i need help what tis 10+10

Rewriting the given term (55.44).33 using the Associative Law of Multiplication, we have 55.(44.33). Therefore, 1st option is correct.

The given terms are written as -

(55.44).33

We have to rewrite the given term using the Associative Law of Multiplication.

According to the Associative Law of Multiplication, the terms or factors can be associated in any expected ways, i.e.,

a(bc) = (ab)c

So, our given term in the question (55.44).33 can be rewritten according to the Associative Law of Multiplication as -

(55.44).33 = 55.(44.33)

Thus, rewriting the given term (55.44).33 using the Associative Law of Multiplication gives us 55.(44.33). Therefore, 1st option is correct.

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Answer:

837/1150=0.727

Or 73%

Step-by-step explanation:

Answer: 96 R12

Step-by-step explanation:

The end points behavior of the function:

(a) If x goes to positive infinity then the function goes to positive infinity. If x goes to negative infinity then the function goes to negative infinity.

(b) The zeros of the function f(x) are -3, -1, -1, and 1.

(c) The y-intercept is at (0,-3).

What is the endpoint behaviors of a polynomial?

A polynomial function's final behaviour is how its graph behaves as x gets closer to positive or negative infinity. The graph's final behavior is determined by a polynomial function's degree and leading coefficient.

What are zeros of a polynomial?

The locations where a polynomial becomes zero overall are known as the zeros of the polynomial. The term "zero polynomial" refers to a polynomial with a value of zero (-1). The highest power of the variable x is referred to as a polynomial's degree. A linear polynomial is a polynomial with degree 1.

Given function is f(x) = (x+3)(x+1)^2(x-1).

If x = ∞, then f(x) = ∞. The one endpoint of the function will go positive infinity.

If x =- ∞, then f(x) = -∞. The one endpoint of the function will go negative infinity.

To find the zeros of the polynomial, equate f(x) with zero.

(x+3)(x+1)^2(x-1) = 0

Either, x + 3 =0 → x = -3

or, (x+1)^2 =0 → x = -1

or, x-1 = 0 → x = 1

The zeros of the function are -3, -1, and 1.

To find y-intercept, put x=0 in the given function:

f(0) = (0+3)(0+1)^2(0-1)

→ f(0) = -3

The y-intercept is at (0,-3).

The x-intercepts of the function are zeros of the function.

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Answer:

Step-by-step explanation:

1. Make Words into Math

6 to the power of -3 =

6^-3=

-6*-6*-6=

0.00462962962

Answer:0.00462962962

Step-by-step explanation:

If you take the 4:3 aspect ratio and divide 4 by 3, the result is 1.33. Therefore, you could alternately describe the 4:3 aspect ratio as 1.33:1, meaning that for every 1.33 units in width, there is 1 unit in height. Again, the same applies for the 16:9.

The values of the following functions are:

a. (f ºg)(x) = x+2

b.  (g º f)(x) = 3x + 14

c.  (f º g)(-1) = 3

d.  (g º f)(-1) = 11

Given:

f(x) = x+4 and

g(x) = 3x+2

we are asked to determine the following functions:

a.  (f º g)(x)

⇒ f(g(x))

⇒ f(3x+2)

⇒  (f º g)(x) = (3x+2)+4

= 3x+6

divide by 3

= x+2

b.  (g º f)(x)

⇒ g(f(x))

⇒ g(x+4)

⇒  (g º f)(x) = 3(x+4)+2

= 3x+12+2

= 3x+14

c.  (f º g)(-1)

⇒ f(g(-1))

⇒ f(3(-1)+2)

⇒ f(-3+2)

⇒ f(-1)

⇒  (f º g)(-1) = -1+4

= 3

d.  (g º f)(-1)

⇒ g(f(-1))

⇒ g(-1+4)

⇒ g(3)

⇒  (g º f)(-1) = 3(3)+2

= 11

Hence we get the required answer.

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Answer:

y = 5x + 15

Step-by-step explanation:

You can pick any two points on the graph that intersect the trend line. For instance (5,40) and (3,30)

Formula for Slope:

[tex]y = \frac{y_2 - y_1}{x_2 - x_1} = \frac{40 - 30}{5 - 3} = \frac{10}{2} = 5[/tex]

y intercept:

[tex]y = 15[/tex]

Equation of a line:

[tex]y = mx + b\\m = slope \\b = intercept \\\\y = 5x + 15[/tex]

** also be cautious of the different scaling of the x and y axis.

Answer:

I would say the answer is 1500/3/7/13

Step-by-step explanation:

con for 3,7,13 find it divife it by 1500 cost of burrito

The area of the circle with radius 33 cm is 3419.5 square centimeters.

