Has an album that holds. 500 Each page of the album holds 5 photo. If 59​% of the album is​ empty, how many pages are filled with photos​?

Here is the summary of the relation J on all integers:

a. 1 J 2 : No

b. 2 J 1 : Yes

c. 3 J 6 : Yes

d. 17 J 51 : No

e. Another example of x and y in relation J: 4 J 12 (4 is related to 12 under relation J)

To define a relation J on all positive integers is following:

a. No, 1 is not a factor of 2, so 1 does not divide 2.

Therefore, 1 is not related to 2 under relation J.

b. Yes, 2 is a factor of 1 (specifically, 2 divides 1 zero times with a remainder of 1), so 2 divides 1.

Therefore, 2 is related to 1 under relation J.

c. Yes, 3 is a factor of 6 (specifically, 3 divides 6 two times with a remainder of 0), so 3 divides 6.

Therefore, 3 is related to 6 under relation J.

d. No, 17 is not a factor of 51, so 17 does not divide 51.

Therefore, 17 is not related to 51 under relation J.

e. Let's choose x = 4 and y = 12.

Then we need to check if x divides y. We can see that 4 is a factor of 12 (specifically, 4 divides 12 three times with a remainder of 0), so 4 divides 12.

Therefore, 4 is related to 12 under relation J.

To summarize:

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The missing side length. Round to the nearest tenth if needed is 10.2

Let the length of the missing side = "s" Applying the Pythagorean theorem to this right triangle gives:

4^2 + s^2 = 11^2  

 => 16 + s^2 = 121      

=>     ( 4*4 = 16, 11*11 = 121)

16 - 16  + s^2 = 121 - 16 =>     (subtract 16 from both sides)

s^2 = 105 =>

x = sqrt (105) which is approximately 10.2

Therefore the missing length is 10.2 units

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The value of the definite integral ∫(from 0 to 3) [tex]e^{(2x)[/tex] dx is [tex](1/2)(e^6 - 1).[/tex]

To evaluate the definite integral, you'll need to find the antiderivative of the function [tex]e^{(2x)[/tex] and then apply the limits of integration (0 to 3).

The antiderivative of  [tex]e^{(2x)[/tex] is [tex](1/2)e^{(2x)[/tex], since the derivative of [tex](1/2)e^{(2x)[/tex] with respect to x is [tex]e^{(2x)[/tex]. Now, you can apply the Fundamental Theorem of Calculus:

∫(from 0 to 3) [tex]e^{(2x)[/tex] dx = [tex][(1/2)e^{(2x)][/tex](from 0 to 3)

First, substitute the upper limit (3) into the antiderivative:

[tex](1/2)e^{(2*3)} = (1/2)e^6[/tex]
Next, substitute the lower limit (0) into the antiderivative:

[tex](1/2)e^{(2*0)} = (1/2)e^0 = (1/2)[/tex]

Now, subtract the result with the lower limit from the result with the upper limit:

[tex](1/2)e^6 - (1/2) = (1/2)(e^6 - 1)[/tex]

So, the exact value of the definite integral is:

[tex](1/2)(e^6 - 1)[/tex]

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To find the 30th and 75th quantiles of the random variable Y, we first need to calculate the cumulative distribution function (CDF) of Y.

CDF of Y:
F(y) = ∫ f(y) dy from 0 to y (since f(y) = 0 for y < 0)
= ∫ e^(-y) dy from 0 to y
= -e^(-y) + 1

Now, to find the 30th quantile, we need to find the value y_30 such that F(y_30) = 0.3.
0.3 = -e^(-y_30) + 1
e^(-y_30) = 0.7
y_30 = -ln(0.7) ≈ 0.357

Similarly, to find the 75th quantile, we need to find the value y_75 such that F(y_75) = 0.75.
0.75 = -e^(-y_75) + 1
e^(-y_75) = 0.25
y_75 = -ln(0.25) ≈ 1.386

Therefore, the 30th quantile of Y is approximately 0.357, and the 75th quantile of Y is approximately 1.386.
Given the density function of Y as f(y) = e^(-y) for y > 0 and f(y) = 0 for y ≤ 0, we can find the 30th and 75th quantiles of the random variable Y.

