good buy electronics has a markup of 150% on a keyboard that cost the retailer $25. find the retail "selling" price and show your work

There are 5,245,786 possible winning number combinations in a 6/42 lottery, and for every ticket purchased, there is a 1 in 5,245,786 chance of winning the jackpot prize.

What is the combinations?

Combinations refer to the different ways of selecting a subset of items from a larger set without regard to the order in which the items are selected. In other words, combinations are the different ways of choosing a group of items without taking into account their arrangement or order.

In a 6/42 lottery, there are 6 numbers drawn from a pool of 42 numbers. To determine the number of possible winning number combinations, we can use the formula for combinations:

C(n,r) = n! / (r! * (n-r)!)

where n is the total number of items in the set and r is the number of items being chosen.

In this case, we have 42 numbers in the pool and we need to choose 6 numbers, so the formula becomes:

C(42,6) = 42! / (6! * (42-6)!)

which simplifies to:

C(42,6) = 5,245,786

Therefore, there are 5,245,786 possible winning number combinations in a 6/42 lottery.

To calculate the probability of winning the jackpot prize, we need to divide the number of ways to win by the total number of possible outcomes. Since there is only one winning combination, the probability of winning the jackpot is:

1 / 5,245,786

which simplifies to approximately:

0.000019% or 1 in 5,245,786.

This means that for every ticket purchased, there is a 1 in 5,245,786 chance of winning the jackpot prize.

hence,  there are 5,245,786 possible winning number combinations in a 6/42 lottery, and for every ticket purchased, there is a 1 in 5,245,786 chance of winning the jackpot prize.

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The height of the Zeta Tower as a percentage of the height of the Delta tower is the 94.72%

Here we know that:

The epsilon tower is 23% taller than the delta one, then the height is:

H = 55m*(1 + 0.23) = 67.65 m

And we know that the Zeta tower is 23 short than the epsilon one, then the height of this twoer is.

H' = 67.65m*(1 - 0.23) = 52.0905 m

The height of the delta tower is 55m, this is our 100%.

Then the height of the zeta tower written as a percentage will be:

(52.0905 m/55m)*100% = 94.72%

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Answer:

Step-by-step explanation:

To solve the differential equation:

y′′′ + y = 3(y′ − 1)

we first find the characteristic equation:

r^3 + 1 = 0

The roots of this equation are:

r = -1, 0 ± i

So, the general solution of the homogeneous equation (y′′′ + y = 0) is:

y_h(t) = c1 e^(-t) + c2 cos(t) + c3 sin(t)

To find a particular solution of the non-homogeneous equation (3(y′ − 1)), we assume a solution of the form:

y_p(t) = a t + b

Taking the first, second and third derivatives of y_p(t), we get:

y′_p(t) = a

y′′_p(t) = 0

y′′′_p(t) = 0

Substituting these into the differential equation, we get:

0 + (a t + b) = 3(a - 1)

Solving for a and b, we get:

a = 1

b = 2

Therefore, the particular solution of the non-homogeneous equation is:

y_p(t) = t + 2

So, the general solution of the non-homogeneous equation is:

y(t) = y_h(t) + y_p(t) = c1 e^(-t) + c2 cos(t) + c3 sin(t) + t + 2

To find the values of c1, c2 and c3, we use the initial conditions:

y(0) = c1 + c2 + 2 = 1

y′(0) = -c1 + c2 + c3 = 0

y′′(0) = c1 - c2 = 0

Solving these equations simultaneously, we get:

c1 = c2 = 1/2

c3 = -1/2

So, the solution of the differential equation with initial conditions (0) = 1, ′(0) = 0, ′′(0) = 0 is:

y(t) = 1/2 e^(-t) + 1/2 cos(t) - 1/2 sin(t) + t + 2

The cost of capital for the second option, issuing new preferred stock, is 0.00356, or 0.356%. This means that for every dollar of capital raised through issuing preferred stock, the company will need to pay 0.356 cents in annual interest or dividend payments.

To calculate the cost of capital for the second option, we need to first calculate the cost of the preferred stock. The cost of preferred stock is the dividend yield, or the annual dividend divided by the market price of the stock. In this case, the annual dividend is $5.00 and the market price is $56,000.

Cost of preferred stock = Annual dividend / Market price of stock

Cost of preferred stock = $5.00 / $56,000

Cost of preferred stock = 0.000089

To calculate the cost of capital, we need to weight the cost of preferred stock with the proportion of capital that is financed by preferred stock. Let's assume that the preferred stock will finance 40% of the total capital.

