Give an expression that generates all angles coterminal with each angle. Let n represent any interger?
1. 60°
2. 120°

Answer:

18?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given the line L1 as y = 2x perpendicular to an unknown line L2 passing through the point P = (1, 2), we are to find the equation of line L2. to find the equation of the line L2, we will use the point-slope equation of a line expressed as y-y₀ = m(x-x₀)

m is the slope of the unknown line

(x₀, y₀) is the given point.

First is to get the slope of the known line:

comparing the line L1: y = 2x with the standard equation of the line y = mx+c, it can be seen that m = 2

Then we will calculate the slope of the required line.

Since L1 is perpendicular to L2, the product of their slope will be -1 i.e

mm₁ = -1 where m₁ is the slope of the required line L2.

Given m =2

m₁ = -1/m

m₁ = -1/2

Finally we will calculate the equation of line L2 by substituting the slope of line L2 and the point in the point slope equation above;

y-y₀ = m(x-x₀)

Given (x₀, y₀) = (1,2) and m₁ = -1/2

y-2 = -1/2(x-1)

open the parenthesis

y-2 = -x/2+1/2

multiply through by 2:

2y-4 = -x+1

2y+x = 1+4

2y+x = 5

Hence the equation of the line L2 is 2y+x = 5

Answer:

  32 ft

Step-by-step explanation:

The length of the larger rectangle is double that of the smaller one. If we assume the rectangles are similar, the perimeter will be double as well:

  2·(16 ft) = 32 feet . . . . perimeter of larger rectangle

__

The width of the larger one is 2·1.8 ft = 3.6 ft.

Answer:

C) 32 feet

Step-by-step explanation:

＼(ﾟｰﾟ＼)

20(n - 1)

2(n - 7) - 3(2 -6n) =

= 2n - 14 - 6 + 18n

= 20n - 20

= 20(n - 1)

The value of the equation A = 2(n - 7) - 3(2 -6n) is

A = 20 ( n- 1 )

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be A

Now , the equation A = 2( n - 7 ) - 3( 2 - 6n )

The equation can be simplified as

A = 2(n) - 2(7) - 3(2) + 3(6n)

A = 2n - 14 - 6 + 18n

Now , on adding the similar terms in the equation , we get

A = 2n + 18n - ( 14 + 6 )

A = 20n - 20

Taking the common term of 20 , we get

A = 20 ( n - 1 )

Therefore , the value of A is 20 ( n - 1 )

Hence , The value of the equation A = 2(n - 7) - 3(2 -6n) is A = 20 ( n- 1 )

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Answer:

whatever 42 times 10 equals, it also equals what ten minus 4 times seventy is

Step-by-step explanation:

so both 42 × 10

and 10 – 4 × 70

EQUAL

420

(pffft 420....sorry its funny)

Answer:

Associative properties

Step-by-step explanation:

42 x 10 = 420

(10-4)=6

6 x 70 = 420

Answer:

I'm just as confused as you lol

Answer:

I think the answer is A. 49% of the respondents were women

Answer:

t=-6.3

Step-by-step explanation:

-1 (t + 8) = -1.7

-1*t+-1*8=-1.7

-1t-8=-1.7

   +8      +8

-1t=-1.7+8

-1t=6.3

-1t/-1=6.3/-1

t=-6.3

I hope this helped you.

Please mark Brainliest.

Have a great day!!!!!!!!

Answer: -6.3

Step-by-step explanation:

let me know if you have any questions

Answer:

you can just calculate the answer

Step-by-step explanation:

on a calculated put 7766 times 21 and that will be your answer

Answer:

45 Feet

Step-by-step explanation:

4.5 divided by 0.5=9

9 times 5=45

Hoped this helped!

Answer:

(5/2, 6)

Step-by-step explanation:

(x, y)=[(5+0)/2, (9+3)/2]

(x, y)=[5/2, 12/2]

(x, y)=(5/2, 6)

The Midpoint of the Line Segment that has the endpoints (5,9) and (0,3) is (5/2,6).

