a, a² + 1 and a + 6 are all in arithmetic progression, in which there is a fixed difference d between consecutive terms. This mean we have
a² + 1 = a + d
a + 6 = a² + 1 + d
Eliminate d and solve for a :
(a² + 1) - (a + 6) = (a + d) - (a² + 1 + d)
a² - a - 5 = -a² + a - 1
2a² - 2a - 4 = 0
a² - a - 2 = 0
(a - 2) (a + 1) = 0
a - 2 = 0 or a + 1 = 0
a = 2 or a = -1
Match each value with its formula for ABC.
The solution to the question is:
c is 6 = [tex]\sqrt{a^{2} + b^{2} -2abcosC }[/tex]
b is 5 = [tex]\sqrt{a^{2} + c^{2} -2accosB }[/tex]
cosB is 2 = [tex]\frac{a^{2} + c^{2} - b^{2} }{2ac}[/tex]
a is 4 = [tex]\sqrt{b^{2} + c^{2} -2bccosA }[/tex]
cosA is 3 = [tex]\frac{b^{2} + c^{2} -a^{2} }{2bc}[/tex]
cosC is 1 = [tex]\frac{b^{2} + a^{2} - c^{2} }{2ab}[/tex]
What is cosine rule?it is used to relate the three sides of a triangle with the angle facing one of its sides.
The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.
Analysis:
If c is the side facing the included angle C, then
[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] -2ab cos C-----------------1
then c = [tex]\sqrt{a^{2} + b^{2} -2abcosC }[/tex]
if b is the side facing the included angle B, then
[tex]b^{2}[/tex] = [tex]a^{2}[/tex] + [tex]c^{2}[/tex] -2accosB-----------------2
b = [tex]\sqrt{a^{2} + c^{2} -2accosB }[/tex]
from equation 2, make cosB the subject of equation
2ac cosB = [tex]a^{2}[/tex] + [tex]c^{2}[/tex] - [tex]b^{2}[/tex]
cosB = [tex]\frac{a^{2} + c^{2} - b^{2} }{2ac}[/tex]
if a is the side facing the included angle A, then
[tex]a^{2}[/tex] = [tex]b^{2}[/tex] + [tex]c^{2}[/tex] -2bccosA--------------------3
a = [tex]\sqrt{b^{2} + c^{2} -2bccosA }[/tex]
from equation 3, making cosA subject of the equation
2bcosA = [tex]b^{2}[/tex] + [tex]c^{2}[/tex] - [tex]a^{2}[/tex]
cosA = [tex]\frac{b^{2} + c^{2} -a^{2} }{2bc}[/tex]
from equation 1, making cos C the subject
2abcosC = [tex]b^{2}[/tex] + [tex]a^{2}[/tex] - [tex]c^{2}[/tex]
cos C = [tex]\frac{b^{2} + a^{2} - c^{2} }{2ab}[/tex]
In conclusion,
c is 6 = [tex]\sqrt{a^{2} + b^{2} -2abcosC }[/tex]
b is 5 = [tex]\sqrt{a^{2} + c^{2} -2accosB }[/tex]
cosB is 2 = [tex]\frac{a^{2} + c^{2} - b^{2} }{2ac}[/tex]
a is 4 = [tex]\sqrt{b^{2} + c^{2} -2bccosA }[/tex]
cosA is 3 = [tex]\frac{b^{2} + c^{2} -a^{2} }{2bc}[/tex]
cosC is 1 = [tex]\frac{b^{2} + a^{2} - c^{2} }{2ab}[/tex]
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Please Help I Don't Understand
Answer:
7.5
Step-by-step explanation:
10 is to 8 as x is to 6
10/8 = x/6
6 (10/8) = x = 7.5
Answer:
Step-by-step explanation:
The two triangles are similar because the corresponding angle in each is equal to the angle corresponding angles in the other.
Put in simpler language. ΔAEB ~ ΔADC by parallel lines properties. If that's the case 10/(10 + 8) = x/(x + 6)
Equation
AE/AD = AB/AC Substitute values
Solution
10/(10 + 8) = x/(x + 6) Cross Multiply
10*(x + 6) = x* (10 + 8) Combine
10*(x + 6) = 18x Remove the Brackets
10x + 60 = 18x Subtract 10x from both sides
8x = 60 Divide by 8.
x = 60/8
x = 7.5
Answer: A
PLEASE HELPPP!