Cost of capital = Cost of preferred stock * Proportion of capital financed by preferred stock

Cost of capital = 0.000089 * 0.40

Cost of capital = 0.0000356

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All the values are,

Compound interest = $1280.2

Future value = $1280.2 + $x

Given that;

P = $865

r = 4%

T = 10 years

Formula is,

Compound Interest = P(1 + r)^t

Where, Principal = P, Interest rate = r, Number of compounds = n, Interest time = t

Plug, p = 865, r = 0.04, t = 10

Compound Interest = 865 (1 + 0.04)¹⁰

Compound Interest = 865 (1.04)¹⁰

Compound Interest = 865 x 1.48

Compound Interest = 1280.2

Hence, We get;

Future value = Compound Interest + Principal

Future value = $1280.2 + $x

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The distance of P at north of Q is 34.98 km.

The distance of P at east of Q is 19.39 km.

The distance of P at the given directions is calculated by resolving the vector into vertical and horizontal components.

The distance of P at north of Q is calculated as follows;

Py = d sinθ

Py = 40 km x sin (61)

Py = 34.98 km

The distance of P at east of Q is calculated as follows;

Px = d cosθ

Px = 40 km x cos (61)

Px = 19.39 km

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Answer:

a) 1/6

b) 1/2

c) 1/2

d) 1

e) 1/6

Step-by-step explanation:

a)Getting a six

=1/6

b)Gettingan even number =3/6=1/2

c)number greater than 3

=3/6=1/2

d)number greater than 0

=6/6=1

e)number greater than 4 and an odd number

=1/6

The numeric value of the function at x = 4 is given as follows:

f(4) = 0.

The expression for the numeric value of the function in this problem is given as follows:

f(4).

This means that the input is given as follows:

x = 4.

Passing a vertical line through x = 4 the value of y in which the vertical line crosses the graph is given as follows:

y = 0.

Hence the numeric value is given as follows:

f(4) = 0.

The graph is given by the image presented at the end of the answer.

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Answer: 5.26

Step-by-step explanation:

458,930/87,178 =
5.264 =
5.26

The correct option- C: 75T + 70S + 160, represent their combined earnings of Terry and Susan  for the week.

Every feature, number, or amount that can be gauged or quantified is referred to as a variable. An amount that can fluctuate depending on the mathematical issue is referred to as a variable. The generic letters x, y, and z are frequently employed in mathematical expressions and equations. A variable, then, is a symbol denoting a number whose value is unknown.

Given data:

T - number of cars detailed by Terry (T)

S - number of cars detailed by Susan (S).

Terry's charge - $75 for each car .

Total Terry's charge for T number of cars - 75T

Additional tip - $65

Susan's charge - $70 for each car.

Total Susan's charge for S number of cars - 70T

Additional tip - $95

Combined earnings = 75T + 65 + 70T + 95

Combined earnings = 75T + 70T + 160

Thus,  75T + 70S + 160, represent their combined earnings of Terry and Susan  for the week.

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Complete question:

Terry and Susan both detail cars. Terry chargers $75 for each car and Susan charges $70 for each car. This week Terry made an additional $65 in tips and Susan made an additional $95 in tips. Given that T and S represent the number of cars detailed by Terry (T) and Susan (S), which expression can be used to represent their combined earnings for the week?​

A: 145(T+S) + 160

B: 65T + 70S + 160

C: 75T + 70S + 160

D: 145TS + 160

If each person drove at a constant rate, the person who drove the fastest (in miles per hour) is: C. Nathan.

In Mathematics and Science, speed is the distance covered by a physical object per unit of time. This ultimately implies that, speed can be measured by using the following unit of measurement;

In Mathematics and Science, the speed of any a physical object can be calculated by using this formula;

Speed = distance/time

For Hank, we have:

Speed = 176/3.2 = 55 miles per hour.

For Laura, we have:

Speed = 150/2.5 = 60 miles per hour.

For Nathan, we have:

Speed = 112.5/2.25 = 50 miles per hour (Fastest).

For Raquel, we have:

Speed = 286/4.4 = 65 miles per hour.

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Answer: x=22

Step-by-step explanation:

see image for explanation

The six rational numbers between 3 and 4 are: 3.1, 3.2, 3.3, 3.4, 3.5 and 3.6

To find 6 rational numbers between 3 and 4, we can start by finding the difference between 4 and 3, which is 1.