First, let's find the cumulative distribution function (CDF) F(y) by integrating the density function f(y):

F(y) = ∫f(y)dy = ∫e^(-y)dy = -e^(-y) + C

Since F(0) = 0, C = 1. So, F(y) = 1 - e^(-y) for y > 0.

Now, we can find the quantiles by solving F(y) = p, where p is the probability:

1. For the 30th quantile (p = 0.3):

0.3 = 1 - e^(-y)
e^(-y) = 0.7
-y = ln(0.7)
y = -ln(0.7)

2. For the 75th quantile (p = 0.75):

0.75 = 1 - e^(-y)
e^(-y) = 0.25
-y = ln(0.25)
y = -ln(0.25)

So, the 30th quantile of the random variable Y is -ln(0.7), and the 75th quantile is -ln(0.25).

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For the first question, we need to find the chi-square statistic value. Using the given table, we can calculate the expected frequencies and then use the chi-square formula to get the value.

The calculated chi-square value is 13.99. Since alpha is 0.1, we compare this value to the critical chi-square value at 2 degrees of freedom (since we have 2 rows and 3 columns), which is 4.605. Since the calculated value is greater than the critical value, we reject the null hypothesis that the listed occupations and personality preferences are independent.

For the second question, we need to find the P-value of the sample test statistic. Using the given table, we can calculate the expected frequencies and then use the chi-square formula to get the chi-square value. The calculated chi-square value is 6.27. Since we have 2 degrees of freedom, we can find the P-value using a chi-square distribution table or calculator. The calculated P-value is 0.043, which is less than alpha (0.01). Therefore, we reject the null hypothesis that the listed occupations and personality preferences are independent.

For the third question, we need to find the P-value of the sample test statistic and then determine whether to reject or fail to reject the null hypothesis. Using the given table, we can calculate the expected frequencies and then use the chi-square formula to get the chi-square value.

The calculated chi-square value is 3.39. Since we have 2 degrees of freedom, we can find the P-value using a chi-square distribution table or calculator. The calculated P-value is 0.183, which is greater than alpha (0.1). Therefore, we fail to reject the null hypothesis that the listed occupations and personality preferences are independent at the 0.10 level of significance.

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Therefore, we can use cofactor expansion along column 3 to calculate the determinant of matrix A.

The determinant of a 5x5 matrix can be calculated by expanding along any row or column. However, we can try to minimize the number of determinants that need to be computed in the second step by selecting the row or column with the most zeros.

In this case, we can see that column 3 has three zeros, which means that expanding along this column will result in the fewest number of determinants that need to be computed in the second step. Therefore, we can use cofactor expansion along column 3 to calculate the determinant of matrix A.

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The area of the canvas can be calculated by taking the product of its length and width, which is 2w-5 and w+2, respectively, and then simplifying this expression to 5w²+3w-2, which is option D.

An expression is a mathematical statement that contains numbers, variables, and operations but lacks the equal sign.

To calculate the area of the canvas, we need to know the length and width of the canvas.

Since the length of the canvas will be 5 inches less than twice the width, the length can be expressed as:

2w-5.

The width of the canvas must include the extra 2 inches of fabric on each side to stretch and secure it around the frame, so the width is expressed as:

w+2.

The area of the canvas is then the product of the length and width,

= (2w-5)(w+2).

When this equation is simplified, it reduces to 5w²+3w-2, which is option D.

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A real relationship, not accounted by other variables, is a causal relationship. This type of association suggests that one variable directly causes changes in the other. In other words, there is a cause-and-effect relationship between the two variables.

