I need help with my math, please?

Answer: Consider the plot created from the residuals of a line of best fit for a set of data. Does the residual plot show that the line of best fit is appropriate for the data? Yes, the points have no pattern.

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

Both legs of an isosceles triangle are congruent so they can be made to say that one leg=the equation of the other leg.

Answer:

I think its number 4

Step-by-step explanation:

but im not sure

Step-by-step explanation:

here is your answer hope you will enjoy

please mark me as a brainlist

thank you

Answer:

6543÷29

=225.620.......

Answer:

x = 1, -2, -7

Step-by-step explanation:

Just factor, you got this!

Answer:

g.....

Step-by-step explanation:

g.....

the letter is g

The letter g comes after the letter f.

An alphabet is a set of graphs or characters used to represent the phonemic structure of a language

The english alphabets are a, b, , c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u , v, w, x, y and z.

The alphabets help to form the basis of our language and communication for a lifetime.

There are twenty six letters in the english alphabets.

As we  see the order of alphabets.

The letter g is next to the letter f.

They help to form the basis of our language and communication for a lifetime.

Hence, the letter g comes after the letter f.

To learn more on Alphabets click:

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Answer:

-1 and -6.

Step-by-step explanation:

-1 and -6

-1*-6 = 6

-1 + (-6) = -1-6= -7.

Answer:

Step-by-step explanation:

1) Sum = - 9

Product = -36

Factors = -12 , 3     {-12 + 3 = -9  & -12*3 = -36}

3a²  - 9a - 12 = 3a² + 3a - 12a - 12

                    =3a(a + 1) - 12(a + 1)

                    = (a + 1) (3a - 12)

2) 4a² + 38a - 20 = 4a² + 40a - 2a  - 20

                            =4a(a + 10) - 2(a + 10)

                            =(a + 10)(4a - 2)

3) 11a² + 30a - 9 = 11a² + 33a - 3a - 9

                          = 11a(a + 3) - 3(a + 3)

                          =(a + 3)(11a - 3)

Step-by-step explanation:

The answer is dhdt=325πmmin.

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

V=πr2h

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

V=π(5m)2h

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

dVdt=(25m2)πdhdt

In the problem, we are given 3m3min which is dVdt. So we substitute this in:

dhdt=3m3min(25m2)π=325πmmin

Answer:

Step-by-step explanation:

2.  Should be 500

8.  Should be 290

The rest are correct

Answer:

1. 100 good job

2. 500 round to the nearest hundred either 400 or 500. 500 is closer.

3. 9,000 good job

4. 7,800 good job

5. 250 good job

6. 4,000 good job

7. 6,800 good job

8. 290 round to the nearest 10 either 290 or 300 290 is closer

9. 400 good job

10. 8,000 good job

Step-by-step explanation:

Rounding to the nearest number is up at 5 and below for 4 and less. The same concept applies to larger numbers.

Answer:

8/13

Step-by-step explanation:

8x

------

13x

The x in the numerator and denominator cancel

8/13

Answer: 45

Step-by-step explanation:

Answer:

your answer i think is 2/3 sorry if i'm wrong

Step-by-step explanation:

I will do that soon okay I will

Answer:

The length of Due to the accuracy of the tape measure Avani used, the play area is 7.5 meters. The width of the play area is the amount of foam needed to cover the play area is 5.3 meters.

Step-by-step explanation:

Answer:

39.8

Step-by-step explanation:

edge 2022

Answer:

-4,-8 : 8,8

Step-by-step explanation:

(hope this helps) :)

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]

Answer:

the point (0,6) is the point that is 1/6 of the way

Answer:

I would think its C

Step-by-step explanation:

Since you are subtracting 15 from 275, it would be 275-15

i am assuming you dont need any help on the variables, so I hope this helps :)

If i am wrong, please let me know :DD

have a nice day, *insert preferred referral here*!!

The function that can be used to evaluate 't', the total number of gallons of water in the tank after w weeks is G(t) = 275 - 15w and this can be determined by using the given data.

Given :

The following steps can be used in order to determine the function that can be used to evaluate 't', the total number of gallons of water in the tank after w weeks:

Step 1 - Let the total number of weeks be 'w'.

Step 2 - So, the total amount of water reduced from the tank is:

= 15w

Step 3 - So, the function that can be used to evaluate 't', the total number of gallons of water in the tank after w weeks is given below:

G(t) = 275 - 15w

Therefore, the correct option is B).

For more information, refer to the link given below:

https://brainly.com/question/25834626

Answer:

-120

Step-by-step explanation:

subtract 45 to both sides

m/8 = -15

multiply by 8 on both sides.

with the fraction just multiply by the bottom number to make m by itself.

m = -15*8

m= -120

Answer:

-120

Step-by-step explanation:

30-45= -15

-15×8= -120

Answer:

i think it is a or c

Step-by-step explanation:

Answer:

[tex] \frac{8}{21} . \: \frac{5}{16} \\ \\ \frac{5}{42} \\ \\ 0.119[/tex]

[tex] \frac{12}{25} . \: \frac{15}{16} \\ \\ \frac{9}{20} \\ \\ 0.45[/tex]

Answer:

8/21 . 5/16 = 5/42

12/25 . 15/16 = 9/20

Step-by-step explanation:

16 = 2 x 8

8/21 . 5/16

= ( 8 x 5 ) / ( 21 x 16 )

= ( 8 x 5 ) / ( 21 x 2 x 8 )

= 5 / ( 21 x 2 )

= 5/42

12 = 3 x 4

15 = 3 x 5

25 = 5 x 5

16 = 4 x 4

12/25 . 15/16

= ( 3 x 4 ) / ( 5 x 5 ) . ( 3 x 5 ) / ( 4 x 4 )

= ( 3 x 4 x 3 x 5 ) / ( 5 x 5 x 4 x 4 )

= ( 3 x 3 ) / ( 5 x 4 )

= 9/20

Answer:

it would just be a DOT at positive one on a graph

Answer:

The associative property

Step-by-step explanation:

:/ wait its u again lol

Answer:

I think its 30 hope this helps and sorry if I get it wrong

Answer:

B) 30

Ok now that you have the answer......

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WHAT AM I???????

[tex] {\large\underline{\sf{Solution-}}}[/tex]

Given function is

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

We know

Domain of a function is defined as set of those real values of x for which function is well defined.

So, y is defined when

[tex]\rm \longmapsto\: {x}^{2} - 4 \geqslant 0[/tex]

[tex]\rm \longmapsto\: {x}^{2} - {2}^{2} \geqslant 0[/tex]

[tex]\rm \longmapsto\: (x - 2)(x + 2) \geqslant 0[/tex]

[tex]\rm\implies \:x \leqslant - 2 \: \: or \: \: x \geqslant 2[/tex]

[tex]\rm\implies \:x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

Now, To find the range of function

We know,

Range of a function is defined as set of those real values which is obtained by assigning the values to x.

So,

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

On squaring both sides, we get

[tex]\rm \longmapsto\: {y}^{2} = {x}^{2} - 4[/tex]

[tex]\rm \longmapsto\: {y}^{2} + 4= {x}^{2}[/tex]

[tex]\rm \longmapsto\:x = \sqrt{ {y}^{2} + 4 } [/tex]

Now, x is defined when

[tex]\rm \longmapsto\: {y}^{2} + 4 \geqslant 0 \: which \: is \: always \: true \: \forall \: y \in \: real \: number[/tex]

But,

[tex]\rm \longmapsto\:y \geqslant 0[/tex]

Hence,

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

So, we have

[tex]\rm\implies \:Domain \: of \: function : x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

and

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]