Help I will mark brainliest

Simple the answer is: n=14

Answer:

If you mean percent, its 350%

Answer:

1134

Step-by-step explanation:

1134/63=18

Answer:

12

Step-by-step explanation:

the answer is just 12.

Answer:

45 miles in 3 days

Step-by-step explanation:

if she drives 3 miles an hour for 5 hours a day that would be 3x5=15

15x3 days=45 miles in 3 days

Answer:

Any number in the form of p/q where p and q are integers and q is not equal to 0 is a rational number.

So, 323.2685109 is IRRATIONAL number.

Answer:

7!!

Step-by-step explanation:

Answer:

B)120º

Step-by-step explanation:

70+50=x

120=x

Sum of two interior angles=exterior angle

[tex]\\ \sf\longmapsto 50+70=x[/tex]

[tex]\\ \sf\longmapsto x=120[/tex]

Option B

Answer:

15×15×16=3600

15×15=225

225×16=3600

Answer:

1st: $50 2nd: $250 3rd: $85

Answer:

1/4

Step-by-step explanation:

Slope = (change in the y-values)/(change in the x-values)

Slope = (4 - 2)/(1 - (-7) )

Slope =  (4 - 2)/(1 + 7)

Slope = 2/8

Slope = 1/4

Answer:

64, -64, -64

-27, 27, 27

Step-by-step explanation:

If x = 4,

x³ = 4³ = 64

-x³ = -4³ = -64

(-x)³ = (-4)³ = -64

If x = -3,

x³ = -3³ = -27

-x³ = -(-3)³ = 27

(-x)³ = (-(-3))³ = 27

Answer: 1/4

Given : On average, Carson spends about 26% of his allowance each month on candy and soft drinks.  

To Find : When creating a circle graph of what Carson does with his money, which of the following fractions would be the best to represent how much he spends on food?

If these are your Choices:

A) 1/4

B) 1/3

C) 3/4

D) 1/2

Solution:

To Convert fraction into % multiply by 100  

(1/4) * 100 = 25 %

(1/3) * 100  = 33.33 %

(3/4) * 100 = 75 %

(1/2) * 100 = 50 %

Therefore 1/4 fraction best represent how much he spends on food

Answer:

Every point of a number line is assumed to correspond to a real number, and every real number to a point. The integers are often shown as specially-marked points evenly spaced on the line.

Answer:

Answer 1 is 4:2 or also write as 2:1.

Answer:

(f ∘ g) (3) = 22

Step-by-step explanation:

f( x + 3x - 5; g (x) = x² ∴ g ( 3 ) = 3² = 9

( f ∘ g ) ( 3 ) = f(g(3)) = f ( 9 ) =  3 · 9 - 5 = 27 - 5 = 22 [Ans]

Answer:

2 is the correct answer

[tex]\large\underline{\sf{Solution-}}[/tex]

Given function is

[tex]\rm \longmapsto\:f(x) = \dfrac{1}{ \sqrt{ |cosx| + cosx} } [/tex]

Now,

[tex]\rm \longmapsto\:f(x) \: is \: defined \: if \: |cosx| + cosx > 0[/tex]

We know,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |x| = \begin{cases} &\sf{ - x \: \: when \: x < 0} \\ \\ &\sf{ \: \: x \: \: when \: x \geqslant 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |cosx| + cosx = \begin{cases} &\sf{ \: \: 0 \: \: when \: cosx \leqslant 0} \\ \\ &\sf{ \: \: 2 \: cosx \: \: when \: cosx > 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\rm\implies \:f(x) \: is \: defined \: when \: cosx > 0[/tex]

So, from graph we concluded that cosx > 0 in the following intervals.

[tex]\begin{gathered}\boxed{\begin{array}{c|c} \bf cosx & \bf \: x \: \in \: \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf + ve & \sf \bigg( - \dfrac{\pi}{2} ,\dfrac{\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{3\pi}{2} ,\dfrac{5\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{7\pi}{2} ,\dfrac{9\pi}{2} \bigg) \end{array}} \\ \end{gathered}[/tex]

So, if we generalized this we get

[tex]\rm\implies \:cosx > 0 \: when \: x \: \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z[/tex]

Hence,

Domain of the function is

[tex]\red{\rm\implies \boxed{\tt{ \: x \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z}}}[/tex]

[tex]\textsf{More to know :-} \\[/tex]

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf T-eq & \bf Solution \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf sinx = 0 & \sf x = n\pi \: \forall \: n \in \: Z\\ \\ \sf cosx = 0 & \sf x = (2n + 1)\dfrac{\pi}{2}\: \forall \: n \in \: Z\\ \\ \sf tanx = 0 & \sf x = n\pi\: \forall \: n \in \: Z\\ \\ \sf sinx = siny & \sf x = n\pi + {( - 1)}^{n}y \: \forall \: n \in \: Z\\ \\ \sf cosx = cosy & \sf x = 2n\pi \pm \: y\: \forall \: n \in \: Z\\ \\ \sf tanx = tany & \sf x = n\pi + y \: \forall \: n \in \: Z\end{array}} \\ \end{gathered}\end{gathered}[/tex]

Answer:

our vertex for f(x) = 3x² + 18x + 32 = (-3, 5 )

Step-by-step explanation:

let me write the standard form of a quadratic equation

[tex]a {x}^{2} + bx + c[/tex]

Now let me rewrite the original equation

[tex]3 {x}^{2} + 18x + 32[/tex]

Now we use this simple formula to find the vertex (h, k)

[tex]x = h = - \frac{b}{2a} \\ = - \frac{18}{2(3)} = - \frac{18}{6} = - 3 \\ h = - 3[/tex]

substitute -3 for x back into our original equation to solve for y our k value of our vertex

[tex]y = 3 ({ - 3})^{2} + 18( - 3) + 32 \\ = 3(9) - 54 + 32 \\ = 27 + 32 - 54 \\ = 59 - 54 \\ k = 5[/tex]

our vertex for f(x) = 3x² + 18x + 32 = (-3, 5 )

Answer:

Emily has a higher relative score since her z-score is higher. This would mean she scored further above the mean than Xiaoyu.

Step-by-step explanation:

Find the z-scores by subtracting the score they got by the mean and then dividing by the standard deivation of their respective exams.

Xiaoyu:

z = [tex]\frac{27 - 18}{6}[/tex] = 1.5

Emily:

z = [tex]\frac{720 - 500}{100}[/tex] = 2.2

______

Emily has a higher relative score since her z-score is higher. This would mean she scored further above the mean than Xiaoyu.

Answer:

N0O0O0O0O0O0O0O0O0O0O

Step-by-step explanation:

Answer:

Step-by-step explanation:

A= W*L

A= 31/3*21/4

A=10.3*5.25

A=54.075cm^2

Answer:

7 1/2in^2

Step-by-step explanation:

LxW=A

2 1/4 x 3 1/3 = A

A = 7 1/2

Answer:

4.5927 x 10^-2 ?

Step-by-step explanation:

Answer:

no, it is incorrect it is 1-100 the value

Step-by-step explanation:

0.006×10= 0.06

0.006×100=0.6

The upper bound means the highest number that you can round up to the nearest unit, in this case meters. So the upper bound for the distance of 100 meters is 100.4 meters.

Answer:

bye

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

substitute the values of x in the table into g(x)

Using the rule of exponents

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

g(- 2) = [tex]4^{-2}[/tex] = [tex]\frac{1}{4^{2} }[/tex] = [tex]\frac{1}{16}[/tex]

g(- 1) = [tex]4^{-1}[/tex] = [tex]\frac{1}{4}[/tex]

g(0) = [tex]4^{0}[/tex] = 1

g(1) = [tex]4^{1}[/tex] = 4

g(2) = 4² = 16

nth number is 83 hope you understand my answer thanks

Answer: 3n^2 + 8

Step-by-step explanation:

an^2 + bn + c

It is a quadratic sequence

11, 20, 35, 56, 83

 +8 +15 +21 +27

    +6   +6   +6

a + b + c

4a + 2b + c

9a + 3b + c

4a + 2b + c - a + b + c = 20 - 11

4a + 2b + c - a + b + c = 9

3a + b = 9

9a + 3b + c - 4a + 2b + c = 35 - 20

5a + b = 15

-2a = -6

a = -6/-2

a = 3

Substitute to find the values of b & c

For b

5(3) + b = 15

15 + b = 15

b = 15 - 15

b = 0

For c

9(3) + 3(0) + c = 35

27 + c = 35

c = 35 - 27

c = 8

3n^2 + 0n + 8

3n^2 + 8