In this type of association, changes in one variable directly cause changes in the other variable, without any other variables influencing the relationship. This contrasts with spurious or indirect associations, where the relationship between two variables is due to the influence of other variables. To determine if an association is a real relationship, researchers often control for potential confounding variables to isolate the direct effect of the variables in question. However, it is important to note that establishing a causal relationship requires careful research design and data analysis to rule out the effects of other variables that could be influencing the relationship.

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True, if A is an invertible n x n matrix, then the equation Ax = b is consistent for each b in Rⁿ.

When A is an invertible n x n matrix, it means that A has a unique inverse, denoted as A⁻¹, which is also an n x n matrix. This implies that for any given vector b in Rⁿ, there exists a unique solution x in Rⁿ that satisfies the equation Ax = b.

To understand why this is true, consider the definition of matrix multiplication. In the equation Ax = b, A is multiplied by x to obtain b. Since A is invertible, we can multiply both sides of the equation by A⁻¹ (the inverse of A) on the left, yielding A⁻¹Ax = A⁻¹b.

Now, according to the properties of matrix multiplication, A⁻¹A results in the identity matrix I_n (an n x n matrix with ones on the diagonal and zeros elsewhere), and any vector multiplied by the identity matrix remains unchanged. Therefore, we get I_nx = A⁻¹b, which simplifies to x = A⁻¹b.

This shows that for any given vector b in Rⁿ, there exists a unique solution x = A⁻¹b that satisfies the equation Ax = b when A is an invertible matrix. Hence, the equation Ax = b is consistent for each b in Rⁿ.

Therefore, the correct answer is True.

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Answer:

Line A = 3

Line B = - 1

Step-by-step explanation:

To find the gradient, you need two points on a line right. The formula for gradient is

[tex] \frac{y2 - y1}{x2 - x1} [/tex]

So on line A, try to find 2 points (coordinates)

You have (-2,1) , (-1,4) , (0,7)

Choose any two

Let's say (-1,4) and (0,7)

Gradient =

[tex] \frac{7 - 4}{0 - - 1} = \frac{3}{1} = 3[/tex]

Gradient of line A is 3

For line B, let's take (1,7) and (2,6)

Gradient =

[tex] \frac{7 - 6 }{1 - 2} = \frac{1}{ - 1} = - 1[/tex]

Gradient of line B = - 1

The value of the constant c for which the integral converges is c > 2.

The value of the convergent integral for this value of c is π/4c.

To find the value of the constant c for which the integral converges, we need to determine the range of values for c that makes the integral finite.

Using the limit comparison test, we compare the given integral with the integral ∫[infinity]0 xx^2 dx, which is known to converge.

lim x→∞ [(xx^2 1−c3x 1) / xx^2] = lim x→∞ [1/(x^(c-1))]

This limit converges if and only if c-1 > 1, or c > 2. Therefore, the integral converges for c > 2.

To evaluate the integral for this value of c, we need to use partial fractions.

(xx^2 1−c3x 1) = A/x + Bx + C/(x^2+1)

Multiplying both sides by x(x^2+1) and equating coefficients, we get

A = 0
B = -c/3
C = 1/2

Substituting these values into the partial fraction decomposition and integrating, we get

∫[infinity]0 (xx^2 1−c3x 1) dx = ∫[infinity]0 [-c/3 x + 1/2 (arctan x)] dx

Evaluating this integral from 0 to infinity, we get

-c/6 [x^2]0∞ + 1/2 [arctan x]0∞ = π/4c

Therefore, the value of the constant c for which the integral converges is c > 2, and the value of the convergent integral for this value of c is π/4c.

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The value of the constant c for which the integral converges is c > 2.

The value of the convergent integral for this value of c is π/4c.

To find the value of the constant c for which the integral converges, we need to determine the range of values for c that makes the integral finite.

Using the limit comparison test, we compare the given integral with the integral ∫[infinity]0 xx^2 dx, which is known to converge.

lim x→∞ [(xx^2 1−c3x 1) / xx^2] = lim x→∞ [1/(x^(c-1))]

This limit converges if and only if c-1 > 1, or c > 2. Therefore, the integral converges for c > 2.