We can then divide this difference by any number and add it to 3

So that the number will be less than 4 but greater than 3

Now, we can add this gap size successively to 3, starting with the first rational number after 3, to find the six rational numbers between 3 and 4:

3.1, 3.2, 3.3, 3.4, 3.5, 3.6

So, the six rational numbers between 3 and 4 are: 3.1, 3.2, 3.3, 3.4, 3.5 and 3.6

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the area of the trapezoidal base of the first prism is 9 square units, and the area of the trapezoidal base of the second prism is 16 square units.

What is Volume of both the trapezoidal prisms?

volume = area of cross section of object*  height of object (A)

V = (1/2) * h * (b1 + b2) * H

For the first trapezoid prism, we have:

24 = (1/2) * 6 * (b1 + b2) * 8

Simplifying this equation, we get:

3 = (b1 + b2)

For the second trapezoid prism, we have:

24 = (1/2) * 8 * (b1' + b2') * 6

Simplifying this equation, we get:

4 = (b1' + b2')

A = (1/2) * h * (b1 + b2)

For the first trapezoidal prism:

A = (1/2) * 6 * 3

A = 9 square units

For the second trapezoidal prism:

A = (1/2) * 8 * 4

A = 16 square units

Therefore, the area of the trapezoidal base of the first prism is 9 square units, and the area of the trapezoidal base of the second prism is 16 square units.

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Para despejar "a" de la ecuación 2as = vf^2 - vo^2, podemos seguir los siguientes pasos:

2as + vo^2 = vf^2

a = (vf^2 - vo^2) / 2s

Por lo tanto, la fórmula para calcular "a" a partir de la distancia de desplazamiento "s", la velocidad final "vf" y la velocidad inicial "vo" es:

a = (vf^2 - vo^2) / 2s

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[tex]\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}[/tex]

[tex]\textcolor{blue}{\small\texttt{If you have any further questions,}}[/tex] [tex]\textcolor{blue}{\small{\texttt{feel free to ask!}}}[/tex]

♥️ [tex]{\underline{\underline{\texttt{\large{\color{hotpink}{Sumit\:\:Roy\:\:(:\:\:}}}}}}\\[/tex]

Answer:

To compare the texting rates of Student A and Student B, we need to calculate their respective rates of change.

For Student A, we can use the formula for the slope of a line:

slope = (change in y) / (change in x)

In this case, the "y" variable represents the number of texts sent, and the "x" variable represents the number of tests sent. Looking at the table, we can see that Student A sent 10.5 texts after sending 1 test, and 10 texts after sending 2 tests. So the change in y is -0.5 (10.5 - 10), and the change in x is 1. Therefore:

slope = (-0.5) / 1 = -0.5

So Student A's texting rate is -0.5 texts per test.

For Student B, we can look at the graph and find the slope of the line connecting any two points. Let's choose the points (2, 15) and (5, 23) because they are easy to read off the graph. The change in y is 8 (23 - 15), and the change in x is 3 (5 - 2). Therefore:

slope = 8 / 3 = 2.67

So Student B's texting rate is 2.67 texts per minute.

To find the difference in their texting rates, we simply subtract:

difference = Student B's rate - Student A's rate

difference = 2.67 - (-0.5) = 3.17

So the difference in their texting rates is 3.17 texts per test.

Step-by-step explanation:

14% of the time the mean weight of 23 fruits will be greater than approximately 594.33 grams.

What is the Central Limit Theorem (CLT)?

According to the CLT, the distribution of sample means from a population with mean μ and standard deviation σ, will be approximately normal with mean μ and standard deviation σ/√n, where n is the sample size.

In this case, the population mean is 589 grams and the population standard deviation is 16 grams. We are picking a sample of 23 fruits at random, so the standard deviation of the sample means will be:

σ/√n = 16/√23 ≈ 3.33

To find the value of x such that 14% of the time the sample mean will be greater than x, we need to find the z-score that corresponds to the 86th percentile of the standard normal distribution. We can use a table or a calculator to find that z-score:

z = invNorm(0.86) ≈ 1.08

The sample mean is normally distributed with a mean of 589 grams and a standard deviation of 3.33 grams. Using the formula for z-score:

z = (x - μ) / (σ / √n)

We can solve for x:

x = z × (σ / √n) + μ

x = 1.08 × (16 / √23) + 589

x ≈ 594.33 grams

Therefore, 14% of the time the mean weight of 23 fruits will be greater than approximately 594.33 grams.

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The length of the hypotenuse is 28.3

Pythagoras theorem states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.

A right angle triangle is a triangle that has one of it's angles has 90°. And Pythagoras theorem is applied to only right angled triangle.

