Give three examples of unbalanced forces in your everyday life. HELP FAST PLZ

Answer:

D

Explanation:

You should compare your results and data with your original hypothesis.  It is okay to have a hypothesis that was shown to be false.  That's science. Things do not always work out.  You can always discuss what you could have done differently and things that went wrong.  There is no right answer in science!

Answer: Total force = 636,554.55N

Explanation: To determine tension of strings, wave speed on a string is necessary. Speed is found by:

v = f.λ

f is frequency

λ is wavelength

For the strings, wavelength equals to:

[tex]\lambda = 2L[/tex]

L is the length of the bass guitar string

Then, wave speed:

[tex]v=f.2L[/tex]

Tension on a string is

[tex]v=\sqrt{\frac{F_{T}}{\mu} }[/tex]

[tex]v^{2}=\frac{{F_{T}} }{\mu}[/tex]

[tex]F_{T} = v^{2}\mu[/tex]

[tex]F_{T} = (2f\lambda)^{2}\mu[/tex]

[tex]F_{T} = 4(f\lambda)^{2}\mu[/tex]

μ is linear mass density

For g string:

[tex]F_{T} = 4(98.0.865)^{2}.4.8[/tex]

[tex]F_{T}[/tex] = 137970.3N

For d string:

[tex]F_{T} = 4(73.4.0.865)^{2}.4.8[/tex]

[tex]F_{T}=[/tex] 77397.25N

For a string:

[tex]F_{T} = 4(55.0.865)^{2}.29.8[/tex]

[tex]F_{T}=[/tex] 269795N

For e string:

[tex]F_{T} = 4(41.2.0.865)^{2}.29.8[/tex]

[tex]F_{T}=[/tex] 151392N

Total force = 137,970.3 + 77,397.25 + 269,795 + 151,392

Total force = 636,554.55N

Total force exerted on the neck by the strings is 636,554.55N.

This question involves the concepts of the tension force in strings, linear mass density, and frequency.

The total force exerted by strings on the guitar is "359.4 N".

The tension force exerted by each string is given as:

[tex]F_T=v^2\mu[/tex]

where,

F_T = tension force = ?

v = speed = (frequency)(wavelength) = fλ

μ = linear mass density

Therefore,

[tex]F_T=f^2\lambda^2\mu[/tex]

but for strings in this case:

[tex]\lambda = 2(Length of string) = 2(0.865\ m)=1.73\ m[/tex]

Therefore,

[tex]F_T=f^2(1.3\ m)^2\mu[/tex]

For string g:

[tex]F_{Tg}=(98\ Hz)^2(1.3\ m)^2(4.8\ x\ 10^{-3}\ kg/m)\\F_{Tg}=77.9\ N[/tex]

For string d:

[tex]F_{Td}=(73.4\ Hz)^2(1.3\ m)^2(4.8\ x\ 10^{-3}\ kg/m)\\F_{Td}=43.7\ N[/tex]

For string a:

[tex]F_{Ta}=(55\ Hz)^2(1.3\ m)^2(29.8\ x\ 10^{-3}\ kg/m)\\F_{Ta}=152.3\ N[/tex]

For string e:

[tex]F_{Te}=(41.2\ Hz)^2(1.3\ m)^2(29.8\ x\ 10^{-3}\ kg/m)\\F_{Te}=85.5\ N[/tex]

So, the total force will be the sum of all tension forces:

[tex]F=F_{Tg}+F_{Td}+F_{Ta}+F_{Te}[/tex]

F = 77.9 N + 43.7 N + 152.3 N + 85.5 N

F = 359.4 N

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Answer:

722.89

Explanation:

mass=24000kg

volume=33•2

density=?

now,

density=mass/volume

=24000/33•2

=722•89

density=722•89 kg/m^3

Answer:

A boat sails across the Ocean

Explanation:

Out of all the options on Edmentum none of them where moving so it would only make sense that this is the only one with kinetic energy.

Answer:

nnkn

Explanation:

nkn

Answer:

B is correct. Electrons are added to the rod.