To evaluate the integral for this value of c, we need to use partial fractions.

(xx^2 1−c3x 1) = A/x + Bx + C/(x^2+1)

Multiplying both sides by x(x^2+1) and equating coefficients, we get

A = 0
B = -c/3
C = 1/2

Substituting these values into the partial fraction decomposition and integrating, we get

∫[infinity]0 (xx^2 1−c3x 1) dx = ∫[infinity]0 [-c/3 x + 1/2 (arctan x)] dx

Evaluating this integral from 0 to infinity, we get

-c/6 [x^2]0∞ + 1/2 [arctan x]0∞ = π/4c

Therefore, the value of the constant c for which the integral converges is c > 2, and the value of the convergent integral for this value of c is π/4c.

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Refer to the photo taken. Comment any questions you may have.

To show that a mod m = b mod m if a ≡ b (mod m), we can use the definition of modular arithmetic.

To show that a mod m = b mod m if a ≡ b (mod m) for a positive integer m, we can follow these steps:

1. First, understand the given condition: a ≡ b (mod m) means that a and b have the same remainder when divided by the positive integer m. In other words, m divides the difference between a and b. Mathematically, this can be written as m | (a - b), which means there exists an integer k such that a - b = mk.

2. Next, recall the definition of modular arithmetic: a mod m is the remainder when a is divided by m, and similarly, b mod m is the remainder when b is divided by m.

3. We know that a - b = mk, so a = b + mk.

4. Now, divide both sides of the equation a = b + mk by m.

5. Since b and mk are both divisible by m, the remainder of this division will be the same for both sides. In other words, a mod m and b mod m have the same remainder when divided by m.

6. Therefore, we can conclude that a mod m = b mod m if a ≡ b (mod m) for a positive integer m.

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The probability that three randomly chosen people have different birth date is 0.9918.

To calculate the probability that three randomly chosen people have different birthdates, we can first consider the probability that the second person chosen does not have the same birth day as the first person.

This probability is (364/365), since there are 364 possible birthdates that are different from the first person's birthdate, out of 365 possible birthdates overall.

Similarly, the probability that the third person chosen does not have the same birthdate as either of the first two people is (363/365), since there are now only 363 possible birthdates left that are different from the first two people's birthdates.

To find the overall probability that all three people have different birthdates, we can multiply these individual probabilities together:

(364/365) x (363/365) = 0.9918

So the probability that three randomly chosen people have different birth date is approximately 0.9918, or about 99.2%.

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The probability that three randomly chosen people have different birthdates is approximately 0.9918, or 99.18%.

The counting principle can be used to determine how many different birthdates can be selected from a pool of 365 potential dates. As we assume that people are born with equal probability on each of the 365 days of the year (ignoring leap years).

The first individual can be born on any of the 365 days. The second individual can be born on any of the remaining 364 days. The third individual can be born on any of the remaining 363 days. Therefore, the total number of ways to choose three different birthdates is:

365 x 364 x 363

Let's now determine how many different ways there are to select three birthdates that are not mutually exclusive (i.e., they can be the same). The number of ways to select three birthdates from the 365 potential dates is simply this:

365 x 365 x 365

Consequently, the likelihood that three randomly selected individuals have different birthdates is:

(365 x 364 x 363) / (365 x 365 x 365) ≈ 0.9918

Therefore, the likelihood is roughly 0.9918, or 99.18%.

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The square root and cube root of the given expression are:  √(16) = 4 ,∛O = 0, √(1) = 1

To find the square root of an integer, you need to find a number that, when multiplied by itself, equals the original number. As such, you really want to distinguish the number that, when duplicated without anyone else, approaches 25, to decide the square foundation of that number. Subsequently, 5 is the square base of 25.

To determine the cube root of an integer, you must find a number that, when multiplied twice by itself, equals the original number.

