Identify the clusters in the data.

The number of seconds it takes until the ball reaches max height is 2 seconds and the maximum height is 112 feet, and the number of seconds it takes until the ball hits the ground will be 6.9 seconds.

When a body is thrown in the air then the motion under the gravity is known as projectile motion.

A person standing close the the edge on the top of a 80 foot building throws a baseball vertically upward. the quadratic function

h(t) = -8t² + 32t + 80 models the ball's height above the ground, h(t), in feet, t seconds after it was thrown.

The number of second to reach at maximum height will be

We know that at maximum height, the rate will be zero. Then we have

       h'(t) = 0

-16t + 32 = 0

            t = 2 seconds

Then the maximum height will be

h(t) = -8(2)² + 32 x 2 + 80

h(t) = -32 + 64 +80

h(t) = -32 + 144

h(t) = 112 feet

Then the number of the seconds to reach at the ground will be

-8t² + 32t + 80 = -80

-8t² + 32t + 160 =0

t² - 4t - 20 = 0

Then t will be

[tex]\rm t = \dfrac{-(4) \pm \sqrt{(-4)^2 - 4 * 1 * -160}}{2*1}[/tex]

Then we have

t = 6.9 and -2.9

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Answer:

Step-by-step explanation:

From left to right:

(don't listen to the other ways. this should be correct).

(Just g o o g l e it).

Using a dot plot, it is found that the number of dots of each point are given as follows:

The dot plot shows the number of times each measure appears in the data-set.

In this problem, one measure has a value of 1/8, hence:

The value [tex]\frac{1}{8}[/tex] will have one dot above it.

Two measures have a value of 1/4, hence:

The value [tex]\frac{1}{4}[/tex] will have two dots above it.

Three measures have a value of 3/8, hence:

The value [tex]\frac{3}{8}[/tex] will have three dots above it.

Five measures have a value of 1/2, hence:

The value [tex]\frac{1}{2}[/tex] will have five dots above it.

Two measures have a value of 5/8, hence:

The value [tex]\frac{5}{8}[/tex] will have two dots above it.

Three measures have a value of 3/4, hence:

The value [tex]\frac{3}{4}[/tex] will have three dots above it.

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Answer:

1 2 3 5 2 3

Step-by-step explanation:

Answer:

$0.60 per pound

Step-by-step explanation:

Dollars per pound :

Answer:

14.7868 ml are equal to 1 tablespoon

Step-by-step explanation:

1 tablespoon is equivalent to __14.7868___ ml.

Hope This Helped

Answer:

14.7868ml or 15 ml

Step-by-step explanation:

it can be either one since 14.7686 is close to 15

Answer:

279 miles

Step-by-step explanation:

31 miles/gal  *  9 gallons = 279 miles

Answer:

2 733.25 + 7270 = 10 003.25

Step-by-step explanation:

192 * 36 = 6 912 +358 = 7 270

45425 - 36000 ( allowed miles for 3 years )

9 425 * 0.29 = 2 733.25

Answer:

3, 11, 32, 35, 38

Step-by-step explanation:

Ascending order means to place in order from smallest to largest.

Hope this helps!

If not, I am sorry.

Answer:

392

Step-by-step explanation:

hope this helps!!

Answer:

Always include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their own.

Step-by-step explanation:

Answer:

angle c: 28.5°

angle a: 123°

Step-by-step explanation:

The system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have three linear equations in three variables:

x - y - z = 0 ..(1)

2x - y + 2z = 1 ..(2)

x - y + z = -2 ..(3)

From the equation (1):

[tex]\rm x=y+z[/tex]

Plug this value in the equation (2) and (3):

[tex]\rm 2\left(y+z\right)-y+2z=1\\\\ y+z-y+z=-2[/tex]

After solving we get:

z = -1

y = 5

Plug the above two values in equation (1) we get:

x = 4

Thus, the system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

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To find the length of the sides of this parallelogram, we just have to calculate the length of each side and then proceed to find the perimeter.

The perimeter of the parallelogram is 13 units.

To calculate the perimeter of a parallelogram, we need the values of the length of the sides. However, if we have the details of two opposite sides, we can find the perimeter of the parallelogram because opposite sides are equal.

The perimeter of MNOP can be calculated as

[tex]perimeter = 2(MP + MN)[/tex]

We can substitute the values into the equation and solve

[tex]perimeter = 2(MP + MN)\\perimeter = 2 * (4.5 + 2)\\perimeter = 2 * 6.5\\perimeter = 13[/tex]

The perimeter of the parallelogram is 13 units.

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Answer:

6618

Step-by-step explanation:

6896 - 278 = 6618

Hope this helps

Answer:It’s 6,618

Step-by-step explanation: Since it’s less you have to subtract, 6,896 - 278 = 6,618.

Hope this helped ya! :D

The expressions for (h+g)(x) and (h-g)(x) and evaluate (h-g) (4) is 9x-3 ,  x+3 and 7

A function is defined as the law that build relation between a dependent variable and an independent variable.

It is given that

functions g and h are defined for all real numbers x as follows.

g(x) = 5x

h(x) = 4x-3

the expressions for (h+g)(x)= ?

(h+g)(x)= 5x+4x-3

(h+g)(x)= 9x-3

and (h-g)(x) = ?

(h-g)(x) = 5x - 4x +3

(h-g)(x) = x+3

and evaluate (h-g) (4).

