How much tin II fluoride will be made when reacting 45.0 grams of tin with an excess of hydrofluoric acid if the percent yield for the reaction is 60%

Sn + HF = SnF2 + H2

Answers

Answer 1

Mass of SnF₂ produced : 35.634 g

Further explanation

Reaction

Sn+2HF⇒SnF₂+H₂

mol Sn (Ar 118.710 g/mol) :

[tex]\tt \dfrac{45}{118.710}=0.379[/tex]

mol SnF₂ = mol Sn = 0.379

mass SnF₂ (MW=156.69 g/mol) :

[tex]\tt 0.379\times 156.69=59.39~g[/tex]⇒theoretical

[tex]\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\60\%=\dfrac{actual}{59.39}\times 100\%\\\\actual=0.6\times 59.39=35.634~g[/tex]


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Answers

Answer:

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Explanation:

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Answers

Answer:

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Answers

Answer:

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Explanation:

Explanation:

A magnesium atom that loses two electrons to become a magnesium cation has the same electron configuration as neon. An oxygen atom that gains two electrons to become an oxygen anion also has the same electron configuration as neon.

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Answer:

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C. Cellular respiration

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Which traits are polygenic? Select three options.

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Answer:

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Answer:

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Explanation:

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Answers

Answer:

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General Formulas and Concepts:

Chemistry - Solutions

Reading a Periodic TableUsing Dimensional AnalysisMolarity = moles of solute / liters of solution

Explanation:

Step 1: Define

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Step 2: Define conversions

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Answers

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Answers

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Answer:

Explanation:

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Answer:

OMG Why has nobody answered this FREE 40 POINTS!!!!

For your ConVenIence Sir!

I shall provide thine with the answer, copied from other great sir.

B.) multiplying the first equation by 2.

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Here is an image for Thine HappyNess!!!!!!!!!!!!! :D :D :D :D

Before adding the intermediate chemical equations to get the final products first we have to multiplying the first equation by 2.

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Stoiciometry of any chemical reaction gives idea about the amount of species present before and after the completion of the reaction.

Given first intermediate chemical equation is:

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