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To solve the equation f(x, y) = 8y cos(x), 0 ≤ x ≤ 2, means to find the values of y that satisfy the equation for each given value of x between 0 and 2. To do this.

we can isolate y by dividing both sides by 8cos(x): f(x, y)/(8cos(x)) = y So the solution for y is y = f(x, y)/(8cos(x)), for any given value of x between 0 and 2. you'll want to evaluate the function within this range of x values. However, since the function has two variables (x and y), we cannot provide a unique solution without additional constraints or information about the variable y.

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Answer:

Therefore, the estimated horizontal distance traveled by each golf ball is 122.4 feet and 147.7 feet, respectively.

Step-by-step explanation:

We can use the following kinematic equations to solve this problem:

Horizontal distance (d) = initial velocity (v) x time (t) x cosine(theta)

Vertical distance (h) = initial velocity (v) x time (t) x sine(theta) - (1/2) x acceleration (a) x time (t)^2

We know that the initial velocity is 66 feet per second for both golf balls, and the angles made by the golf balls with the horizontal are 35​° and 49​°. We also know that the acceleration due to gravity is 32.2 feet per second squared.

For the first golf ball, the angle with the horizontal is 35​°, so the horizontal distance traveled can be estimated as:

d = v x t x cos(theta)

d = 66 x t x cos(35​°)

For the second golf ball, the angle with the horizontal is 49​°, so the horizontal distance traveled can be estimated as:

d = v x t x cos(theta)

d = 66 x t x cos(49​°)

To find the time (t) for each golf ball, we can use the fact that the vertical distance traveled by each golf ball will be zero at the highest point of its trajectory. Therefore, we can set the vertical distance equation equal to zero and solve for time:

0 = v x t x sin(theta) - (1/2) x a x t^2

t = 2v x sin(theta) / a

Substituting the values for each golf ball, we get:

For the first golf ball:

t = 2 x 66 x sin(35​°) / 32.2 = 2.38 seconds

d = 66 x 2.38 x cos(35​°) = 122.4 feet

For the second golf ball:

t = 2 x 66 x sin(49​°) / 32.2 = 3.05 seconds

d = 66 x 3.05 x cos(49​°) = 147.7 feet

Therefore, the estimated horizontal distance traveled by each golf ball is 122.4 feet and 147.7 feet, respectively.

Answer:
La primera pelota recorrió una distancia horizontal de 128.44 pies y la segunda pelota recorrió una distancia horizontal de 125.93 pies.

Step-by-step explanation:

Primero, vamos a calcular la componente horizontal de la velocidad inicial. Para ello, utilizaremos la fórmula:

Vx = V0 * cos(θ)

donde V0 es la velocidad inicial y θ es el ángulo de lanzamiento con la horizontal.

Para la primera pelota, con un ángulo de lanzamiento de 35°, tenemos:

Vx1 = 66 * cos(35°) = 54.14 pies/segundo

Para la segunda pelota, con un ángulo de lanzamiento de 49°, tenemos:

Vx2 = 66 * cos(49°) = 42.11 pies/segundo

Ahora, vamos a calcular el tiempo que tarda cada pelota en llegar al suelo. Para ello, utilizaremos la fórmula de tiempo de vuelo:

t = (2 * Voy) / g

donde Voy es la componente vertical de la velocidad inicial y g es la aceleración debido a la gravedad (32.2 pies/segundo^2).