(h-g)(x) = x+3

at x = 4

(h-g)(4) = 4+3 = 7

Therefore the value for the functions have been determined.

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The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π

An equation is an expression that shows the relationship between two or more numbers and variables.

angle of arc ACB = 360° - 35° = 325°

The length of major arc ACB = (325/360) * π * 10 = (325/36)π

The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π

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The value of the diagonal will be equal to 20√2.

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal to the square of the sum of the other two sides.

The value of the diagonal by the Pythagorean theorem.

H²  =  B²  +  P²

H²  =  20²  +   20²

H²  =  400   +  400

H  =  √800

H  =  20√2

Therefore the value of the diagonal will be equal to 20√2.

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Inequalities are expression not separated by an equal sign. None of the inequality is correct since there is absence of equal sign.

Inequalities are expression not separated by an equal sign. According to the question, we ned the inequality's graph that will have a dashed boundary line.

An inequality that will have solid boundary line must include only the less than or equal to sign < or greater than or equal to > sign.

From the option given, none of the inequality is correct since there is absence of equal sign.

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Step-by-step explanation:

this is the problem to sum the numbers 1 ... n.

remember the old trick by adding

n + 1

n-1 + 2 = n + 1

n-2 + 3 = n + 1

...

and doing this n/2 times, giving us a sum

n×(n+1)/2

for n = 30 we get

30×31/2 = 15×31 = 465

so, 465 people will perform.

Answer:  93 boxes will be needed

Step-by-step explanation:

     If each box holds 16 paperweights, and 1,486 need to be packaged, we will divide 1,486 by 16.

1,486 / 16 = 92.875

    We will assume you cannot have 0.875 of a box, so we will round up to:

              93 boxes will be needed

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Answer:

w=2  w = -9

Step-by-step explanation:

w^2 + 7w - 18 = 0

We can factor this equation

What 2 numbers multiply to -18 and add to 7

9*-2 = -18

9+-2 = 7

(w-2) (w+9) = 0

Using the zero product property

w-2 = 0    w+9 =0

w=2  w = -9

Answer:

[tex]w_1=2\\w_2=-9[/tex]

Step-by-step explanation:

This is going to be solved using the quadratic formula.

1. Determine the quadratic equation’s coefficient [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex].

Use the standard form, [tex]ax^2+bx+c=0[/tex]  , to find the coefficients of our equation,

[tex]w^2+7w-18=0[/tex]:

a = 1

b = 7

c = -18

2. Plug these coefficients into the quadratic formula

The quadratic formula gives us the roots for  [tex]aw^2+bw+c=0[/tex] , in which [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] are numbers (or coefficients), as follows:

[tex]w=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

7 additional steps:

a = 1

b = 7

c = -18

[tex]w=\frac{-7\pm\sqrt{7^2=4*1*-18} }{2*1}[/tex]

Simplify exponents and square roots

[tex]w=\frac{-7\pm\sqrt{49-4*1*-18} }{2*1}[/tex]

Perform any multiplication or division, from left to right:

[tex]w=\frac{-7\pm\sqrt{49-4*-18}}{2*1}\\w=\frac{-7\pm\sqrt{49--72}}{2*1}\\\\w=\frac{-7\pm\sqrt{49+72}}{2*1}\\w=\frac{-7\pm\sqrt{121}}{2*1}[/tex]

to get the result:

[tex]w=\frac{-7\pm\sqrt{49-4*-18}}{2}[/tex]

3. Simplify square root [tex]\sqrt{121}[/tex]

Simplify 121 by finding its prime factors:

121 ( 11 * 11)

The prime factorization of 121 is 11^2

Write the prime factors:

[tex]\sqrt{121}=\sqrt{11\cdot 11}[/tex]

Group the prime factors into pairs and rewrite them in exponent form:

'[tex]\sqrt{11\cdot 11}=\sqrt{11^2}[/tex]

Use the rule [tex]\sqrt{x^2=x}[/tex]  to simplify further:

[tex]\sqrt{11^2}=11[/tex]

4. Solve the equation for w

[tex]w=\frac{-7\pm11}{2}[/tex]

The ±  means two answers are possible.

Separate the equations:

[tex]w_1=\frac{(-7+11)}{2}[/tex] and [tex]w_2=\frac{-7-11}{2}[/tex]

[tex]w_1=\frac{-7+11}{2}[/tex]

[tex]w_1=\frac{4}{2}[/tex]

[tex]w_1=2[/tex]

[tex]w_2=\frac{-7-11}{2}[/tex]

[tex]w_2=\frac{-18}{2}[/tex]

[tex]w_2=-9[/tex]

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Why learn this

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Terms and topics

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Learn more:

Answer:

See below

Step-by-step explanation:

The CENTER will de directly between the two given points

h, k   = -1,7

so...so far the circle eq is

  (x+1)^2 + ( y-7)^2

the RADIUS is  1/2 of the distance between the given points

1/2  d = (using distance formula) = 1/2 sqrt 80     = 4.472

then the equation of the circle in standard form

 (x+1)^2  + (y-7)^2 = 20          

to get the equation of any straight line, we simply need two points off of it, let's use those two points from the table in the picture below.

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{13})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-17}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-17}-\stackrel{y1}{13}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-4)}}} \implies \cfrac{-30}{6 +4} \implies \cfrac{ -30 }{ 10 }\implies -3[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{13}=\stackrel{m}{-3}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-13=-3(x+4)\implies y-13=-3x-12\implies y=-3x+1[/tex]