Answer:
14.2g
Explanation:
The reaction expression is given as:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Given mass of propane combusted;
4.74g
Unknown:
Mass of carbon dioxide produced = ?
Solution:
To solve this problem, we find the number of moles of the given propane;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of C₃H₈ = 3(12) + 8(1) = 44g/mol
Number of moles = [tex]\frac{4.74}{44}[/tex] = 0.11mol
From the balanced reaction equation:
1 mole of C₃H₈ will produce 3 moles of CO₂
0.11mole of C₃H₈ will produce 3 x 0.11 = 0.33mole of CO₂
Mass of CO₂ = number of moles x molar mass
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Mass of CO₂ = 0.33 x 44 = 14.2g
Calculate the lithium ion (Li+) concentration for a 0.821 M Li2S solution.
The lithium ion[Li⁺]=1.642 M
Further explanationIonic compounds will dissociate into ions when dissolved in water. The strength of the dissociation depends on the strength of the electrolyte properties. The stronger it is, the more ions will dissociate
Reaction
Li₂S⇒2Li⁺+S²⁻
mol ratio Li₂S : Li⁺: S²⁻ = 1 : 2 : 1
so the lithium-ion (Li⁺) concentration :
[tex]\tt 2\times 0.821=1.642~M[/tex]
Write a decay equation for neon-19
Answer:
Neon
Mass Number Half-life Decay Mode
Electron Capture
Electron Capture with delayed Proton Emission
18 1.6670 seconds Electron Capture
19 17.22 seconds Electron Capture
How much heat is required to vaporize 15.8 g CH3OH(l) at its boiling point? (∆Hvap = 38.0 kJ/mol) a a. 2.41 kJ b 77.0 kJ c 18.8 kJ d 600. kJ
Answer:
be.77.0kj.
Explanation:
add moles then times
Considering the definition of enthalpy of vaporization, the correct answer is option c. the heat required to vaporize 15.8 g of CH₃OH at its boiling point is 18.8 kJ.
When a material changes phase from solid to liquid, or from liquid to gas, a certain amount of energy is involved in this phase change.
In case of phase change from liquid to gas, this amount of energy is known as enthalpy of vaporization (symbolized as ∆H vap), also known as (latent) heat of vaporization or heat of evaporation.
In other words, the enthalpy of vaporization is the amount of energy required to change a unit of mass (for example, moles or kg) of a substance from phase liquid to phase gas at constant temperature and pressure.
In this case, you know that enthalpy of vaporization is ∆Hvap = 38.0 kJ/mol.
On the other side, you want to vaporize 15.8 g of CH₃OH. Then, being the molar mass of the compound 32 g / mole (that is, the amount of mass contained in one mole), the number of moles to be vaporized is:
[tex]15.8 gramsx\frac{1 mol}{32 grams}= 0.49375 moles[/tex]
Then, the heat required to vaporize 0.49375 moles of CH₃OH at its boiling point is calculated taking into account the enthalpy of vaporization by:
0.49375 moles× 38.0 kJ/mol= 18.76 kJ ≅ 18.8 kJ
Finally, the correct answer is option c. the heat required to vaporize 15.8 g of CH₃OH at its boiling point is 18.8 kJ.
Learn more:
https://brainly.com/question/21655944?referrer=searchResultshttps://brainly.com/question/7580155?referrer=searchResultshttps://brainly.com/question/4035699?referrer=searchResultshttps://brainly.com/question/11475740https://brainly.com/question/2212655?referrer=searchResultsWhich of the following is an example of a carnivore?
A. human
B. giraffe
C. elephant
D. lion
Answer:
D, Lions
Explanation:
Lions are meat eaters, meaning their food and energy requirements derive solely from anima tissue or meat (whether from hunting or scavenging)
Please show work: A car travels at a rate of 65 miles per hour. If the car gets 33.5 miles to the gallon, how many hours can a car travel on 25.0 pounds of fuel? (density of fuel is 6.50 pounds/gallon)
Answer:
Explanation:
First divide 25.0 by 6.5 to get the amount of fuel you have.
Determine the acid dissociation constant for a 0.010 M nitrous acid (HNO2) solution that has a pH of 2.70. Nitrous acid is a weak monoprotic acid and the equilibrium equation of interest is:________
Answer:
HNO₂ ⇄ H⁺ + NO₂⁻
Ka = 4.0 × 10⁻⁴
Explanation:
Step 1: Given data
Concentration of nitrous acid (Ca): 0.010 MpH of the solution: 2.70Step 2: Write the acid dissociation reaction
Nitrous acid is a weak acid that dissociates according to the following expression.
HNO₂ ⇄ H⁺ + NO₂⁻
Step 3: Calculate the concentration of H⁺
We will use the definition of pH.
pH = -log [H⁺]
[H⁺] = antilog - pH = antilog -2.70 = 2.00 × 10⁻³ M
Step 4: Calculate the acid dissociation constant (Ka)
For a weak acid, we can calculate Ka using the following expression.
Ka = [H⁺]²/Ca
Ka = (2.00 × 10⁻³)²/0.010
Ka = 4.0 × 10⁻⁴
6.At a pressure of 5.0 atmospheres, a sample of gas occupies 40 liters. What volume
will the same sample occupy at 1.0 atmosphere?
(a) 50 L
(b) 100 L
O (C) 80 L
(d) 200 L
Answer:
The answer is 200 LExplanation:
The new volume can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the new volume
[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]
So we have
[tex]V_2 = \frac{5 \times 40}{1} \\ = 5 \times 40[/tex]
We have the final answer as
200 LHope this helps you
Based on what you have seen in this gizmo what is the best definition of the doppler effect?
Answer:
Based on what you have seen in the Doppler Effect Gizmo, what is the best definition of the Doppler effect? A change in the frequency of a wave caused by the motion of the source relative to the observer. The increase in volume of a sound as the source approaches an observer.
Explanation:
Th ph value of milk is close to
Answer:
6.5
Explanation:
What is the structure of amylopectin?
Answer:
Not sure if you just wanted the basic structure or full on structure.
Explanation:
What type of particles move to create electicity?
electrons
protons
neutrons
the answer is electrons.....
Answer:
electrons
Explanation:
Liquid 1 has a density of 2.0 g/ml, Liquid 2
has a density of 1.5 g/ml, and Liquid 3 has a density of 1.8 g/ml. Which liquidwill make up
the top layer?
Liquid 2 because the lower the density the more it floats and the higher the density the more it sinks. The order from top to bottom is liquid 2, liquid 3, liquid 1
An object with a mass of 20.0 kg has a force of 5.0 Newton's applied to it. What is the resulting acceleration of the object?
28 mL of 0.10 M HCl is added to 60.0 mL of 0.10 M Sr(OH)2. Determine the concentration of OHin the resulting solution.
Answer:
Explanation:
Sr(OH)₂.+ 2HCl = SrCl₂ + 2H₂O
Moles of HCl in 28mL of .10 M HCl = .028 x .1 = .0028 moles .
Moles of Sr(OH)₂ in 60mL of .10 M Sr(OH)₂ = .060 x .1 = .0060 moles
2 moles of HCl reacts with 1 mole of Sr(OH)₂
.0028 moles of HCl reacts with .0014 mole of Sr(OH)₂
moles of Sr(OH)₂ remaining = .0060 - .0014 = .0046 moles .
Sr(OH)₂ = Sr⁺ + 2OH⁻
1 mole 2 mole
.0046 .0092
Total volume of solution = 88 mL .
88 mL of solution contains .0092 moles of OH⁻
concentration of OH⁻ = .0092 / .088
= .1045 M .
When Strontium hydroxide, Sr(OH)₂ will react with hydrochloric acid (HCl) then the reaction formed will be:
Sr(OH)₂+ 2 HCl ⇒ SrCl₂ + 2 H₂O
The concentration of OH in the resulting solution will be 0.1045 M.
This can be calculated by:
Molarity (HCl) = 0.10 MVolume (HCl) = 28 mLMolarity (Sr(OH)₂) = 0.10 M Volume (Sr(OH)₂) = 60.0 mL[tex]\text{Molarity} = \dfrac{\text{moles}}{\text{volume of the solution in litres}}[/tex]
Moles of HCl = 0.028 x 0.1 = 0.0028 moles
Moles of Sr(OH)₂ = 0.060 x 0.1 = 0.0060 moles
2 moles of hydrochloric acid will react with 1 mole of Sr(OH)₂So, 0.0028 moles of HCl will react with 0.0014 mole of Sr(OH)₂Remaining moles of Sr(OH)₂ = 0.0060 - 0.0014 = 0.0046 moles
Sr(OH)₂ ⇒ Sr⁺ + 2OH⁻
1 mole 2 mole
0.0046 0.0092
Total volume of solution = 88 mL
88 mL of solution contains 0.0092 moles of OH⁻
Hence, concentration of OH⁻ :
[tex]= \dfrac{0.0092 }{0.088}[/tex]
= 0.1045 M
Therefore, 0.1045 M will be the concentration of OH in the solution.
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What is the compound NH3
can you help me out pleas
Answer:a a atom
Explanation:
Answer:
a. carbon
b. atomic number
c. mass number
d. 6
e. 7
f. 8
pls mark as brainliest
Describe what a limiting reactant is
Answer:
The reactant in a chemical reaction that limits the amount of product that can be formed. The reaction will stop when all of the limiting reactant is consumed. Excess Reactant - The reactant in a chemical reaction that remains when a reaction stops when the limiting reactant is completely consumed.
Explanation:
HElp me plzzzzz??????
Answer:
The answer to your question is given below
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Zn + 2HCl —> ZnCl2 + H2
Thus, we can write out the atoms present in both the reactant and the product by doing a simple head count. The atoms present are listed below:
Element >>> Reactant >>> Product
Zn >>>>>>>> 1 >>>>>>>>>> 1
H >>>>>>>>> 2 >>>>>>>>> 2
Cl >>>>>>>>> 2 >>>>>>>>> 2
A sample of vinegar containing 0.100 mol of ethanoic acid has a concentration of 0.125M of ethanoic acid. What is the volume of the solution.
0.8 L
Explanation:We are given:
Molarity of Ethanoic Acid in vinegar = 0.125 M
Number of moles of Ethanoic Acid = 0.1 mole
Finding the volume of the solution:
We know that the molarity of a solution is defined as:
Molarity = n / V (where n is the number of moles and V is the volume in L)
replacing the variables with the given values:
0.125 = 0.1 / V
Multiplying by V on both the sides
0.125V = 0.1
Dividing both sides by 0.125
V = 0.1 / 0.125
V = 0.8 L
Therefore, the volume of the solution is 0.8 L
would you like to explore outer space? Why or why not? If you could travel to any part of the galaxy at lightning speed would like to see what is truly out in the universe would you do it? Why or why not?
Answer:
Yes!
Explanation:
I think It would be fun!, Going thought space going from planet to planet. once i get back to earth i can make a document about my time in space.
A student drew a diagram of the quantum model of an atom, as shown.
A small circle is shown. Six light gray spheres and six dark gray spheres are shown inside the circle. On the outer side of the circle is another circle of larger radius. This circle has two small circle on its boundary. Another circle of even greater radius is on the outside of the second circle. This outermost circle has four small circles on its boundary.
Which of the following explains if the student's diagram is correct or incorrect?
A - The diagram is incorrect because electrons follow an elliptical path instead of a circular path.
B - The diagram is incorrect because the exact location of the electrons cannot be determined.
C - The diagram is correct because protons and neutrons are concentrated at the center of the atom.
D - The diagram is correct because electrons are present in distinct energy levels around the nucleus.
The diagram is correct because electrons are present in distinct energy levels around the nucleus. Option D
What is the quantum model?Let nus just take a minute to be able to remind ourselves that when we look at the atom that there are several subatomic particles that can be shown to be able to make up the atom. We know that the electron is the particle that can be shown to be arranged in shells.
What we saw in the inner or the core of the atom is the nucleus and the six grey spheres that we can see there would have to do with the nucleus of the atom that is in the question.
As we now look up at the shells, we can see the electrons as they have been arranged into the respective shells were they can be found in the atom on the basis of the energy that they possess.
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23.1 G Of HCI (a Strong Acid) Is Added To Water To Make 1250 ML Of Solution.
Answer:
[H₃O⁺] = 0.0507 M
pH = 1.29
Explanation:
23.1 g of HCI (a strong acid) is added to water to make 1250 mL of solution. Calculate [H₃O⁺] and pH of the solution.
Step 1: Given data
Mass of HCl (solute): 23.1 gVolume of solution: 1250 mLStep 2: Calculate the concentration of HCl
We will use the following expression.
[HCl] = mass HCl / molar mass HCl × liters of solution
[HCl] = 2.31 g / 36.46 g/mol × 1.250 L
[HCl] = 0.0507 M
Step 3: Calculate the concentration of H₃O⁺
HCl is a strong acid according to the following equation.
HCl(aq) + H₂O(l) ⇒ H₃O⁺(aq) + Cl⁻(aq)
The molar ratio of HCl to H₃O⁺ is 1:1. Then, [H₃O⁺] = 0.0507 M.
Step 4: Calculate the pH of the solution
We will use the following expression.
pH = -log [H₃O⁺]
pH = -log 0.0507
pH = 1.29
Question 4 of 5
Most paints include a pigment (the color), a binder (the
glue), and a solvent. The binder makes the paint color stick
to the surface being painted.
