g(x) is a vertical shift of f(x) , as shown in the graph. How do the two equations relate to each other?

Answer:

The average speed is 80km/h.

Step-by-step explanation:

In order to calculate the average speed you have to divide the total distance by the total elapsed time:

Let t represent time (in hours)

t=12:30-11:30=1

Let D represent distance (in kilometers)

D=80

Therefore, since t=/=0:

D/t=80/1=80km/h

And there you have it! Your answer is 80 km per hour.

Answer:

[tex](f+g)(x)=7x^2-3x-5[/tex]

Step-by-step explanation:

Step 1: What you are given & need to find

Step 2: Set up the problem

Step 3: Simplify

Using the concepts of function, we got that to tell how far the turtle has travelled ,my function will be defined as: def distance(x, y) where x and y are the final co-ordinates of turtle.

The turtle module actually provides turtle graphics primitives, in both the object-oriented and the procedure-oriented ways. Because it uses kinter for the underlying graphics, it needs a version of Python installed with Tk support.

Turtle. distance()

This method is actually used to return the distance from the turtle to (x, y) in turtle step units.

Hence, if am going create a new function to tell how far the turtle has travelled. your function will be defined as: def distance(x, y) where x and y are the final co-ordinates of turtle.

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According to the Pythagoras theorem, the value of x is 13.8

Pythagoras theorem:

Pythagoras theorem describes that the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides.

Given,

Here we have the two right angled triangles with the side values.

Here we have to find the value of x.

In order to find the value of x, we have to find the value of the bisector KM,

So, for that we have to use the concept of Pythagoras theorem,

We can written this one the following type of equation,

=> (12.3)² = (5.4)² + KM²

=> 151.29 = 29.16 + KM²

=> KM² = 122.13

=>  KM = 11.05

Therefore, the value of x is calculated in the same manner,

=> x² = (8.2)² + (11.05)²

=> x² = 67.24 + 122.10

=> x² = 189.34

=> x = √189.34

=> x = 13.76

When we round off this into the nearest tenth the we get the value of x as 13.8.

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Answer:

0.18

Step-by-step explanation:

1005 - 82% = 18%  Divide by 100 to get the decimal answer of 0.18

Salomi's mother's age , represented with algebraic expression is x + 25.

An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc).

In other words, algebraic expression is an expression where variables and constant are combined using operations.

Salomi is 25 year younger than her mother.

Therefore,

let

x = Salomi age.

Hence, Salomi mother's age in algebraic expression is as follows:

Salomi mother's age = x + 25

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The percentage of people who filed their taxes during the week of tax day is 10%

I can estimate how many people filed their taxes during the week of April 15th using a percentage of 100 is a/b * 100.

A percentage is a portion of a sum divided into 100 equal parts.

Calculate (Number of persons who submitted their taxes during the week of April 15th / total people who filed their taxes that year) times 100 to get the percentage of people who filed during that week.

Let :

a represents the total number of taxpayers during the week of April 15th.

b represents the total number of taxpayers for that year.

The original equation is reduced to

a/b× 100

As an illustration, 100 individuals submitted their taxes the week of April 15th and

Let's say that year, 1000 persons filed their taxes.

= 100/1000 = 10%

Thus, 10% of Americans submitted their taxes during the week of April 15th, or 100 out of 1,000.

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According to the given expression, the inequality that can model the given situation can be stated as 520 < 400 + 15x.

Since Dan wants to know how many hours he needs to spend walking dogs, let us assume this to be x:

15x + 400

Dan wants to know how many hours he needs to spend walking dogs to earn more than $520 in a week. So the above expression is greater than 520:

15x + 400 > 520

When400 is subtracted from 520, the result is true:

15x > 120

Thus, the first inequality expression can be rearranged as:

520 < 400 + 15x

Thus, the inequality that can model the given situation can be stated as 520 < 400 + 15x.

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Answer:

It is A. C. and D.

Step-by-step explanation.

The question is asking for the three different points to be moved, answer choice A is the answer for one point, answer C is for the second point, and answer D is for the third point.