According to the question,

We have the following information:

Radius of the circle = 33 cm

We know that the following formula is used to find the area of the circle:

Area of the circle = π[tex]r^{2}[/tex] where r is the radius of the circle

There are two approximate values of π which are 22/7 and 3.14. In this case, we will use the value of π as 3.14.

So, we have the following expression:

Area of the circle = 3.14*33*33

Area of the circle = 3419.46 square centimeters

Rounding it off to one decimal point:

3419.5 square centimeters

Hence, the area of the circle with radius 33 cm is 3419.5 square centimeters.

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The tangential speed of the ball is 1.5267

The centripetal acceleration is 2.5897 m/s²

Mass of the ball is m = 7.90 kg

ball moves in a circle having radius r = 0.9 m

angular speed is ω = 0.27 rev /s

given that 1 revolution = 6.283 rad / sec

0.27 rev / sec = ?

ω = 1.696 rad / sec

a. The tangential speed Velocity = rω

w =  1.696

r = 0.9

= 1.696  * 0.9 m

= 1.5267 m / s

b ) centripetal acceleration a = v² / r

= (1.5267 m/s)^2 / 0.9 m

= 2.3308 / 0.9

= 2.5897 m/s²

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Answer:

$9.00 a journal.

Step-by-step explanation:

First off, you can start by subtracting $0.50 from $80.50 because it costs $0.50 to use the card.

You’re left with a new value of $80.00. Since Nabil had $44.00 left over on his card, you can subtract $44.00 from $80.00 to figure out how much he spent.

$80.00

-$44.00

————

$36.00

Since Nabil bought four journals, and they are all equal in cost, you can divide $36.00 by 4 (36/4) and get $9.00.

As per the given relation between ordered mg to kg and supplied mg to ml then weighs  40kg is equal to 2ml.

As given in the question,

Relation between mg to kg as per the ordered is given by ,

0.5 mg / kg

⇒ For 1 kg   = 0.5 mg

Relation between mg to ml as per the supplied is given by ,

10 mg / ml

⇒ 1 ml = 10 mg

Now for 40 kg weighs the relation is given by,

1 kg   = 0.5 mg

⇒ 40 kg   = ( 40 × 0.5) mg

⇒ 40 kg = 20 mg  ___(1)

And

1 ml = 10 mg

⇒ ( 2 × 1) ml = ( 2 × 10 ) mg

⇒ 2ml = 20mg    ____(2)

From  (1) and (2) we get ,

For 40 kg weighs we need 2ml.

Therefore, As per the given relation between ordered mg to kg and supplied mg to ml then weighs  40kg is equal to 2ml.

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The simple interest on $5400 at a rate of 10% per annum for 3 years is $ 1620

The interest on a loan at a fixed rate per annum. The formula used for simple interest is given by

Simple interest (I) = ptr

Where p = principal amount

t = time period

r = rate of interest per year.

Here we have

The sum of $5400 was borrowed from a bank at a rate of 10% per annum for 3 years

Find the simple interest that can be payable

From above observations

Principal amount, P = $5400

Rate of interest = 10% = 10/100 = 0.1

Time period, t = 3 years

The simple interest that can be payable = $5400(3)(0.1) = $ 1620

Therefore,

The simple interest on $5400 at a rate of 10% per annum for 3 years is $ 1620

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Answer:

there is no picture but m∠EBD = m∠EBD would be one of the best one as a guess to what the photo might be

Step-by-step explanation:

Point E is added to the given figure so that point E lies on segment BD and it is exactly halfway between points B and D

The probability that you win is 6%, and the two choices are dependent events option (B) is correct.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

It is given that:

A standard deck of playing cards contains 52 total cards, 13 of which are "spades".

The probability of the first draw:

Probability = favorable outcomes/total outcomes

First draw: 1/4

For the second draw:

Second draw = 12/51

The probability that you win = (1/4)(12/51) = 3/51

In percent:

= (3/51)x100

= 5.88 = 6%

Thus, the probability that you win is 6%, and the two choices are dependent on events option (B) is correct.

