I need help on this it need me to label thermal, chemical nuclear, electric, mechanical, electromagnetic

Answer:

1. speed is the distance travelled by an object in unit time

2. velocity is the displacement of a body in in unit time

3. formula of speed =total distance (d)÷ total elapsed time

Answer:

the balls would move closer to each other

Explanation:

Answer:

F = 100 Newtons

Explanation:

F = ma

F = (50 kg)(2 m/s)

F = 100 kg*m/s

Answer: E

Explanation: I looked it up and it said E.

Answer:

plant cell's vacuole can make up 90% of the cell's volume. The large central vacuole essentially stores water. In animal cells, vacuoles are much smaller

Answer:

The answer is "They involve changes in energy".

Explanation:

Energy change is quite important in chemicals because nearly all reactions involve activation energy. They will learn and learn how to utilize different types of energy shifts in the steam cycle. A conversation about what drives chemical processes contributes to entropy and natural energy principles. It may shift from the shape of form. For example, chemicals might change to heat. Laser light can turn substances into power. Its energy can be changed into different kinds, but not wasted or produced.

Answer:

D

Explanation:

change in energy please give brainliest (edge 2021)

Answer: I didnt understand it sorrryryyyyyyy

Explanation:

Answer:

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Answer:

It represents Distance.

Explanation:

Answer:

Bad things

Explanation:

Global warming has many terrible effects on people and the earth itself

such as, death, birth defects, asthmea, breathing conditions, increased diseases.

Answer:

D. Wind

Explanation:

Wind is Basically nothing how can you even use wind again when you cant even touch it you can only feel wind.

Answer:

Elastic potential energy  E = 0.5 J

Explanation:

Let us assume we have to find the elastic potential energy stored in the spring.

Given: k = 100

change in the length of the spring x = 0.2-0.1 = 0.1 m

Elastic potential energy

E = [tex]\frac{1}{2} kx^2[/tex]

plugging the values we get

[tex]E = 0.5\times100\times0.1^2\\=0.5 J[/tex]

Hence, Elastic potential energy  E = 0.5 J

Amy pulls a spring with a spring constant k = 100 N/m, stretching it from its rest length of 0.10 m to 0.20 m.

What is the elastic potential energy stored in the spring?

Answer: 0.5 J

Answer:

ture i think

Explanation:

It is false that one cannot classify matter based on chemical properties.

Matter is the scientific term for any type of material. Matter is defined as anything with mass that occupies space.

Matter requires at least one subatomic particle, though most matter is made up of atoms. A pure substance is sometimes referred to as matter.

Solids, liquids, and gases are the three forms or phases of matter. A substance is defined as matter that is homogeneous and has identical parts.

Substances are classified as either elements or compounds. Elements are pure substances that cannot be chemically decomposed into simpler substances.

Chemically, matter can be classified as pure substance elements and compounds, mixture, or impure substance.

Thus, the given statement is false.

For more details regarding matter, visit:

https://brainly.com/question/10893210

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Respuesta:

0,0560 cal / gºC.

Explicación:

Cantidad de calor; (Q)

Q = mcΔt; Δt = t2 - t1

m = masa, c = capacidad calorífica específica; Δt = cambio de temperatura

c de agua = 1 cal / gºC

c de aluminio = 0,22 cal / gºC

QTotal = Q de agua + Q de aluminio

Q de agua = 450 * 1 * (26 - 23) = 1350 cal

Q de aluminio = 60 * 0.22 * (26 - 23) = 39.6 cal

QTotal = 1350 + 39,6 = 1389,6 cal

Calor perdido = calor ganado

QTotal = calor perdido

- 1389,6 = 335,2 * c * (26 - 100)

-1389,6 = −24804,8 * c

c = 1389,6 / 24804,8

c = 0,056021 cal / gºC.

Capacidad calorífica específica de la plata = 0,0560 cal / gºC.

Answer:

[tex]\alpha =434312\ rev/s^2[/tex]

Explanation:

Given that,

Initial angular speed, [tex]\omega_i=0[/tex]

Final angular speed, [tex]\omega_f=466\ rpm[/tex]

Angular displacement, [tex]\theta=0.25\ rev[/tex]

We need to find the angular acceleration of the CD. Using third equation of rotational kinematics as follows :

[tex]\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{\omega_f^2-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{466^2-0^2}{2\times 0.25}\\\\\alpha =434312\ rev/s^2[/tex]

So, the angular acceleration of the CD is equal to [tex]434312\ rev/s^2[/tex].