The length of the side x on the right triangle is 41.06

A right triangle is a triangle that has one interior angle of 90°

The parameters in the right triangle are;

Acute angle = 47°

Leg length of side adjacent to 47° = 28

Length of the hypotenuse = x

From trigonometric ratios, we have;

[tex]cos(\theta) =\mathbf{ \dfrac{Length \, of \, adjacent \, side}{Length \, of \, Hypotenuse}}[/tex]

The cosine of the 47° angle is therefore;

[tex]cos(47^{\circ}) = \dfrac{28}{x}[/tex]

From which we have;

[tex]x= \dfrac{28}{cos(47^{\circ}) } \approx 41.06[/tex]

The length of the side, x ≈ 41.06

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Answer:

90 liters

Step-by-step explanation:

It's given in the question!

74-126+329/2

-52+329/2

277/2

138.5

Answer:

[3, ∞]

Step-by-step explanation:

The value of g = 4π²l/T²

Operators are Mathematical operations that emphasize particular actions like summing up, dividing, and adding multiple times, etc.

In Mathematics, the basic arithmetic operations are Addition, Subtraction Division, and Multiplication.  

The symbols which are used for each operation are

Addition  - (+)

Subtraction  - (-)

Division  - (÷)

Multiplication  - (x)  

Given [tex]l = \frac{gT^{2} }{4 \pi ^{2} }[/tex]  

To get the 'g' value we will use Multiplication and Division

Multiply both sides with 4π²  

=> [tex]4 \pi ^{2} (l )= \frac{gT^{2} }{4 \pi ^{2} }(4 \pi ^{2} )[/tex]  

=> [tex]4 \pi ^{2} (l )= gT^{2}[/tex]  

Divide by T² on both sides

=> [tex]4 \pi ^{2} (l )\frac{1}{T^{2}} = g\frac{T^{2}}{T^{2}}[/tex]

=> [tex]\frac{ 4 \pi ^{2} l }{T^{2}} = g[/tex]

=> [tex]g = \frac{ 4 \pi ^{2} l }{T^{2}}[/tex]  

Therefore,

The value of g = 4π²l/T²

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Answer:

1st

Step-by-step explanation:

Explanation in the picture.

When analyzing two quantitative variables the first thing that should be done make a scatterplot.

When comparing two quantitative variables, a scatterplot is the most useful display technique. We plot the variable we consider the response variable on the y-axis and the explanatory or predictor variable on the x-axis.

How do we know which variable is which? The explanatory variable, in general, attempts to explain or predict the observed outcome. A study's outcome is measured by the response variable. One may even consider investigating whether one variable causes variation in another variable; for example, a popular research study found that taller people are more likely to earn higher wages. In this case, the explanatory variable Height would be used to explain the variation in the response variable Salaries.

When summarizing the relationship between two quantitative variables, we must consider the following:

1.Association/Direction (i.e. positive or negative)

2.Form (i.e. linear or non-linear)

3.Strength (weak, moderate, strong)

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Answer:

The number of candy bars each friend will receive is 1.66.

Step-by-step explanation:

Given that Becky has 5 candy bars

She wants to share them with 3 friends.

To determine the number of candy bars each friend will receive

We need to determine the number of candy bars each friend will receive

So,  the number of candy bars would be

5/3 which would = to 1.66

and that's how much she will give each friend

Answer:

both

Step-by-step explanation:

because the first one, since the number 4 isn’t next to the parentheses then we are not multiplying so it’s actually adding so it still equals 7

Answer:

Step-by-step explanation:

Half of the 80 people are women, so divide 80 by 2.

[tex]80/2=40[/tex]

One quarter of that is men.

[tex]40/4=10[/tex]

The rest are children, so:

[tex]40+10=50\\80-50=30[/tex]

There are 30 children, 40 women, and 10 men.

The number of children to men is n:1.

There are 30 children to 10 men, and after simplifying that by dividing by 10, so the value of n is 3, and the ratio is 3:1.

Answer:

3:1

Step-by-step explanation:

Half of the 80 people are women. 80 divided by 2 is 40.

One-quarter of the 40 women are men. 40 divided by 4 is 10.

The total number of men and women is 50, and the rest are children. 50 subtracted from 80 is 30.

There are 40 women, 30 children, and 10 men.

The ratio of children to men is 30:10, which simplifies to 3:1.

