How to find the missing number in a given array from number 1 to n in Java?

Finding the missing number from the N numbers in the given array arr[] of size N-1 with integers in the range [1, N] is the task. The list must not contain any duplicates.

Java method for locating a missing integer in an array of integers from 1 to N:

Make a temp array temp[] of size n + 1 with a value of 0 for each element.

For each element in the input array arr[i], perform the following.

If (temp[arr[i]] == 0), then temp[arr[i]] is 1.

traverse temp[] and output an element of an array with the value of 0. (This is the missing element).

class GFG; import java.io.*; import java.util.*

public static void findMissing(int arr[], int N)

{

int i;

int temp[] = new int[N + 1];

for (i = 0; i <= N; i++) {

 temp[i] = 0;

}for (i = 0; i < N; i++) {

 temp[arr[i] - 1] = 1;

} int ans = 0;

for (i = 0; i <= N; i++) {

 if (temp[i] == 0)

  ans = i + 1;

} System.out.println(ans);

}

public static void main(String[] args) {

int arr[] = { 1, 3, 7, 5, 6, 2 };

int n = arr.length; // Function call

findMissing(arr, n);

}

}

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