help me, please ist question 1

Answer:

-18 + x = 11

x = 29

Step-by-step explanation:

To solve this, you can use the formula of a + b = c

[tex]-18 + x = 11\\-18 = 18\\11 + 18 = 29\\x = 29[/tex]

Answer:

29

Step-by-step explanation:

Your equation can be -18+x=11. Since we don't know the number, we can use x. We are trying to find out a number that when it's added to -18, the answer will be 11.

Now, we solve the equation:

-18+x=11

x=11+18

x=29. Answer

To check this answer:

we can use our equation and substitute 29 for x.

-18+x=11

-18+(29)=11

11=11.

They are equal. Therfore, the answer is correct.

Answer:

[tex](x+1-i)(x+1+i)[/tex]

Step-by-step explanation:

[tex](x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2[/tex]

Step-by-step explanation:

once the level of medicine reaches a value, where 30% are 23mL (so, whatever is lost, is immediately replaced again), that is then the long run value for the amount of the drug in the patient's body.

so,

30% = 23 mL

1% = 30%/30 = 23/30 = 0.766666666...

100% = 1%×100 = 0.766666666... × 100 = 76.666666...

so, once the level reaches 76.666666... mL in the body, it will remain constant, as the daily filtered out 30% are 23 mL, and the daily add-on is also 23 mL.

so, the answer is

76.667 mL

Answer:

  B; (-4, -8)

Step-by-step explanation:

The given forms of the equation are standard form, vertex form, and intercept form.

__

It is not surprising that the vertex form yields the vertex most quickly.

  B) m(x) = 2(x +4)² -8

Compare this to the generic vertex form ...

  f(x) = a(x -h)² +k . . . . . . . . . vertex (h, k)

We see that the vertex is (h, k) = (-4, -8).

I assume by f¹, you actually mean f⁻¹ as in the inverse of f. I also assume you are asked to find f(x) (as in the inverse of f⁻¹) and f⁻¹(4).

Given that

[tex]f^{-1}(x+2) = \dfrac{x-1}{x+1}[/tex]

with x ≠ 1, we can find f⁻¹(x) by replacing x + 2 with x :

[tex]f^{-1}(x + 2) = \dfrac{x-1}{x+1} = \dfrac{(x+2) - 3}{(x + 2) - 1} \implies f^{-1}(x) = \dfrac{x-3}{x-1}[/tex]

Then when x = 4, we have

[tex]f^{-1}(4) = \dfrac{4-3}{4-1} = \dfrac13[/tex]

Of course, we also could have just substituted x = 2 into the definition of f⁻¹(x + 2) :

[tex]f^{-1}(4) = f^{-1}(2+2) = \dfrac{2-1}{2+1} = \dfrac13[/tex]

To find f(x), we fall back to the definition of an inverse function:

[tex]f^{-1}\left(f(x)\right) = x[/tex]

Then by definition of f⁻¹, we have

[tex]f^{-1}\left(f(x)\right) = \dfrac{f(x)-3}{f(x)-1} = x[/tex]

Solve for f :

[tex]f(x) - 3 = x (f(x) - 1)[/tex]

[tex]f(x) - 3 = x f(x) - x[/tex]

[tex]f(x) - x f(x) = 3 - x[/tex]

[tex](1 - x) f(x) = 3-x[/tex]

[tex]f(x) = \dfrac{3-x}{1-x} = \dfrac{x-1}{x-3}[/tex]

The probability that the next spin lands on red is

The table of values is given as:

Red = 4

Blue = 3

Green = 20

Yellow = 14

Purple = 16

The probability that the next spin lands on red is:

P(Red) = Red/Total

This gives

P(Red) = 4/(4+3+20+14+16)

Evaluate

P(Red) = 7%

Hence, the probability that the next spin lands on red is

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Answer:8%

Step-by-step explanation:

i cant help you with that bc there is no graph so...

Answer:

First answer:

A

Second answer:

I think A

Answer:

A and B

Step-by-step explanation:

1

the volume (V) of a rectangular prism is calculated as

V = lwh ( l is length, w is width, h is the height )

  = Bh ( B is the area of the base )

2

the volume of a cone is [tex]\frac{1}{3}[/tex] the volume of a cylinder with the same base area (B) and height (h)

Answer-10x+46

Step-by-step explanation: hope this helps

Answer: Answer-10x+46

Answer:

3x³ + 12x

Step-by-step explanation:

3x(x² + 4)

3x³ + 12x

Answer:

4

Step-by-step explanation:

(3 × 14) × 3 = 126

7 × 18 = 126

Boubacar will have to increase each dimension by 4 ft so that its area is triple.

The area of a rectangle is given by -

A[R] = L x B

where -

L is Length of rectangle

B is Breadth or width of rectangle.

Given is a deck that measures 3 feet by 14 feet. Boubacar wants to increase each dimension by equal lengths so that its area is tripled.

Assume that he increases the dimensions by x ft.

Initial Area = [A] = 3 x 14 = 42 ft².

Final Area = [A'] = 3[A] = 3 x 42 = 126 ft²

Initial dimensions = (L x B) = 3 feet x 14 feet

Final dimensions = (L' x B') = (3 + x) × (14 + x)

Now -

(L' x B') = 126

(3 + x)(14 + x) = 126

3(14 + x) + x(14 + x) = 126

42 + 3x + 14x + x² = 126

x² + 17x - 84 = 0

Solving the equation, we get -

x = 4  [ non negative number ]

Therefore, Boubacar will have to increase each dimension by 4 ft so that its area is tripled.

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Answer:

11,800 lb

Step-by-step explanation:

dnt worry i got my wayz :)

Answer:

11,800 lbs

Step-by-step explanation:

5.9x2,000=11,800

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

that is :-

[tex]{ \boxed{✠\underline{ \boxed{ \sf{ \red✰Cost \: price =100 \times \frac{selling \: price}{100 + profit\%} }}}✠}}[/tex]

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

[tex]\rm{➾x = 100 \times \frac{690}{100 + 15}} \\\rm{➾x \frac{100 \times 690}{100 + 15}~~~~~~~~~~~~~~~ } \\ \rm{➾x = \frac {100 \times \cancel{ 690}}{ \cancel{115}}}~~~~~~~ \\ \rm{➾x = 100 \times 6}~~~~~~~~~~~~~~~ \\ \rm{➾x =106}~~~~~~~~~~~~~~~[/tex]

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

➣ Hence "x" (Cost price) of the item

[tex] \large{ \boxed{✠\underline{ \boxed{ \sf{ Rs.106\green✓}}}✠}}[/tex]

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘

Hope it helps !

Answer:

Rhombus

Step-by-step explanation:

Sides are parallel but have no right angles.

Answer:

  parallelogram

Step-by-step explanation:

Opposite sides of the figure have the same slope (0 or 5/2), so are parallel. The product of the slopes is not -1, so the angles are not right angles. Adjacent sides are different lengths, so the figure is not a rhombus.

__

The figure is a parallelogram.

_____

Additional comment

The slope is the "rise" (change in y-coordinate) of the segment divided by its "run" (change in x-coordinate). The left and right sides have a rise of 7-2 = 5, and a run of 6-4 = 2 -0 = 2. Their slope is 5/2.

The top and bottom sides have a rise of 0, so a slope of 0.

When the product of the slopes of different segments is -1, those segments are perpendicular. The perpendicular to a horizontal line has "undefined" slope, so the product of the slopes would be (0)×(undefined). This is a special case of perpendicular lines where the product of slopes is not -1.

Answer:

2 months

Explanation:

50 - 40 = 10

25-20 = 5

10/5 = 2

The months for which Joey have to belong to each before the costs are the same are 2 months.

Equation modelling is a method of writing a mathematical relation from a mathematical statement for mathematical analyses of the problem given.

Given is different fees structure of two gyms →  Gym A has a $40 sign up fee and it costs $25 per month. Gym B has a $50 sign up fee and costs $20 per month.

Assume that the months for which Joey have to belong to each before the costs are the same be x.

Then -

For Gym A -

Total cost for x months = C[A] = 25x + 40

For Gym B -

Total cost for x months = C[B] = 20x + 50

For same cost -

C[A] = C[B]

25x + 40 = 20x + 50

25x - 20x = 50 - 40

5x = 10

x = 2

Therefore, the months for which Joey have to belong to each before the costs are the same are 2 months.

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Answer:

x=3

13x-5=1+11x

(ADD 5 TO BOTH SIDES)

13x-5+5=1+11x+5

SIMPLIFY

13x=11x+6

SUBTRACT 11x FROM BOTH SIDES

13x-11x=11x+6-11x

SIMPLIFY

2x=6

DIVIDE BOTH SIDES BY 2

2x/2 = 6/2

SIMPLIFY TO GET FINAL ANSWER

x=3

[tex]\dfrac{5-i}{4+3i}=\dfrac{(5-i)(4-3i)}{(4+3i)(4-3i)}=\dfrac{20-15i-4i-3}{16+9}=\dfrac{17-19i}{25}=\dfrac{17}{25}-\dfrac{19}{25}i[/tex]

The given figure is quadrilateral, parallelogram, and a  rhombus but not a square. So brett is not correct.

A square is a quadrilateral with all the sides equal and all the four sides are perpendicular to each other.

We know that it is a quadrilateral as a quadrilateral is having four sides and the sum of the angles is 180 degrees.

The given figure is a parallelogram as opposite sides of the figure are parallel and equal.

The given figure is a rhombus as all the sides are parallel and equal.

The given figure can not be a square as in the square all the four sides are perpendicular to each other.

Therefore given figure is quadrilateral, parallelogram, and a  rhombus but not a square. So brett is not correct.

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Answer:

x<-4 or x≤4

Step-by-step explanation:

The solution of the inequality is x > -4 and x ≤ 4.

So, the graph B is correct.

Given is an inequality, x+7 > 3 and x-5 ≤ -1, we need to solve and identify the graph,

To solve the compound inequality, let's solve each inequality separately and then find the intersection of the solutions.

Inequality 1: x + 7 > 3

Subtract 7 from both sides:

x > 3 - 7

x > -4

Inequality 2: x - 5 ≤ -1

Add 5 to both sides:

x ≤ -1 + 5

x ≤ 4

Now, we need to find the intersection of the solutions for both inequalities.

Since the conjunction between the two inequalities is "and," we need to find the common solution.

The common solution is the values of x that satisfy both x > -4 and x ≤ 4. From the two inequalities, we can see that the common solution range is from -4 to 4, including -4 but not including 4.

Therefore, the solution to the compound inequality is: -4 < x ≤ 4

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Answer:

x = -2

Step-by-step explanation:

Given :

[tex]\frac{8}{x+1} = \frac{-16}{x+4}[/tex]

=============================================================

Cross multiplying the terms :

⇒ 8 (x + 4) = -16 (x + 1)

⇒ 8x + 32 = -16x - 16

⇒ 24x = -48

⇒ x = -2

Answer: 17.2

Step-by-step explanation:

By the Pythagorean theorem,

[tex]10^{2}+14^{2}=(AC)^{2}\\\\(AC)^{2}=296\\\\AC=\sqrt{296} \approx \boxed{17.2}[/tex]

Answer: 16-30 because it has the most numbers in between

Step-by-step explanation: brainliest?

The interval that has the highest frequency is 16-30. That is option A.

To determine the class interval with the highest frequency, the following steps should be taken as follows;

The class interval taken are:

0-15 = 13, 14

16-30= 17,28,22,25

31-45= 37,33,41

46-60 = 0

61-75 = 61

Therefore,the class interval with the highest number of animals weight = 16-30.

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Answer:

Part A:

In order to find a coterminal angle, or angles of the given angle, simply add or subtract 360 degrees of the terminal angle as many times as possible.

Part B:Simply put, coterminal angles start at 0° and end at the same place, though in different directions and multiple times around (you're probably going to want to make that sound a little more formal). Since each time around is 360°, boom

Part C: 75° is in Quadrant II, right? If I go one more time around, 75 + 360 = 435°. I can also go "backward. Starting at 0 and going clockwise, I'm going 75 fewer degrees than all the way around, so 360-75 = 285° but since I'm going "backward" 75 - 360 = -285°. One more is on you.

Step-by-step explanation:

prolly 4.36 just use the Pythagorean theorem