In geometry, a line segment is a part of a line that is bounded by two end points, and contains every point on the line that is between end points.

Now it is given that,

The endpoints of line segment is (5,9) and (0,3)

So, x₁ = 5

y₁ = 9

x₂ = 0

y₂ = 3

Let (x,y) be the midpoint of segment .

∴To find the midpoint of segment we have,

(x,y) =  {[(x₁+x₂ )/2] , [(y₁+y₂ )/2]}

Put the values, we get

(x,y) = (5+0)/2 , (9+3)/2

solving them,

(x,y) = {(5/2) ,(12/2)}

or,

(x,y) = (5/2,6)

which is the required midpoint of the line segment.

Hence,the Midpoint of the Line Segment that has the endpoints (5,9) and (0,3) is (5/2,6).

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Answer:

6 pencils cost $5.16.

Step-by-step explanation:

1. Find the cost of one pencil.

Divide: $7.74 ÷ 9 = $0.86 for one pencil

2. Multiply 0.86 by 6

$0.86 × 6 = $5.16

Answer:

2/3 multiply with 7.74

=5.16

Answer:

Volume is the measure of how big an object is in three dimensions, so the volume of a box measure how much room there is inside of the box. To find it, you need to make a few simple measurements of length, width, and height, and then multiply them.

Step-by-step explanation:

Answer:

The answer is "x = 0"

Step-by-step explanation:

Step-by-step explanation: Hope this answer is helpful...

Make me as brainliest...

Answer:

First Graph

Step-by-step explanation:

3y-5x<-6

3y<5x-6

y<5/3x-6/3

y<5/3x-2

plug in the coordinates (0,0)

0<0-2

0<-2

0 is not less than -2

therefore the graph would be shaded opposite of (0,0)

Answer:

Two angles are said to be supplementary when they add up to 180°.

Answer:

Angles are supplementary if the add up to 180 degrees

Step-by-step explanation:

So many different angles can be supplementary.

Examples:

Ajacent Angles

Corresponding Angles

Alternate Interior Angles

Alternate Exterior Angles

And a few other angles

Hope This Helps :)

Answer:

14hours

Step-by-step explanation:

Since Andre and Morgan are both heading to the same location i.e Florida, they will have the same distance.

Distance = Speed × Time

For Morgan:

His speed = 55mi/hr

Let his time = x

Distance covered by Morgan = 55x

For Andre

His speed = 70mi/hr

Time = x-3 (since morgan leaves 3 hours earlier than Andre)

Distance covered = 70× (x-3) = 70(x-3)miles

Since they are driving towards the same location;

55x = 70(x-3)

55x = 70x-210

55x-70x = -210

-15x = -210

x = 210/15

x = 14

Hence Morgan will have been driving 14hours before Andre catch up

Answer:

7.12

Step-by-step explanation:

The formula for the effective annual yield is given as:

i = ( 1 + r/m)^m - 1

Where

i = Effective Annual yield

r = interest rate = 7% = 0.07

m= compounding frequency = semi annually = 2

i = ( 1 + 0.07/2)² - 1

i = (1 + 0.035)² - 1

= 1.035² - 1

= 1.071225 - 1

= 0.071225

Converting to percentage

0.071225 × 100

= 7.1225%

Approximately to 2 decimal places = 7.12

Therefore, the annual effective yield = 7.12

Answer:

1) The polynomials [tex]p_{1}(t) = 1 +t^{2}[/tex] and [tex]p_{2}(t) = 1-t^{2}[/tex] are linearly independient, 2) The polynomials [tex]p_{1}(t) = 2\cdot t +t^{2}[/tex] and [tex]p_{2}(t) = 1+t[/tex] are linearly independent, 3) The polynomials [tex]p_{1}(t) = 2\cdot t - 4\cdot t^{2}[/tex] and [tex]p_{2}(t) = 6\cdot t^{2}-3\cdot t[/tex] are linearly dependent.

