How much energy is released when 6.0 g of water is condensed from water
vapor?
A. 6.0 g x 1 mol/18.02 g x 4.186 kJ/mol
B. 6.0 g 1 mol/18.02 g 6.03 kJ/mol
O C. 6.0 g x 1 mol/18.02 g * (-285.83 kJ/mol)
O D. 6.0 g x 1 mol/18.02 g x 40.65 kJ/mol

Answer:

The molecular formula of the compound is C10H16O.

Explanation:

Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.

The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.

The formula of osmotic pressure is,

P = CRT

Now putting the values in the formula we get,

0.328 = C*0.0821*300

C = 0.013317

C = (mass/molecular mass) * (1000/volume of solution in ml)

0.013317 = (0.152/Molecular mass) * (1000/75)

Molecular mass = 152.186

C mass = 152.186 * 0.789 = 120.07 grams

C mole = 120.07/12 = 10

H mass = 152.186 * 0.1059 = 16.11 grams

H mole = 16.11/1 = 16

O mass = 152.186 - 120.07 - 16.116 = 16 grams

O mole = 16/16 = 1

Thus, the molecular formula of the compound will be,

C10H16O

Answer: The correct answer is actually: The final temperature is 400 K, while volume is kept constant.

Explanation: Got it right on test!

Answer:

Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction. The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction.

Answer:

Answer:

don't know really and don't know at alll

Answer:

See explanation and image attached

Explanation:

Hydrogen peroxide is made up of two atoms of hydrogen and two atoms of oxygen as shown in the image attached.

The two oxygen atoms are joined together by a single covalent bond and each of the oxygen atoms are bonded to one hydrogen atom each.

There are two lone pairs on each of the oxygen atoms.

The Lewis(dot) structure for hydrogen peroxide is shown in the image attached to this answer.

Answer:

A. Orange light

Explanation:

According to the band spectrum of white light ( ROYGBIV )

Answer:

I think it blue light is higher

Answer:

1 mole of potassium hydroxide, KOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

KOH + HCl —> KCl + H₂O

Considering the balanced equation above, we can see clearly that 1 mole of potassium hydroxide, KOH reacted with 1 mole of hydrochloric acid, HCl.

Therefore, we can conclude that at every given point, 1 mole of potassium hydroxide, KOH is required to react with 1 mole of hydrochloric acid, HCl.

Answer:

1) donate an H+ ion

Explanation:

option 1 is correct

The given question is incomplete, the complete question is:

A chemist adds 35.0mL of a 6.19 * 10^−4/mmol magnesium fluorideMgF2 solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to

3 significant digits.

Answer:

The correct answer is 1.35 microgram.

Explanation:

Based on the given information,

The volume of magnesium fluoride given is 35 ml, and the concentration of magnesium fluoride is 6.19 × 10⁻⁴ mmol/L.

Now the moles of MgF₂ can be determined by using the formula,

Moles = Concentration × Volume

Moles of MgF₂ = Concentration of MgF₂ × Volume of MgF₂

= 6.19 × 10⁻⁴ mmol/L × 35 ml × L/1000 ml

= 217 × 10⁻⁷ mmol

The molecular mass of magnesium fluoride is 62.3 gram per mole

Thus, the mass of MgF₂ is,

= 217 × 10⁻⁷ mmol × 62.3 g/mol

= 13500 × 10⁻⁷ mg

= 1.35 microgram

Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

Answer:

In the question the mass has two significant figures; thus the mass of O2 released would be 4.0 g (two significant figures). 122.55 g of KClO3 yields 3*32 g of O2

Explanation:

Answer: When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Explanation:

The chemical energy present in fuels actually releases when these fuels are burned or by combustion.

Hence when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

For example, gasoline present in vehicles burns and undergoes chemical change which is then converted into thermal energy. This thermal energy then converts into mechanical energy due to which car moves.

Thus, we can conclude that when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

here's your answer..

Answer:

Following are the responses to the given question:

Explanation:

In the given question the OH could be generated as the H-bond with both the N (nitrogen), which is used to place its N as the partially positive value(+). It is used to simplifies the addition for either its  AA with the imine C. In the above H-bond, the w N is not required as the possibility to use the OCH3

Answer:

baba

Explanation:

ndjshddjdjshshshsushs

Answer:

Your answer would be B because In the first move energy was absorbed, because when energy is gained an electron moves to a higher energy level in the second move energy will be released because that is how an atom moves to a lower energy level.  The jump from level 1 to 4 was bigger than the drop from 4 to 2, because in the first move it moved from more orbitals. thus describing the the energy in the first move had a far energy released in the second move.

Answer:

TRUE ,hope it helped you

Explanation:

Answer:100

Explanation:

Given :

Molarity of HCl solution, M = 0.686 M.

Number of moles, n = 0.037 moles.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

[tex]M = \dfrac{Number \ of \ moles \ of \ solute}{Volume \ in \ liter}\\\\0.686 = \dfrac{0.037}{V}\\\\V = \dfrac{0.037}{0.686}\ L\\\\V = 0.053935 \ L \\\\V = 53.94 \ ml[/tex]

Hence, this is the required solution.

Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Hope this helps Have a good day

Answer:

Density = 2.137 gram per liter (Approx.)

Explanation:

Given:

Gaseous fuel Butane C4H10

Pressure = 0.897 atm

Temperature = 24°C = 24 + 273 = 297 k

Find:

Density of butane gas

Computation:

We know that molar mass of butane = 58.12 g/mol

Density = [molar mass x pressure] / Rt

Density = [58.12 x 0.897] / [0.0821 x 297]

Density = [52.13] / [24.3837]

Density = 2.137 gram per liter (Approx.)