The area of a triangle whose vertices are r(3, 4), s(6, 2), and t(7, 10) is calculated to be 9.5 units²

Given that,

Vertices are  r(3, 4), s(6, 2), and t(7, 10) which means ,

(x₁,y₁) = (3,4)

(x₂,y₂) = (6,2)

(x₃,y₃) = (7,10)

From formula,

The triangle area

A= 1/2 (|x₁(y₂ -y₃) + x₂(y₂ - y₁) + x₃(y₁ -y₂))

A=1/2(3(2 - 10) + 6(2-4) + 7(4-2))

A = 1/2 (3* -7 + 6* -2 +7* 2 )

A = 1/2 |(-21-12+14)|

A = 1/2 (19)

A = 9.5 units²

area of triangle is 9.5 units² with the given vertices.

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Answer:

[tex]x=10^{\frac{4}{3}}=\sqrt[3]{10000}[/tex]

Step-by-step explanation:

Given equation:

[tex]9^{\log_3 (\log x)}= \log x-2\log^2x+4[/tex]

Rewrite 9 as 3²:

[tex]\implies (3^2)^{\log_3 (\log x)}= \log x-2\log^2x+4[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies 3^{2\log_3 (\log x)}= \log x-2\log^2x+4[/tex]

[tex]\textsf{Apply the log power law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies 3^{\log_3 (\log x)^2}= \log x-2\log^2x+4[/tex]

[tex]\textsf{Apply log law}: \quad a^{\log_ab}=b[/tex]

[tex]\implies (\log x)^2= \log x-2\log^2x+4[/tex]

Simplify:

[tex]\implies\log ^2 x= \log x-2\log^2x+4[/tex]

[tex]\implies 3\log ^2 x- \log x-4=0[/tex]

Let log(x) = u:

[tex]\implies 3u^2-u-4=0[/tex]

Factor:

[tex]\implies 3u^2+3u-4u-4=0[/tex]

[tex]\implies 3u(u+1)-4(u+1)=0[/tex]

[tex]\implies (3u-4)(u+1)=0[/tex]

Apply the zero-product property:

[tex]\implies 3u-4=0 \implies u=\dfrac{4}{3}[/tex]

[tex]\implies u+1=0 \implies u=-1[/tex]

Substitute u=log(x) back in:

[tex]\implies \log x = -1[/tex]

[tex]\implies \log x= \dfrac{4}{3}[/tex]

On the left side of the original equation, we have log₃ (log x).  

As logs of negative numbers cannot be taken, log(x)=-1 is not a valid solution since this would give log₃(-1) which is undefined.

Therefore, the only valid solution is:

[tex]\implies \log x= \dfrac{4}{3}[/tex]

[tex]\implies x=10^{\frac{4}{3}}[/tex]

[tex]\implies x=\left(10^4\right)^{\frac{1}{3}}[/tex]

[tex]\implies x=10000^{\frac{1}{3}}[/tex]

[tex]\implies x=\sqrt[3]{10000}[/tex]

Note: If a log has no base, assume that the base is 10.

Answer:

  5.5%

Step-by-step explanation:

You want the interest rate that can be compounded continuously to give $1490 from an investment of $650 after 15 years.

The formula for account value with continuously compounded interest is ...

  A = Pe^(rt) . . . . P=principal, r=interest rate, t=years

Solving for r, we find ...

  ln(A/P)/t = r

  ln(1490/650)/15 = 0.0553...

The interest rate is about 5.5%.

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The formula for T in terms of B and C is T=4B+10C.

How are phrases converted into expressions and equations?

In order to give verbal explanations of mathematical operations:

Find any phrases or key words that denote an operation.

Add the individual processes together to create an expression or equation. Ensure that the sequence of events is maintained.

Let Doughnuts sold in bag be B

Let Doughnuts sold in cartons be C

As given in the question a bag can contain 4 Doughnuts

∴ it is 4B

as cartons can contain 10 Doughnuts

∴ it is 10C

As T is the total number of Doughnuts

∴ the formula is

T=4B+10C

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Answer:

l = 1

Step-by-step explanation:

v = lwh

8 = l(2)(4)

8 = l8  Divide both sides by 8

1 = l

Thus, solving the linear inequalities for y we have

y > 4 - (2/3)x,

y > (3/2)x - 3, and

y ≥ 6x - 6

We have to solve each of the linear inequality for y.

