How many moles are in 12 liters of Cl2?

Answer:

7.97 moles of neon are present in the canister.

Explanation:

Avogadro's constant or "Avogadro's number" is the number of constituent particles found in the amount of substance in one mole.

In other words, Avogadro's number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

So, you can apply the following rule of three: if 6.023*10²³ atoms are present in 1 mole, 4.8*10²⁴ atoms are present in how many moles?

[tex]amount of moles=\frac{4.8*10^{24}atoms*1 mole }{6.023*10^{23}atoms}[/tex]

amount of moles= 7.97 moles

7.97 moles of neon are present in the canister.

Answer:

165 ml

Explanation:

We are given;

Initial volume; V_a = 55 ml

Initial molarity; M_a = 3 M

Molarity of desired solution; M_b = 0.75 M

Volume of desired solution; V_b = (55 + x) ml

Where x is the volume of water to be added.

To solve for V_b, we will use the equation ;

M_a•V_a = M_b•V_b

V_b = (M_a•V_a)/M_b

V_b = (3 × 55)/0.75

V_b = 220 mL

Thus;

(55 + x) = 220

x = 220 - 55

x = 165 mL

Answer:

gotta concert mL to L

3.0=mol/0.055( you multiply morality and liter)

0.165 mol

you divide the mole by the other given molarity

0.165/0.75= 0.22 L

0.22 *1000= 220 mL

Explanation:

Answer:

the tables below pull together numbers on the amount of sunshine that each US state usually has a year. there's information by state on the annual average dor percent, hours and days of sun

A map that includes the number of sunny days in South America would be used to study the total amount of sunlight the country receives.

A map is a symbolic depiction emphasizing relationships between elements of some space, such as objects, regions, or themes.

Many maps are static, fixed to paper or some other durable medium, while others are dynamic or interactive. Although most commonly used to depict geography, maps may represent any space, real or fictional, without regard to context or scale, such as in brain mapping, DNA mapping, or computer network topology mapping.

The space being mapped may be two dimensional, such as the surface of the earth, three dimensional, such as the interior of the earth, or even more abstract spaces of any dimension, such as arise in modeling phenomena having many independent variables.

Although the earliest maps known are of the heavens, geographic maps of territory have a very long tradition and exist from ancient times.

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The required answer for the molar solubility of BaSO4 in a 0.250 M solution of NaHSO4 is 1.05 × 10-5 M.

Explanation: Molar solubility is defined as the number of moles of a solute that can dissolve per liter of solution before the solution becomes saturated. It can be determined by calculating the equilibrium concentration of the solute using the solubility product expression for the given ionic compound, BaSO4. We are given the concentration of NaHSO4 and the acid dissociation constant for HSO4-.

The balanced chemical equation is:BaSO4(s) ↔ Ba2+(aq) + SO42-(aq)We are assuming the solution is dilute and that the ionic strength is low. Therefore, we can simplify the expression for the solubility product to:Ksp = [Ba2+][SO42-]The expression for the acid dissociation constant of HSO4- is:Ka = [H+][SO42-]/[HSO4-]

The first step is to calculate the concentration of HSO4-. We can use the equilibrium expression for the acid dissociation reaction to solve for [HSO4-]:Ka = [H+][SO42-]/[HSO4-]Rearranging the expression and solving for [HSO4-]:[HSO4-] = [H+][SO42-]/Ka[HSO4-] = (0.250 × x)/(1.2 × 10-2)[HSO4-] = 20.8333 × xThe molar solubility of BaSO4 in a 0.250 M solution of NaHSO4 is x. At equilibrium, the concentration of Ba2+ and SO42- are both x. Using the solubility product expression:Ksp = [Ba2+][SO42-]Ksp = x2x = sqrt(Ksp)[BaSO4] = x = sqrt(Ksp) = sqrt(1.1 × 10-10) = 1.05 × 10-5 MTherefore, the molar solubility of BaSO4 in a 0.250 M solution of NaHSO4 is 1.05 × 10-5 M.

