Hot air is less dense than cold air. Could a hot-air balloon be flown on the moon, where there is no atmosphere?.

The ball rises up to 30.625 m high.

The force that pulls items toward the centre of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.

Given parameters:

Horizontal range of the ball; R = 84 m.

Time of flight of the ball: T = 5 s.

Acceleration due to gravity; g = 9.8 m/s².

We have to find, maximum height obtained by the ball; H = ?

In projectile motion, time of flight is; T = 2usinθ/g

Where, u = initial velocity of the ball and θ = angle of projection.

So, 2usinθ/g = 5

⇒ usinθ = 5g/2 = (5×9.8)/2m/s = 24.5 m/s.

Then maximum height obtained by the ball;

H = u²sin²θ/2g

= 24.5²/(2×9.8) = 30.625 m.

Hence,  maximum height obtained by the ball is 30.625 m.

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The effect of adding bonded atoms and lone pairs to the central atom is similar in a way that both repel the other atoms away to create more space for themselves, taking all the available space.

While it's generally understood that the effect of adding bonded atoms and lone pairs to the central atom is similar, it is not all the same. The repulsions caused by bonding atoms are lesser than the repulsions caused by lone pairs because lone pairs are closer in position to the nucleus than the bonding atoms, resulting in a different shape of the molecule.

The difference above makes some people think the effect is more not similar than similar because of the result.

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Answer:

Explanation:

Given:

m = 9 kg

F = 450 N

_________

a - ?

According to Newton's 2nd law:

a = F / m

a = 450 / 9 = 50 m/s²

Consider two masses in a closed system. The Newton 3rd law, F₁₂ = -F₂₁, will result in conservation of momentum m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.

Suppose we have two masses, m₁ and m₂. According to the Newton's 3rd Law:

F₁₂ = -F₂₁

Where:

F₁₂ = force on m₁  due to m₂

F₂₁ = force on m₂  due to m₁

If there is collision between two masses, we can assume that the forces acted in the same time interval. Hence,

F₁₂ . t = -F₂₁ . t

Force is defined as the change of momentum (Δp) over time (t), or

F = Δp / t

Substitute F . t = Δp on both sides,

Δp₁ = –Δp₂

p₁_final - p₁_initial =  –(p₂_final - p₂_initial)

p₁_initial + p₂_initial = p₁_final + p₂_final

This is the conservation law of momentum.

Let:

u = initial velocity

v = final velocity

Then,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

This is another form of  the conservation law of momentum. Hence, we have shown that the Newton 3rd Law will lead to the conservation of momentum.

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The new speed while holding the sack is v₂ = 4.32 m/s as per the given mass and velocity.

Velocity is the rate of change in position of a moving object as observed from a specific frame of reference and measured by a specific time standard.

Given,

The mass of first object m₁=55kg

The mass of second object m₂=5kg

The velocity of first object v₁=4.5m/s

The velocity of second object v₂=?

The mass of the object that is dropped m₃=2.5 kg

When two bodies contact, the momentum of the two bodies before the collision equals the momentum after the collision, according to the law of conservation of momentum.

Pa= Pb

Where Pa denotes the momentum before the impact and Pb denotes the momentum after the collision.

When we apply this law to the preceding situation, we get Momentum before collision= Momentum after collision.

Momentum before impact = ( m₁+m₂) x v₁ = (55+5)x 4.5 = 270 Kg m/s

Momentum after impact = ( m₁+m₂+m₃) x v₂ = (55+5+2.5) x v₂

We now understand that momentum before contact equals momentum after impact:

270 = 62.5 v₂

v₂ = 4.32 m/s

The new speed while holding the sack is v₂ = 4.32 m/s

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The magnitude of the acceleration of the robot is  1 m/s².

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass of doll = 0.20 kg

mass of robot = 0.30 kg

Force on dall by robot = 0.30 N

acceleration on doll = mass of doll / force of robot

                                = 0.20 / 0.30

                                = 0.67 m/s²

Same force applied to the robot by Newton's third law of motion = 0.30 N

acceleration of the robot = mass of robot/force

                                         = 0.30 / 0.30

                                         = 1 m/s²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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Brownlee Heat Exchange Anomaly -Greenhouse Effect. when heat cannot escape into space.

