How to do this question plz answer me ​

Answer:

Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

a is [tex]2q^2r[/tex]

b is: [tex]3s^2t[/tex]

Step-by-step explanation:

We need to factor [tex]8q^6r^3 + 27s^6t^3[/tex]

[tex]8q^6r^3 + 27s^6t^3\\=(2q^2r)^3+(3s^2t)^3\\Applying \ formula: a^3 + b^3 = (a + b)(a^2 - ab + b^2)\\=(2q^2r+3s^2t)((2q^2r)^2-2(2q^2r)(3s^2t)+(3s^2t)^2)\\=(2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

So, Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]

What is a? a is [tex]2q^2r[/tex]

What is b? b is: [tex]3s^2t[/tex]

Answer:

The next answers for the page are 2, 3, 4, 9

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

A: 42/2 = 21

B: 87.5/5 = 17.5

C: 147/7 = 21

only B is not 21

Answer:

(8, 11)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define systems

12x + 6y = 162

2x + 10y = 126

Step 2: Simplify systems

2x + y = 27

x + 5y = 63

Step 3: Rewrite systems

2x + y = 27

x = 63 - 5y

Step 4: Solve for y

Step 5: Solve for x

Answer:

x = 8 and y = 11

Step-by-step explanation:

solve for y

12x + 6y = 162

-12x          -12x

6y = 162 - 12x

/6             /6  

y = 27 - 2x

substitute

2x + 10(y) = 126

2x + 10(27 - 2x) = 126

2x + 270 - 20x = 126

-18x + 270 = 126

       -270    -270

-18x = -144

-18        -18

x = 8

substitute again:

y = 27 - 2(x)

y = 27 - 2(8)

y = 27 - 16

y = 11

Answer:B

Step-by-step explanation:just took it

Answer: In 36 minutes both buses will end up at the library.

Step-by-step explanation:

Given: Buses from one route stop at the library every 9 minutes.

Buses from the other route stop at the library every 12 minutes.

The number of minutes in which both buses will end up at the library= LCM(9,12)

Now , 9= 3 x 3

12= 2 x 2 x 3

LCM(9,12) = 2 x 2 x 3 x 3 = 36

Answer:

its 1575/255 or 6.176470588

Step-by-step explanation:

Answer:

x ➡️ ×3 ➡️÷ 2 ➡️ - 4 ➡️ × 6 ➡️ 30

6⬅️ ÷3 ⬅️× 2 ⬅️ +4 ⬅️ ÷6 ⬅️ 30

x=6

Answer:

x=3.76 (3.7 recurring rounded to 2 decimal places)

x= [tex]\frac{34}{9}[/tex]

Step-by-step explanation:

You follow the simple steps of finding the value of a variable in an equation by doing PEMDAS/BOMDAS backwards

[tex]6(\frac{3x}{2}-4)=30[/tex]

[tex]6(\frac{3x}{2}-4+4)=30+4[/tex]

[tex]6(\frac{3x/3}{y})=\frac{34}{3}[/tex]

[tex]6(2\frac{x}{2})=2\times11.3 recurring[/tex]

[tex]\frac{6x}{6} = \frac{22.6}{6}[/tex]

[tex]x=3.76\\x=\frac{34}{9}[/tex]

Answer:

Im pretty sure its 16 but please for the love of god wait for someone else to answer

Answer:

44554

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

120 divided by 60 = 2. The length of the box is 2 inches. This can be proven through substitution: 120 = 6 x 10 x 2.

Answer:

14976

Step-by-step explanation:

20/100=0.2

12480*0.2=2496

12480+2496=14976

Answer:

Step-by-step explanation:

24 - 3 = 21 • 4 = 84

Answer:

Alpha JKL has vertices J(-3,7), K(2,8), and L(-3, 12). Find ...brainly.com › Mathematics › High School

20 hours ago — Alpha JKL has vertices J(-3,7), K(2,8), and L(-3, 12). Find the perimeter of AJKL to the nearest tenth. - 18900060.

Step-by-step explanation:

Answer:

Step-by-step explanation:

a) Perimeter = sum of the length of the sides

                    = 13.4 +9.8 +12.3 +11.5

                   = 47 cm

b) Perimeter = 55.3 cm

11.5 + 15.7 +19.8 +x = 55.3

                     47 + x = 55.3

                             x = 55.3 - 47

                             x = 8.3 cm

c) Perimeter of regular hexagon = 67.5 cm

                     Length of one side = 67.5÷ 6

                                                     = 11.25 cm

d) Cost of 1 metre = $ 8.95

Cost of 7.5 metres = 8.95 * 7.5

                               = $ 67.125

Answer:

12 of $3.2 grade is needed

Step-by-step explanation:

Answer:

the ratio would be 03:18, 1:6, 2:12

Answer: I have the same problem exact same what grade are you in?

Step-by-step explanation:

Answer:

See sample table below.

