I need help with this

Answer: 2 miles per hour

Step-by-step explanation:

Answer:

the ratio would be 03:18, 1:6, 2:12

Answer: I have the same problem exact same what grade are you in?

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

120 divided by 60 = 2. The length of the box is 2 inches. This can be proven through substitution: 120 = 6 x 10 x 2.

Answer:

Step-by-step explanation:

24 - 3 = 21 • 4 = 84

Answer:

13/3

Step-by-step explanation:

3(4x)+6(4x)+30-x

39=9x

divide 9 on each side

x=13/3

yw if its right make me brainliest

Answer: In 36 minutes both buses will end up at the library.

Step-by-step explanation:

Given: Buses from one route stop at the library every 9 minutes.

Buses from the other route stop at the library every 12 minutes.

The number of minutes in which both buses will end up at the library= LCM(9,12)

Now , 9= 3 x 3

12= 2 x 2 x 3

LCM(9,12) = 2 x 2 x 3 x 3 = 36

Answer:

n = -7-5i

Step-by-step explanation:

This is the inverse property of addition

Ok, so you got the parent function y = x^2 and it changed to y = x^2 -8

#'s inside the parenthesis would move it left or right and #'s outside the parenthesis would move it up or down. Since there are no parenthesis the x coordinate is 0, hence it doesn't move left or right. Because of this we know that the graph will be moved up or down. Now we look to see is the # negative or positive. If negative, we move it down. If positive, we move it up. Looking at this problem, we see that it will move it down. Next look at the #. This will indicate how much you will move the graph. In this problem, we will move the graph down 8.

Therefore,

When you change the graph y = x^2 to y = x^2 -8, you are moving the graph down 8.

Answer: So if the equation change the graph as y=x^2-8 the graph will move 8 points down.

Step-by-step explanation:

Answer:

x ➡️ ×3 ➡️÷ 2 ➡️ - 4 ➡️ × 6 ➡️ 30

6⬅️ ÷3 ⬅️× 2 ⬅️ +4 ⬅️ ÷6 ⬅️ 30

x=6

Answer:

x=3.76 (3.7 recurring rounded to 2 decimal places)

x= [tex]\frac{34}{9}[/tex]

Step-by-step explanation:

You follow the simple steps of finding the value of a variable in an equation by doing PEMDAS/BOMDAS backwards

[tex]6(\frac{3x}{2}-4)=30[/tex]

[tex]6(\frac{3x}{2}-4+4)=30+4[/tex]

[tex]6(\frac{3x/3}{y})=\frac{34}{3}[/tex]

[tex]6(2\frac{x}{2})=2\times11.3 recurring[/tex]

[tex]\frac{6x}{6} = \frac{22.6}{6}[/tex]

[tex]x=3.76\\x=\frac{34}{9}[/tex]

Answer:

Joe is 48 Aaron is 16

Step-by-step explanation:

64=3x+x

64=4x

64/4=16

16

16x3=48

21 21 21......... im gonna write to take up space random dumb thingz tingz hee bhee

Answer:

Step-by-step explanation:

(2x -3y + 5z) - (-4x -y +8z)

6x-2y-3z  combine terms With the - in between, it changes the signs to the opposite in the second ()

Answer:

The 16 ounce bottle is the cheapest costing only .15 cents per ounces wile the 12 ounce bottle costs .16 cents and ounce.

Step-by-step explanation:

Answer:

The Bottle that cost $2.40

Step-by-step explanation:

You divide the cost by the number of ounces to get the the cost per ounce

You do that to both bottles

The bottle with the less amount of money per ounce is the answer

Bottle that is $1.92 = $0.16 a ounce

Bottle that is $2.40 = $0.15 a ounce

Answer:

I believe the answer is 3. AM = MB

Step-by-step explanation:

For the first option, 1/2 of AB is obviously equal to AM. Therefore, the second option is also correct.

As far as the fourth option, CD equals AB since a compass was used to gather the points, ensuring they are equidistance.

We have to calculate the EAC for both the conveyor belt system.

Solutions :

Equivalent Annual Cost or (EAC) for the SYSTEM-A

[tex]$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $[/tex]tax rate )

                                [tex]$=-855,000(1-0.23)+\left[\left(\frac{280,000}{4}\right)\times 0.23\right]$[/tex]

                               [tex]$= (-85,000 \times 0.77 ) + (70,000 \times 0.23)$[/tex]

                               = $ 49,350

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -49,350                  0.909091                          -44,863.64

2                  -49,350                   0.826446                          -40,785.12

3                   -49,350                  0.751315                            -37,077.39

4                   -49,350                 0.683013                         -33,706.71  

     Total                                    $ 3.169865                       $ -156,432.86  

Therefore, Net Present value = present value of the annual cash flow - initial investment.