The greenhouse effect is a process that occurs when electricity from a planet's host star is going via its ecosystem and heats the planet's floor, however, greenhouse gases within the surroundings prevent some of the warmth from returning without delay to the area, ensuing in a hotter planet. Earth's natural greenhouse impact maintains the planet from having the under-freezing temperature that it would have if there have been no greenhouse gases. moreover, human-induced increases in greenhouse gases trap more amounts of warmth, inflicting the Earth to develop warmer over the years.

most gases inside the ecosystem are transparent to infrared, however, the small share of the surroundings that constitutes greenhouse gases absorbs some of the heat emitted through the floor rather than letting it get away into space. those greenhouse gas molecules then emit radiant heat in all instructions, passing warmness to the surrounding air and warming different greenhouse gas molecules.

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Answer: speed = distance ÷ time

Answer: 980 Newtons

Explanation:

Space telescopes have the advantage of being above the blurring effects of the Earth's atmosphere.

A surrounding is a layer of fuel or layers of gases that envelop a planet and is held in a region through the gravity of the planetary frame. A planet retains its surroundings whilst the gravity is exceptional and the temperature of the surroundings is low. A stellar ecosystem is the outer area of a celeb, which includes the layers above the opaque photosphere; stars of low temperature may have outer atmospheres containing compound molecules.

The atmosphere of Earth consists of nitrogen (78%), oxygen (21%), argon (0.9%), carbon dioxide (0.04%), and trace gases. most organisms use oxygen for breathing; lightning and bacteria perform nitrogen fixation to provide ammonia that is used to make nucleotides and amino acids; flora, algae, and cyanobacteria use carbon dioxide for photosynthesis.

The layered composition of the ecosystem minimizes the damaging results of daylight, ultraviolet radiation, solar wind, and cosmic rays to defend organisms from genetic harm. The modern composition of the atmosphere of the Earth is made from billions of years of biochemical modification of the paleo atmosphere by residing organisms.

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If he covers a distance of 10 meters, the work he has done on the javelin is 0 joule.

In physics, it measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. In its simplest form, for a constant force aligned with the direction of motion, it equals the product of the force strength and the distance traveled.

How to determine the work he has done on the javelin?

The actual formula of finding the work is

W = F × S cos a, a is the angle in which the athlete is carrying the javelin.

or, W = 5 × 10 cos90, angle is 90 with the vertical component of the force (because the force of 5N that the athlete is applying to the javelin can't possibly be in the direction that he and the javelin are moving, otherwise the javelin would be accelerating)

cos 90 = 0

therefore 5*10*0=0,

Hence work done in joules is 0 joules.

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Answer:

3 hours

Explanation:

[tex](54 km)\frac{1 h}{18 km} = 3 h[/tex]

Answer:

Below

Explanation:

Here is a way:

When the ball reaches its maximum height , it is 1/2 of the way back to your hand AND its velocity = 0     Find this time and double it to get to your hand.

Vf = vo - at

0 = 30 - 9.81(t)    shows to to max height = 3.06 seconds

                                double it : = 6.12 seconds

The displacement of the object that accelerates uniformly from rest is 35.25 m due East.

Displacement can be defined as distance in a specified direction.

To calculate the displacement of the object, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the displacement of the body is 35.25 m due East.

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The Impulse is - 74 Ns

Impulse (symbolized by J or Imp) is the integral of a force, F, over the time interval, t, for which it acts.

The SI unit of impulse is the newton second (N⋅s)

Examples of impluse in real life could include hitting a ball,tossing a coin, kick starting scooter etc.

The values known to us are -

J =?

Mass (m) = 74 kg

Initial velocity (Vi) = 4 m/s

Final velocity (Vf) = 3 m/s

To find Impulse-

J = ΔP = m ( Vi-Vf)

J = 74kg ( 3m/s- 4m/s)

J = - 74 Ns

The impulse is -74Ns, here the negative sign indicates the direction of impulse, in the opposite direction of motion.

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Answer:

Explanation:

a wave of compression and rarefaction, by which sound is propagated in an elastic medium such as air.

The calculated value is 84.03 ft. The deceleration will be calculated by multiplying the final velocity by the initial velocity, then dividing that result by the time it takes for the velocity to drop.

Given that you don't have enough time to complete this task, you can only apply the kinematic formula Vf 2 = Vi 2 + 2aD, which includes all the variables.

0 for Vf = Final Velocity (since you are trying to stop)

Initial Velocity = 50 MPH (Vi)

a= acceleration equals 32 ft/s2.

D is the distance covered (displacement)

We must ensure that all variables and constants are in the same units before we can use this formula. This means that all of your measurements should be in feet (ft) or miles (mi), and all of your time measurements must be in seconds (s) or meters (m).

Now calculate the distance by separating D by itself.