If a and b are the legs of the triangle and c is the other side(hypotenuse) then,

c² = a²+b²

c² = 19² +21²

c² = 361+441

c² = 802

c = √802

c = 28.3

therefore , if the two legs are 19 and 21, the length of the other side is 28.3

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The length of the hypotenuse is 28.3

Pythagoras theorem states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.

A right angle triangle is a triangle that has one of it's angles has 90°. And Pythagoras theorem is applied to only right angled triangle.

If a and b are the legs of the triangle and c is the other side(hypotenuse) then,

c² = a²+b²

c² = 19² +21²

c² = 361+441

c² = 802

c = √802

c = 28.3

therefore , if the two legs are 19 and 21, the length of the other side is 28.3

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The value of x, y, and z in the rhombus below x = 20, y = -7, z = -11

Recall that a  rhombus is an equilateral parallelogram with both pairs of opposite sides parallel and all sides the same length.

Sum of interior angles of a rhombus = 360°

The opposite angles of a rhombus are equal to each other.

The adjacent angles are supplementary (add up to 180°)

Therefore,

66 + (6x - 6) = 180

⇒ 66 + 6x - 6 = 180

⇒ 6x = 180 - 66 + 6

⇒ 6x = 120

⇒ x = 120 ÷ 6

⇒ x = 20

66 + (-10z + 4) = 180

⇒ 66 - 10z + 4 = 180

⇒ -10z= 180 - 66 - 4

⇒ -10z = 110

⇒ z = 110 ÷ -10

⇒ z = -11

(6x - 6) + (-10y - 4) = 180

⇒ 6x - 6 - 10y - 4 = 180

⇒ 120 - 6 - 10y - 4 = 180

⇒ -10y = 180 - 120 + 6 + 4

⇒ -10y = 70

⇒ y = 70 ÷ -10

⇒ y = -7

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Answer:

[tex]\sf{x = 2}[/tex]

Step-by-step explanation:

Question type: solving equations with variables on both sides.

[tex]\textsf{This is a question with variables on both sides, to solve this we need to get the variable x }[/tex]

[tex]\textsf{alone. (getting the x on one side)}[/tex]

--------------------------------------------------------------

[tex]\sf{-2x~+~4~=~2x~-~4[/tex]

Subtract 4 from both sides.

[tex]\sf{-2x~=~2x~-8[/tex]

Subtract 2x from both sides.

[tex]\sf{-4x~=~-8}[/tex]

Divide both sides by -4.

[tex]\bf{x~=~2[/tex]

Therefore, x would be 2.

[tex]-jurii[/tex]

Answer:

x=2

Step-by-step explanation:

Answer:

155000 milliliters of water

Step-by-step explanation:

We Know

The platoon drank 155 liters of water.

How many milliliters did the platoon drink?

1 liter = 1000 milliliters

155 liters = 155 x 1000 = 155000 milliliters of water

So, the platoon drank 155000 milliliters of water.

The platoon drank 155,000 milliliters of water.

1 liter = 1000 milliliters

Therefore, 155 liters = 155,000 milliliters

So, the platoon drank 155,000 milliliters of water.

Answer:

3/8

Explanation:

I just know :) (;

The answers to Q11 to 14 with the figure representing angles with protractor are as follows:

11.Acute angle= JEH & measure=25°

12.Obtuse angle=JEK & measure=75°

13.One right angle=DEJ

14.One straight angle=DEF

What is protractor ?

With the aid of the scale on it, it serves as a tool for measuring angles. Protractors often feature two sets of numbers that face each other. A protractor is a tool having a semicircular shape and markings from 0° to 180° on both its inner and outer scales. Angles come in many different shapes and sizes in geometry, including obtuse (>90), acute (90), right (90), reflex (180–270), complete (360), and straight (>90).(180).

11)Acute angles:

HEJ=25

JEK=50

KEF=40

HED=65

12)Obtuse angles:

KED=140

JEK=75

13)right angles:

JEF

JED

14)straight lines

DEF

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Step-by-step explanation:

This is basically an inscribed angle in a circle which encompasses twice as many degrees of arc (246) as the angle measure : angle 3 = 123 degrees

The standard form based on the information given will be:

a) 2.35 x 10^-3 = 0.00235 (in standard form)

b) 2.35 x 10^3 = 2350 (in standard form)

It should be noted that in mathematics and computer science, a normal, or standard form of a mathematical object is a standard way of presenting that object as a mathematical expression.

Often, it is one which provides the simplest representation of an object and allows it to be identified in a unique way

he standard form for linear equations in two variables is Ax+By=C. For example, 2x+3y=5 is a linear equation in standard form.

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Answer:

Step-by-step explanation: