help ASAP please again and again​

Answer:B

Step-by-step explanation:

This is because -3 is going to multiple numbers, which cannot happen in a function.

Answer:

the answer is defently 405

Step-by-step explanation:

so you have 400 and 5 and 400+5=405

Answer:

it is 27/16 or 1 11/16

Step-by-step explanation:

Answer:

cant tell what ths says

Step-by-step explanation:

Answer:

3.5hours

Step-by-step explanation:

7 hours is the max but divided by 2 people it is 3½ hours

Answer:

I need helpw with this is too

Step-by-step explanation:

Answer:

l*b*h is the answer of this question

Truck (2 or 3 axles): $3.00

Truck (4 or 5 axles): $6.25

Truck (6 or more axles): $10.00

Day1= 3 trucks with 5 axles and 1 truck with 8 axles passed the bridge

What we need to find:

Part a: an expression that represents the first passing of the 4 trucks and

a solution to the the first expression

Part b: a modification of first expression that includes the return passing of the 4 trucks and a solution for the trucks passing both times.

Part a:

3(6.25)+1(10.00)

3(6.25)+1(10.00)=$28.75

Part b:

2[3(6.25)+1(10.00)]

2[3(6.25)+1(10.00)]=2[28.75]=$57.50

Answer:

|6x+12|= 12 has 2 solutions --> x = -4 or x = 0

|6x+12|= -1 has No solutions

∣6x+12∣=0 has 1 solution --> x = -2

Explanation:

|6x+12|= 12

- Break |6x+12| = 12 down into two equations -

                                ↓

                       6x + 12 = 12

                       6x + 12 = −12

          - Solve both equations to x -

                       6x + 12 = 12

                       6x + 12 = −12

                                ↓

                            6x = 0

                           6x = −24

                                ↓

                             x = 0

                             x = −4

|6x+12|= -1

The absolute value function is always positive or 0 so false.

∣6x+12∣=0

- Because its 0, we simply just solve the equation -

                              6x + 12 = 0

                                     ↓

                                6x = -12

                                     ↓

                                  x = -2

~That's All Folks~

-Siascon

Answer: The answer is X∈[3,12).

Answer:

-8≤3x-17<19

-8+8 ≤ 3x - 17 + 8 < 19 + 8

0 ≤  3x - 9 < 27

0 ≤  3x - 9 + 9 < 27 + 9

0 ≤  3x <  36

0 ≤ 3x / 3 <  36/3

0 ≤ x < 12

So x can be 0 or less than 12. A number between 0 and 12

Answer:

80% of the class picked the pizza

Step-by-step explanation:

In order to find a percentage, you are supposed to divide the amount of how much someone has picked by the total amount (in this case pizza's). Here is how I got 80%,

28/35 = 0.8

0.8*100 = 80

So the answer is 80%

Answer:

120 cm^3

Step-by-step explanation:

1. 9 times 5 =45

2. 45 divided by 3 = 15

3. 15 times 8 = 120

Answer:

q=4v/x

Step-by-step explanation:

Answer:

x=1, y=-3. (1, -3).

Step-by-step explanation:

6x-9=y

y=-3x

-----------

6x-9=-3x

6x-(-3x)=9

6x+3x=9

9x=9

x=9/9

x=1

y=-3(1)

y=-3

[tex](2x^2+6x-3)+(3x^2-8x-6)\\\\=2x^2+3x^2+6x-8x -6 -3\\\\=5x^2-2x-9[/tex]

Answer:

3x + 1

 ——————

   2x  

Step-by-step explanation:

https://www.tiger-algebra.com/drill/(3x~2-8x-3)/(2x~2-6x)/

it will give you the step by srep explaation

Answer:

i think x = -4, y = 5

Step-by-step explanation:

x = 16 - 4y

3x + 4y = 8

3(16 - 4y)+4y = 8

48-12y+4y = 8

48-8y = 8

48-8 = 8y

40 = 8y

5 = y

so

x = 16 - 4y

x = 16 - 4(5)

x = 16 - 20

x = -4

The total cost during a school year to attend a given number of daces is a

linear function of the number of dances attended.

The correct responses are;

Reasons:

The given parameter are;

Admission price per person = $4

The annual fees members pay = $50

A. The function that can be used to determine c is a linear function, with a y-intercept (initial value) of 50 and a rate (slope) of 4

The total cost to attend n dances a year, c = 50 + 4·n

B. If a member attends 15 dances a year, we have;

n = 15

Therefore;

The total cost, c = 50 + 4 × 15 = 110

The total cost for 15 dances a year, c = $110

1. As the number of dances attended increase, the total cost increase, and the cost when no dance is attended by a member during the year is $50.

2. The essential information that can be used to find the solution are;

3. Part A; c = 50 + 4·n

Part B; c = $110

Learn more about linear functions here:

https://brainly.com/question/20478559

Answer:

80%

Step-by-step explanation:

First, you multiply 20 by 5, which gives you 100. Then multiply 16 by 5, which is 80. 80 out of 100 is 80%

Answer:80%

Step-by-step explanation:16/20=0.8 Knowing this the answer will be 80% of cans are recycled in this equation

The equation you can use to find the amount of money, v, Samir received for each video game is;

4v - 23.65 = 6.35 and v = $7.5

Samir sold 4 oh his old star leaper video games.

If the amount received for each video game is v, the total cost of the 4 video games is; 4v

Thus, this equation is;

4v - 23.65 = 6.35

Solving this gives;

v = $7.5

Read more about algebra word problems at; https://brainly.com/question/21405634

Answer:

2a7-1

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

set equations equal to each other and solve for x

6x + 20 = -4x + 150

10x = 130

X = 13

Answer:

the correct is 39

Step-by-step explanation:

there is nine number there so the fifth is it and it was in order that helped alot

[tex]\\ \sf\Rrightarrow \lim_{n\to \infty}\left(\dfrac{1}{1-n^2}+\dfrac{2}{2-n^2}\dots \dfrac{n}{1-n^2}\right)[/tex]

[tex]\\ \sf\Rrightarrow \lim_{n\to \infty}\left(\dfrac{1+2+3\dots n}{1-n^2}\right)[/tex]

[tex]\\ \sf\Rrightarrow \lim_{n\to \infty}\left(\dfrac{\dfrac{n(n+1)}{2}}{1-n^2}\right)[/tex]

[tex]\\ \sf\Rrightarrow \lim_{n\to \infty}\dfrac{n(n+1)}{2(1-n^2)}[/tex]

[tex]\\ \sf\Rrightarrow \lim_{n\to infty}\dfrac{n(1+n)}{2(1-n)(1+n)}[/tex]

[tex]\\ \sf\Rrightarrow \lim_{n\to \infty}\dfrac{n}{2(1-n)}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{\infty}{2-\infty}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{-1}{2}[/tex]

[tex]{\sf \lim_{n \to \infty} (\frac{1}{1-n^2}+\frac{2}{1-n^2} +...\: \frac{n}{1-n^2}) } \\ = {\sf \lim_{n \to \infty} (\frac{1 + 2 + ..n}{1-n^2})} \\ = {\sf \lim_{n \to \infty} ( \frac{n(n + 1)}{2} \div 1 - {n}^{2} )} \\ = {\sf \lim_{n \to \infty} ( \frac{n(n + 1)}{2} \times \frac{1}{ 1 - {n}^{2}} )} \\ ={\sf \lim_{n \to \infty} ( \frac{n(n + 1)}{2(1 - {n}^{2} )} )} \\ = {\sf \lim_{n \to \infty} ( \frac{n(n + 1)}{2 (1 - n )(1 + n) } )} \\ = {\sf \lim_{n \to \infty} ( \frac{n(1 + n)}{2 (1 - n )(1 + n) } )} \\ = {\sf \lim_{n \to \infty} ( \frac{n}{2 (1 - n )} )} \\ = {\sf \lim_{n \to \infty} ( \frac{n}{2 - 2 n } )} \\ = \sf \frac{ \infty }{2 - \infty } \\ = \frac{ - 1}{2}

[/tex]

Answer:

[tex] \frac{ - 1}{2} [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

[tex]\dfrac{6+ \sqrt{27}}{4-\sqrt3} \\\\\\=\dfrac{\left(6+\sqrt{27}\right)\left(4+\sqrt 3 \right)}{\left(4-\sqrt 3\right) \left(4+\sqrt 3\right)}\\\\\\=\dfrac{24+6\sqrt 3+4\sqrt{27}+\sqrt{27\cdot 3}}{4^2 - \left(\sqrt 3 \right)^2}\\\\\\=\dfrac{24+6\sqrt3+4\sqrt{9\cdot 3} +\sqrt{81}}{16-3}\\\\\\=\dfrac{24+6\sqrt 3 +12\sqrt 3 + 9 }{13}\\\\\\=\dfrac{33+18\sqrt 3}{13}\\\\\\\text{Hence, r = 33 and s = 18}[/tex]