D= (-5377.7778/ -64)\s

= 84.03 ft

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If a direct current of 5 Volts, goes through a primary coil, the voltage in the secondary coil will be double is the false statement.

The voltage across the secondary coil is greater than the voltage across the primary. There are fewer turns on the secondary coil than the primary.

The output power is greater than the input power. The current in the secondary coil is greater than the current in the primary coil.

The secondary voltage of a transformer may be either in phase or out of phase with the primary voltage. This depends on the direction in which the windings are wound and the arrangement of the connections to the external circuit.

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The resultant density of the sphere when its radius is halved is eight times the initial density of the sphere.

Let the radius of the sphere = r

The volume of the sphere = [tex]\frac{4}{3} \pi r^{3}[/tex]

Mass of the sphere = M

Now, The density of the sphere = D = Mass/Volume

So, The density will be,

[tex]D = \frac{M}{\frac{4}{3} \pi r^{3} } = \frac{3M}{4\pi r^{3} }[/tex]

It is given that the radius of the sphere is halved, then

[tex]D' = \frac{M}{\frac{4}{3} \pi (\frac{r}{2} )^{3} } = \frac{24M}{4\pi r^{3} } = \frac{6M}{\pi r^{3} }[/tex]

Now, Dividing  both the densities, D and D', we get

[tex]\frac{D}{D'} = \frac{1}{8}\\ \\D' = 8D[/tex]

Hence, The resultant density of the sphere when its radius is halved is eight times the initial density of the sphere.

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The listed characteristics of storms are sorted according to whether they are associated with Jovian storms only, terrestrial storms only, or both Jovian and terrestrial storms.

The terrestrial planets are the planets of inner solar system such as Mercury, Venus, Earth and Mars. Unlike terrestrial planets Jovian planets do not have a solid surface. They are primarily composed of hydrogen and helium in their atmosphere.

Therefore, the listed characteristics of storms are sorted according to whether they are associated with Jovian storms only, terrestrial storms only, or both Jovian and terrestrial storms.

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The velocity of the aircraft to move over the upper surface to create the ideal lift is  67.64 m/s.

Describe Bernoulli's principle?

Because of Bernoulli's principle, which states that when air speeds up, pressure decreases, airplanes are able to fly. Thus, the reason a wing produces lift is because the air moves faster over the top, resulting in a region of low pressure and lift.

The ideal lift is determined by the fluid density and velocity relationship, so:

F_lift = 1/2 x p x A x (v_f^2 - v_i^2)

As a result, the fluid's density may be calculated.

p = 1.29 kg / m^3

The situation's environment indicates that the wings generate roughly 100N of lift per square meter of wings, therefore

A = 1 m^2

the beginning speed is

v_i = 55.0 m/s

Replacing

F_lift = 1/2 x 1.29 x 1 x (v_f^2 - 55 x 55)

1000 = 0.645 x (v_f^2 - 3025)

1550.387 =  (v_f^2 - 3025)

v_f^2 = 4575.387

v_f = 67.64 m/s.

Hence, the velocity of the aircraft to move over the upper surface to create the ideal lift is  67.64 m/s.

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The wind turbine gives maximize its output when a turbine having longer blades.

Wind turbines :

A wind turbine is a device that uses the wind's kinetic energy to create electricity.

Three things should be taken into account when determining value:

(1) Installation fees

(2) projected annual power output

(3) assurance regarding the projected yearly power production

The wind turbine gives maximize its output when a turbine having longer blades.

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The velocity flow field is irrotational and the conservation of mass is preserved.

Irrotational flow for a two-dimensional velocity field happens when

[tex]\frac{dv}{dx} \:-\: \frac{du}{dy} \:=\: 0[/tex]

Conservation of mass for an incompressible happens when

[tex]\frac{du}{dx} \:+\: \frac{dv}{dy} \:=\: 0[/tex]

Perimeter

Calculate the derivate in each function.

Checking the irrotational flow

[tex]\frac{dv}{dx} \:-\: \frac{du}{dy} \:=\: 2y - 2y = 0[/tex]

Checking conservation of mass for an incompressible

[tex]\frac{du}{dx} \:+\: \frac{dv}{dy} \:=\: - 2x - 1 + 2x + 1 = 2x - 2x + 1 - 1 = 0[/tex]

So the velocity flow field is irrotational and the conservation of mass is preserved.

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The speed immediately after stopping the ball is 0.049 m/s.

Velocity is the directional speed of a moving object as an indication of its rate of change in location as perceived from a specific frame of reference and measured by a specific time standard.

Given,

The mass of ball m = 140 g = 0.140 kg.

The speed of ball u = 23 m/s.

We must determine the speed at which the ballplayer is at the peak of his leap. They will remain together. Allow them to move at the speed of V.

Allow a 65-kilogram baseball player to jump straight up to catch a hard-hit ball. Then, according to linear momentum conservation.

mu+ Mu'=(m+ M)V

In this case, u' represents the player's initial speed. Because the player was initially at rest, u' = 0.

(0.140×23)+(65×0)=(0.140+65)V

V=(0.140×23)/(0.140+65)

V=3.22/65.14

V=0.0494

Therefore, the speed immediately after stopping the ball is 0.049 m/s.

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According to Newton's first law, an object will accelerate at a constant rate if its net force is zero. The calculated value is 39.2 N

This indicates that the velocity is constant but does not necessarily imply that the item is at rest.

F = m a

= 4 kg x 2.5 m/s/s x 10 N, correct.

The formula for Fgrav is:

Fgrav = m • g

= 4 kg • 9.8 m/s/s

= 39.2 N since the mass is known.

The normal force is equivalent to the gravitational force since there is no vertical acceleration. A force in physics is any interaction that, if left unchecked, will alter an object's motion. An object with mass can change its velocity due to a force, which includes starting to move from a state,

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The time taken by the elevator to stop if the cable lifting an elevator is wrapped around a 1.0-m-diameter cylinder and the elevator is moving upward at a speed of 1.9 m/s is 3.28 s

d = 1 m

r = d / 2

r = 1 / 2 = 0.5 m

Vertical distance travelled = Circumference of the cylinder

s = 2 π r

s = 2 * 3.14 * 0.5

s = 3.14 m

v² = u² + 2 a s

v = 0

u = 1.9 m / s

0 = 1.9² + ( 2 * a * 3.14 )

6.28 a = - 3.61

a = - 0.58 m / s²

v = u + at

0 = 1.9 + ( - 0.58 * t )

t = 1.9 / 0.58

t = 3.28 s

Therefore, the time taken by the elevator to stop is 3.28 s

The given question is incomplete. The complete question is:

The cable lifting an elevator is wrapped around a 1.0-m-diameter cylinder that is turned by the elevator's motor. The elevator is moving upward at a speed of 1.9 m/s. It then slows to a stop as the cylinder makes one complete turn at constant angular acceleration. How long does it take for the elevator to stop?

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Answer:

5.8km=5800m

Explanation:

You have to convert kilometres into metres

Answer:

It's 5,800 meters

Explanation:

In the question the distance has been already given, what's required is converting it from Kilometers to Meters. This means you will need to multiply 5.8 by 1000 to get your answer.

Answer:

Explanation:Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.

Now our wavelength is getting longer because the waves are stretching out. This makes the 1. Frequency is lower as well as the pitch we hear.

Wavelength is the gap among equal factors (adjacent crests) in the adjacent cycles of a waveform sign propagated in the area or alongside a twine. In wi-fi systems, this duration is generally laid out in meters (m), centimeters (cm), or millimeters (mm).

Equation of the wavelength, we will tell that the wavelength of a wave is inversely proportional to its frequency, i.e., because the frequency of a wave increases, its wavelength decreases.

A better-frequency sound has a better pitch, and a decreased-frequency sound has a lower pitch. In discern 10.2 sound A has a better pitch than sound B. for example, the chirp of a bird would have an excessive pitch, but the roar of a lion could have a low pitch. The human ear can discover a huge variety of frequencies.

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Disclaimer:- your question is incomplete, please see below for the complete question.

Now our wavelength is getting longer because the waves are stretching out. This makes the _________ lower as well as the pitch we hear.

1. Frequency

2. Loudness

3. Amplitude

The force implemented at the rod is  P=zero.25lb P = zero.25 l b. the burden of the rod is  w=1.75lb w = 1. seventy-five lb. The kinematic diagram of the rod.

Friction is any point in the consumer's journey with an organization wherein they hit a snag that slows them down or causes dissatisfaction. in the most primary concept, offering frictionless customer support way tracking the consumer adventure and improving the consumer revel in.

The overwhelming consensus is that ice has low friction because of a skinny film of liquid water coating its surface. for this reason, skaters balanced on skinny steel blades can float easily throughout the ice rink, but grind to a halt at the timber ground beyond.

Motion is certainly viable without friction even though an item is stationary in a single reference frame, in some other reference body shifting with admire the first, that identical object may be seen to be transferring. So movement actually does not need friction at all.

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