Explanation:

Because the fur lose electrons to the rode and because positively charged while the rod because negative

Answer:

Explanation:

a(t)= -2.00 m/s^2 + (3 m/s^3)t.

dv / dt =  -2.00 m/s^2 + (3 m/s^3)t.

dv = (-2.00 m/s^2 + (3 m/s^3)t.)dt

v  = - 2t + 3 t² / 2 + c , where c is a constant

for initial velocity t = 0

v0 = c

v  = - 2t + 3 t² / 2 + v0

ds / dt =  - 2t + 3 t² / 2 + v0

ds =  (- 2t + 3 t² / 2 + v0)dt

s = - 2t²/2 + 3 t³/6 + vot + c₁

At t = 0

s = c₁

At t = 4

s = -16 + 32 + 4v0 + c₁

=  4v0 + c₁ + 16

Given

4v0 + c₁ + 16  = c₁

v0 = - 4 m /s

Putting this value in the equation of velocity

v  = - 2t + 3 t² / 2 - 4

At t = 4

v = -8 + 24 - 4

= 12 m / s

Answer:

No there won't be.

Explanation:

An insulator does not conduct electricity readily. An insulator that is charged at one end will have the charges remain at that end, since it does not allow the free flow of charges through it. If you touch the other end of the insulator that is void of electric charges, there would be no charge transfer between you and the insulator, and hence no electric shock.

Answer:

C.

Explanation:

The element that is most likely to be shiny is calcium. The correct option is 3.

Calcium (Ca) is the most likely to be sparkly of the elements shown. Calcium is a metallic element with a glossy or shining look when newly cut or polished.

It belongs to the alkaline earth metals group, which have metallic characteristics and a distinctive lustre.

Sulphur (S), boron (B), and carbon (C), on the other hand, are non-metallic elements with a dull look.

They come in a variety of forms, including powders, crystals, and amorphous solids, although they are not noted for their metallic lustre.

Thus, the answer is 3. calcium.

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Your question seems incomplete, the probable complete question is:

Which element is most likely to be shiny?

Answer:

a

[tex]I  =  6637 \  W/m^2[/tex]

b

[tex]E_{max} =  500 \ N/m[/tex]

And

[tex]B_{max} =  1.67*10^{-6} \  T[/tex]

Explanation:

From the question we are told that  

   The  power is  [tex]P =  75 \  W[/tex]

   The  diameter is  [tex]d =  6.0 \ cm =  0.06 \  m [/tex]

Generally the radius is mathematically represented as

      [tex]r =  \frac{d}{2}[/tex]

=>   [tex]r =  \frac{ 0.06}{2}[/tex]

=>   [tex]r =  0.03 \  m[/tex]

Generally the area of the sphere is mathematically evaluated as

          [tex]A = 4 \pi r^2[/tex]

=>      [tex]A = 4 * 3.142 *  (0.03)^2[/tex]

=>       [tex]A =  0.0113 \ m^2[/tex]

Generally the total  Intensity of the  incandescent light bulb is mathematically represented as

     [tex]I= \frac{P}{A}[/tex]

=>    [tex]I  =  \frac{75}{ 0.0113}[/tex]

=>   [tex]I  =  6637 \  W/m^2[/tex]

Given that 5%  of the energy goes to visible  light

Then the intensity that goes visible light is  

    [tex]I_v  =  0.05 * 6637[/tex]

    [tex]I_v  =  332 \ W/m^2[/tex]

The amplitude of the electric field at the surface is mathematically represented as

      [tex]E_{max} =  \sqrt{\frac{2 * I_v}{\epsilon_o *  c } }[/tex]

=>   [tex]E_{max} =  \sqrt{\frac{2 * 332}{ 8.85*10^{-12} *  3.0*10^8} }[/tex]

=>     [tex]E_{max} =  500 \ N/m[/tex]

The amplitude of the magnetic  field at the surface is mathematically represented as

     [tex]B_{max} =  \frac{E_{max}}{c}[/tex]

=>     [tex]B_{max} =  \frac{ 500}{3.0*10^8}[/tex]

=>   [tex]B_{max} =  1.67*10^{-6} \  T[/tex]

Answer:

charcoal

Explanation:

Answer:

charcoal

Explanation:

Mark as Brainliest

➝ Density of block = 10.5 g/cm³

➝ Volume of block = 30 cm³

We have to find mass of block[tex].[/tex]

➠ Density is defined as mass of substance per unit volume[tex].[/tex]

[tex]\dag\:\boxed{\bf{Density=\dfrac{Mass}{Volume}}}[/tex]

[tex]:\implies\sf\:Mass=Density\times Volume[/tex]

[tex]:\implies\sf\:Mass=10.5\times 30[/tex]

[tex]:\implies\boxed{\boxed{\bf{\red{Mass=315\:g}}}}[/tex]

Answer:

a

[tex]N_e  =  906 \  electrons[/tex]

b

[tex]M =  9.43 *10^{-25} \  kg[/tex]

Explanation:

From the question we are told that

   The total number of particles is  n =  1470 particles

    The  the total amount of charge on the particles is  [tex]Q =  - 5.456*10^{-17} \  C[/tex]

Generally this total number of particles can be mathematically represented as

      [tex]n  =  N_p + N_e[/tex]

Where  [tex]N_p \  and  \  N_e[/tex] represent the number of proton and electron respectively

=>    [tex]N_p  =  1470  -  N_e[/tex]

Also the total charge of these particles can be mathematically represented as

       [tex]Q = (N_p  - N_e ) e[/tex]

Here e is the charge on a single electron or proton with value  

The  negative sign is due to the fact the electrons are negative signed

     [tex]e =  1.60 *10^{-19} \  C[/tex]

[tex]-5.456*10^{-17} = ( 1470 -2N_e )* 1.60 *10^{-19}  [/tex]

    [tex]N_e = 906[/tex]

Thus  

      [tex]N_p  =  1470 - 906[/tex]

      [tex]N_p  =  564[/tex]

Generally the mass of the system is mathematically represented as

     [tex]M  =  N_e  * M_e  +  N_p  *  M_p[/tex]

Here  [tex]M_e  \  and  \  M_p  \  are  \  mass  \  of  \  electron \  and \  proton \  with \  values \\   M_e = 9.1 *10^{-31} \  kg \  and  \  M_p  =  1.67 *10^{-27} \  kg  \ respectively[/tex]

So

     [tex]M  =  906 *  9.1 *10^{-31}  +  564  *  1.67 *10^{-27}[/tex]

      [tex]M =  9.43 *10^{-25} \  kg[/tex]

Answer:

Step-by-step explanation:

1. Find acceleration:

2. Find distance traveled:

3. Find work done by friction:

Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.

Explanation:I'm very stupid so I don't think this is the right answer

Answer:

21

Explanation:

I think its 21 because its 21

Answer:

Explanation:

Males measuring;

161 - 165 = 2

166 - 170 = 1

171 - 175 = 7

176 - 180 = 1

181 - 185 = 6

186 - 190 = 3

Males taller than 175 cm = 1 + 6 + 3 = 10

Total number of Males = 2 + 1 + 7 + 1 + 6 + 3  = 20

Percentage of total over 175 cm

= 10 / 20

= 50%

Answer:

Option (A)

Explanation:

From the picture attached,

Given : Vector A with magnitude 12 m.

To Find : Components of vector A.

There are two components of any vector.

1). Horizontal component

2). Vertical component

If vector A represents the velocity, horizontal component of a vector decides the horizontal motion and vertical component decides the vertical motion.

To find these components we draw a right triangle OBA as shown in the figure,

From ΔOBA,

Sin(37)° = [tex]\frac{\text{AB}}{\text{OA}}[/tex]

             = [tex]\frac{{A_x}}{{A}}[/tex]

[tex]A_x=A\text{Sin}(37)[/tex]

     = 12Sin(37)°

     = 7.22 m

[tex]A_y=A\text{Cos}(37)[/tex]

     = 12Cos(37)°

     = 9.58 m

Therefore, Option (1) is the correct option.

Answer: They are made of gases

The physical property that all stars have will be they are made of gases. option 1 is correct.

A star is a heavenly body made up of a brilliant spheroid of plasma held together by gravity. The Sun is the closest star to Earth.

Many additional stars may be seen with the normal eye at night, but due to their great distance from Earth, they appear as stationary points of light in the sky.

The physical property that all stars have will be they are made of gases.

Hence option 1 is correct.