Step-by-step explanation:

The function is given as :

f(x) = 3ˣ

A table of values can be formed as ;

x                calculations           f(x)

-4               3⁻⁴                          0.0123

-3               3⁻³                          0.0370

-2               3⁻²                          0.1111

-1                3⁻¹                           0.3333

0                 3⁰                            1.000

1                  3¹                             3.000

2                 3²                             9.000

3                 3³                              27.00

4                 3⁴                              81.00

Answer:ED=9, DF=9sqrt3, and EF=18

Step-by-step explanation:30-60-90 triangle, a:short, asqrt3:longer, 2a:longest

m∠E=60°

Ok, so you got the parent function y = x^2 and it changed to y = x^2 -8

#'s inside the parenthesis would move it left or right and #'s outside the parenthesis would move it up or down. Since there are no parenthesis the x coordinate is 0, hence it doesn't move left or right. Because of this we know that the graph will be moved up or down. Now we look to see is the # negative or positive. If negative, we move it down. If positive, we move it up. Looking at this problem, we see that it will move it down. Next look at the #. This will indicate how much you will move the graph. In this problem, we will move the graph down 8.

Therefore,

When you change the graph y = x^2 to y = x^2 -8, you are moving the graph down 8.

Answer: So if the equation change the graph as y=x^2-8 the graph will move 8 points down.

Step-by-step explanation:

Answer:

x=4

Step-by-step explanation:

jus answered this

Answer:

X= +4

Step-by-step explanation:

[tex] - 8x + 24 = - 8 \\ - 8x = - 32 \\ x = \frac{ - 32}{ - 8} = + 4[/tex]

Answer:

Scientific Notation:21.5*10^3

Standard Notation:21,500

Step-by-step explanation:

Answer:

Joe is 48 Aaron is 16

Step-by-step explanation:

64=3x+x

64=4x

64/4=16

16

16x3=48

We have to calculate the EAC for both the conveyor belt system.

Solutions :

Equivalent Annual Cost or (EAC) for the SYSTEM-A

[tex]$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $[/tex]tax rate )

                                [tex]$=-855,000(1-0.23)+\left[\left(\frac{280,000}{4}\right)\times 0.23\right]$[/tex]

                               [tex]$= (-85,000 \times 0.77 ) + (70,000 \times 0.23)$[/tex]

                               = $ 49,350

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -49,350                  0.909091                          -44,863.64

2                  -49,350                   0.826446                          -40,785.12

3                   -49,350                  0.751315                            -37,077.39

4                   -49,350                 0.683013                         -33,706.71  

     Total                                    $ 3.169865                       $ -156,432.86  

Therefore, Net Present value = present value of the annual cash flow - initial investment.

           = 156,432.86 - 280,000

          = $ 436,432.86 (negative)

Now the EAC or the Equivalent Annual Cost for System A :

[tex]$\text{EAC}= \text{Net present value / (PVIFA 10 percent, 4 years)}$[/tex]

        [tex]$=\frac{436,432.86}{3.169865}$[/tex]

        [tex]$= 137,681.86 $[/tex] dollar (negative)

[tex]$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $[/tex]tax rate)

[tex]$=79,000(1-0.23)+\left[\left(\frac{360,000}{6}\right) \times 0.23\right]$[/tex]

[tex]$=(-78,000 \times 0.77)+(60,000 \times 0.23)$[/tex]

= -$ 47,030

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -47,030                  0.909091                          -42,754.55

2                  -47,030                   0.826446                          -38,867.77

3                   -47,030                  0.751315                           -35,334.34

4                   -47,030                 0.683013                            -32,122.12

5                  -47,030                  0.620921                            -29,201.93

6                  -47,030                 0.564474                            -26,547.21  

    Total                                     $ 4.355261                       $  -204,827.91

Net Present Value = Present Value of annual cash inflows – Initial Investment

[tex]$= 204,827.91 - 360,000$[/tex]

= -$ 564,827.91 (negative)

EAC for system B:

Equivalent Annual Cost for system B [tex]$=\frac{\text{net present value}}{\text{PVIFA 10 \text percent, 6 years}}$[/tex]

[tex]$=\frac{-564,827.91}{4.355261}$[/tex]

= -$129,688.66 (negative)

Answer:

Josh should by the dump truck with 30,000 pounds of gravel in it

Step-by-step explanation:

the easiest way to find this out is divide 30,000 and 2,500 by 150 and if the answer is a whole number, then you know that is the correct answer.

30,000/150 = 200

2,500/150 = 16.6666666666666

May I have brainliest please? :)

Answer: -3

Step-by-step explanation: I just know this from my previous questions in math.

Answer:

The 16 ounce bottle is the cheapest costing only .15 cents per ounces wile the 12 ounce bottle costs .16 cents and ounce.

Step-by-step explanation:

Answer:

The Bottle that cost $2.40

Step-by-step explanation:

You divide the cost by the number of ounces to get the the cost per ounce

You do that to both bottles

The bottle with the less amount of money per ounce is the answer

Bottle that is $1.92 = $0.16 a ounce

Bottle that is $2.40 = $0.15 a ounce

Answer:

Step-by-step explanation:

1). Replace one equation with a multiple of itself.

2x + 7y = 3 ⇔ 4(2x) + 4(7y) = 4(3)

2). Yes, systems are equivalent.