Answer:

DNA IS SMALLEST

NUCLEUS IS BIGGEST

PLEASE MARK BAiniRINIiEST

Answer:

the answer is A

Explanation:

hope this helps you will u plz mark me sa brainliest?

Answer:

correct answer is priming

Explanation:

on plato took the test got 100%

Answer:

a) The distance covered by the moving object is approximately 18.85 km

b) The magnitude of the displacement of the object is 0 (no displacement)

Explanation:

From the drawing, we have;

The sale of the drawing is 1 unit = 1 km

The radius of the circle in the drawing along which the object moves = 3 units

Therefore;

The radius of the circle along which the object moves, r = 1 km/unit × 3 units = 3 km

a) The distance covered by the object that moves from point A to B to C to D and finally to A is equal to the circumference of the circle

Therefore;

The distance covered by the moving object, d = 2·π·r

By pugging the value for r = 3 km

d = 2 × π × 3 km = 6·π km ≈ 18.85 km

The distance covered by the moving object, d ≈ 18.85 km

b) The displacement = The object's change in position

The initial position of the object = Point A

The final position of the object = Point A

Therefore, the displacement of the object, A = No displacement = 0 (No difference between the initial and final location of the object

Answer:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Explanation:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

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Explanation:

Answer:

is this the full question?

Explanation:

Answer:

the answer is B. it's too easy

Answer:

h = 20 m

Explanation:

Given that,

Force to lift a firefighter's equipment, F = 270 N

Work done, W = 5400 J

We need to find the height climbed by the firefighter. We know that,

Work done, W = Fd

So,

[tex]d=\dfrac{W}{F}\\\\d=\dfrac{5400}{270}\\\\d=20\ m[/tex]

So, the firefighter climb from a height of 20 m.

Answer:

Its A

Explanation: I got it right on Edge *lip bite*

Answer:

(a) Luna

(b) Luna

Explanation:

(b)

The final speed can be found by using the third equation of motion:

[tex]2as = v_f^2 - v_i^2\\[/tex]

where,

a = acceleration

s = distance covered

vf = final speed

vi = initial speed

For Angela:

a = 2 m/s²

s = 30 m

vi = 4 m/s

vf = v_fa

therefore,

[tex]2(2\ m/s^2)(30\ m) = (v_{fa})^2 - (4\ m/s)^2\\v_{fa}^2 = 120 m^2/s^2 + 16\ m^2/s^2\\v_{fa} = 11.66\ m/s\\[/tex]

For Luna:

a = 3 m/s²

s = 30 m

vi = 3 m/s

vf = v_fl

therefore,

[tex]2(3\ m/s^2)(30\ m) = (v_{fa})^2 - (3\ m/s)^2\\v_{fa}^2 = 180 m^2/s^2 + 9\ m^2/s^2\\v_{fa} = 13.74\ m/s\\[/tex]

Therefore, Luna will be running faster at the end of the race.

(b)

To calculate the time of completion we will use the first equation of motion:

[tex]v_f = v_i + at[/tex]

FOR ANGELA:

[tex]11.66\ m/s = 4\ m/s + (2\ m/s^2)t_a\\t_a = \frac{7.66\ m/s}{2\ m/s^2}\\\\t_a = 3.83\ s[/tex]

FOR LUNA:

[tex]13.74\ m/s = 3\ m/s + (3\ m/s^2)t_l\\t_l = \frac{10.74\ m/s}{3\ m/s^2}\\\\t_l = 3.58\ s[/tex]

Hence, LUNA finishes the race first.

Answer:

They are theories which have a really dark twist or meaning behind the whole theory, some conspiracy theories can also lead to a cliffhanger.

Answer:

80 volts.

Explanation:

From the question,

Applying Ohm's law

V = IR...................... Equation 1

Where V = Voltage, I = maximum current of the bulb, R = Resistance of the bulb.

Given: I = 10 A, R = ohms

Substitute these values into equation 1

V = 10×8

V = 80 volt.

Hence the voltage that can be applied is 80 volt.

The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.