Step-by-step explanation:

A set is linearly independent if and only if the sum of elements satisfy the following conditions:

[tex]\Sigma_{i=0}^{n} \alpha_{i} \cdot u_{i} = 0[/tex]

[tex]\alpha_{0} = \alpha_{1} =...=\alpha_{i} = 0[/tex]

1) The set of elements form the following sum:

[tex]\alpha_{1}\cdot p_{1}(t)+\alpha_{2}\cdot p_{2}(t) = 0[/tex]

[tex]\alpha_{1}\cdot (1+t^{2})+\alpha_{2}\cdot (1-t^{2}) = 0[/tex]

[tex](\alpha_{1}+\alpha_{2})\cdot (1) +(\alpha_{1}-\alpha_{2})\cdot t^{2} = 0[/tex]

From definition this system of equations must be satisfied:

[tex]\alpha_{1} + \alpha_{2} = 0[/tex] Eq. 1

[tex]\alpha_{1}-\alpha_{2} = 0[/tex] Eq. 2

From Eq. 2:

[tex]\alpha_{1} = \alpha_{2}[/tex]

In Eq. 1:

[tex]2\cdot \alpha_{1} =0[/tex]

[tex]\alpha_{1} = 0[/tex]

[tex]\alpha_{2} = 0[/tex]

The polynomials [tex]p_{1}(t) = 1 +t^{2}[/tex] and [tex]p_{2}(t) = 1-t^{2}[/tex] are linearly independient.

2) The set of elements form the following sum:

[tex]\alpha_{1}\cdot p_{1}(t)+\alpha_{2}\cdot p_{2}(t) = 0[/tex]

[tex]\alpha_{1}\cdot (2\cdot t+t^{2})+\alpha_{2}\cdot (1+t) = 0[/tex]

[tex]\alpha_{2}\cdot (1) +(2\cdot \alpha_{1}+\alpha_{2})\cdot t +\alpha_1 \cdot t^{2} = 0[/tex]

From definition this system of equations must be satisfied:

[tex]\alpha_{2} = 0[/tex]

[tex]2\cdot \alpha_{1}+\alpha_{2} = 0[/tex]

[tex]\alpha_{1} = 0[/tex]

The polynomials [tex]p_{1}(t) = 2\cdot t +t^{2}[/tex] and [tex]p_{2}(t) = 1+t[/tex] are linearly independent.

3) The set of elements form the following sum:

[tex]\alpha_{1}\cdot p_{1}(t)+\alpha_{2}\cdot p_{2}(t) = 0[/tex]

[tex]\alpha_{1}\cdot (2\cdot t-4\cdot t^{2})+\alpha_{2}\cdot (6\cdot t^{2}-3\cdot t) = 0[/tex]

[tex](2\cdot \alpha_{1}-3\cdot \alpha_{2})\cdot t + (-4\cdot \alpha_{1}+6\cdot \alpha_{2})\cdot t^{2} = 0[/tex]

From definition this system of equations must be satisfied:

[tex]2\cdot \alpha_{1}-3\cdot \alpha_{2} = 0[/tex] (Eq. 1)

[tex]-4\cdot \alpha_{1}+6\cdot \alpha_{2} =0[/tex] (Eq. 2)

It is easy to find that each coefficient is multiple of the other one, that is:

[tex]\alpha_{1} =\frac{3}{2}\cdot \alpha_{2}[/tex] (From Eq. 1)

[tex]\alpha_{1} = \frac{6}{4}\cdot \alpha_{2}[/tex] (From Eq. 2)

[tex]\alpha_{1} = \frac{3}{2}\cdot \alpha_{2}[/tex]

Which means that polynomials [tex]p_{1}(t) = 2\cdot t - 4\cdot t^{2}[/tex] and [tex]p_{2}(t) = 6\cdot t^{2}-3\cdot t[/tex] are linearly dependent.