Para ambas pelotas, la componente vertical de la velocidad inicial es:

Voy = V0 * sin(θ)

Para la primera pelota, tenemos:

Voy1 = 66 * sin(35°) = 38.05 pies/segundo

Por lo tanto, el tiempo de vuelo de la primera pelota es:

t1 = (2 * 38.05) / 32.2 = 2.37 segundos

Para la segunda pelota, tenemos:

Voy2 = 66 * sin(49°) = 47.91 pies/segundo

Por lo tanto, el tiempo de vuelo de la segunda pelota es:

t2 = (2 * 47.91) / 32.2 = 2.99 segundos

Finalmente, podemos calcular la distancia horizontal recorrida por cada pelota utilizando la fórmula:

d = Vx * t

Para la primera pelota, tenemos:

d1 = 54.14 * 2.37 = 128.44 pies

Para la segunda pelota, tenemos:

d2 = 42.11 * 2.99 = 125.93 pies

Por lo tanto, la primera pelota recorrió una distancia horizontal de 128.44 pies y la segunda pelota recorrió una distancia horizontal de 125.93 pies.

The area of Kite PQRS at the right is concave. If we have PQ = QR = 20, PS= SR= 15, and QS = 7 is  220 square units

First, we can find the length of the diagonal PR using the Pythagorean theorem:

PR² = PQ² + QR² = 20² + 20² = 800

PR = sqrt(800) ≈ 28.28

Similarly, we can find the length of the diagonal QS:

QS² = QR² + RS² = 20² + 15² = 625

QS = sqrt(625) = 25

Now, we can split the kite into two triangles, PQS and QRS, and use the formula for the area of a triangle:

area of PQS = (1/2) * PQ * QS = (1/2) * 20 * 7 = 70

area of QRS = (1/2) * QR * RS = (1/2) * 20 * 15 = 150

So the total area of the kite is:

area of PQRS = area of PQS + area of QRS = 70 + 150 = 220

Therefore, the area of kite PQRS is 220 square units

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The sequence  aₙ = 2n is divergent.

To show that the sequence aₙ is divergent, we need to show that it does not converge to a finite limit.

Let's assume that the sequence aₙ converges to some finite limit L, i.e., lim(aₙ) = L. Then, for any ε > 0, there exists an integer N such that |aₙ - L| < ε for all n ≥ N.

Let's choose ε = 1. Then, there exists an integer N such that |aₙ - L| < 1 for all n ≥ N. In particular, this means that |2n - L| < 1 for all n ≥ N.

However, this is impossible because as n gets larger, 2n gets arbitrarily large and so it is not possible for |2n - L| to remain less than 1 for all n ≥ N. Therefore, our assumption that aₙ converges to a finite limit L is false, and hence aₙ is divergent.

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The given question is incomplete, the complete question is:

Show that each of the following sequences is divergent aₙ=2n

The correct answer is [tex]90[/tex]% confidence interval for the difference between the two population means is (0.07, 3.93).

(a) The point estimate of the difference between the two population means can be calculated as:[tex]x1 - x2 = 13.6 - 11.6 = 2[/tex]. Therefore, the point estimate of the difference between the two population means is 2.

(b) To find a 90% confidence interval for the difference between the two population means, we can use the formula: [tex]CI = (x1 - x2) ± z*(SE)[/tex]

Where CI is the confidence interval, x1 - x2 is the point estimate, z is the z-score associated with a 90% confidence level (1.645), and SE is the standard error of the difference between the means, which can be calculated as:[tex]SE = \sqrt{(σ1^2/n1) + (σ2^2/n2)}[/tex]

Plugging in the given values, we get:[tex]SE = \sqrt{ ((2.4^2/60) + (3^2/25)) }[/tex]

Therefore, the 90% confidence interval for the difference between the two population means is:[tex]CI = 2 ± 1.645*0.764[/tex]

[tex]CI = (0.07, 3.93)[/tex]

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The values we have found, we get:

a. sin(2theta) = 2(-20/29)(21/29) = -840/841

b. cos(2theta) = (21/29)² - (-20/29)² = 441/841 - 400/841 = 41/841

c. tan(2theta) = (2(-20/29))/(1 - (-20/29)²) = 40/9

What is trigonometry?

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles.

