Hey guys this is Ap physics please help I need this to pass i will mark brainliest for a good attempt

Complete Question

a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop? Assume that the car does not skid and that each tire has a radius of 0.307 m. Answer in units of rev.

Answer:

The value is  [tex]N = 109 \ rev[/tex]      

Explanation:

From the question we are told that

    The speed of the car is  [tex]u = 28.4 \ m/s[/tex]

     The constant deceleration experienced is  [tex]a = 1.92 \ m/s^2[/tex]

      The radius of the tire is  [tex]r = 0.307 \ m[/tex]

Generally from kinematic equation we have that

      [tex]v^2 = u^2 + 2as[/tex]

Here  v is the final velocity which is  0 m/s

   So

         [tex]0^2 = 28.4^2 + 2 * 1.92 * s[/tex]

=>      [tex]s = 210.04 \ m[/tex]

Generally the circumference of the tire is mathematically represented as

         [tex]C = 2 \pi r[/tex]

=>      [tex]C = 2 * 3.142 * 0.307[/tex]    

=>      [tex]C = 1.929 \ m[/tex]

Generally the number of revolution is mathematically represented as

         [tex]N = \frac{ s}{C}[/tex]    

=>     [tex]N = \frac{210.04}{1.929}[/tex]

=>     [tex]N = 109 \ rev[/tex]      

Answer:

P = 33.33 [Pa]

Explanation:

The pressure can be calculated by the relationship of the force over the area.

[tex]P =F/A[/tex]

where:

F = force = 20 [N]

A = area = 1 x 0.6 = 0.6 [m²]

Now replacing:

[tex]P=20/0.6\\P=33.33 [Pa][/tex]

Answer:

D. The force on the wire is 24 N.

Explanation:

Given;

length of the wire,  L = 0.6 m

current in the wire, I = 4 A

magnitude of the magnetic field, B = 10 T

The fore on the wire is calculated as;

F = BILsinθ

where;

θ is the angle of inclination of the wire on magnetic field = 90°

F = (10)(4)(0.6)(sin 90°)

F = 24 N

Therefore, the force on the wire is 24 N.

[tex]d = s \times t \\ d = 90 \times \frac{30}{60} \\ d = 90 \times \frac{1}{2 } \\ d = 45km[/tex]

Answer:

F = 0.014 N

Explanation:

       [tex]F_{SC} =G *\frac{m_{S}*m_{C} }{r_{SC} ^{2} } (1)[/tex]

       where G= Universal Constant of Gravitation = 6.67*10⁻¹¹ N*m2/kg2

       mS = mass of Sally = 77 kg.

       mC = mass of Ceres = 8.7*10²⁰ kg

       rSC = distance between Sally and Ceres = 18,000 km

       [tex]F_{SC} =6.67e-11 N*m2/kg2 *\frac{77kg*8.7e20kg}{(18,000km)^{2}} = 0.014 N (2)[/tex]

Heya!!

For calculate aceleration, let's applicate second law of Newton:

[tex]\boxed{F=ma}[/tex]

⇒ Being:

→ F = Force = 12 N

→ m = Mass = 3 kg

→ a = aceleration = ?

Lets replace according formula and leave the "a" alone:

[tex]12\ N = 3\ kg * \textbf{a}[/tex]

[tex]\textbf{a} = 12\ N / 3\ kg[/tex]

[tex]\textbf{a} = 4\ m/s^{2}[/tex]

Result:

The aceleration of the object is of 4 m/s²

Answer:

(ans147.15m/s downward)

Explanation:

initial velocity (u)=0m/s

final velocity (v)=?

v=u+gt. ( t)time taken=15seconds

?=0+(9.81)×15

?=147.15m/s

hope this helped

Answer:

Decreasing

Hope this helps! :)

Answer:

68.6 m/s

Explanation:

Recall that the velocity formula to use for accelerated motion due to gravity (g) is:

vf =vi + g * t

so if 19.6 m/s is the initial velocity for the free falling object, then, 5 seconds later under the acceleration of gravity (g) :

vf = 19.6 + 9.8 * (5) = 68.6 m/s

Answer: 3.

Explanation:

The correct answer is a higher amplitude and lower frequency. Since an opera singer is lowering his pitch it means that he is creating higher amplitude and because he is raising his voice for a song with that higher amplitude he is creating lower frequency.