           = 156,432.86 - 280,000

          = $ 436,432.86 (negative)

Now the EAC or the Equivalent Annual Cost for System A :

[tex]$\text{EAC}= \text{Net present value / (PVIFA 10 percent, 4 years)}$[/tex]

        [tex]$=\frac{436,432.86}{3.169865}$[/tex]

        [tex]$= 137,681.86 $[/tex] dollar (negative)

[tex]$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $[/tex]tax rate)

[tex]$=79,000(1-0.23)+\left[\left(\frac{360,000}{6}\right) \times 0.23\right]$[/tex]

[tex]$=(-78,000 \times 0.77)+(60,000 \times 0.23)$[/tex]

= -$ 47,030

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -47,030                  0.909091                          -42,754.55

2                  -47,030                   0.826446                          -38,867.77

3                   -47,030                  0.751315                           -35,334.34

4                   -47,030                 0.683013                            -32,122.12

5                  -47,030                  0.620921                            -29,201.93

6                  -47,030                 0.564474                            -26,547.21  

    Total                                     $ 4.355261                       $  -204,827.91

Net Present Value = Present Value of annual cash inflows – Initial Investment

[tex]$= 204,827.91 - 360,000$[/tex]

= -$ 564,827.91 (negative)

EAC for system B:

Equivalent Annual Cost for system B [tex]$=\frac{\text{net present value}}{\text{PVIFA 10 \text percent, 6 years}}$[/tex]

[tex]$=\frac{-564,827.91}{4.355261}$[/tex]

= -$129,688.66 (negative)

Answer:

Step-by-step explanation:

1). Replace one equation with a multiple of itself.

2x + 7y = 3 ⇔ 4(2x) + 4(7y) = 4(3)

2). Yes, systems are equivalent.

Answer:

It is C

Step-by-step explanation:

To get the new coordinates you would move the shape up the y-axis 8 times, and right on the x-axis 8 times as well.

Answer:

C

Step-by-step explanation:

You can either compare two similar points or just count the units on the graph

Answer:

14976

Step-by-step explanation:

20/100=0.2

12480*0.2=2496

12480+2496=14976

Answer:B

Step-by-step explanation:just took it

Answer:

(8, 11)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define systems

12x + 6y = 162

2x + 10y = 126

Step 2: Simplify systems

2x + y = 27

x + 5y = 63

Step 3: Rewrite systems

2x + y = 27

x = 63 - 5y

Step 4: Solve for y

Step 5: Solve for x

Answer:

x = 8 and y = 11

Step-by-step explanation:

solve for y

12x + 6y = 162

-12x          -12x

6y = 162 - 12x

/6             /6  

y = 27 - 2x

substitute

2x + 10(y) = 126

2x + 10(27 - 2x) = 126

2x + 270 - 20x = 126

-18x + 270 = 126

       -270    -270

-18x = -144

-18        -18

x = 8

substitute again:

y = 27 - 2(x)

y = 27 - 2(8)

y = 27 - 16

y = 11

Answer:

Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

a is [tex]2q^2r[/tex]

b is: [tex]3s^2t[/tex]

Step-by-step explanation:

We need to factor [tex]8q^6r^3 + 27s^6t^3[/tex]

[tex]8q^6r^3 + 27s^6t^3\\=(2q^2r)^3+(3s^2t)^3\\Applying \ formula: a^3 + b^3 = (a + b)(a^2 - ab + b^2)\\=(2q^2r+3s^2t)((2q^2r)^2-2(2q^2r)(3s^2t)+(3s^2t)^2)\\=(2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

So, Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

What is a? a is [tex]2q^2r[/tex]

What is b? b is: [tex]3s^2t[/tex]

Answer:

The next answers for the page are 2, 3, 4, 9

Step-by-step explanation:

Answer:

0.4 times .7 equals .28. So e = .7

Step-by-step explanation:

Answer:

44554

Step-by-step explanation:

Answer:

its 1575/255 or 6.176470588

Step-by-step explanation:

Answer:

[tex]m=\frac{2}{3}[/tex]

General Formulas and Concepts:

Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Step-by-step explanation:

Step 1: Define points

(3, 5)

(6, 7)

Step 2: Find slope m

m = y2 - y1 / x2 - x1

substitute values (3,5) , (6,7)

m = 7 - (5) / 6 - (3)

simplify

m = 2/3

Answer:

in about 0.92 hours or 55.2 minutes

Step-by-step explanation:

The time they take to paint the room:

Pragnesh and Qazi  = 2 hours

Pragnesh and Ronghui = 3 hours

Qazi and Ronghui = 4 hours

Meaning, each hour (1)  they'll paint:

Pragnesh and Qazi  =  [tex]\frac{1}{2th}[/tex] of the room

Pragnesh and Ronghui = [tex]\frac{1}{3th}[/tex] of the room

Qazi and Ronghui = [tex]\frac{1}{4th}[/tex] of the room

By summing all their work abilities we can determine how long it would take if all three students worked together to paint the fence, which is:

[tex]\frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{13}{12th}[/tex] of the room each hour. Therefore the whole (1) room would be painted in 1 ÷ [tex]\frac{13}{12}[/tex] = [tex]\frac{12}{13} hours[/tex] or 0.92 hours or 55.2 minutes (0.92 * 60).

Answer:

-24 = 3x + 9

-24 - 9 = 3x

-33 = 3x

-33/3 = x

-11 = x

x = -11

Add 9 to both sides

So

-15=2x

Divide both sides by 2

So

X=-7.5

Hope this helps!

19 mph + 14 mph = 33 mph

198 miles / 33 mph = 6 hours

It will take them 6 hours to meet.

im pretty sure it's 6 hours

hopefully you get it right :)