Which part of the manufacturing process occurs when binders are added to a
paint mixture?
A. Separating
B. Forming
C. Finishing
D. Combining
SUE
Answer:
answer is d Combining
Explanation:
I did the test and got it correct
As a chemical change takes place when binders are added to a paint mixture combining part of the manufacturing process occurs.
What are chemical changes?Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.
There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.
There are three types of chemical changes:
1) inorganic changes
2)organic changes
3) biochemical changes
During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.
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Type your answer in decimal form. Do not round.
7 days = hours
CH3
CH,CCHCHCHCl
OH
Spell out the full name of the compound.
Answer:
CH3 – CH – CH – CH2 – CH – CH3
| | |
CH3 CH2 CH3
|
CH3
Explanation:
3 - etil - 2, 5 - dimetilhexano
What is the molar ratio of Li to N2 in the given reaction?
6Li + N2 → 2Li3N
Answer:
6moles of Li : 1 mole of N₂
Explanation:
The reaction equation is given as:
6Li + N₂ → 2Li₃N
Mole ratio of Li to N₂;
From the balanced reaction equation:
6 moles of Li will react with 1 mole of N₂;
The mole ratio is:
6moles of Li : 1 mole of N₂
How many mL of 0.650 M solution can be prepared by dissolving 15.0 g of copper(II) nitrate in
water?
Answer:
123.1L
Explanation:
Given parameters:
Molarity of Cu(NO₃)₂ = 0.650M
Mass of Cu(NO₃)₂ = 15g
Unknown:
Volume of Cu(NO₃)₂ = ?
Solution:
To solve this problem, we have to first find the number of moles of the given mass;
Number of moles of Cu(NO₃)₂ = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of Cu(NO₃)₂ = 63.5 + 2 (14 + 3(16)) = 187.5g/mol
Number of moles of Cu(NO₃)₂ = [tex]\frac{15}{187.5}[/tex] = 0.08 mol
Molarity is given as;
Molarity = [tex]\frac{number of moles }{volume}[/tex]
Volume = [tex]\frac{number of moles }{molarity }[/tex]
Insert the parameters and solve;
Volume = [tex]\frac{0.08}{0.65}[/tex] = 0.12L
Now mL;
1L = 1000mL
0.12L will give 1000 x 0.12 = 123.1L
what is the missing value
Answer:
72
Explanation:
The pattern here may be hard to find at first, but it's this: the number in the middle of the triangle = (number at lower left corner of triangle x number at upper vertex of triangle) + (number at upper vertex of triangle x number at lower right corner of triangle).
Thus, for the missing value...
Missing value = (3x8) + (8x6) = 24+48 = 72.
Could you tell me what concept in chemistry relates to this? I'm interested.
Also check out stylesben's answer. Seems like there's several ways of doing this.
Answer:
the answer is 72
Explanation:
6+3=9 and multiply 9 with 8 and answer comes 72
A 25.225 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 75.815 g of water. A 14.842 g aliquot of this solution is then titrated with 0.1068 M HCl . It required 29.99 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH3 in the aqueous waste
Answer:
1.43 (w/w %)
Explanation:
HCl reacts with NH3 as follows:
HCl + NH3 → NH4+ + Cl-
1 mole of HCl reacts per mole of ammonia.
Mass of NH3 is obtained as follows:
Moles HCl:
0.02999L * (0.1068mol / L) = 3.203x10-3 moles HCl = Moles NH3
Mass NH3 in the aliquot:
3.203x10-3 moles NH3 * (17.031g / mol) = 0.0545g.
Mass of sample + water = 22.225g + 75.815g = 98.04g
Dilution factor: 98.04g / 14.842g = 6.6056
That means mass of NH3 in the sample is:
0.0545g * 6.6056 = 0.36g NH3
Weight percent is:
0.36g NH3 / 25.225g * 100
1.43 (w/w %)q=m(delta)T Calculate the final temperature reached when 324 J of heat is added to a 22.5g iron bar initially at 20.0 degrees C. The specific heat capacity of iron is 0.45 J/g degrees C.
Answer:
T(final) = 52°C
Explanation:
1st, you need to correct your heat flow formula => q = mcΔT.
m = 22.5g
c = 0.45 j/g·°C
ΔT = T(final) - T(initial) = T(final) - 20°C
q = (22.5g)(0.45j/g·°C)((final) - 20°C) = 324j
=> T(final) = [324j/(22.5g)(0.45j/g·°C)] + 20°C = 52°C