Answer:

1.736m/s²

Explanation:

According to Newton's second law;

[tex]\sum F_x = ma_x\\[/tex]

[tex]Fm - Ff = ma_x\\[/tex] where;

Fm is the moving force = 70.0N

Ff is the frictional force acting on the body

[tex]Ff = \mu R\\Ff = \mu mg\\[/tex]

[tex]\mu[/tex] is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

a is the acceleration/deceleration

The equation becomes;

[tex]Fm - Ff = ma_x\\Fm - \mu mg = ma\\[/tex]

Substitute the given parameters

[tex]Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a = 1.736m/s^2\\[/tex]

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

Answer:

1.92 m/s2

Explanation:

Answer:

Transparent or Translucent

Explanation:

Answer:

The water has potential energy at the top of the waterfall and increasing kinetic energy as it falls.

Explanation:

Answer:

Explanation:

I think is B

Answer:

724.3J/Kg.K

Explanation:

CHECK THE COMPLETE QUESTION BELOW

Compute the specific heat capacity at constant volume of nitrogen (N2) gas.and compare with specific heat of liquid water. The molar mass of N2 is 28.0 g/mol.

The specific heat capacity can be computed by using expression below

c= CV/M

Where c= specific heat capacity

M= molar mass

CV= molar hear capacity

Nitrogen is a diatomic element, the Cv can be related to gas constant with 5/2R

Where R= 8.314J/mol.k

Molar mass= 28 ×10^-3Kg/mol

If we substitute to the expression, we have

c= (5R/2)/(M)

=5R/2 × 1/M

=(5×8.314) /(2×28 ×10^-3)

=724.3J/Kg.K

Hence, the specific heat capacity at constant volume of nitrogen (N2) gas is

724.3J/Kg.K

The specific heat of liquid water is about 4182 J/(K kg) which is among substance with high specific heat, therefore specific heat of Nitrogen gas is 724.3J/Kg.K which is low compare to that of liquid water.

Answer:100 miles

Explanation:

Answer:

10 Km

Explanation:

He is going 5km per hour and he arrived at his friend's house in 2 hours. You multiply 5 by 2 and you get 10.

Answer:

transition metals im sorry if this was too late

Answer:

A. 28.42 m/s

B. 41.21 m.

Explanation:

A. Determination of the initial velocity of the ball:

Time (t) to reach the maximum height = 2.9 s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going against gravity)

Initial velocity (u) =?

Thus, we can obtain the initial velocity of the ball as follow:

v = u + gt

0 = u + (–9.8 × 2.9)

0 = u – 28.42

Collect like terms

u = 0 + 28.42

u = 28.42 m/s

Therefore, the initial velocity of the ball is 28.42 m/s.

B. Determination of the maximum height reached.

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going against gravity)

Initial velocity (u) = 28.42 m/s.

Maximum height (h) =?

Thus, we can obtain the maximum height reached by the ball as follow:

v² = u² + 2gh

0² = 28.42² + (2 × –9.8 × h)

0 = 807.6964 + (–19.6h)

0 = 807.6964 – 19.6h

Collect like terms

0 – 807.6964 = – 19.6h

– 807.6964 = – 19.6h

Divide both side by – 19.6

h = –807.6964 / –19.6

h = 41.21 m

Therefore, the maximum height reached by the ball is 41.21 m

Answer:

23.51 m/s

Explanation:

Parameters given:

Kinetic energy, K = 295 J

Momentum, p = 25.1 kgm/s

a) The kinetic energy of a body is given as:

where m = mass of the body and v = speed of the body

Answer:

Explanation:

Where,

[tex]\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}[/tex]

[tex]\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}[/tex]

[tex]\to\:\:\sf\green{5000 = 50 \times v^{2}}[/tex]

[tex]\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}[/tex]

[tex]\to\:\:\sf\purple{100 = v^{2}}[/tex]

[tex]\to\:\:\sf\red{\sqrt{100} = v}[/tex]

[tex]\to\:\:\sf\orange{ 10 = v}[/tex]

[tex]\to\:\:\bf\pink{v = 10\:m/s}[/tex]

Answer:

Oh well have your parents do something bout that. They are there to help you. Or guardian they all shall help you that is what they are there for. They are they to take care of you, answer you questions, and last but not least, they are there to also raise you. Ask you mom, dad, guardian, and maybe even you teacher to post pone the date. Teachers are to help you. Your guardian is to watch you make sure your safe while your parents are away (bascially like raising you). And parents to raise you, make sure you safe, and many other things like to make sure you are fed.

Explanation:

I hope they all have some type of help for you.

Answer:

The initial horizontal and vertical components are 12.5 m/s and 21.7 m/s, respectively?

Explanation:

Answer:

18.9s

Explanation:

Using the formula;

ω = v/r

Where;

ω = angular velocity (rad/s)

v = linear velocity (m/s)

r = radius of the circular track (m)

According to the given information, v = 30m/s, r = 90m

ω = v/r

ω = 30/90

ω = 3/9

ω = 0.3333 radians/seconds.

Since ω = 2π/T

Where;

π = 3.142

T = period (s)

ω = angular velocity

0.333 = 2 × 3.142/T

T = 2 × 3.142/0.333

T = 6.284/0.333

T = 18.87s

T = 18.9s

Answer:

There are 25,000 marbles in the container

Explanation:

There is a certain number of marbles in a container.

We know each marble has a mass of 80 mg and we also know the total mass of the marbles in the container is 2 Kg.

Since the data is given in different units of mass, we convert them into one unit in common.

Let's convert 2 Kg to milligrams. There are 1,000 grams in a kilogram, and there are 1,000 milligrams in a gram, thus there are one million milligrams in one kilogram, that is:

1 Kg = 1,000,000 mg

And 2 Kg = 2,000,000 mg

The number of marbles can be found by dividing the total mass by the individual mass:

No. of marbles = 2,000,000 / 80 = 25,000

There are 25,000 marbles in the container

Answer:

D.-1500Joules

Explanation:

The change in kinetic energy of the object s equivalent to the workdone by the body in the west direction (negative x direction)

Workdone = Force * Distance

Given

Force = 30N

Distance moved by the object = 30m

Required

Kinetic energy

Kinetic energy = 30 * 50

Kinetic energy = 1500Joules

Since the body moves in the negative  direction, hence the kinetic energy will be -1500Joules

Potential energy+Kinetic energy=Total energy

When you release a spring the velocity increases, therefore the kinetic energy increases ke=1/2*mv^2 and the displacement decreases therefore the potential energy decreases pe=1/2*kx^2.

Answer:

d=75 m

Explanation:

Before Skidding

[tex]v^2-v_o^2=2ad[/tex]

[tex]0^2-49^2=2a(12)[/tex]

After Skidding

[tex]v^2-v_o^2=2ad[/tex]

[tex]0^2-122.5^2=2ad[/tex]

[tex]\frac{49^2}{122.5^2}=\frac{12}{d}[/tex]

[tex]d=75 m[/tex]

Hope it helps

Answer:10000000

Explanation:

Answer:

The velocity of the car when it hits the ground is approximately 55.574 meters per second.

Explanation:

According to this expression, the car goes straight into the cliff and goes down due to gravity, whose situation is described by the Principle of Energy Conservation and supposing that all non-conservative forces are negligible:

[tex]U_{g,1}+K_{1} = U_{g,2}+K_{2}[/tex] (1)

Where:

[tex]U_{g,1}[/tex], [tex]U_{g,2}[/tex] - Gravitational potential energies of the car at the top and the bottom, measured in joules.

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Translational kinetic energies of the car at the top and the bottom, measured in joules.

By definitions of gravitational potential and translational kinetic energies, we expand and simplify the equation above:

[tex]\frac{1}{2}\cdot m\cdot v_{2}^{2} = \frac{1}{2}\cdot m \cdot v_{1}^{2}+m\cdot g \cdot (z_{1}-z_{2})[/tex] (2)

[tex]v_{2}^{2} = v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})[/tex]

[tex]v_{2} = \sqrt{v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})}[/tex]

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Velocity of the car at the top and the bottom, measured in meters per second.

[tex]g[/tex] - Gravitaitional acceleration, measured in meters per square second.

[tex]z_{1}[/tex], [tex]z_{2}[/tex] - Height of the car at the top and at the bottom, measured in meters.

If we know that [tex]v_{1} = 50\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{1} = 30\,m[/tex] and [tex]z_{2} = 0\,m[/tex], then the velocity of the car when it hits the ground is:

[tex]v_{2} = \sqrt{\left(50\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (30\,m-0\,m)}[/tex]

[tex]v_{2}\approx 55.574\,\frac{m}{s}[/tex]

The velocity of the car when it hits the ground is approximately 55.574 meters per second.