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Mg is reduced to Mg2+.Hence, the correct option is Mg is oxidized, Co is reduced, and Co is oxidized

In the given reaction, Mg(s) + CoSO4(aq) ⟶ MgSO4(aq) + Co(s), the true statements regarding the given spontaneous reaction are: Mg is oxidized.Co is reduced.Co is oxidized. The reduction half-reaction of the given reaction is Co2+ + 2e− ⟶ Co. The oxidation half-reaction of the given reaction is Mg ⟶ Mg2+ + 2e−.The oxidation number of Co changes from +2 in CoSO4(aq) to 0 in Co(s), therefore, Co is oxidized in the given reaction. The oxidation number of Mg changes from 0 in Mg(s) to +2 in MgSO4(aq), therefore, Mg is oxidized in the given reaction. Therefore, Mg is reduced to Mg2+.Hence, the correct option is Mg is oxidized, Co is reduced, and Co is oxidized. The explanation of each of the true statements is already given above.

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Answer: Denver is named after James W. Denver, a governor of the Kansas Territory. It is nicknamed the Mile High City because its official elevation is exactly one mile (5280 feet or 1609.344 meters) above sea level.

Answer:

Heredity, also called inheritance or biological inheritance, is the passing on of traits from parents to their offspring; either through asexual reproduction or sexual reproduction, the offspring cells or organisms acquire the genetic information of their parents.

Explanation:

Plss markk mee brainlistt

Answer: 5.39

Explanation: you are adding the balloon's volume and the container's volume

The redox reactions that occur spontaneously in the forward direction are:

2Ag+(aq) + Ni(s) → 2Ag(s) + Ni2+(aq)

Ca2+(aq) + Zn(s) → Ca(s) + Zn2+(aq)

Among the given redox reactions, the ones that occur spontaneously in the forward direction are: 2Ag+(aq) + Ni(s) → 2Ag(s) + Ni2+(aq) and Ca2+(aq) + Zn(s) → Ca(s) + Zn2+(aq). These reactions occur because the reduction potentials of Ag+ and Ca2+ are higher than those of Ni2+ and Zn2+, respectively. As a result, Ag+ and Ca2+ are reduced, while Ni and Zn are oxidized. The other two reactions, 2Cr(s) + 3Pb2+(aq) → 2Cr3+(aq) + 3Pb(s) and Sn(s) + Mn2+(aq) → Sn2+(aq) + Mn(s), do not occur spontaneously in the forward direction due to the lower reduction potentials of the species being reduced.

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Answer:

it will decrease because there will not be food for all of them and there is very little space for them now so if there is more they will start to fight

Explanation:

there is very little habitat left for panda bears so if there population increases the food and space with be filed

Hello! jamilialves888

I'm glad you asked my name is ✰Tobie✰

And I will help you understand why the population of ⚝pandas ⚝

is decreasing .

-Your answer :βy Tobie

≛So why are pandas going extinct?

One of the main cause is due to the destruction of their own habitat

Since china is a country that is constantly growing their own homes are slowly   being destroyed Since their habitats are becoming destroyed it forces them to live in small unhabitable area .

≛This leads to another problem.....

If they are forced to live in a small area there will be less food...

Since there is a shortage of food that will leave the panda's to slowly starve to death since pandas only eat bamboo they could never be able to live anywhere else....Another reason panda's are going extinct is because they are being hunted for their fur.

ex·tinct

/ikˈstiNG(k)t/

_____________

It means that the species does not exist anymore and

are no longer in existence

Hope this helps!

                                                                                             -Tobie <3

ʕ •ᴥ•ʔ

The correct statement (e) captures the fundamental principle of the second law of thermodynamics, emphasizing the tendency of entropy to increase in spontaneous processes, leading to a positive net entropy change of the universe.

The second law of thermodynamics is a fundamental principle that describes the behavior of energy and entropy in physical systems. It can be stated in various ways, but the correct statement corresponding to the second law is: In any spontaneous process, ΔS universe - ΔS system + ΔS surroundings > 0.

