I REALLY NEED HELP WITH QUESTION!! URGENTLY!! ANYONE WHO'S GOOD AT MATHS ​

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

Look back at the plans these students used to solve the word problem below.
Who found a correct solution?
- STEP 4: LOOK BACK
According to soap box derby rules, a racer must weigh 250
pounds or less. The Math Club's car weighed in at 266
pounds on the day of the derby. How many pounds did the
Math Club need to remove from their soap box racer?
Dana added the weight limit to the Hector subtracted the weight limit
racer's weight. Since
from the racer's weight. Since
250 +266 = 516, the Math Club 266 - 250 = 16, the Math Club
needed to remove 516 pounds from needed to remove 16 pounds
the racer
from the racer
O A. Dana
B. Hector

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Use inductive reasoning to create two possible sequences that describe the giant panda bear's
daily diet. Write the first five terms of each sequence.
First Sequence:
Second Sequence:
Describe the pattern you used to write each sequence. Which sequence do you think is more
likely? Explain your reasoning.

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Plz I need help

























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Total amount =

Total interest =

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Help , please ?? If you can thank you ..4 more

Learning Task 2 B. Perform the indicated operations. Write your solution in the box below. Add Subtract: 1. (5x4 - 3x2 + 4) + (6x3 - 4x2 - 7) 6. (5x3 - 7x2 + 3x - 4) -(873 + 2x2 32-7) 2.-7x3y + 4x2y2 - 2 and 4x3y + 1 - 8x2y2 7. (2x2y - 5xy + 3y2 -- (7xy -- 672 - 5729) 3. (5 + 24y3 - 7y2) + (-6y3 + 7y2 + 5) 8. (9x5 - 623 + 712) - (773 4. (2xs - 6x3 - 12x2 - 4) + (-11x + 8x + 2x2 + 6) 9. Subtract 4x3.5x - 8 from 672 - 3x + 8 5. (3y5 - 2y + y* + 2y3 + 5) and (238 + 3y8 + 2+ 7) 10. (1.599 + 4.8y2 + 12) - (ya - 1.742 + 2y) Solution and Answer 67 + 2x2) -​

Can someone please help me

An investor makes an investment of $1,000,000.00 to buy a small, select service hotel in Daytona Beach. She achieves a
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Anyone??

help me please please ​

Math isn't really my thing, so if you could help I would really, really appreciate!!​

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help me pls
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EXERCISE 11D

1. Draw MON = 81° and bisect it.
2. Draw an angle of measure 175°.
3. Construct a right angle and then bisect it.
4. Draw ABC= 162º and divide it into four equal parts.
5. Construct the following angles using a ruler and compass. a 60° b. 30° C. 120° d. 135°
6. Draw an angle of 107° and make a copy of it. Verify your construction by ac measurement. a.
7. Draw an angle of 83º. Make a copy of its complementary angle.

✅help me to solve this

​

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Help help help math math

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