How long would it take you to travel 163 meters at a speed of 33 meters per second?

Answer:

The use of a telescope is to see distant objects

Explanation:

For example: you can look through a telescope to see constellations and stars. Hope this helps <3

Answer:

To show that magnets repel, you must place the strong and weak magnets to another magnet with their poles being both south or both north facing eachother.

To show they attract, place opposite poles near eachother.

Answer:

resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.

Explanation:

assume that the ship started moving from A to B (north at 50km/hr for 2 hours) so the covered distance will be: 50*2 = 100 km

then it moves from B to C so the covered distance will be: 3*60 = 180 km

using Pythagoras, we get the resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.

Answer:

-2.68m/s²

Explanation:

To find acceleration use the formula:

acceleration = change in velocity ÷ time

Substitute in the values:

acceleration = -8.3 ÷ 3.1

acceleration = -2.67741.. ≈ -2.68m/s²

Hope this helps!

Answer:

v2^2 - v1^2 = 2 g s        fundamental formula

v2 = v1 + 2 g    = v1 + 19.8         increase in velocity in 2 sec

v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76

v1 = (2412.76 - 392) / 39.6 = 51.03

v2 = 51.03 + 19.6 = 70.63

T = 70.63 / .8 = 7.207 sec     time to fall height of tower

S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m

(Note  v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m

2385 / (2 * 9.8) = 122 m (close to 123.1    as was given

Answer:

A siphon is a tube that allows liquid to travel upward, above the surface of the origin reservoir, then downwards to a lower level without using a pump. When a certain amount of water moves over the bend in the siphon, gravity pulls it down on the longer leg lowers the atmospheric pressure in the bend of the siphon.

Mark me as brainlest, please?

Explanation:

The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.

The given parameter;

The equations that model the motion of the ball is given as follows;

[tex]h = v_0_y + \frac{1}{2} gt^2[/tex]

[tex]v_f = v_0_y + gt[/tex]

All the unknown variables in the equations include;

The vertical distance traveled by the ball is calculated as follows;

[tex]h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m[/tex]

The final velocity of the ball is calculated as follows;

[tex]v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s[/tex]

Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.

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Answer:

1 st question: Control variable

2nd question: random variable

3rd question: if the two objects are dropped from the same height they will hit the ground at the same time

Answer:

it IS the control variable

Explanation:

Explanation:

I don't understand this question

could you please explain

Explanation:

Well ball on ramp .Which factors are affected?

So if we put the ball right above the centre of mass it can be best stabled

Answer:

140m 13 degree

Explanation:

yan po thank nalang po sa point

According to who.int,

"The UV region covers the wavelength range 100-400 nm and is divided into three bands: UVA (315-400 nm) UVB (280-315 nm) UVC (100-280 nm).Mar 9, 2016"

in short 100-400nm

The magnitude of the adhesive force allows the top block to remain

attached to the bottom when the blocks and the wire are balanced.

The option that must be true is; [tex]\mathbf{W_{bottom} = F_{adhesion}}[/tex]

Reason:

The tension exerted by the wire attached to the top block = T

Magnitude of the adhesive = [tex]F_{adhesion}[/tex]

Weight of the top block = [tex]W_{top}[/tex]

Weight of the bottom block = [tex]W_{bottom}[/tex]

Given that with the exertion of the tension, the two blocks remain at rest, we have;

The adhesive causes the bottom block to remain attached to the top block, we have;

Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;

The magnitude of the adhesive force = The weight of the bottom block

Therefore;

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Answer:

Wbottom=Fadhersion it was right on y test

Explanation:

We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that  the minimum force that must be applied on the book is

From the question we are told

A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the  Force  is mathematically given as

[tex]F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\[/tex]

F=44N

Therefore

the minimum force that must be applied on the book is

F=44N

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Explanation:

An analog signal has some feature that is a continuous function of the program material being transmitted. It may take on any of a range of values.

In radio, amplitude, frequency, or phase are features of the radio signal commonly modulated when transmitting an analog signal.

__

A digital signal has some feature that is a discrete function of the program material being transmitted. It may take on any of a specific set of values.

A digital radio signal typically uses some combination of amplitude, frequency, and phase to represent a discrete state being transmitted. Only specific values of these are used by the transmitter.

(The receiver generally has to deal with corruption of the signal by the transmission channel, so the received set of values may not correlate well with those intended at the transmitter. This is why error-correcting codes are often used with digital signal transmission.)

_____

Additional comment

Analog radio signals are generally transmitted using a carrier wave at a specific frequency (or in some specific frequency range, in the case of frequency modulation). Processing techniques may be used at the transmitter to limit the bandwidth used in the transmission. One commonly-used technique is to limit the transmitted spectrum to one side of the carrier wave frequency. (This is called "single side-band" radio.)

Digital signals offer the opportunity to transmit different bits of the information at different frequencies. Sometimes, "frequency hopping" is used, so that the transmitted carrier wave jumps around from one frequency to another in a predetermined pattern. The effect of this is to spread out the spectrum of the transmitted signal so that average power in any frequency band is significantly reduced. In fact, it may be indistinguishable from background noise, except by a receiver that tunes to the carrier wave in the predetermined frequency pattern.

Answer:

Solubility in gasses and liquids increase as pressure increases. This is due to colligative properties. The nitrogen gas levels would increase the farther the diver dives due to the increase of pressure causing the solubility of the nitrogen to increase, thus increasing the amount of it as you go deeper in the ocean.

Explanation:

As they plummet down, the driver would be in more risk. The solubility of gases and liquids increases as pressure increases. This is due to the existence of colligative properties. The nitrogen gas levels grow when the diver descends further into the water due to increased pressure, which causes the nitrogen's solubility to rise, increasing the amount of nitrogen present.

Answer:

Answer:

i dont understand sorry

Answer:C

Explanation:

For parallel connection

For series connection

Net resistance

Answer: (Sorry, but I don't know how to calculate mass)

1. 15 N

2. 0.4921 [tex]\frac{ft}{s^2}[/tex] (feet per second squared)

4. 150 N

5. 8.202 feet per second squared

Explanation:

It obeys the inverse square law.

It is always attractive in nature.

It is a long range force. ...

The graviton is the field particle of gravitational force.

Answer:

Gravitational force−Properties:

(1) It is a universal attractive force. It is directly proportional to the product of the masses of the two bodies.

(2) It obey inverse square law.

(3) It is the weakest force known in nature.

Answer:

For example, one method for estimating the length of time it takes something to occur is to time it once using a stopwatch. You can reduce the uncertainty in this estimate by repeating the measurement and taking the average.

There are a lot of way to reduce the uncertainty however with real life sciences like quantum mechanics it will reveal more about the world and life if we have better measuring tools. Being precise is essential to understanding many parts of life.

Hope this helped! Have a great day!!!

Answer:

question 1 is centripetal acceleration question 2 is 4

Explanation:

centripetal acceleration basically is acceleration that only changes velocity but not speed, while for question 2, you divide 10 by 2.5

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 8 g

volume = 10 cm³

We have

[tex]density = \frac{8}{10} = \frac{4}{5} = 0.8 \\ [/tex]

We have the final answer as

Hope this helps you

The force is different because of the amount of weight applied so the answer is A

The force that makes a difference in the weight of each person is Gravitational. Correct option is B.

Gravitational force is a fundamental force of nature that exists between any two objects with mass. It's the force that keeps us and everything else on Earth anchored to its surface. This force is proportional to the mass of the objects involved and inversely proportional to the square of the distance between them.

For example, if you were standing on a bathroom scale, the reading on the scale represents the force of the Earth's gravity acting on your body, which is why it's often referred to as your "weight." The actual mass of an object remains constant regardless of its location, but its weight can vary depending on the strength of the gravitational field at different locations (e.g., the weight on the Moon would be less than on Earth due to the Moon's weaker gravitational pull).

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