Consider triangle ABC. What is b?
Answer: 18.7346314730578
This value is approximate.
=================================================
Explanation:
Use the law of sines to find side b
sin(A)/a = sin(B)/b
sin(112)/37 = sin(28)/b
b*sin(112) = 37*sin(28)
b = 37*sin(28)/sin(112)
b = 18.7346314730578
Round that value however you need to.
The portion on your screenshot says "round to the nearest", but it doesn't say to the nearest what. Is it nearest tenth? Hundredth? Something else? That part is cut off. So I'll just write down all of the decimal digits my calculator is showing, and let you do the final rounding step.
The function g(x) is defined as g(x)=-2x+3x the value of g(-3)is
Answer:
-3
Step-by-step explanation:
g(-3) = -2x+3x
-2(-3) +3(-3)
6+-9 = -3
give brainliest please
hope this helps :)
Answer:
just commenting so you can give the other guy brainliest !
Step-by-step explanation:
The volume of a rectangular prism is 400 cm3 . If the length is 16 cm and the width is 5cm, what is its height?
Answer:
H = 5
Step-by-step explanation:
rectangular prism:
V = L x W x H
400 cm3 = 16 x 5 x H
400 cm3 = 80 x H
400/80 = 5
h = 5 cm
95% sure this is correct! :)
Answer:
5 cm
Step-by-step explanation:
Formula used :
Volume of the rectangular prism = Length × Width × Height
=========================================================
Given :
⇒ Volume = 400 cm³
⇒ Length = 16 cm
⇒ Width = 5 cm
===========================================================
Solving :
⇒ 400 cm³ = 16 cm × 5 cm × Height
⇒ Height = 400 cm³ / 80 cm²
⇒ Height = 5 cm
Three pupils are given some books to share among themselves. Molly receives 772 books, which is 345 more than Marie. Marie receives six times more books than Melanie. There are some books left over. If Melanie's share is 1/25 of the total number of books, how many books are left over?
Using proportions, it is found that the number of books that was left over was of 505.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The number of books received by Marie is given by:
M = 772 - 345 = 427.
Melanie received one-sixth of Marie, hence:
Me = 427/6 = 71.
The total amount is 25 times Melanie's amount, hence:
T = 25 x 71 = 1775.
The amount left over is:
L = 1775 - (772 + 427 + 71) = 505
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can someone help me please
Replace x with -2 and solve:
A) -2 + -2 = -4 which is not less than or equal to -8
B) 2 + -2 = 0, this is greater than or equal to -8
C) -2 + -2 = -4, this is not less than -8
D) 2 + -2 = 0, this is not greater than 8
Answer: B is true
HELP ME PLEASEEEE ANSWER MY MATH
The water consumption based on the information for three Months will be 22267m³.
How to calculate the values?The total water consumption for the three months will be:
= 7219 + 7390 + 7658
= 22267m³
In conclusion, the information simply want you to add the values of the water given.
Therefore, the water consumption based on the information for three Months will be 22267m³.
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what is n^10/n^-5?
pls no explanation just answer
will mark brainliest!
Answer:
n¹⁵
Key:
[tex]\frac{x^a}{x^b}=x^{a-b}[/tex]Step-by-step explanation:
[tex]\frac{n^{10}}{n^{-5}}\\=n^{10-\left(-5\right)}\\n^{10} = n10\\^{-5} = -5\\n10 - -5 = n15\\= n^{15}[/tex]
What is a pair of overlapping triangles?
△EDB and △DEC
△ADE and △FCB
△BDE and △EDA
The mass of a dust particle is approximately
7.5 x 10-10 kilograms and the mass of an electron
is 9.1 x 10-31 kilograms. Approximately how many
electrons have the same mass as one dust particle?
Total electrons
Mass of dust/Mass of electron7.5×10^{-10}\9.1×10^{-31}0.824×10²¹8.25×10²⁰Answer:
Given:
[tex]\textsf{Mass of a dust particle} = \sf 7.5 \times 10^{-10}[/tex][tex]\textsf{Mass of an electron} = \sf 9.1 \times 10^{-31}[/tex]To calculate how many electrons have the same mass as one dust particle, divide the mass of a dust particle by the mass of an electron:
[tex]\begin{aligned}\implies \dfrac{\textsf{Mass of a dust particle}}{\textsf{Mass of an electron}} & = \sf \dfrac{7.5 \times 10^{-10}}{9.1 \times 10^{-31}}\\\\& = \sf \dfrac{7.5}{9.1} \times \dfrac{10^{-10}}{10^{-31}}\\\\& = \sf 0.8241... \times 10^{(-10-(-31))}\\\\& = \sf 0.8241... \times 10^{21}\\\\& = \sf 8.2 \times 10^{20}\end{aligned}[/tex]
Therefore, approximately [tex]\sf 8.2 \times 10^{20}[/tex] electrons have the same mass as one dust particle.
can someone help me to number 2,4&5.
just 2,4&5 that's all thank you.
Answer:
See below ~
Step-by-step explanation:
216, 36,6, Find the 8th term.
Answer:
1
Step-by-step explanation:
216 is term 1
36 is term 2
6 is term 3
1 is term 4
The number of swimsuits purchased at a department store is positively correlated with each of these variables. a change in which variable most likely caused a change in the number of swimsuits purchased?
The variable that is most likely to have a positive correlation with the number of swimsuits purchased is the temperature changing outside.
What is positive correlation?Correlation measures the relationship between two variables. When there is a positive correlation, it means that the two variables move in the same direction. If one of the variables increases, the other variable increases. If one of the variables decreases, the other variable decreases.
When it is summer, it is expected that the number of swimsuits bought would increase. When it is winter, it is expected that the number of swimsuits bought would decrease.
Here are the options:
A. The number of swimsuit cover-ups the store has in stock
B. The number of sand castles built by store customers
C. The temperature outside changing
D. The number of minutes it takes the store's employees to get to work
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Find the largest interval centered about x = 0 for which the given initial-value problem has a unique solution. (enter your answer using interval notation. ) y'' (tan(x))y = ex, y(0) = 1, y'(0) = 0
The largest interval centered about x = 0 is ([tex]-\frac{\pi}{2}, \frac{\pi}{2}[/tex]) for which the given initial-value problem has a unique solution: [tex]y'' + tan(x)y = e^x[/tex], y(0) = 1, y'(0) = 0.
An initial-value problem (IVP) is one kind of mathematical problem that contains obtaining a solution to a differential equation along with a set of initial conditions. It is commonly encountered in the field of differential equations.
Since it is mentioned in the theorem that in an initial-value problem y' + p(t)y = g(t), y([tex]t_o[/tex]) = [tex]y_o[/tex] has a unique solution if p(t) and g(t) are continuous functions on the interval (a, b) containing [tex]t_o[/tex].
Since [tex]e^x[/tex] is continuous everywhere and tanx is continuous on ([tex]-\frac{\pi}{2}, \frac{\pi}{2}[/tex]) containing 0.
Since R, a set of real numbers, and ([tex]-\frac{\pi}{2}, \frac{\pi}{2}[/tex]), both contain 0.
Thus the largest interval centered about x = 0 is ([tex]-\frac{\pi}{2}, \frac{\pi}{2}[/tex]).
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what is the GCF of (8x-6)
sos T-T
Hi student, let me help you out! :)
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
We are asked to find the G.C.F. of 8x-6.
[tex]\triangle~\fbox{\bf{KEY:}}[/tex]
G.C.F. stands for Greatest Common Factor.So what is the G.C.F. of 8x-6? We can list all of their common factors and then select the greatest one, like so:
[tex]\longmapsto\bf{Factors\;of\;8x:}[/tex] 1, 2, 4, 8, x
[tex]\longmapsto\bf{Factors\;of\;-6:}[/tex] -1, 1, 2, -3, 3, -6, 6
So the GCF is:
2
Now, we can also factor it out by placing it outside the parentheses ():
2(4x-3)
See, we factored it out by dividing both terms of the expression by the G.C.F.
[tex]\ddot\bigstar[/tex] Remember this...
[tex]\fbox{\bf{We\;factor\;out\;the\;G.C.F.\;by\;dividing\;all\;the\;terms\;of\;the\;expression\;by\;it}}[/tex]
Hope this helps you out! :D
Ask in comments if any queries arise.
~Just a smiley person helping fellow students :)
Answer: 2, you have to use math apps man it will save your life
Enter your answer and show all the steps that you use to solve this problem in the space provided. Use the binomial expression ( p + q ) n (p+q)n to calculate a binomial distribution with n = 5 and p = 0.3.
The binomial expression (p + q ) n (p+q)n to calculate the binomial distribution given will give a value of 10.
How to calculate the binomial expression?From the information given, the expression (p + q ) n (p+q)n is given to calculate a binomial distribution with n = 5 and p = 0.3.
p = 0.3
q = 1 - 0.3 = 0.7
n = 5
Therefore, expression ( p + q ) n (p+q)n will b:
= (0.3 + 0.7)× 5 + (0.3 + 0.7)× 5
= 5 + 5
= 10
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At 13:00, a water tank contained 180 litres of water. Water flowed from the tank at a constant rate until, at 17:30, the tank was completely empty. Calculate the rate of flow of water from the tank in litres per hour. If your answer is a decimal, give it to 1 d.p.
The drain rate is constant and thus equal to the average drain rate over the entire 4.5 hour period. This rate is
[tex]\dfrac{0 \,\mathrm L - 180 \,\mathrm L}{4.5 \,\rm h} = -40 \dfrac{\rm L}{\rm h}[/tex]
which is to say, water flows from the tank at a rate of 40 L/h.
A library checked out 20 books on Tuesday if 15 of the books are fiction find the ratio of nonfiction books to fiction books checked out
The ratio of nonfiction books to fiction books checked out is 1 : 3
How to determine the ratio?The given parameters are:
Total = 20
Fictions = 15
This means that:
Non Fictions = 20 - 15
Evaluate
Non Fictions = 5
The ratio is then represented as:
Ratio = Non Fiction : Fiction
This gives
Ratio = 5 : 15
Simplify
Ratio = 1 : 3
Hence, the ratio of nonfiction books to fiction books checked out is 1 : 3
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3n + 19 = 28
How do I solve this
Answer:
to solve this you need to find out what number n is to make it equal 28.
Step-by-step explanation:
19+3 =22 so 3 is not it
19+9=28
answer is 9
hopefully this is right and this gets to you on time
Answer:
err Im not sure if this is a multiple-choice but n=3
Step-by-step explanation:
3(n) + 19 is 28 meaning you have to find what multiplies with 3 to get 9 because 19+9 is 28
Hope this helps
use the tables below to find (p+q)(2).
The value of the composite function (p + q)(2) is 1
How to evaluate the function?The function expression is given as:
(p + q)(2)
As a general rule
(p + q)(x) = p(x) + q(x)
Substitute 2 for x
(p + q)(2) = p(2) + q(2)
From the table, we have:
p(2) = 3 and q(2) =-2
So, we have:
(p + q)(2) = 3 - 2
Evaluate
(p + q)(2) = 1
Hence, the value of the composite function (p + q)(2) is 1
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Answer: (p+q)(2)=1
Step-by-step explanation:
Edge
Find the volume and round to the nearest tenth if necessary 7.5 In 4in 2in
[tex]\huge\huge\bold{\green a \blue n \pink s \purple w \orange e \red r}[/tex]
volume of rectangular prism
Formula to calculate:
[tex]\large\bold{\green V\green = \green l \green * \green w \green * \green h}[/tex]
[tex]\large\bold{V= 7.5*4*2}[/tex]
[tex]\huge\boxed{\red V\red = \red 6 \red 0 \: {\red i \red n}^{\red 3}}[/tex]
length= 7.5 in
width= 2 in
height= 4 in
To find:The volume of the rectangular prism or cuboid.