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Answer:

-10x+4

Step-by-step explanation:

distribute the minus

-4x-1-6x+5

-10x+4

hopes this helps please mark brainliest

Answer:

43 cm^2

Step-by-step explanation:

Area of the triangle:

A = (1/2) x base x height

A = (1/2) x (2 cm + 4 cm) x 7 cm

A = (1/2) x (6 cm) x 7 cm

A = (1/2) x 42 cm^2

A = 21 cm^2

The area of the triangle is 21 cm^2

Area of the rectangle:

A = length x width

A = 11 cm x 2 cm

A = 22 cm^2

The area of the rectangle is 22 cm^2

Area of the figure = Area of the triangle + Area of the rectangle

Area of the figure = 21 cm^2 + 22 cm^2

Area of the figure = 43 cm^2

The solution to the system of equations y = 1/8x −1 and −5x + 4y = −13 is (2, −3/4). Option D is correct.

We are given:

y = 1/8 x − 1                 ..............equation i.

− 5x + 4y = − 13          ..............equation ii.

We will use the substitution method to solve the given equation.

substitute the value of y from equation i in equation ii, and we will get;

− 5x + 4(1/8 x − 1) = − 13

− 5x + 1/2 x − 4 = − 13

(-10 + 1) / 2 x = -13 + 4

-9/2 x = -9

x = -9 * 2 / -9

x = 2

Put the value of x in equation i, we will get;

y = 1/8 *2 − 1

y = 1/4 - 1

y = 1 - 4 / 4

y = -3 / 4

So, the value of x = 2 and the value of y = -3 / 4.

Thus, the solution to the system of equations y = 1/8x −1 and −5x + 4y = −13 is (2, −3/4). Option D is correct.

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The equation of the line is option (C) y = 2x - 1

First we have to choose two points

The first point = (1, 1)

The second point = (2, 3)

The slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Where m is the slope of the line

[tex](x_1,y_1)[/tex] is the coordinates of first point

[tex](x_2,y_2)[/tex]  is the coordinates of the second point

Substitute the values in the equation

Slope of the line = (3-1) / (2-1)

= 2 / 1

= 2  

From the graph line is intersecting on y axis at y = -1

The slope intercept form of the line

y = mx + b

where m is the slope of the line

b is the y intercept

Substitute the values

y = 2x - 1

Hence, the equation of the line is option (C) y = 2x - 1

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Answer:

Unless you wrote the wrong expressions, non of your choice answers are correct!

Step-by-step explanation:

Solve for x:

2 (x - 7) = 36

Divide both sides of (x - 7)×2 = 36 by 2:

(2 (x - 7))/2 = 36/2

2/2 = 1:

x - 7 = 36/2

The gcd of 36 and 2 is 2, so 36/2 = (2×18)/(2×1) = 2/2×18 = 18:

x - 7 = 18

Add 7 to both sides:

x + (7 - 7) = 7 + 18

7 - 7 = 0:

x = 18 + 7

18 + 7 = 25:

Answer: x = 25

The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

In the question ,

it is given that ,

the fixed rent for a car is = $35 .

the per mile charge for the car is = $0.10 miles

let the number of miles driven is = n miles

the function C that represents the linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is given by

C(n) = fixed charge + (per mile charge)×(number of miles)

Substituting the values , we get

C(n) = 35 + 0.10×n

Therefore , The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

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Answer:
id say, C=0.10=35

Step-by-step explanation:

not really sure, but I tried!

The values of x that make the equation true are approximately  5.7 and  -0.7  .

The given equation is :

[tex]\frac{x+1}{x} = \frac{2}{x-4}[/tex]

Using cross multiplication this can be written as:

or, ( x + 1 ) ( x - 4 ) = 2 x

or, x² + x - 4x - 4 = 2x

Putting all the like terms together.

or, x² + x - 4x -2x - 4 = 0

or, x² - 5x  - 4 = 0

Now we will use the quadratic formula to find the values of x :

[tex]{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }[/tex]

or, [tex]{\displaystyle x={\frac {5\pm {\sqrt {(-5)^{2}-4(1)(-4)}}}{2(1)}}\ \ }[/tex]

or, [tex]x = \frac{5+\sqrt{41}}{2} , \frac{5-\sqrt{41}}{2}[/tex]

or, x ≈ 5.7 , -0.7

The roots or zeros of the expression, which are also on the left side of the equation, are used to indicate the values of x that satisfy the equation.

There can only be two possible solutions to a quadratic problem. One argues that if there is only one remedy, there are many different causes of the problem. There are only four possibilities: one real double root, two complex solutions that appear to be complex conjugates of one another, two real solutions, or two real solutions if each of the coefficients has a real value.

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