Answer:

____________

y = 2x - 2

____________

I think this is correct

here's it plotted

Answer

y = 2x - 2

Step-by-step explanation

Algebra questions.

if x=3 then 2x3-2=4

So if it WAS 3 then Y would be 4

Answer:

the composition results in [tex]\frac{23}{4}[/tex]

Step-by-step explanation:

Assuming that what you typed for function g is correct (looks a bit peculiar, but we will use it as typed):

[tex]g(x)=-\frac{1}{-4x} +6[/tex]

gof(-2) can be understood as: g(f(-2)), so what we need to do is to find the value for f(-2) using its given expression, and using then the obtained value as input for g(x):

[tex]f(x)=2x^2+2x-5\\f(-2)=2\,(-2)^2+2\,(-2)-5\\f(-2)= 8-4-5\\f(-2)= -1[/tex]

So, we now evaluate g(-1):

[tex]g(x)=-\frac{1}{-4x} +6\\g(-1)= -\frac{1}{-4(-1)} +6\\g(-1)= -\frac{1}{4} +6\\g(-1)=\frac{23}{4}[/tex]

Answer:

18 square units

Step-by-step explanation:

Since the shape is a square lets find the distance between two close point then square the distance to find the answer.

Lets take the point (-7,-5), (-4,-2)

Distance= √((y2-y1)²+(x2-x1)²)

Distance= √((-2--5)²+(-4--7)²)

Distance= √((-2+5)²+(-4+7)²)

Distance= √((3)²+(3)²)

Distance= √(9+9)

Distance= √18 units

Area= distance ²

area= √18²

Area= 18 square unit

Answer:

x > -15

Step-by-step explanation:

-x / 3 < 5

(-x / 3) * 3 < 5 * 3

-x < 15

x > -15 (Remember to flip the sign when multiplying or dividing an inequality by a negative number.)

Answer:

49

Step-by-step explanation:

Answer:

7123

Step-by-step explanation:

The only requirement is to have 7 in the thousands place, which I've done, and the rest of the numbers can be any number you choose!

Answer:

In Alaska, it was -10 degrees in the morning and rose by 12 degrees.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Consider the following planes.  x + y + z = 5, x + 3y + 3z = 5

the parametric equations for the line of intersection of the planes are determined as follows:

From the first plane, the normal of the first plane is [tex]n_1 = (1,1,1)[/tex]

from the second plane, the normal of the second plane is [tex]n_2 = (1,3,3)[/tex]

[tex]n_1 \times n_2 = \begin {vmatrix} \left \begin{array}{ccc}i&j&k\\1&1&1\\1&3&3 \end{array}\right \end {vmatrix}[/tex]

= i(3-3) -j(3-1)+k(3-1)

= i(0) - j(2) + k(2)

= -2j +2k

Suppose z = 0

x+y + 0 = 5  ---(1)

x+3y + 3(0) = 5 (2)

subtracting by elimination

-2y = 0

y = 0/-2

y = 0

The intersection on point of the plane is (5,0,0)

The  equation of plane is r (t) =(5, 0, 0) + t(0, -2, 2)

∴

(x(t), y (t), z(t) ) = (5, -2t, 2t)

B) Find the angle between the planes

The angle between the planes can be represented by the equation:

[tex]cos \theta = \dfrac{a_1a_2+b_1b_2 + c_1c_2}{\sqrt{a^2_1+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}[/tex]

[tex]cos \theta = \dfrac{1 \times 1+1\times 3 +1 \times 3}{\sqrt{1^2+1^2+1^2}\sqrt{1^2+3^2+3^2}}[/tex]

[tex]cos \theta = \dfrac{1+ 3 +3}{\sqrt{3}\sqrt{19}}[/tex]

[tex]cos \theta = \dfrac{7}{\sqrt{3}\sqrt{19}}[/tex]

[tex]\mathbf{\theta = cos ^{-1} (\dfrac{7}{\sqrt{57}})}[/tex]

Answer:

[tex]a^{2} +b^{2} =c^{2}[/tex]

Step-by-step explanation:

C is the horisontal and a or b can be the height, plug in the numbers and you solve for length.

Answer:

(sqr) 30^2/100^2+3^2

Step-by-step explanation: