help me pleaseeeeeeeee

Answer: Hope this helps you!

6th floor

Step-by-step explanation:

If it starts on the 9th floor and goes down 7 floors that is:

9 (9 floors) + -7 (down 7 floors)

which is also equal to 9-7

9-7 = 2

Next, we need to go up by 4 floors starting with 2, 2+4

2+4 = 6

Brainliest?

.✎let's answer it :3

question ⇩

✎ The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.

The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.The width of the page is ___ inches.

hope it helps

correct me if I am wrong

Recall that the derivative of a function f(x) at a point x = c is given by

[tex]\displaystyle f'(c) = \lim_{x\to c} \frac{f(x) - f(c)}{x - c}[/tex]

By substituting h = x - c, we have the equivalent expression

[tex]\displaystyle f'(c) = \lim_{h\to0} \frac{f(c+h) - f(c)}h[/tex]

since if x approaches c, then h = x - c approaches c - c = 0.

The two given limits strongly resemble what we have here, so it's just a matter of identifying the f(x) and c.

For the first limit,

[tex]\displaystyle \lim_{h\to0} \frac{\sin\left(\frac\pi3 + h\right) - \frac{\sqrt3}2}h[/tex]

recall that sin(π/3) = √3/2. Then c = π/3 and f(x) = sin(x), and the limit is equal to the derivative of sin(x) at x = π/3. We have

[tex](\sin(x))' = \cos(x)[/tex]

and cos(π/3) = 1/2.

For the second limit,

[tex]\displaystyle \lim_{a\to0} \frac{e^{2a} - 1}a[/tex]

we observe that e²ˣ = 1 if x = 0. So this limit is the derivative of e²ˣ at x = 0. We have

[tex]\left(e^{2x}\right)' = e^{2x} (2x)' = 2e^{2x}[/tex]

and 2e⁰ = 2.

Answer:

48

Step-by-step explanation:

66*2=132

180-132=48

Hope this helps!

If not, I am sorry.

Using the combination formula, it is found that 35 different combination of teams can make it to the playoffs.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, 4 students are taken from a set of 7, hence the number of combinations is given by:

[tex]C_{7,4} = \frac{7!}{4!3!} = 35[/tex]

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Answer:

The answer is the third bullet. (number 3)

Answer:

135°

Step-by-step explanation:

That triangle in the corner is an right angle isosceles triangle as that line the midpoint of both sides :

the base angle of this triangle (x) will be :

180 = 90 + 2x

90 = 2x

x= 45

Angles on a straight line add up to 180. So to work out a :

180 = 45 + a

135 = a

Hope this helped and brainliest please

Answer:

a) Length= (x+2) and breadth=(x-1) b) 4 m^2 c) R1000

Answer:

answers in photo / +explanation

Step-by-step explanation:

a)

length: x+2

width/breadth: x-1

b)

length: 4m

width/breadth: 1m

area: 4m²

c)

R1000

The response that represents the 86th percentile is 7.884

The response that represents the 55th percentile is 5.69

The response that represents the first percentile 3.85

mean = 5.4

sd = 2.3

p(X>x) = 0.86

find the value of z using the NORMSINV function in excel with a probability of 0.86

z = 1.080

x = mean + sd*z

= 5.4 + 2.3 * 1.080

= 7.88

mean = 5.4

sd = 2.3

p(X>x) = 0.55

find the value of z using the NORMSINV function in excel with a probability of 0.55

z = 0.1257

x = mean + sd*z

= 5.4 + 2.3 * 0.1257

= 5.69

c. The first quartile is 25%

z = -0.6745

5.4 + 2.3 * -0.6745

= 5.4-1.551

= 3.85

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Answer:

there are 75 colors of each candy

Step-by-step explanation:

300÷4=75

The best statement that describes the angle JKL is inscribed angle.

An inscribed angle in a circle is formed by two chords that have a common end point on the circle. The chord JK and LK intersect in the circle.

The angle ∠JKL is not an obtuse angle because it's less than 90 degrees.

The angle ∠JKL is not a vertical angle because it's not vertically opposite  any angle.

The angle ∠JKL is not a central angle because it was not from from the centre of the circle.

The angle is an inscribed angle because it was formed by the intersection of two chords in the circle.

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The average rate of a function is 81 if a quadratic function with a vertex at (6, 8).

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

Quadratic function with a vertex at (6, 8).

It is required to find the average rate of the function:

Here the data table is not given, so we are assuming the value of a function:

At x = 13 is 196

f(13) = 144

At x = 14 is 225

f(14) = 225

The average rate of a function:

= [f(14) - f(13)]/(14 - 13)

= [225 - 144]/(1)

= 81

Thus, the average rate of a function is 81 if a quadratic function with a vertex at (6, 8).

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The number of lines of symmetry for the given figure will be 4.

Symmetry is described in geometry as a balanced and proportionate likeness between two halves of an object.

As we know that similarity is defined as when the image is divided into two halves and one portion is completely overlapped by the other.

So in the given figure, the figure can be divided into two halves by drawing four lines along with the arrows and along with the corners. In all cases, the two halves overlap with the other.

Therefore the number of lines of symmetry for the given figure will be 4.

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Answer:

y = 3

Step-by-step explanation:

given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

to find k use the condition y = 57 when x = 19 , then

57 = 19k ( divide both sides by 19 )

3 = k

y = 3x ← equation of variation

when x = 1 , then

y = 3 × 1 = 3

Based on the quadrilaterals given, the types of angles that we see are Acute and Obtuse.

Acute angles are those that are less than 90° and these are shown in the trapezium quadrilateral.

Obtuse angles are higher than 90° and so are drawn outwards as seen in the parallelogram.

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Answer:

place the decimal number over its place value

Step-by-step explanation:

For example in 0.4 the four is in the tenths place, so we place 4 over 10 like 4/10

Answer:

Step-by-step explanation:

Example:

   4.52

[tex]4.52 =\dfrac{4.52}{1}[/tex]

In 4.52, there are two decimal places. So multiply the numerator and denominator by 100

[tex]\dfrac{4.52*100}{1*100}=\dfrac{452}{100}=\dfrac{452 \div 4}{100 \div 4}=\dfrac{113}{25}[/tex]

Answer:

-2

Step-by-step explanation:

[tex](5 \times 1) - 7 \\ 5 - 7 \\ - 2[/tex]

Step-by-step explanation:

5(x+2)
1. Distributive property
2. Multiply
(5*x) + (5*2)
(5x)+(10)
Remove parenthesis

5x+10 ;

Therefore, 5(x+2) = 5x+10

Hopefully this helps! :3

Answer:

'''

Step-by-step explanation:

(3x-2)^2

squares area is 2 times its side length, since all the sides are the same. if the side length is 3x-2, take its second power

Using it's concept, it is found that the percent increase in the amount of iron per serving was of 50%.

It is given by the increase divided by the initial value, and subtracted by 100%.

In this problem:

Hence the percent increase is given by:

P = 0.6/1.2 x 100% = 50%.

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Answer:

hope you can understand

Answer:

neither can be factored any further but if it is (9x^4) - (16y^4) it can be factored down to ((3x^2)+(4y^2)) ((3x^2)+(4y^2))

Step-by-step explanation:

Sorry don't no the answer

sorry if I kwon the answer

I telling u the answer

The probability that the dog that's selected will weigh less than 30 pounds will be 55%.

From the information given, it was stated that 45% of the dogs weigh more than 30 pounds. Therefore, the probability that the dog that's selected will weigh less than 30 pounds will be:

= 1 - 45%

= 55%

The probability that it weighs more than 30 pound given that it has long fur will be 27%.

The events are independent since the occurence of one doesn't affect the other one.

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We will get the areas of each one of the given triangles:

7) A = 12.69 mm²

8) A = 19.21 in²

9) A = 16.81 yd²

7) First, we have an equilateral triangle, where all the sides measure 5.4mm

For an equilateral triangle of side length S, the area is:

[tex]A = \frac{\sqrt{3} }{4}S^2[/tex]

In this case, S = 5.4 mm, replacing we get:

[tex]A = \frac{\sqrt{3} }{4}(5.4mm)^2 = 12.62 mm^2[/tex]

8) Now we have two equal sides and one different. The general area of a triangle of base B and height H is:

A = B*H/2.

In this case, the base measures 3.4 in.

To get the height, let's divide the triangle into two right triangles, such that one cathetus is 3.4in/2 = 1.7 in.

The hypotenuse measures 5.9 in

And the other cathetus is the height of the triangle.

Then, by using the Pythagorean theorem, we see that the height is:

[tex]H = \sqrt{(5.9 in)^2 - (1.7in)^2} = 5.65 in[/tex]

Then the area of this triangle is:

[tex]A = (3.4 in)*(5.65 in)/2 = 19.21 in^2[/tex]

9) Here the base measures 8.2 yds, and the height 4.1 yds, so the area is just:

[tex]A = (4.1 yd)*(8.2 yd)/2 = 16.81 yd^2[/tex]

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Answer:

r > -69

Step-by-step explanation:

13 - r < 82

subtract 13 from both sides

13 - r - 13 < 82 - 13

- r < 69

to flip the inequality sign, multiply both side by -1 to make r positive:

- r (-1) < 69 (-1)

r > -69

        [tex]\rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}[/tex]

    13-r<82

      [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}[/tex]

   First of all, we need to isolate r (get r by itself). What I Mean by that is

       We need to get r by itself on one side of the inequality.

      So it should look something like this:-

     r<___

So r is all by itself.

How will we get r by itself? Well, First of all, we need to subtract 13 on both sides:-

[tex]\longmapsto\bf{-r < 82-13[/tex]

Simplifying,

[tex]\longmapsto\bf{-r < 69}[/tex]

Now, is r by itself? Nopes, There's also a minus sign next to it , which indicates that r is multiplied by -1.

So we do the opposite operation and divide both sides by -1:-

(watch what happens)

[tex]\longmapsto\bf{r > -69}[/tex]

The inequality sign changed from "less than" to "greater than".

This happened because we divided by a negative number on both sides.

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[tex]\rule{300}{1}[/tex]