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GalileoGalilei is known as the father of science

Answer:

a) 1.19 x 10^7 N/C

b) 2 x 10^-12 N

Explanation:

field due to Cl on (9.0xE¡)(1.6x10-19 C) (1.5Å—10-9m) -6.4x10 N/C field due to Ca+3 ion, 2(90x10 (1.6x10-19c) ((4.5-1.5)Å—10-9 m)' magnitude of net field at given point without dielectric E E+E 6.4x108 +3.2x108-9.6x10 N/C magnitude of net field at given point with di electric K 80.4 the force on sodium ion at this point, F-Edq= (1.19å—107 N/C)(1.6å—10-19C)= 2.0Å—10-12 N

Answer:

The height of the building is 60 m.

Explanation:

Given;

mass of the mass of the ball, m = 3 kg

time of motion, t = 3.5 s

The velocity of the ball is given by;

v = u + gt

where;

u is the initial velocity of the ball = 0

v = 0 + 9.8 x 3.5

v = 34.3 m/s

When the ball hits the ground, energy is conserved;

mgh = ¹/₂mv²

gh = ¹/₂v²

h = (0.5 v²) / g

h = (0.5 x 34.3²) / (9.8)

h = 60.025 m

h = 60 m

Therefore, the height of the building is 60 m.

The height of the building is 60 m.

The velocity of the ball should be provided by

v = u + gt

here,

u is the initial velocity of the ball = 0

v = 0 + 9.8 x 3.5

v = 34.3 m/s

Now

When the ball hits the ground, energy is conserved;

mgh = ¹/₂mv²

gh = ¹/₂v²

h = (0.5 v²) / g

h = (0.5 x 34.3²) / (9.8)

h = 60.025 m

h = 60 m

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Answer:

Serotonin

___________

Answer:

The  value is  [tex]v =  12.5 \  m/s[/tex]

Explanation:

From the question we are told that

    The  height is  [tex]h  =  50 \  m[/tex]

    The  time taken is  [tex]t =  8 \ s [/tex]

From the equation of motion we have  that

 [tex]s =  ut + \frac{1}{2}  * a * t^2[/tex]

Here u = 0  because the rocket started at rest

  [tex]50 =  0 + \frac{1}{2} * a  * 8^2[/tex]

=>   [tex]a =  \frac{100}{64}[/tex]

=>    [tex]a =  1.5625 \ m/s^2[/tex]

Also from the kinematic equation we have that

    [tex]v  =  u + at[/tex]

=>  [tex]v =  0 +  (8  *  1.5625)[/tex]

=>   [tex]v =  12.5 \  m/s[/tex]

Answer:

Explanation:

a) the speed increment of the hammer as it drops past the first window, is greater than that of the speed of the hammer as it drops past the second window. This can also be translated as saying that the hammer spent more time at the second window.

b) III

The best answer would be answer III, The hammer spends more time dropping past window 1, which I had already included in my explanation in (a) above.

Answer:

Explanation:

We may notice that change in velocity can be obtained by calculating areas between acceleration lines and horizontal axis ("Time"). Mathematically, we know that:

[tex]v_{b}-v_{a} = \int\limits^{t_{b}}_{t_{a}} {a(t)} \, dt[/tex]

[tex]v_{b} = v_{a}+ \int\limits^{t_{b}}_{t_{a}} {a(t)} \, dt[/tex]

Where:

[tex]v_{a}[/tex], [tex]v_{b}[/tex] - Initial and final velocities, measured in meters per second.

[tex]t_{a}[/tex], [tex]t_{b}[/tex] - Initial and final times, measured in seconds.

[tex]a(t)[/tex] - Acceleration, measured in meters per square second.

Acceleration is the slope of velocity, as we know that each line is an horizontal one, then, velocity curves are lines with slopes different of zero. There are three region where velocities should be found:

Region I (t = 0 s to t = 4 s)

[tex]v_{4} = 2\,\frac{m}{s} +\int\limits^{4\,s}_{0\,s} {\left(-2\,\frac{m}{s^{2}} \right)} \, dt[/tex]

[tex]v_{4} = 2\,\frac{m}{s}+\left(-2\,\frac{m}{s^{2}} \right) \cdot (4\,s-0\,s)[/tex]

[tex]v_{4} = -6\,\frac{m}{s}[/tex]

Region II (t = 4 s to t = 6 s)

[tex]v_{6} = -6\,\frac{m}{s} +\int\limits^{6\,s}_{4\,s} {\left(1\,\frac{m}{s^{2}} \right)} \, dt[/tex]

[tex]v_{6} = -6\,\frac{m}{s}+\left(1\,\frac{m}{s^{2}} \right) \cdot (6\,s-4\,s)[/tex]

[tex]v_{6} = -4\,\frac{m}{s}[/tex]

Region III (t = 6 s to t = 10 s)

[tex]v_{10} = -4\,\frac{m}{s} +\int\limits^{10\,s}_{6\,s} {\left(2\,\frac{m}{s^{2}} \right)} \, dt[/tex]

[tex]v_{10} = -4\,\frac{m}{s}+\left(2\,\frac{m}{s^{2}} \right) \cdot (10\,s-6\,s)[/tex]

[tex]v_{10} = 4\,\frac{m}{s}[/tex]

Finally, we draw the object's velocity graph as follows. Graphic is attached below.

The velocity of a body under constant acceleration increases steadily with time

Please find attached the required velocity graph for values of t that are separated by Δt = 2s

The reasons the attached graph is correct are given as follows:

The initial velocity of the object at t = 0 is v = 2.0 m/s

The first point on the graph is (0, 2.0)

The acceleration from t = 0, to t = 4, a₁ = -2 m/s²

The velocity at t = 4 s, v₂ = 2.0 + (-2)×4 = -6

Therefore, the next point on the graph is (4, -6)

From t = 4 to t = 6, the acceleration, a₂ = 1 m/s²

Therefore, v₃ = -6 + 1 × 2 = -4

The third point on the velocity graph is (6, -4)

From t = 6 s to t = 10 s, we have, the acceleration, a₃ = 2 m/s²

The velocity, v₄ = -4 + 4 × 2 = 4

Therefore, the fourth point on the velocity graph is (10, 4)

With the above points, the velocity graph can be plotted using MS Excel

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Answer:

1.4 m/s

Explanation:

From the question given above, we obtained the following data:

Initial Displacement (d1) = 0.9 m

Final Displacement (d2) = 1.6 m

Initial time (t1) = 1.5 secs

Final time (t2) = 2 secs

Velocity (v) =..?

The velocity of an object can be defined as the rate of change of the displacement of the object with time. Mathematically, it can be expressed as follow:

Velocity = change of displacement /time

v = Δd / Δt

Thus, with the above formula, we can obtain the velocity of the car as follow:

Initial Displacement (d1) = 0.9 m

Final Displacement (d2) = 1.6 m

Change in displacement (Δd) = d2 – d1 = 1.6 – 0.9

= 0.7 m

Initial time (t1) = 1.5 secs

Final time (t2) = 2 secs

Change in time (Δt) = t2 – t1

= 2 – 1.5

= 0.5 s

Velocity (v) =..?

v = Δd / Δt

v = 0.7/0.5

v = 1.4 m/s

Therefore, the velocity of the car is 1.4 m/s

The rock's altitude y at time t, thrown with initial velocity v, is given by

[tex]y=74\,\mathrm m+vt-\dfrac12gt^2[/tex]

where [tex]g=9.80\frac{\rm m}{\mathrm s^2}[/tex] is the acceleration due to gravity.

After t = 2.7 s, the rock reaches the water (0 altitude), so

[tex]0=74\,\mathrm m+v(2.7\,\mathrm s)-\dfrac12g(2.7\,\mathrm s)^2[/tex]

[tex]\implies v=-\dfrac{74\,\mathrm m-\frac g2(2.7\,\mathrm s)^2}{2.7\,\mathrm s}\approx-14.177\dfrac{\rm m}{\rm s}[/tex]

so the rock was thrown with a velocity with magnitude 14 m/s and downward direction.

Its velocity at time t is [tex]v-gt[/tex] (with no horizontal component), so that at the moment it hits the water, its velocity is

[tex]v-g(2.7\,\mathrm s)\approx-40.637\dfrac{\rm m}{\rm s}[/tex]

That is, its final velocity has an approximate magnitude of 41 m/s, also directed downward.

Answer:

A. Known variables include

Wavelength = 600nm

Theta= 65°

m= 2

B.

d= m x wavelength / sin theta

= 2 * 600*10^-9 /sin 65°

= 1.3*10^-6m

C.

N = 1/d

So N = 1/1.3*10^-6m

=76.9 lines per micro meter