(vC)²/R - mg

m is mass vB is velocity at B

vC= √mgR/m = √gR

For conservation of energy at point C and B

1/2 * m * (vB)² + 1/2 * m * (vC)² + mg (2R)   ( height of c = 2R)

(vB)² = gR + 2(2gR)

So, vB = √5gR

Conservation of energy between point A and B,

1/2 * m * (vB)² = mgh

Height, h = 5R/2

b) Normal force at topmost point C is

= m(vC)²/R - mg

Normal force at bottom point B is

= mg + m (vB)²/R

NB = mg + m(5gR)/R

= 6 mg

Therefore, we can say that NB > NC

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The magnitude of the provided average friction force F (in n) which is acting on the toboggan during it was moving is  8.66 N

Toboggan is a long flat-bottomed light sled composed usually of thin boards curved up at one end with usually low handrails at the sides. : a downward course as well as a sharp decline.

Given:

vi = 4.1 m/s

vf = 0

Δv = v final - v initial

= 0 - 4.1 = -4.1 m/s

Δ momentum i.e  mΔv = (19 kg).(-4.1 m/s)

= 77.9 kgm/s

The average friction force (Ff) takes 9 seconds to take the toboggan to a end point, hence,  impulse = Ft

= Ff(9)

Impulse is = Δ momentum, so

Ff(9) = 77.9;

Ff = 8.66 N

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