Since cos(theta) is positive and lies in quadrant IV, we know that sin(theta) is negative. We can use the Pythagorean identity to find sin(theta):

sin²(theta) + cos²(theta) = 1

sin²(theta) = 1 - cos²(theta)

sin(theta) = -sqrt(1 - cos²(theta))

Substituting cos(theta) = 21/29, we get:

sin(theta) = -sqrt(1 - (21/29)²) = -20/29

Now, we can use the double angle formulas to find sin(2theta), cos(2theta), and tan(2theta):

sin(2theta) = 2sin(theta)cos(theta)

cos(2theta) = cos²(theta) - sin²(theta)

tan(2theta) = (2tan(theta))/(1 - tan²(theta))

Substituting the values we have found, we get:

a. sin(2theta) = 2(-20/29)(21/29) = -840/841

b. cos(2theta) = (21/29)² - (-20/29)² = 441/841 - 400/841 = 41/841

c. tan(2theta) = (2(-20/29))/(1 - (-20/29)²) = 40/9

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Using the associative property of multiplication on the given expression the value of k = 24.

The associative property of multiplication is a property of numbers that states that the way in which numbers are grouped when they are multiplied does not affect the result. In other words, if you are multiplying more than two numbers together, you can group them in any way you like and the result will be the same.

Formally, the associative property of multiplication states that for any three numbers a, b, and c:

(a × b) × c = a × (b × c)

For example, consider the expression (2 × 3) × 4. Using the associative property of multiplication, we can group the first two numbers together or the last two numbers together and get the same result:

(2 × 3) × 4 = 6 × 4 = 24

2 × (3 × 4) = 2 × 12 = 24

We can simplify the expression (3 8/2) (3 8/4) as follows:

(3 8/2) (3 8/4) = (3×(8/2))×(3×(8/4)) (using the associative property of multiplication)

= (3×4)×(3×2) (simplifying the fractions)

= 12×6

= 72

Therefore, the expression (3 8/2) (3 8/4) is equal to 72. We are told that this expression can be rewritten as 3k, where k is a constant. So we have:

3k = 72

Dividing both sides by 3, we get:

k = 24

Therefore, the value of k is 24.

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Answer: The value for k would be 24.

Step-by-step explanation: Using the associative property of multiplication on the given expression the value of k = 24. Formally, the associative property of multiplication states that for any three numbers a, b, and c: (a × b) × c = a × (b × c).

(3×4)×(3×2). If you solve this, you will then get 12×6. 12×6= 72. This therefore turns into 3k=72. Therefore you would have to isolate the k by dividing both sides by 3. This turns into k=24. This is why the value for k is 24.

The probability of outcome e4 is 0.1, which means the option (b). 0.100 is the correct answer.

To comprehend this response, keep in mind that the total probability for all outcomes in an experiment must equal 1. We now know the probability for e1, e2, and e3, which total 0.9 (0.2 + 0.3 + 0.4 = 0.9). Because the total of probabilities must equal one, we may remove 0.9 from one to get the chance of e4. As a result, the likelihood of e4 is 0.1 (1 - 0.9 = 0.1).

In other words, there are four possible outcomes in this experiment, with probabilities 0.2, 0.3, 0.4, and an unknown for e4. We may multiply the known probabilities by 0.9, leaving 0.1 for e4. This means that there is a 10% chance of outcome e4 occurring in this experiment.

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The dimensions of the rectangle with maximum area are x = 22 meters and y = 44 - x = 22 meters.

To find the dimensions of the rectangle with maximum area, we need to use the fact that the perimeter is 88. Let's use x to represent the length of the rectangle and y to represent the width.

We know that the perimeter is given by 2x + 2y = 88, which simplifies to x + y = 44.

We also know that the area of a rectangle is given by A = xy.

We are given that A"(x) = -2, which means that the second derivative of the area function is negative at x = 22. This tells us that the area function has a maximum at x = 22.

To find the corresponding value of y, we can use the fact that x + y = 44. Solving for y, we get y = 44 - x.

Substituting this into the area function, we get A(x) = x(44 - x) = 44x - x^2.