1. The given linear inequality is -

2x + 3y > 12

=> 3y > 12 - 2x

=> y > 4 - (2/3)x

2. The given linear inequality is -

3x - 2y < 6

=> -2y < 6 - 3x

=> 2y > 3x - 6

=> y > (3/2)x - 3

3. The given linear inequality is -

4y - 2x ≥ 4x + 3(y-2)

=> 4y - 2x ≥ 4x + 3y - 6

=> 4y - 3y ≥ 4x + 2x - 6

=> y ≥ 6x - 6

Thus, solving the linear inequalities for y we have

y > 4 - (2/3)x,

y > (3/2)x - 3, and

y ≥ 6x - 6

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In the binomial expansion of (2 + 3x)ⁿ, the value of n = 22/5

Binomial expansion is the expansion of the binomial (a + b)ⁿ = ∑ⁿCₓaˣbⁿ⁻ˣ where ⁿCₓaˣbⁿ⁻ˣ is the general term and x = 0 to n

Since we require the expansion of  (2 + 3x)ⁿ, comparing it with the binomial expansion equation above  (a + b)ⁿ.

So, a = 2 and b = 3x

So, the binomial expansion is (2 + 3x)ⁿ = ∑ⁿCₓ2ˣ(3x)ⁿ⁻ˣ

= ∑ⁿCₓ2ˣ(3ⁿ⁻ˣ)xⁿ⁻ˣ

So, the general term of  (2 + 3x)ⁿ = ∑ⁿCₓ2ˣ(3ⁿ⁻ˣ)xⁿ⁻ˣ and the coefficient term is ⁿCₓ2ˣ(3ⁿ⁻ˣ)

Now since coefficient of x³ and x⁴ are in the ratio if 8:15. Then

For the x³ term, xⁿ⁻ˣ = x³

⇒ n - x = 3

⇒ x =n - 3

So, substituting this into the coefficient term, we have

ⁿCₓ2ˣ(3ⁿ⁻ˣ) = ⁿCₙ₋₃2ⁿ⁻ˣ(3³) =

Also, for the x⁴ term, xⁿ⁻ˣ = x³

⇒ n - x = 4

⇒ x =n - 4

So, substituting this into the coefficient term, we have

ⁿCₓ2ˣ(3ⁿ⁻ˣ) = ⁿCₙ₋₄2ⁿ⁻ˣ(3⁴)

Now since coefficient of x³ and x⁴ are in the ratio if 8:15, we have that

ⁿCₙ₋₃2ⁿ⁻ˣ(3³)/ⁿCₙ₋₄2ⁿ⁻ˣ(3⁴) = 8/15

ⁿCₙ₋₃/(ⁿCₙ₋₄ × 3)= 8/15

ⁿCₙ₋₃/ⁿCₙ₋₄= 8/15 × 3

ⁿCₙ₋₃/ⁿCₙ₋₄= 8/5

n!/(n - 3)![n - (n - 3)]!  ÷ n!/(n - 4)![n - (n - 4)]! = 8/5

n!/(n - 3)![n - n + 3)]!  ÷ n!/(n - 4)![n - n + 4)]! = 8/5

n!/(n - 3)!3!  ÷ n!/(n - 4)!4! = 8/5

n!/3!(n - 3)! ÷ n!/4!(n - 4)(n - 3)! = 8/5

n!/3!(n - 3)! × 4!(n - 4)(n - 3)!/n! = 8/5

4!/3! × (n - 4) = 8/5

4 × 3!/3! × (n - 4) = 8/5

4(n - 4) = 8/5

Dividing through by 4, we have

(n - 4) = 8/(5 × 4)

(n - 4) = 2/5

Cross-multiplying, we have

5(n - 4) = 2

Expanding the brackets, we have

5n - 20 = 2

5n = 20 + 2

5n = 22

n = 22/5

So, the value of n = 22/5

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The sample size will now have to be is 3200.

Given:

the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum allowable error (e) must be reduced to just 0.025. if the original calculation led to a sample size of 1000.

n = p(1-p)(z/E)^2

800 = 0.5(1-0.5)(z/0.05)^2

800 = 0.5*0.5* z^2/0.0025

800 = 0.25 * z^2/0.0025

800 = 25/100*10000*z^2/25

800 = 1*100*z^2

800/100 = z^2

8 = z^2

z = [tex]\sqrt{8}[/tex]

z = 2.8284

n = p(1-p)(z/E)^2

= 0.25(2.8284/0.025)^2

= 0.25*(113.136)^2

= 0.25*12799.754496

= 3199.938 ≈ 3200

Therefore the sample size will now have to be is 3200.

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