Solution:Formula: volume= length × width × height
so, V= 7.5 × 2 × 4
[tex]\bold{V= 60 \: {\: in}^{3}}[/tex]
hope this helps!
x^2+3x-18 use factoring to determine the zeros
Answer:
x = 3
x = -6
Step-by-step explanation:
Hello!
Let's first set the equation to 0.
x² + 3x - 18 = 0To factor, first think about two numbers that multiply to -18, but add up to 3. The two numbers are 6 and -3.
Now, expand 3x to 6x and -3x. Then, factor by grouping.
Factorx² + 3x - 18 = 0x² + 6x - 3x - 18 = 0(x² + 6x) - (3x + 18) = 0x(x + 6) -1(3)(x + 6) = 0(x - 3)(x + 6) = 0Now, set each factor to 0 and solve for x
Solve(x - 3) = 0x = 3, x = -6
Write the ratio of squares to shapes.
Are the equations 5x=24+2x and 3x=24 equivalent?
Answer:
Yes they are.
Step-by-step explanation:
By simply moving 2x from the LHS to the RHS we'll get it's equivalent to be 3x.
i.e 5x - 2x = 3x
I’m really struggling! Please help me!!
Answer:
8.0
Step-by-step explanation:
The triangle is a right triangle, so we are able to use trigonometric functions. Relative to the angle of 37°, we have the opposite side which is 6 and the adjacent side which is x. The trig function that uses the opposite and adjacent is tangent(SohCahToa). We can set up the following equation:
[tex]tan(37) = \frac{opposite}{adjacent}[/tex]
[tex]tan(37) = \frac{6}{x}[/tex]
tan(37) evaluates to about , so we can plug it in and solve for x:
[tex]0.7536 = \frac{6}{x} \\0.7536x = 6\\x = 7.962[/tex]
To the nearest tenth, x rounds to 8.0.
If f(x) = 3x + 2 and g(x) = x² + 1, which expression is equivalent to (fog)(x)?
O (3x + 2)(x2 + 1)
Answer:
Hi,
Step-by-step explanation:
[tex](fog)(x)=g(f(x))=g(3x+2)=(3x+2)^2+1=9x^2+6x+5[/tex]
Answer:
hi
Step-by-step explanation:
plsssss. Quadrilateral IJKL is similar to quadrilateral MNOP. Find the measure of side MN. Figures are not drawn to scale.
[tex]\\ \rm\Rrightarrow \dfrac{IJ}{IL}=\dfrac{MN}{MP}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{24}{12}=\dfrac{MN}{3.8}[/tex]
[tex]\\ \rm\Rrightarrow 2=\dfrac{MN}{3.8}[/tex]
[tex]\\ \rm\Rrightarrow MN=3.8(2)[/tex]
[tex]\\ \rm\Rrightarrow MN=7.6[/tex]
According to a survey, 48% of adults in the united states believe that unidentified flying objects (ufos) are observing our planet. you ask 8 randomly chosen adults whether they believe ufos are watching earth.
The expected number of adults that believe ufos are watching earth is 4
How to determine the number of adults?The given parameters are:
p = 48%
Sample size, n = 8
The expected number of adults that believe ufos are watching earth is calculated as:
E(x) = np
This gives
E(x) = 8 * 48%
Evaluate
E(x) = 3.84
Approximate
E(x) = 4
Hence, the expected number of adults that believe ufos are watching earth is 4
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Isabelle has a five-sided chicken coop in her yard. each side has an equal length. what is the total perimeter of the chicken coop if the length of one side is yards? recall that the perimeter is the sum of all sides of a shape or boundary. yards yards yards yards
The total perimeter of the chicken coop if the length of one side is 3√5 yards is; 15√5 yards.yards
How to calculate the total perimeter?We are told that Isabelle had a five sided chicken coop in her yard and that the length was equal in all the sides.
Now, we need to find the total perimeter of the chicken coop.
The length of one side of the coop from online sources is 3√5 yards.
Since the coop is 5 sided, it means that it is a pentagon and we know that;
Perimeter of a pentagon = 5a
Where a is length of one side of the pentagon. Thus;
Perimeter = 5 x 3√5
Perimeter = 15 √5 yards
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