Taking the derivative, we get A'(x) = 44 - 2x.

Setting this equal to 0 to find the critical point, we get 44 - 2x = 0, which gives x = 22.

Therefore, the dimensions of the rectangle with maximum area are x = 22 meters and y = 44 - x = 22 meters.

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Answer: 65

Step-by-step explanation:

area of triangle = 1/2 of base * height

so 13*10 = 130

130 * 1/2 = 65

We can see that the third equation gives us z = 0. Substituting this into the second equation gives us y = 0. Substituting z = 0 and y = 0 into the first equation gives us x = (1-y)/111 = -1/111. Thus, the general solution is:

[tex]\begin{aligned} x &= -1/111 \ y &= 0 \ z &= 0 \end{aligned}[/tex]

For the first system of equations, the associated augmented matrix is:

[tex]\begin{bmatrix} 2 & 1 & 2 & 5 \ 2 & 2 & 1 & 5 \ 4 & 3 & 3 & 10 \end{bmatrix}[/tex]

We perform elementary row operations to obtain the row-reduced echelon form:

[tex]\begin{bmatrix} 1 & 0 & 1/2 & 1 \ 0 & 1 & 1/2 & 2 \ 0 & 0 & 0 & 0 \end{bmatrix}[/tex]

From this, we see that the system has two free variables, say z and w. We can write the solution in terms of these variables as:

x = 1/2 - z/2 - w

y = 2 - z/2 - w

z = z

w = w

Thus, the general solution is:

[tex]\begin{aligned} x &= 1/2 - z/2 - w \ y &= 2 - z/2 - w \ z &= z \ w &= w \end{aligned}[/tex]

For a particular solution, we can set z and w to zero to obtain:

[tex]\begin{aligned} x &= 1/2 \ y &= 5/2 \ z &= 0 \ w &= 0 \end{aligned}[/tex]

Thus, one particular solution is:

[tex]\begin{aligned} x &= 1/2 \ y &= 5/2 \ z &= 0 \end{aligned}[/tex]

For the second matrix equation, we first write it in augmented form:

[tex]\begin{bmatrix} 111 & 10 & 1 \ 0 & 1 & y \ 0 & 0 & z \end{bmatrix}[/tex]

[tex]\begin{aligned} x &= -1/111 \ y &= 0 \ z &= 0 \end{aligned}[/tex]

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The word problem for the company is:

An electricity company charges its customers a monthly service fee of $3.50 plus 8.3 cents per kWH. Find the total cost for a month if 250kW is used.

A word problem is a mathematical problem presented in the form of a story or a narrative, usually involving real-world scenarios or situations.

Word problems often require the use of arithmetic, algebra, geometry, or other mathematical concepts and methods to find a solution. They can range in complexity from simple arithmetic problems to multi-step equations involving multiple variables.

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Thus, the number of adult tickets that were sold that day was 60.

A linear equation with two variables is shown by the equation axe + by = r if a, b, and r are all real values and both are not equal to 0. The equation's two variables are represented by the letters x and y. The coefficients are denoted by the numerals a and b.

When the unknown variables in a polynomial equation have a degree of one, the equation is said to be linear. In other words, a linear equation's unknown variables are all increased to the power of 1.

For the given question:

Let the number of child tickets - x

Let the number of adult ticket - y

Price of each  child tickets - $6.10

Price of each adult ticket- - $9.40

Thus, the system of linear equation forms -

x + y = 136

x = 136 - y   ...eq 1

6.10x + 9.40y = 1027.60 ..eq 2

Put the value of x in eq 2

6.10x + 9.40y = 1027.60

6.10(136 - y) + 9.40y = 1027.60

829.6 - 6.10y + 9.40y = 1027.60

3.3y = 1027.60 - 829.6

3.3y = 198

y = 198/3.3

y = 60

x = 136 - 90

x = 46

Thus, the number of adult tickets that were sold that day was 60.

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