This statement captures the essence of the second law, which is that the entropy of an isolated system tends to increase over time. The entropy change of the universe (ΔS universe) is the net change in entropy of the system and its surroundings. For a spontaneous process, where the system undergoes a change without external intervention, the total entropy change of the universe must be greater than zero.

The entropy change of the system (ΔS system) and the entropy change of the surroundings (ΔS surroundings) may have opposite signs, but their magnitudes must be such that the net entropy change of the universe is positive. This reflects the irreversibility of natural processes, where entropy tends to increase and energy becomes more dispersed. The correct statement (e) captures the fundamental principle of the second law of thermodynamics, emphasizing the tendency of entropy to increase in spontaneous processes, leading to a positive net entropy change of the universe.

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Answer:

it is a practical question..ASAP

Answer:

I believe it would be Asteroid Belt

Explanation:

little green men and imposters seem very unlikely, and Pluto is definetely not between earth and Jupiter

Answer:

the asteroid belt

Explanation:

it orbits between mars and jupiter

We can say that the equilibrium constant, K, can be calculated at 298 K for each of the following reactions using the data given in Appendix C of the textbook.

The equilibrium constant, K, can be calculated at 298 K for each of the following reactions using the data given in Appendix C of the textbook as follows: Equation: H2(g)+I2(g)↔2HI(g). At equilibrium: [H2] = [I2] = 0.0100 M, and [HI] = 0.0938 M∴ Kc = [HI]2[H2][I2]⇒Kc = (0.0938)2/(0.0100)2= 87.56. Equation: C2H5OH(g)↔C2H4(g)+H2O(g). At equilibrium: [C2H5OH] = 1.00 M, and [C2H4] = [H2O] = 0.0158 M∴ Kc = [C2H4][H2O]/[C2H5OH]⇒Kc = (0.0158)2/1.00= 0.000249. Equation: 3C2H2(g)↔C6H6(g)At equilibrium: [C2H2] = 0.101 M, and [C6H6] = 0.052 M∴ Kc = [C6H6]/[C2H2]3⇒Kc = 0.052/(0.101)3= 0.542

The equilibrium constant (K) is calculated using the formula shown below: Kc = [Products]/[Reactants]For example, for the reaction H2(g)+I2(g)↔2HI(g), the equilibrium constant (K) is calculated as follows: Kc = [HI]2[H2][I2]/[Reactants]. In this reaction, at equilibrium, the concentrations of hydrogen, iodine, and hydrogen iodide are [H2] = [I2] = 0.0100 M and [HI] = 0.0938 M. Therefore, Kc = (0.0938)2/(0.0100)2= 87.56.

Similarly, for the reaction C2H5OH(g)↔C2H4(g)+H2O(g), the equilibrium constant (K) is calculated as follows: Kc = [C2H4][H2O]/[C2H5OH] . In this reaction, at equilibrium, the concentrations of ethyl alcohol, ethylene, and water are [C2H5OH] = 1.00 M, [C2H4] = [H2O] = 0.0158 M. Therefore, Kc = (0.0158)2/1.00= 0.000249Similarly, for the reaction 3C2H2(g)↔C6H6(g), the equilibrium constant (K) is calculated as follows: Kc = [C6H6]/[C2H2]3. In this reaction, at equilibrium, the concentrations of acetylene and benzene are [C2H2] = 0.101 M and [C6H6] = 0.052 M.

Therefore, Kc = 0.052/(0.101)3= 0.542. Hence, the equilibrium constant (K) is calculated at 298 K for each of the given reactions.

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The percent of Ag+ remaining in solution is 0.0158 %.

The concentration of the Cl- ion in the solution is increased by adding more NaCl to it. The solubility product of AgCl is Ksp = [Ag+][Cl-]2. When the solution contains 0.27 M Cl-, AgCl will dissolve until it reaches its solubility limit.The solubility of AgCl at 25°C is 1.3 x 10-5 M (0.000013 M) and its solubility product (Ksp) at the same temperature is 1.8 x 10-10. Therefore, the concentration of [Ag+] in the saturated AgCl solution is: 1.3 x 10-5 MThus, when 0.27 M Cl- is added to the solution, AgCl will dissolve to reach a final [Ag+] of: Ksp = [Ag+][Cl-]2[Ag+] = (Ksp/[Cl-]2) = (1.8 x 10-10)/(0.27)2 = 2.06 x 10-9 MThe amount of Ag+ in solution at this point is: [Ag+] = 2.06 x 10-9 M = 2.06 x 10-3 %AgCl dissolved = (2.06 x 10-9 M)/(1.3 x 10-5 M) x 100 = 0.0158 %Hence, the resulting [Ag+] is 2.06 × 10-9 M. The percent of Ag+ remaining in solution is 0.0158 %.

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If a sample of gas has a volume of 2.50 L at 236 kPa and 75.0 °C, the pressure 1.18 atm is required.

Only ideal gas is subject to the ideal gas law; vanderwaal gas is not. Here, Boyle's and Charles' gas laws are combined. As a result, the new gas pressure is 1.18 atm.

The relation between Pressure, volume, and temperature can be given as:

PV = nRT

In which:

P = pressure of  gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant

= 0.0821 L.atm/K.mol

Combining Boyle's and Charles' gas law

P₁V₁/T₁ = P₂V₂/T₂

{ (5.28atm) (2.50 L)} ÷348 K ={ (P2) (3.75 L)} ÷298 K

P₂ =1.18 atm

Thus, the new pressure of gas is 1.18 atm when the temperature is changed to 348K and volume is increased to 3.75 L.

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Answer:

e. Hydrogen bonds form between the molecule and water.

Explanation:

When a molecule dissolves in water, it is typically because the molecule has polar or charged regions that can interact with the polar water molecules. Water is a highly polar molecule due to its bent shape and the presence of electronegative oxygen atoms. As a result, it forms hydrogen bonds with other water molecules and with other polar or charged substances.

When a molecule dissolves in water, the water molecules surround the individual molecules and interact with them through hydrogen bonding. The positively charged hydrogen atoms of water form hydrogen bonds with negatively charged regions of the dissolved molecule, such as oxygen or nitrogen atoms, or with partially negative regions due to uneven distribution of electron density. This interaction between the water molecules and the dissolved molecule is what allows the molecule to become dispersed and solvated in the water, forming a homogeneous mixture.

It's important to note that during the dissolution process, the covalent bonds within both the water molecules and the dissolved molecule generally remain intact. Dissolving in water does not typically involve breaking the covalent bonds within the molecule or the water molecule. Instead, it involves the formation of hydrogen bonds between the solvent (water) and solute (dissolved molecule).

Answer:

Protons / H+ ions

Explanation:

The acids are compounds with a pH range between 1-7, while the base has a pH range of 7-14. Acids produce hydrogen ions or protons in the solution.

The pH can be defined as the hydrogen ion concentration in the solution. The higher the proton concentration in the solution, the lower will be the pH.

The pH of 7 has an equal number of hydrogen and hydroxide ions contributing to the neutral pH. The alkaline pH is contributed by the hydroxide ion concentration.

The acids fall at the lower pH range with a high hydrogen ion concentration. Thus, acids produce hydrogen ions or protons in the aqueous solution.

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The statement about members of a homologous series that is true is that they differ from their nearest neighbors by 14 amu (c).

A homologous series is a group of compounds with a similar general formula, chemical properties, and a constant increment in molecular structure. As a result, each member varies from the previous by a constant unit, which is often a CH2 group.Each member of the homologous series is classified as either a tautomer or a constitutional isomer. Constitutional isomers, also known as structural isomers, are compounds with the same molecular formula but different structural arrangements. Isomers of tautomers are structural isomers that interconvert by a simple chemical reaction. As a result, the formula and composition of tautomers are the same, but they differ in the distribution of their valence electrons and bonding patterns.Members of a homologous series may or may not be hydrocarbons, and they are not always constitutional isomers. Therefore, statement (a) and statement (b) are both incorrect. Statement (d) is also incorrect because tautomers cannot be classified as members of a homologous series. However, statement (c) is correct because members of a homologous series differ from their nearest neighbors by a constant increment in molecular structure, which is usually 14 amu. Therefore, the correct answer is C.

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Answer:

V2O5 is the empirical formula of vanadium oxide

Explanation:

The molecular mass of Vanadium is  50.949 g/mol

Number of moles of vanadium = 0.3456 g/50.949 g/mol = 0.00696 moles

The molecular mass of Oxygen is 16.0 g/mol

Number of moles of Oxygen = (0.6330 – 0.354) g/16 g/mol = 0.0174 moles

Emperical formula  

V (0.00696 moles/0.00696 moles) O (0.0174 moles /0.00696 moles)

V 1 O2.5

Multiply by two get a whole number  

V2 O5

Answer : The substance that acts as the oxidizing agent in the reaction:Fe(CO)5(l) + 2HI(g) → Fe(CO)4I2(s) + CO(g) + H2(g)is HI, or hydrogen iodide.

Explanation : In this reaction, HI acts as an oxidizing agent and Fe(CO)5(l) acts as a reducing agent.What is an oxidizing agent?An oxidizing agent is a substance that oxidizes or causes oxidation in another compound by transferring electrons to that compound. In the process, the oxidizing agent itself gets reduced.Oxidizing agents are chemicals that accept electrons from other substances. They are generally characterized by their ability to oxidize another substance, which is why they are sometimes referred to as electron acceptors.

Examples of oxidizing agents include hydrogen peroxide, potassium permanganate, and sodium hypochlorite.

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The standard molar entropy of no₂ is 240.0 J/(mol.K).Therefore, the order of increasing standard molar entropy of the given gases is n₂o₄ (g) < no (g) < no₂ (g).

Entropy is the measure of disorder in a system. It is a thermodynamic property that depends on the degree of randomness in the molecules of a substance. The unit of entropy is Joules per Kelvin. In general, the entropy of a substance increases with an increase in temperature.

This is because at higher temperatures, the molecules of a substance have more kinetic energy and can move more freely, leading to an increase in the number of possible arrangements of molecules, which increases entropy.

Increasing Standard Molar Entropy Order n₂o₄ (g) < no (g) < no₂ (g)The standard molar entropy (S°) is the entropy of one mole of a substance at standard temperature and pressure (STP). In the order of increasing standard molar entropy, the gases listed are as follows: n₂o₄ (g) has the least entropy because it is a relatively heavy and rigid molecule. It has fewer possible arrangements of molecules, which results in a lower entropy.

The standard molar entropy of n₂o₄ is 304.3 J/(mol.K).no (g) has more entropy than n₂o₄ because it is a lighter molecule that is more mobile. It has more possible arrangements of molecules, leading to higher entropy.

The standard molar entropy of no is 210.6 J/(mol.K).no₂ (g) has the highest entropy because it is the lightest and most mobile molecule of the three gases. It has the most possible arrangements of molecules, leading to the highest entropy. The standard molar entropy of no₂ is 240.0 J/(mol.K).

Therefore, the order of increasing standard molar entropy of the given gases is n₂o₄ (g) < no (g) < no₂ (g).

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Answer:

81.5g/mol

Explanation:

Molar mass is the ratio between mass of a substance (In this case, 0.207g) and moles presents in this mass.

To solve this question we must find the moles of the gas in order to obtain the molar mass using:

PV = nRT

PV / RT = n

Where P is pressure = 0.980atm

V is volume in Liters = 0.0725L

R is gas constant = 0.082atmL/molK

T is absolute temperature = 68°C + 273.15 = 341.15K

0.980atm*0.0725L / 0.082atmL/molK*341.15K = n

2.54x10⁻³ moles = n

Thus, the molar mass of the gas is:

0.207g / 2.54x10⁻³ moles

The element that is oxidized in the reaction Fe(CO)5 (l) + 2HI (g) → Fe(CO)4I2 (s) + CO (g) + H2(g) is iron (Fe). When determining the oxidation state of iron (Fe), we use the rule that the oxidation state of a monatomic ion is equal to its charge.

The oxidation state of Fe in Fe(CO)5 is zero. In Fe(CO)4I2, the oxidation state of Fe is +2. So, Fe is oxidized in the reaction.Balancing the redox reaction:Fe(CO)5 (l) + 2HI (g) → Fe(CO)4I2 (s) + CO (g) + H2(g)The oxidation half-reaction is:Fe(CO)5 (l) → Fe(CO)4I2 (s) + I- (aq)The reduction half-reaction is:2H+ (aq) + 2e- → H2 (g)By adding both half-reactions, the balanced redox reaction is:Fe(CO)5 (l) + 2HI (g) → Fe(CO)4I2 (s) + CO (g) + H2(g)The oxidation half-reaction shows that iron (Fe) has lost electrons, thereby being oxidized.

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Answer:

[tex][H^+]=3.16x10^{-4}M[/tex]

Explanation:

¡Hola!

En este caso, dado que el pH de una solución se entiende como el potencial de los iones hidrógeno en la misma, es posible recordar la ecuación que se usa para calcularlo:

[tex]pH=-log([H^+])[/tex]

De este modo, al conocer el pH, se resuelve para la concentración de iones hidrógeno como se muestra a continuación:

[tex][H^+]=10^{-pH}[/tex]

Así, reemplazamos el pH para obtener:

[tex][H^+]=10^{-3.5}=3.16x10^{-4}M[/tex]

¡Saludos!

Answer:

4.74 mol

Explanation:

Molarity = [tex]\frac{mol}{L}[/tex]

2.01 M = [tex]\frac{mol}{2.36 L}[/tex]

(2.01 M)(2.36 L) = 4.74 mol

The concentration of A and B after 80 s  if the initial concentration of ab is 0.260 m, and the reaction mixture initially contains no products is 0.0091 M.

To find the concentrations of A and B after 80 s, we must write the kinetic data is given as follows for the reaction:

AB ⟶ A + B

Initial rate of the reaction is 1.62 x 10⁻³ mol/L/s

Order of reaction for AB is first order (n = 1). Now, using the first-order rate equation, the concentration of AB at time t, [AB]t can be calculated as follows:

ln [AB]0/[AB]t = k

tHere, [AB]0 is the initial concentration of AB, [AB]t is the concentration of AB at time t, k is the rate constant, and t is the time interval.

To determine the rate constant, we can use the initial rate of reaction.

Initial rate, ri = k[AB]n

Here, n is the order of reaction.

So, k = ri/[AB]n

Substituting the given values:

ri = 1.62 x 10⁻³ mol/L/s[AB]0

= 0.260 mk = ri/[AB]n

= 1.62 x 10⁻³ mol/L/s / (0.260 m)1

= 6.23 s-1

Now, we can use the rate constant to determine the concentration of AB at 80 seconds:

ln [AB]0/[AB]80 = kt

Here, k = 6.23 s-1, [AB]0 = 0.260 m, and t = 80 s.

Substituting the values:

ln (0.260 m)/[AB]80

= (6.23 s-1) (80 s)[AB]80

= [AB]0 e-kt

= (0.260 m) e-(6.23 s-1) (80 s)

= 0.0091 m

Now, since the stoichiometry of the reaction is 1:1, the concentration of A and B will be equal to each other. Therefore, [A]80 = [B]80 = 0.0091 m.

Thus, the final concentrations of A and B are 0.0091 M after 80 seconds.

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"A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T" is incorrect.

"A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T" is false.A spontaneous process occurs naturally and without any assistance. The rate of the process does not affect its spontaneity; instead, spontaneity is determined by the change in free energy that occurs during the reaction.A reaction is spontaneous if the Gibbs free energy of the reaction is negative (∆G < 0). Gibbs free energy is calculated using the equation: ∆G = ∆H - T∆S, where ∆H is the enthalpy change, T is the temperature, and ∆S is the entropy change of the reaction.A reaction that is endothermic (∆H > 0) and has an increase in entropy (∆S > 0) can be spontaneous at any temperature if the free energy change is negative. As a result, the given statement "A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T" is incorrect.

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